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Glencoe Geometry Interactive Chalkboard Copyright © by The McGraw-Hill Companies, Inc. Developed by FSCreations, Inc., Cincinnati, Ohio 45202 Send all inquiries to: GLENCOE DIVISION Glencoe/McGraw-Hill 8787 Orion Place Columbus, Ohio 43240 Lesson 10-1 Circles and Circumferences Lesson 10-2 Angles and Arcs Lesson 10-3 Arcs and Chords Lesson 10-4 Inscribed Angles Lesson 10-5 Tangents Lesson 10-6 Secants, Tangents, and Angle Measures Lesson 10-7 Special Segments in a Circle Lesson 10-8 Equations of Circles Example 1 Identify Parts of a Circle Example 2 Find Radius and Diameter Example 3 Find Measures in Intersecting Circles Example 4 Find Circumference, Diameter, and Radius Example 5 Use Other Figures to Find Circumference Name the circle. Answer: The circle has its center at E, so it is named circle E, or . Name the radius of the circle. Answer: Four radii are shown: . Name a chord of the circle. Answer: Four chords are shown: . Name a diameter of the circle. Answer: are the only chords that go through the center. So, are diameters. a. Name the circle. Answer: b. Name a radius of the circle. Answer: c. Name a chord of the circle. Answer: d. Name a diameter of the circle. Answer: Circle R has diameters and . If ST 18, find RS. Formula for radius Substitute and simplify. Answer: 9 Circle R has diameters . If RM 24, find QM. Formula for diameter Substitute and simplify. Answer: 48 Circle R has diameters . If RN 2, find RP. Since all radii are congruent, RN = RP. Answer: So, RP = 2. Circle M has diameters a. If BG = 25, find MG. Answer: 12.5 b. If DM = 29, find DN. Answer: 58 c. If MF = 8.5, find MG. Answer: 8.5 The diameters of and are 22 millimeters, 16 millimeters, and 10 millimeters, respectively. Find EZ. Since the diameter of , EF = 22. Since the diameter of FZ = 5. is part of . Segment Addition Postulate Substitution Simplify. Answer: 27 mm The diameters of and are 22 millimeters, 16 millimeters, and 10 millimeters, respectively. Find XF. Since the diameter of is part of . Since Answer: 11 mm , EF = 22. is a radius of The diameters of , and are 5 inches, 9 inches, and 18 inches respectively. a. Find AC. Answer: 6.5 in. b. Find EB. Answer: 13.5 in. Find C if r = 13 inches. Circumference formula Substitution Answer: Find C if d = 6 millimeters. Circumference formula Substitution Answer: Find d and r to the nearest hundredth if C = 65.4 feet. Circumference formula Substitution Divide each side by . Use a calculator. Radius formula Use a calculator. Answer: a. Find C if r = 22 centimeters. Answer: b. Find C if d = 3 feet. Answer: c. Find d and r to the nearest hundredth if C = 16.8 meters. Answer: MULTIPLE- CHOICE TEST ITEM Find the exact circumference of . A B C D Read the Test Item You are given a figure that involves a right triangle and a circle. You are asked to find the exact circumference of the circle. Solve the Test Item The radius of the circle is the same length as either leg of the triangle. The legs of the triangle have equal length. Call the length x. Pythagorean Theorem Substitution Simplify. Divide each side by 2. Take the square root of each side. So the radius of the circle is 3. Circumference formula Substitution Because we want the exact circumference, the answer is B. Answer: B Find the exact circumference of A Answer: C B C . D Example 1 Measures of Central Angles Example 2 Measures of Arcs Example 3 Circle Graphs Example 4 Arc Length ALGEBRA Refer to Find . . The sum of the measures of Substitution Simplify. Add 2 to each side. Divide each side by 26. Use the value of x to find Given Substitution Answer: 52 ALGEBRA Refer to Find . . form a linear pair. Linear pairs are supplementary. Substitution Simplify. Subtract 140 from each side. Answer: 40 ALGEBRA Refer to a. Find m Answer: 65 b. Find m Answer: 40 . In Find bisects . and is a minor arc, so is a semicircle. is a right angle. Arc Addition Postulate Substitution Subtract 90 from each side. Answer: 90 In Find bisects . and since bisects . is a semicircle. Arc Addition Postulate Subtract 46 from each side. Answer: 67 In Find bisects . and Vertical angles are congruent. Substitution. Substitution. Subtract 46 from each side. Substitution. Subtract 44 from each side. Answer: 316 In and bisects a. Answer: 54 b. Answer: 72 c. Answer: 234 are diameters, Find each measure. and BICYCLES This graph shows the percent of each type of bicycle sold in the United States in 2001. Find the measurement of the central angle representing each category. List them from least to greatest. The sum of the percents is 100% and represents the whole. Use the percents to determine what part of the whole circle each central angle contains. Answer: BICYCLES This graph shows the percent of each type of bicycle sold in the United States in 2001. Is the arc for the wedge named Youth congruent to the arc for the combined wedges named Other and Comfort? The arc for the wedge named Youth represents 26% or of the circle. The combined wedges named Other and Comfort represent . Since º, the arcs are not congruent. Answer: no SPEED LIMITS This graph shows the percent of U.S. states that have each speed limit on their interstate highways. a. Find the measurement of the central angles representing each category. List them from least to greatest. Answer: b. Is the arc for the wedge for 65 mph congruent to the combined arcs for the wedges for 55 mph and 70 mph? Answer: no In and . Find the length of In and Write a proportion to compare each part to its whole. . . degree measure of arc degree measure of whole circle arc length circumference Now solve the proportion for . Multiply each side by 9 . Simplify. Answer: The length of is units or about 3.14 units. In and . Find the length of Answer: units or about 49.48 units . Example 1 Prove Theorems Example 2 Inscribed Polygons Example 3 Radius Perpendicular to a Chord Example 4 Chords Equidistant from Center PROOF Write a proof. Given: is a semicircle. Prove: Proof: Statements Reasons 1. 1. Given is a semicircle. 2. 2. Def. of semicircle 3. 3. In a circle, 2 chords are , corr. minor arcs are . 4. 4. Def. of 5. 5. Def. of arc measure arcs Answer: Statements Reasons 6. 6. Arc Addition Postulate 7. 7. Substitution 8. 8. Subtraction Property and simplify 9. 9. Division Property 10. 10. Def. of arc measure 11. 11. Substitution PROOF Write a proof. Given: Prove: Proof: Statements Reasons 1. 1. Given 2. 2. In a circle, 2 minor arcs are , chords are . 3. 3. Transitive Property 4. 4. In a circle, 2 chords are , minor arcs are . TESSELLATIONS The rotations of a tessellation can create twelve congruent central angles. Determine whether . Because all of the twelve central angles are congruent, the measure of each angle is Let the center of the circle be A. The measure of Then . The measure of Then . Answer: Since the measures of equal, . are ADVERTISING A logo for an advertising campaign is a pentagon that has five congruent central angles. Determine whether . Answer: no Circle W has a radius of 10 centimeters. Radius is perpendicular to chord which is 16 centimeters long. If find Since radius is perpendicular to chord Arc addition postulate Substitution Substitution Subtract 53 from each side. Answer: 127 Circle W has a radius of 10 centimeters. Radius is perpendicular to chord which is 16 centimeters long. Find JL. Draw radius A radius perpendicular to a chord bisects it. Definition of segment bisector Use the Pythagorean Theorem to find WJ. Pythagorean Theorem Simplify. Subtract 64 from each side. Take the square root of each side. Segment addition Subtract 6 from each side. Answer: 4 Circle O has a radius of 25 units. Radius is perpendicular to chord which is 40 units long. a. If Answer: 145 b. Find CH. Answer: 10 Chords and If the radius of are equidistant from the center. is 15 and EF = 24, find PR and RH. are equidistant from P, so . Draw to form a right triangle. Use the Pythagorean Theorem. Pythagorean Theorem Simplify. Subtract 144 from each side. Take the square root of each side. Answer: Chords and are equidistant from the center of If TX is 39 and XY is 15, find WZ and UV. Answer: Example 1 Measures of Inscribed Angles Example 2 Proofs with Inscribed Angles Example 3 Inscribed Arcs and Probability Example 4 Angles of an Inscribed Triangle Example 5 Angles of an Inscribed Quadrilateral In and Find the measures of the numbered angles. First determine Arc Addition Theorem Simplify. Subtract 168 from each side. Divide each side by 2. So, m Answer: In and measures of the numbered angles. Answer: Find the Given: Prove: Proof: Statements Reasons 1. 1. Given 2. 2. If 2 chords are , corr. minor arcs are . 3. 3. Definition of intercepted arc 4. 4. Inscribed angles of arcs are . 5. 5. Right angles are congruent 6. 6. AAS Given: Prove: Proof: Statements Reasons 1. 1. Given 2. 2. Inscribed angles of arcs are . 3. 3. Vertical angles are congruent. 4. 4. Radii of a circle are congruent. 5. 5. ASA PROBABILITY Points M and N are on a circle so that . Suppose point L is randomly located on the same circle so that it does not coincide with M or N. What is the probability that Since the angle measure is twice the arc measure, inscribed must intercept , so L must lie on minor arc MN. Draw a figure and label any information you know. The probability that is the same as the probability of L being contained in . Answer: The probability that L is located on is PROBABILITY Points A and X are on a circle so that Suppose point B is randomly located on the same circle so that it does not coincide with A or X. What is the probability that Answer: ALGEBRA Triangles TVU and TSU are inscribed in with Find the measure of each numbered angle if and are right triangles. since they intercept congruent arcs. Then the third angles of the triangles are also congruent, so . Angle Sum Theorem Simplify. Subtract 105 from each side. Divide each side by 3. Use the value of x to find the measures of Given Answer: Given ALGEBRA Triangles MNO and MPO are inscribed in with Find the measure of each numbered angle if and Answer: Quadrilateral QRST is inscribed in find and Draw a sketch of this situation. If and To find To find we need to know first find Inscribed Angle Theorem Sum of angles in circle = 360 Subtract 174 from each side. Inscribed Angle Theorem Substitution Divide each side by 2. To find find we need to know but first we must Inscribed Angle Theorem Sum of angles in circle = 360 Subtract 204 from each side. Inscribed Angle Theorem Divide each side by 2. Answer: Quadrilateral BCDE is inscribed in find and Answer: If and Example 1 Find Lengths Example 2 Identify Tangents Example 3 Solve a Problem Involving Tangents Example 4 Triangles Circumscribed About a Circle ALGEBRA is tangent to at point R. Find y. Because the radius is perpendicular to the tangent at the point of tangency, . This makes a right angle and a right triangle. Use the Pythagorean Theorem to find QR, which is one-half the length y. Pythagorean Theorem Simplify. Subtract 256 from each side. Take the square root of each side. Because y is the length of the diameter, ignore the negative result. Answer: Thus, y is twice . is a tangent to Answer: 15 at point D. Find a. Determine whether is tangent to First determine whether ABC is a right triangle by using the converse of the Pythagorean Theorem. Pythagorean Theorem Simplify. Because the converse of the Pythagorean Theorem did not prove true in this case, ABC is not a right triangle. Answer: So, is not tangent to . Determine whether is tangent to First determine whether EWD is a right triangle by using the converse of the Pythagorean Theorem. Pythagorean Theorem Simplify. Because the converse of the Pythagorean Theorem is true, EWD is a right triangle and EWD is a right angle. Answer: Thus, making a tangent to a. Determine whether Answer: yes is tangent to b. Determine whether Answer: no is tangent to ALGEBRA Find x. Assume that segments that appear tangent to circles are tangent. are drawn from the same exterior point and are tangent to so are drawn from the same exterior point and are tangent to Definition of congruent segments Substitution. Use the value of y to find x. Definition of congruent segments Substitution Simplify. Subtract 14 from each side. Answer: 1 ALGEBRA Find a. Assume that segments that appear tangent to circles are tangent. Answer: –6 Triangle HJK is circumscribed about perimeter of HJK if Find the Use Theorem 10.10 to determine the equal measures. We are given that Definition of perimeter Substitution Answer: The perimeter of HJK is 158 units. Triangle NOT is circumscribed about perimeter of NOT if Answer: 172 units Find the Example 1 Secant-Secant Angle Example 2 Secant-Tangent Angle Example 3 Secant-Secant Angle Example 4 Tangent-Tangent Angle Example 5 Secant-Tangent Angle Find Method 1 if and Method 2 Answer: 98 Find if Answer: 138 and Find Answer: 55 if and Find Answer: 58 if and Find x. Theorem 10.14 Multiply each side by 2. Add x to each side. Subtract 124 from each side. Answer: 17 Find x. Answer: 111 JEWELRY A jeweler wants to craft a pendant with the shape shown. Use the figure to determine the measure of the arc at the bottom of the pendant. Let x represent the measure of the arc at the bottom of the pendant. Then the arc at the top of the circle will be 360 – x. The measure of the angle marked 40° is equal to one-half the difference of the measure of the two intercepted arcs. Multiply each side by 2 and simplify. Add 360 to each side. Divide each side by 2. Answer: 220 PARKS Two sides of a fence to be built around a circular garden in a park are shown. Use the figure to determine the measure of Answer: 75 Find x. Multiply each side by 2. Add 40 to each side. Divide each side by 6. Answer: 25 Find x. Answer: 9 Example 1 Intersection of Two Chords Example 2 Solve Problems Example 3 Intersection of Two Secants Example 4 Intersection of a Secant and a Tangent Find x. Theorem 10.15 Multiply. Divide each side by 8. Answer: 13.5 Find x. Answer: 12.5 BIOLOGY Biologists often examine organisms under microscopes. The circle represents the field of view under the microscope with a diameter of 2 mm. Determine the length of the organism if it is located 0.25 mm from the bottom of the field of view. Round to the nearest hundredth. Draw a model using a circle. Let x represent the unknown measure of the equal lengths of the chord which is the length of the organism. Use the products of the lengths of the intersecting chords to find the length of the organism. Note that Segment products Substitution Simplify. Take the square root of each side. Answer: 0.66 mm ARCHITECTURE Phil is installing a new window in an addition for a client’s home. The window is a rectangle with an arched top called an eyebrow. The diagram below shows the dimensions of the window. What is the radius of the circle containing the arc if the eyebrow portion of the window is not a semicircle? Answer: 10 ft Find x if EF 10, EH 8, and FG 24. Secant Segment Products Substitution Distributive Property Subtract 64 from each side. Divide each side by 8. Answer: 34.5 Find x if Answer: 26 and Find x. Assume that segments that appear to be tangent are tangent. Disregard the negative solution. Answer: 8 Find x. Assume that segments that appear to be tangent are tangent. Answer: 30 Example 1 Equation of a Circle Example 2 Use Characteristics of Circles Example 3 Graph a Circle Example 4 A Circle Through Three Points Write an equation for a circle with the center at (3, –3), d 12. Equation of a circle Simplify. Answer: Write an equation for a circle with the center at (–12, –1), r 8. Equation of a circle Simplify. Answer: Write an equation for each circle. a. center at (0, –5), d 18 Answer: b. center at (7, 0), r 20 Answer: A circle with a diameter of 10 has its center in the first quadrant. The lines y –3 and x –1 are tangent to the circle. Write an equation of the circle. Sketch a drawing of the two tangent lines. Since d 10, r 5. The line x –1 is perpendicular to a radius. Since x –1 is a vertical line, the radius lies on a horizontal line. Count 5 units to the right from x –1. Find the value of h. Likewise, the radius perpendicular to the line y –3 lies on a vertical line. The value of k is 5 units up from –3. The center is at (4, 2), and the radius is 5. Answer: An equation for the circle is . A circle with a diameter of 8 has its center in the second quadrant. The lines y –1 and x 1 are tangent to the circle. Write an equation of the circle. Answer: Graph Compare each expression in the equation to the standard form. The center is at (2, –3), and the radius is 2. Graph the center. Use a compass set at a width of 2 grid squares to draw the circle. Answer: Graph Write the expression in standard form. The center is at (3, 0), and the radius is 4. Draw a circle with radius 4, centered at (3, 0). Answer: a. Graph Answer: b. Graph Answer: ELECTRICITY Strategically located substations are extremely important in the transmission and distribution of a power company’s electric supply. Suppose three substations are modeled by the points D(3, 6), E(–1, 0), and F(3, –4). Determine the location of a town equidistant from all three substations, and write an equation for the circle. Explore You are given three points that lie on a circle. Plan Graph DEF. Construct the perpendicular bisectors of two sides to locate the center, which is the location of the tower. Find the length of a radius. Use the center and radius to write an equation. Solve Graph DEF and construct the perpendicular bisectors of two sides. The center appears to be at (4, 1). This is the location of the tower. Find r by using the Distance Formula with the center and any of the three points. Write an equation. Examine You can verify the location of the center by finding the equations of the two bisectors and solving a system of equations. You can verify the radius by finding the distance between the center and another of the three points on the circle. Answer: AMUSEMENT PARKS The designer of an amusement park wants to place a food court equidistant from the roller coaster located at (4, 1), the Ferris wheel located at (0, 1), and the boat ride located at (4, –3). Determine the location for the food court and write an equation for the circle. Answer: Explore online information about the information introduced in this chapter. Click on the Connect button to launch your browser and go to the Glencoe Geometry Web site. At this site, you will find extra examples for each lesson in the Student Edition of your textbook. When you finish exploring, exit the browser program to return to this presentation. If you experience difficulty connecting to the Web site, manually launch your Web browser and go to www.geometryonline.com/extra_examples. Click the mouse button or press the Space Bar to display the answers. Click the mouse button or press the Space Bar to display the answers. Click the mouse button or press the Space Bar to display the answers. Click the mouse button or press the Space Bar to display the answers. Click the mouse button or press the Space Bar to display the answers. Click the mouse button or press the Space Bar to display the answers. Click the mouse button or press the Space Bar to display the answers. Click the mouse button or press the Space Bar to display the answers. End of Custom Shows WARNING! Do Not Remove This slide is intentionally blank and is set to auto-advance to end custom shows and return to the main presentation.