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Chapter 14 Mendel and the Gene Idea PowerPoint Lectures for Biology, Seventh Edition Neil Campbell and Jane Reece Lectures by Chris Romero Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Gregor Mendel – experiments with garden peas Figure 14.1 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Mendel’s Experimental Approach • Why peas? = available in many varieties = could strictly control mating Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Mendel’s Experimental Approach Stamens (Male) Carpel (Female) Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Mendel’s Experimental Approach Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Mendel’s Experimental Approach Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Genetics Vocabulary Alternative versions of genes = Alleles Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Genetics Vocabulary Organism inherits 2 alleles: • 1 from mom, 1 from dad – A genetic locus is represented twice Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Genetics Vocabulary • If the two alleles at a locus differ… • Dominant allele = determines appearance • Recessive allele = no noticeable effect on appearance Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Genetic Vocabulary: Homozygous vs. Heterozygous • Homozygous for a particular gene – Identical pair of alleles for that gene • Ex: PP (2 purple flower alleles) • True-breeding - Homozygous dominant (PP) - Homozygous recessive (pp) Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Homozygous vs. Heterozygous • Homozygous for a particular gene – Identical pair of alleles for that gene • Ex: PP (2 purple flower alleles) • True-breeding • Heterozygous for a particular gene – Has a pair of alleles that are different for that gene • Ex: Pp (1 purple allele, 1 white allele) Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Homozygous or Heterozygous? Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Genetics Vocabulary • An organism’s genotype (EX: Pp, PP, pp) – genetic makeup • An organism’s phenotype (Ex: Purple or white) – physical appearance Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Phenotype versus genotype Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Phenotype versus genotype Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Mendel used : • Characters that varied in an “either-or” manner • Varieties that were “true-breeding” Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Typical Mendelian Experiment Parental Generation Hybridization F1 Generation F1 self-pollinate F2 generation Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings All Purple Hybrids 3:1 Purple : White Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Does Mendel’s segregation model account for the 3:1 ratio observed in the F2 generation? – We can answer this question using a Punnett square Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Other pea plant characters Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Construct a Punnett Square for the following crosses: • Seed color: Y = Yellow, y = green – YY X Yy – Expected ratio observed in offspring? • Seed shape: R = Round, r = wrinkled – Rr X rr – Expected ratio observed in offspring? Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings The Testcross • In pea plants with purple flowers – Genotype is not obvious (Pp or PP)? = Perform testcross Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings The testcross Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings The testcross Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Monohybrid Cross Mendel Followed a single trait (ex: flower color) • The P = true-breeding (PP or pp) • The F1 offspring = monohybrids (heterozygous for one character) (Pp) Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Dihybrid Cross • Mendel followed 2 characters at the same time • P generation = Cross two, true-breeding parents differing in two characters – YYRR X yyrr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Character 1 Y =YELLOW y =green Character 2 R=ROUND r = wrinkled Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Mendel followed 2 characters at the same time • P generation = Cross two, true-breeding parents differing in two characters – YYRR X yyrr • F1 generation = Produces dihybrids (heterozygous for both characters) – YyRr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 2. Independent Assortment of Chromosomes Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 2. Independent Assortment of Chromosomes Homologous orient randomly at metaphase I of meiosis Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • How are two characters transmitted from parents to offspring? 1. As a package? (Ex: yellow and round YR) • =Dependent Assortment 2. Independently? • =Independent Assortment Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings A dihybrid cross Only YR and yr as inherited from P generation? YR Yr yR yr ? Make a punnett square for each case Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Concept 14.2: The rules of probability govern Mendelian inheritance • Multiplication Rule • Addition Rule Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings The Multiplication and Addition Rules Applied to Monohybrid Crosses • The multiplication rule – Probability that two or more independent events will occur together – Ex: coin toss – Heads ½ X Heads ½ = ¼ Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Ex: Probability in a monohybrid cross Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Rule of Addition • Probability that any one of two or more exclusive events will occur Ex: Heterozygotes: ¼Rr + ¼rR = ½ Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • A multi-character cross = two or more independent monohybrid crosses occurring simultaneously • Calculate the chances for various genotypes: 1. Consider each character separately 2. Go back to question being asked 3. Multiply individual probabilities together 4. Use Rule of addition (if necessary) Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • 3 characters = trihybrid cross – Purple flowers (Pp), Yellow (Yy), Round (Rr) – Purple flowers (Pp), green (yy), wrinkled (rr) • PpYyRr X Ppyyrr Question: What percentage of the offspring from this cross would be predicted to have purple flowers and green and wrinkled seeds? Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • 1. Consider each character separately (make a punnett square for each character) PpYyRr X Ppyyrr: – Pp X Pp = – Yy X yy = – Rr X rr = Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • 1. Consider each character separately (make a punnett square for each character) – PpYyRr X Ppyyrr – Pp X Pp = ¼ PP, ½ pP, ¼ pp – Yy X yy = ½ Yy, ½ yy – Rr X rr = ½ Rr, ½ rr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 2. Go back to the original Question PpYyRr X Ppyyrr – Pp X Pp = ¼ PP, ½ pP, ¼ pp – Yy X yy = ½ Yy, ½ yy – Rr X rr = ½ Rr, ½ rr Question: What percentage of the offspring from this cross would be predicted to have purple flowers and green and wrinkled seeds? Start by listing all genotypes that fulfill this condition: Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 2. Go back to the original Question PpYyRr X Ppyyrr – Pp X Pp = ¼ PP, ½ Pp, ¼ pp – Yy X yy = ½ Yy, ½ yy – Rr X rr = ½ Rr, ½ rr Question: What percentage of the offspring from this cross would be predicted to have purple flowers and green and wrinkled seeds? Start by listing all genotypes that fulfill this condition: Ppyyrr, PPyyrr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 3. Calculate probability for each genotype – Pp X Pp = ¼ PP, ½ pP, ¼ pp – Yy X yy = ½ Yy, ½ yy – Rr X rr = ½ Rr, ½ rr • Ppyyrr ½ X ½ X ½ • Ppyyrr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings = 2/16 3. Calculate probability for each genotype – Pp X Pp = ¼ PP, ½ pP, ¼ pp – Yy X yy = ½ Yy, ½ yy – Rr X rr = ½ Rr, ½ rr • Ppyyrr ½ X ½ X ½ = 2/16 • PPyyrr ¼ X ½ X ½ =1/16 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 4. Rule of addition 2/16 Ppyyrr +1/16 Ppyyrr 3/16 = chance that the offspring from this cross would have purple flowers and green and wrinkled seeds Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • A multi-character cross #2 = two or more independent monohybrid crosses occurring simultaneously • Calculate the chances for various genotypes: 1. Consider each character separately 2. Go back to question being asked 3. Multiply individual probabilities together 4. Use Rule of addition Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • 3 characters = trihybrid cross #2 – white flowers (pp), Yellow (Yy), wrinkled (rr) – Purple flowers (Pp), green (yy), Round (Rr) • ppYyrr X PpyyRr Question: What percentage of the offspring from this cross would be predicted to have white flowers and green and wrinkled seeds? Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • 1. Consider each character separately (make a punnett square for each character) ppYyRr X Ppyyrr: – pp X Pp = ½ Pp, ½ pp – Yy X yy = ½ Yy, ½ yy – rr X Rr = ½ Rr, ½ rr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 2. Go back to the original Question ppYyRr X Ppyyrr: – pp X Pp = ½ Pp, ½ pp – Yy X yy = ½ Yy, ½ yy – rr X Rr = ½ Rr, ½ rr Question: What percentage of the offspring from this cross would be predicted to have white flowers and green and wrinkled seeds? Start by listing all genotypes that fulfill this condition: Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 2. Go back to the original Question ppYyRr X Ppyyrr: – pp X Pp = ½ Pp, ½ pp – Yy X yy = ½ Yy, ½ yy – rr X Rr = ½ Rr, ½ rr Question: What percentage of the offspring from this cross would be predicted to have white flowers and green and wrinkled seeds? Start by listing all genotypes that fulfill this condition: ppyyrr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 3. Calculate probability for each genotype ppYyRr X Ppyyrr: – pp X Pp = ½ Pp, ½ pp – Yy X yy = ½ Yy, ½ yy – rr X Rr = ½ Rr, ½ rr • ppyyrr ½ pp X ½ yy X ½ rr Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings = 1/8 Concept 14.3 • Inheritance patterns are often more complex than predicted by simple Mendelian genetics • The relationship between genotype (Ex: Pp) and phenotype (Ex: purple) is rarely simple Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings The Spectrum of Dominance • Complete dominance – Phenotypes of the heterozygote and dominant homozygote are identical Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Codominance – Two dominant alleles affect the phenotype in separate, distinguishable ways • Ex: human blood group MN • MM = RBC with M molecules • NN = RBC with N molecules • MN = ? Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Incomplete dominance F1 hybrid phenotype is between the phenotypes of the two parental varieties Figure 14.10 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Dominance and Phenotype • Dominant and recessive alleles – Do not “interact” – Different alleles = synthesis of different proteins that produce a phenotype Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Dominance and Phenotype • Dominant and recessive alleles – Do not “interact” – Different alleles = synthesis of different proteins that produce a phenotype • Ex: flower color – White (W) vs. Red (R) – W= protein that produces white pigment – R = protein that produces red pigment Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Multiple Alleles • Most genes exist in populations – In more than two allelic forms 1 2 1 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings 2 3 • The ABO blood group in humans – Is determined by multiple alleles: • 3 different alleles for enzyme I – IA = attaches the A carbohydrate – IB = attaches the B carbohydrate – i = attaches neither A nor B Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Table 14.2 Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Complex inheritance patterns • Codominance • Incomplete dominance • Multiple alleles – Mendel’s fundamental laws still apply! Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Concept 14.4: • Human traits follow Mendelian patterns of inheritance • Humans = not convenient subjects for genetic research How can we study Human Genetics? Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Concept 14.4: • Human traits follow Mendelian patterns of inheritance • Humans = not convenient subjects for genetic research How can we study Human Genetics? = Pedigree analysis Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Male = Female = Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Follow Attached earlobe = ff Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Carriers? • Disease condition = aa • No disease symptoms = Aa or AA Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Mating of Close Relatives • Mating between relatives – Can increase the probability of the appearance of a genetic disease cc Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Cc CC Cc Cc • Albinism- recessive phenotype • Only aa Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Albinism- recessive phenotype Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings • Human achondroplasia phenotype • The phenotype is determined by a dominant allele = AA or Aa Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Human achondroplasia: Dominant allele disease Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings PHENYLKETONURIA - [PKU] pp • Autosomal recessive disorder • Gene for phenylalanine hydroxylase (PAH), found on chromosome 12 mutated • PAH converts the amino acid phenylalanine to tyrosine • No PAH = concentration of phenylalanine in the body can build up to toxic levels Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings PKU: Recessive disease (pp) Pp pp Pp/PP Pp Pp Pp Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Pp Pp Review! • Mendel’s Pea experiments: • Experimental method • Typical Mendelian experiment: – P, F1, F2 • Monohybrid cross vs. Dihybrid cross • Law of Segregation and Law of Independent assortment Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings Review! • Solving Multi-hybrid crosses with probability • More complex inheritance patterns: – Co-dominance, Incomplete dominance, Multiple alleles • Pedigree Analysis Copyright © 2005 Pearson Education, Inc. publishing as Benjamin Cummings