Download Module 11 Act. 1

After completing the exploration of Activity 1,
Module 11
2. SWABT
•use the fundamental counting principle
•apply their knowledge of the fundamental counting
principle to determine simple probabilities
•solve discussion, warm-up and assignment problems
on pages 307-310 with
3. at least 85% accuracy
1.
Fundamental counting principle
Fundamental Counting
Principle =Fancy way of describing how
one would determine the number of
ways a sequence of events can take
place.
You are at your school cafeteria that allows you to choose a lunch
meal from a set menu. You have two choices for the Main course
(a hamburger or a pizza), Two choices of a drink (orange juice,
apple juice) and Three choices of dessert (pie, ice cream, jello).
How many different meal combos can you select?_________
Answer: 12 meals
Method one: Tree diagram
Lunch
Hamburger
Apple
Pie
Icecream
Jello
Orange
Pie
Icecream
Jello
Pizza
Apple
Pie
Icecream
Jello
Orange
Pie
Icecream
Jello
Method two:
Multiply number of choices
2 x 2 x 3 = 12 meals
Ex 2: No repetition
During the Olympic 400m sprint, there are 6 runners. How many possible
ways are there to award first, second, and third places?
1st
2nd
3rd
5 x ____
4 =
3 places 6
____ x ____
120 different ways
Ex 3: With repetition
License Plates for cars are labeled with 3 letters followed by 3 digits.
(In this case, digits refer to digits 0 - 9. If a question asks for numbers,
its 1 - 9 because 0 isn't really a number)
How many possible plates are there? You can use the same number
more than once.
10 x ___
___
26 x ___
26 x ___
26 x ___
10 x ___
10 =
17,576,000 plates
Account numbers for Century Oil Company consist of
five digits. If the first digit cannot be a 0 or 1, how many
account numbers are possible?
Ex 4:
___
8 x ___
10 x ___
10 x ___
10 x ___
10 =
80,000 different account #’s
We are going to collect data from cars in the student parking lot.
License place
1
2
3
4
.
.
.
.
.
50
Vehicle color
Factorials - Quote
Space and time are
intimately intertwined
and indissolubly
connected with each
other.
Sir William Rowan Hamilton
Factorials
5 • 4 • 3 • 2 • 1 = 5! Factorial
7!= 7 • 6 • 5 • 4 • 3 • 2 •1
= 5040
7! 7  6  5  4  3  2  1

 42
5!
5  4  3  2 1
8!
8  7  6  5  4  3  2 1 8  7  6


5!3! 5  4  3  2  1  3  2  1 3  2  1
87
 56
1