* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Lecture09-09
Survey
Document related concepts
Hooke's law wikipedia , lookup
Coriolis force wikipedia , lookup
Relativistic mechanics wikipedia , lookup
Nuclear force wikipedia , lookup
Fictitious force wikipedia , lookup
Newton's theorem of revolving orbits wikipedia , lookup
Electromagnetism wikipedia , lookup
Fundamental interaction wikipedia , lookup
Newton's laws of motion wikipedia , lookup
Centrifugal force wikipedia , lookup
Hunting oscillation wikipedia , lookup
Classical central-force problem wikipedia , lookup
Transcript
Chapter 7 Work and Kinetic Energy Reading and Review Vertical circular motion Centripetal acceleration must be C vertical (down) B horizontal A vertical (up) Condition for falling: N=0 at C: So, as long as: at the top, then N>0 and pointing down. (now apparent weight is in the opposite direction to true weight!) Barrel of Fun A rider in a “barrel of fun” finds herself stuck with her back to the wall. Which diagram correctly shows the forces acting on her? a b c d e Barrel of Fun A rider in a “barrel of fun” finds herself stuck with her back to the wall. Which diagram correctly shows the forces acting on her? a b c d The normal force of the wall on the rider provides the centripetal force needed to keep her going around in a circle. The downward force of gravity is balanced by the upward frictional force on her, so she does not slip vertically. Follow-up: What happens if the rotation of the ride slows down? e Around the Curve You are a passenger in a car, not wearing a seat belt. The car makes a sharp left turn, and you find yourself hitting the passenger door. What is the correct description of what is actually happening? a) centrifugal force is pushing you into the door b) the door is exerting a leftward force on you c) both of the above d) neither of the above Around the Curve You are a passenger in a car, not wearing a seat belt. The car makes a sharp left turn, and you find yourself hitting the passenger door. What is the correct description of what is actually happening? a) centrifugal force is pushing you into the door b) the door is exerting a leftward force on you c) both of the above d) neither of the above The passenger has the tendency to continue moving in a straight line. There is a net centripetal force, provided by the door, that forces the passenger into a circular path. Working Hard... or Hardly Working Atlas holds up the world. Sisyphus pushes his rock up a hill. (b) (a) Who does more work? Working Hard... or Hardly Working Atlas holds up the world. Sisyphus pushes his rock up a hill. (b) (a) With no displacement, Atlas does no work Work Done by a Constant Force The definition of work, when the force is parallel to the displacement: SI unit: newton-meter (N·m) = joule, J Friction and Work I A box is being pulled across a rough floor a) friction does no work at all at a constant speed. b) friction does negative work What can you say c) friction does positive work about the work done by friction? Friction and Work I A box is being pulled across a rough floor a) friction does no work at all at a constant speed. b) friction does negative work What can you say c) friction does positive work about the work done by friction? Friction acts in the opposite direction to N Displacement the displacement, so the work is negative. Or using the definition of work (W = F Pull f (Δr)cos ), because = 180º, then W < 0. mg Friction and Work II Can friction ever do positive work? a) yes b) no Friction and Work II Can friction ever do positive work? a) yes b) no Consider the case of a box on the back of a pickup truck. If the box moves along with the truck, then it is actually the force of friction that is making the box move. Forces not along displacement If the force is at an angle to the displacement: Convenient notation: the dot product The work can also be written as the dot product of the force and the displacement: Force and displacement The work done may be positive, zero, or negative, depending on the angle between the force and the displacement: Sum of work by forces = work by sum of forces If there is more than one force acting on an object, we can find the work done by each force, and also the work done by the net force: Units of Work 1 kcal = 1 Cal = 4.186 kJ Lifting 0.5 L H2O up 20 cm = 1 J Play Ball! In a baseball game, the catcher stops a 90-mph a) catcher has done positive work pitch. What can you say b) catcher has done negative work about the work done by the c) catcher has done zero work catcher on the ball? Play Ball! In a baseball game, the catcher stops a 90-mph a) catcher has done positive work pitch. What can you say b) catcher has done negative work about the work done by the c) catcher has done zero work catcher on the ball? The force exerted by the catcher is opposite in direction to the displacement of the ball, so the work is negative. Or using the definition of work (W = F (Δr)cos ), because = 180º, then W < 0. Note that the work done on the ball is negative, and its speed decreases. Follow-up: What about the work done by the ball on the catcher? Tension and Work A ball tied to a string is being whirled around in a circle. What can you say about the work done by tension? a) tension does no work at all b) tension does negative work c) tension does positive work Tension and Work A ball tied to a string is being whirled around in a circle. What can you say about the work done a) tension does no work at all b) tension does negative work c) tension does positive work by tension? No work is done because the force acts in a perpendicular direction to the displacement. Or using the definition of work (W = F (Δr)cos ), because = 90º, then W = 0. T v Follow-up: Is there a force in the direction of the velocity? Work by gravity Fg a A ball of mass m drops a distance h. What is the total work done on the ball by gravity? W = Fd = Fg x h h W = mgh Path doesn’t matter when asking “how much work did gravity do?” Only the change in height! A ball of mass m rolls down a ramp of height h at an angle of 45o. What is the total work done on the ball by gravity? a Fgx = Fg sinθ N h = L sinθ Fg W = Fd = Fgx x L = (Fg sinθ) (h / sinθ) W = Fg h = mgh θ h Path independence • If a force depends on POSITION only then the work done by it on an object moving from r1 to r2 will NOT depend upon the path. • Such a force is called a Conservative Force Motion and energy When positive work is done on an object, its speed increases; when negative work is done, its speed decreases. Kinetic Energy After algebraic manipulations of the equations of motion, we find: Therefore, we define the kinetic energy: Work-Energy Theorem Work-Energy Theorem: The total work done on an object is equal to its change in kinetic energy. (True for rigid bodies that remain intact) Lifting a Book You lift a book with your hand in a) mg ∆ r such a way that it moves up at b) FHAND ∆ r constant speed. While it is c) [FHAND + mg] ∆ r moving, what is the total work d) zero done on the book? e) none of the above ∆r FHAND mg v = const a=0 Lifting a Book You lift a book with your hand in a) mg ∆ r such a way that it moves up at b) FHAND ∆ r constant speed. While it is c) (FHAND + mg) ∆ r moving, what is the total work d) zero done on the book? e) none of the above The total work is zero because the net force acting on the book is zero. The work done by ∆r FHAND the hand is positive, and the work done by gravity is negative. The sum of the two is v = const a=0 zero. Note that the kinetic energy of the book does not change either! mg Follow-up: What would happen if FHAND were greater than mg? Kinetic Energy I By what factor does the a) no change at all kinetic energy of a car b) factor of 3 change when its speed is c) factor of 6 tripled? d) factor of 9 e) factor of 12 Kinetic Energy I By what factor does the a) no change at all kinetic energy of a car b) factor of 3 change when its speed is c) factor of 6 tripled? d) factor of 9 e) factor of 12 Because the kinetic energy is mv2, if the speed increases by a factor of 3, then the KE will increase by a factor of 9. Slowing Down If a car traveling 60 km/hr can brake to a stop within 20 m, what is its stopping distance if it is traveling 120 km/hr? Assume that the braking force is the same in both cases. a) 20 m b) 30 m c) 40 m d) 60 m e) 80 m Slowing Down If a car traveling 60 km/hr can brake to a stop within 20 m, what is its stopping distance if it is traveling 120 km/hr? Assume that the braking force is the same in both cases. F d = Wnet = ∆KE = 0 – and thus, |F| d = mv2, mv2. Therefore, if the speed doubles, the stopping distance gets four times larger. a) 20 m b) 30 m c) 40 m d) 60 m e) 80 m Application: ball on a track how high must I place the ball so that it can complete a loop? Condition: Fcp > mg at top of loop Fcp = mv2/r = mg v2 = gr KE = mv2 / 2 = mgr/2 Gravity must provide this energy Wg = mg∆h = KE ∆h = r/2 above the top of the loop! Work Done by a Variable Force If the force is constant, we can interpret the work done graphically: Work Done by a Variable Force If the force takes on several successive constant values: Work Done by a Variable Force We can then approximate a continuously varying force by a succession of constant values. Work Done by a Variable Force The force needed to stretch a spring an amount x is F = kx. Therefore, the work done in stretching the spring is Application: work by a spring Hooke’s Law: F = - kx k = (3kg)(9.8 m/s2) / (3.9 cm) k = 760 N/m Loaded spring: W = kx2/2 = (760 N/m) (0.04m)2/ 2 W = 0.61 J How fast?: v = d/t = (0.020 m) (0.020 s) = 1 m/s Kinetic Energy: KE = mv2/2 = (1kg)(1m/s)2 / 2 KE = 0.55 J Power Power is a measure of the rate at which work is done: Pave W t SI unit: J/s = watt, W 1 horsepower = 1 hp = 746 W Power Power If an object is moving at a constant speed in the face of friction, gravity, air resistance, and so forth, the power exerted by the driving force can be written: F x x P F Fv t t Question: what is the total work per unit time done on the object? Electric Bill When you pay the electric company by the kilowatt-hour, what are you actually paying for? a) energy b) power c) current d) voltage e) none of the above Electric Bill When you pay the electric company by the kilowatt-hour, what are you actually paying for? a) energy b) power c) current d) voltage e) none of the above We have defined: Power = energy / time So we see that: Energy = power × time This means that the unit of power × time (watt-hour) is a unit of energy !! A block rests on a horizontal frictionless surface. A string is attached to the block, and is pulled with a force of 45.0 N at an angle above the horizontal, as shown in the figure. After the block is pulled through a distance of 1.50 m, its speed is 2.60 m/s, and 50.0 J of work has been done on it. (a) What is the angle (b) What is the mass of the block? The pulley system shown is used to lift a 52 kg crate. Note that one chain connects the upper pulley to the ceiling and a second chain connects the lower pulley to the crate. Assuming the masses of the chains, pulleys, and ropes are negligible, determine (a) the force F required to lift the crate with constant speed, and (b) the tension in two chains (a) the force F required to lift the crate with constant speed, and (b) the tension in two chains (a) constant velocity, a=0, so net force =0. 2T - (52kg)(9.8m/s2) = 0 T = 250 N F = -250 Ny (b) upper pulley doesn’t move: Tch - 2Trope = 0 Tch = 500 N Mechanical Advantage! lower pulley has constant acceleration Tch -2Trope =0 Tch = 500 N What about work? (a) how much power is applied to the box by the chain? (b) how much power is applied on the rope by the applied force? Trope = 250 N Tchain = 500 N F = -250 Ny (a) P = Fv = 500 N * vbox (b) P = Fv = 250 N * vhand hand moves twice as fast hand moves twice as far