* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download Problem 3.67 For the circuit in Fig. P3.66, find the Thévenin
Survey
Document related concepts
Opto-isolator wikipedia , lookup
Resistive opto-isolator wikipedia , lookup
Flexible electronics wikipedia , lookup
Operational amplifier wikipedia , lookup
Wien bridge oscillator wikipedia , lookup
Transistor–transistor logic wikipedia , lookup
Lumped element model wikipedia , lookup
Valve RF amplifier wikipedia , lookup
Integrated circuit wikipedia , lookup
Charlieplexing wikipedia , lookup
Regenerative circuit wikipedia , lookup
Rectiverter wikipedia , lookup
Zobel network wikipedia , lookup
Index of electronics articles wikipedia , lookup
Two-port network wikipedia , lookup
Current source wikipedia , lookup
Electrical ballast wikipedia , lookup
Transcript
Problem 3.67 For the circuit in Fig. P3.66, find the Thévenin equivalent circuit as seen by the 6-Ω resistor connected between terminals (c, d) as if the 6-Ω resistor is a load resistor connected to (but external to) the circuit. Determine the current flowing through that resistor. 4A c 4Ω + d _ Voc 8Ω 4Ω I1 + _ 10 Ω 48 V I2 Solution: 16I1 − 12I2 = −48 I2 = −4 A Hence, I1 = −6 A. To find Voc , we write a KVL equation for loop in lower right-hand corner: −48 + 8(I2 − I1 ) +Voc + 10I2 = 0 Voc = 48 + 8I1 − 18I2 = 48 − 48 + 18 × 4 = 72 V. Suppressing the sources: Req c 4Ω 4Ω d 10 Ω 8Ω RTh = 14 Ω. I c 6Ω d 14 Ω +_ I= 72 72 = = 3.6 A. 14 + 6 20 72 V c All rights reserved. Do not reproduce or distribute. 2013 National Technology and Science Press