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Physics of Technology PHYS 1800 Lecture 15 Introduction Section 0 Momentum Lecture 1 Slide 1 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 1 PHYSICS OF TECHNOLOGY Spring 2009 Assignment Sheet Date Day Lecture Chapter Jan 5 M Class Admin: Intro.Physics Phenomena 1 6 T Problem solving and math App. B, C 7 W Units, Scalars, Vectors, 1 9 F* Speed and Velocity 2 Jan 12 M Acceleration 2 14 W Free Falling Objects 3 16 F* Projectile Motion 3 Jan 19 M Martin Luther King No Class 21 W Newton’s Laws 4 23 F* Mass and Weight 4 Jan 26 M Motion with Friction 4 28 W Review 1-4 1-4 29 Th Test 1 30 F Circular Motion 5 Feb 2 M Planetary Motion and Gravity 5 4 W Energy 6 6 F* Harmonic Motion 6 Feb 9 M Momentum 7 11 W Impulse and Collisions 7 13Introduction F* Rotational 8 Section 0 Motion Lecture 1 Slide 2 Feb 16 M Presidents Day No Class 17 Tu Angular Momentum (Virtual Monday) 8 18 W Review 5-8 19 5-8 H Test 2 INTRODUCTION TO Modern Physics PHYX 2710 20 F* Static Fluids, Pressure 9 Fall 2004 Feb 23 M Flotation 9 *Homework 25 WHandout Fluids in Motion 9 27 F* Temperature and Heat 10 Mar 2 M First Law of Thermodynamics 10 Physics of Technology—PHYS 1800 4 W Spring 2009Heat flow and Greenhouse Effect Momentum 10 6 F* Climate Change - Homework Due - 1 2 3 4 5 - 6 Lecture 15 Slide 2 7 Physics of Technology PHYS 1800 Lecture 15 Momentum Introduction Section 0 Lecture 1 Slide 3 Introduction INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 3 Describing Motion and Interactions Position—where you are in space (L or meter) Velocity—how fast position is changing with time (LT-1 or m/s) Acceleration—how fast velocity is changing with time (LT-2 or m/s2) Force— what is required to change to motion of a body (MLT-2 or kg-m/s2 or N) Energy—the potential for an object to do work. (ML2T-2 or kg m2/s2 or N-m or J) Work is equal to the force applied times the distance moved. W = F d Kinetic Energy is the energy associated with an object’s motion. KE=½ mv2 Potenital Energy is the energy associated with an objects position. Gravitational potential energy PEgravity=mgh Spring potential energy PEapring= -kx Introduction Section 0 Lecture 1 Slide 4 In this chapter we will develop the concept of…MOMENTUM…and and its associated law of Conservation of Momentum and apply this to collisions. INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 4 Defining Work • Work is equal to the force applied times the distance moved. – Work = Force x Distance: – Work output = Work input W=Fd • units: 1 joule (J) = 1 Nm = 1 kg m2 / s2 [ML2T-2] Introduction Section 0 Lecture 1 Slide 5 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 5 Momentum and Collisions • How can we describe the change in velocities of colliding football players, or balls colliding with bats? • How does a strong force applied for a very short time affect the motion? • Can we apply Newton’s Laws to collisions? • What exactly is momentum? How is it different from force or energy? • What does “Conservation of Momentum” mean? Initial time Δt=tfinal – tinitial Introduction Section 0 Lecture 1 INTRODUCTION TO Modern Physics PHYX 2710 ΔW=F Δd Slide 6 with Δd=dfinal – dinitial Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Final time Δp=F Δt Momentum with Δt=tfinal – tinitial Lecture 15 Slide 6 What happens when a ball bounces? • When it reaches the floor, its velocity quickly changes direction. • There must be a strong force exerted on the ball by the floor during the short time they are in contact. • This force provides the upward acceleration necessary to change the direction of the1 Slide Introduction Section 0 Lecture ball’s velocity. 7 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 7 What happens when a ball bounces? • Forces like this are difficult to analyze: • Strong forces that act for a very short time. • Forces that may change rapidly during the collision. • It will help to write Newton’s second law in terms of the total change in velocity over time, instead of acceleration: Introduction Section 0 Lecture 1 v Fnet ma m t Slide 8 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 8 Momentum and Impulse • Multiply both sides of Newton’s second law by the time interval over which the force acts: • The left side of the equation is impulse, the (average) force acting on an object multiplied by the time interval over which the force acts. v Fnet ma m t Fnet t mv • How a force changes the motion of an object depends on both the size of the force and how long the force acts. • The right side of the equation is the change in the momentum of the object. Introduction Section 0 Lecture 1 Slide 9 • The momentum of the object is the mass of the object times its velocity. p mv INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 9 Momentum and Impulse A bowling ball and a tennis ball can have the same momentum, if the tennis ball with its smaller mass has a much larger velocity. Introduction Section 0 Lecture 1 Slide 10 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 10 Impulse-Momentum Principle The impulse acting on an object produces a change in momentum of the object that is equal in both magnitude and direction to the impulse. impulse = change in momentum = p In analogy, Introduction Section 0 Lecture 1 work INTRODUCTION TO Modern Physics PHYX 2710 Slide 11 = change in energy = ΔE Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 11 Impulse-Momentum Principle When a ball bounces back with the same speed, the momentum changes from mv to -mv, so the change in momentum is 2mv. Introduction Section 0 Lecture 1 Slide 12 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 12 A Closer Look at Collisions Look here carefully! Introduction Section 0 Lecture 1 Slide 13 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 13 Compression on an Atomic Scale Bonds between atoms in a compressed solid can be treated as compressed springs. + + + + Ultimately the forces come from electrostatic interactions between electrons and protons (and a little quantum mechanics). + + Section 0 Lecture 1 Slide 14 + + Introduction Fspring=-k Δx + INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 14 What Happens During the Collision? • Does Newton’s third law still hold? – For every action, there is an equal but opposite reaction. – The defensive back exerts a force on the fullback, and the fullback exerts an equal but opposite force on the defensive back. Introduction Section 0 Lecture 1 Slide 15 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 15 Conservation of Momentum • Does Newton’s third law still hold? – For every action, there is an equal but opposite reaction. – The defensive back exerts a force on the fullback, and the fullback exerts an equal but opposite force on the defensive back. Introduction Section 0 Lecture 1 Slide 16 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 16 Conservation of Momentum – The impulses on both are equal and opposite. – The changes in magnitude for each are equal and opposite. – The total change of the momentum for the two players is zero. Introduction Section 0 Lecture 1 Slide 17 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 17 Conservation of Momentum If the net external force acting on a system of objects is zero, the total momentum of the system is conserved. Introduction Section 0 Lecture 1 Slide 18 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 18 A 100-kg fullback moving straight downfield collides with a 75-kg defensive back. The defensive back hangs on to the fullback, and the two players move together after the collision. What is the initial momentum of each player? Introduction Section 0 Lecture 1 Slide 19 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 19 What is the initial momentum of each player? Fullback: p = mv = (100 kg)(5 m/s) = 500 kg·m/s2 Introduction Section 0 Lecture 1 Defensive back: p = mv = (75 kg)(-4 m/s) = -300 kg·m/s2 Slide 20 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 20 What is the total momentum of the system? Total momentum: ptotal = pfullback + pdefensive back = 500 kg·m/s - 300 kg·m/s = 200 kg·m/s Introduction Section 0 Lecture 1 Slide 21 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 21 What is the velocity of the two players immediately after the collision? Total mass: m = 100 kg + 75 kg = 175 kg Velocity of both: v = pIntroduction m 0 Lecture 1 Slide 22 total / Section = (200 kg·m/s) / 175 kg = 1.14 m/s INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 22 Recoil • Why does a shotgun slam against your shoulder when fired, sometimes painfully? • How can a rocket accelerate in empty space when there is nothing there to push against except itself? Introduction Section 0 Lecture 1 Slide 23 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 23 Physics of Technology Next Lab/Demo: Energy & Oscillations Momentum and Collisions Thursday 1:30-2:45 ESLC 53 Ch 6 and 7 Next Class: Wednesday 10:30-11:20 BUS 318 room Review Ch 6 Slide 24 Read Ch 7 Introduction Section 0 Lecture 1 INTRODUCTION TO Modern Physics PHYX 2710 Fall 2004 Physics of Technology—PHYS 1800 Spring 2009 Momentum Lecture 15 Slide 24