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Lecture 3 CHEM102 Periodic Properties of the Elements Dr. Noha Osman Learning Outcomes By the end of this session, the student should be able to: 1. Identify the trends of properties of elements in the periodic table. 2. Arrange different elements according to the size of their atomic and ionic radii. 3. Arrange elements according to their ionization energies. 4. Arrange elements according to their electronegativity. Development of Periodic Table Dmitri Mendeleev and Lothar Meyer independently came to the same conclusion about how elements should be grouped. Development of Periodic Table Mendeleev, for instance, proposed the existence of an unknown element (which he called eka-silicon) and predicted a number of its properties. When Germanium was discovered later, it matched the predicted properties of eka-silicon remarkably well. Periodic Trends • Periodic trends among the elements will be rationalized with respect to: Atomic/ Ionic radii. Ionization energy. Electron affinity. Effective Nuclear Charge Zeff is the nuclear charge felt by an electron when both the actual nuclear charge and the repulsive effects (shielding) of other electrons are taken into account. • In a many-electron atom, electrons are both attracted to the nucleus and repelled by other electrons. • The nuclear charge that an electron experiences depends on both factors. Effective Nuclear Charge • The effective nuclear charge, Zeff, is found this way: Zeff = Z − S where; - Z : is the atomic number (or actual nuclear charge) - S : is the shielding constant, usually close to the number of inner (core) electrons. Atomic Radius • The size of an atomic orbital cannot be specified exactly, neither can the size of an atom. • The atomic radius is defined as one-half of the distance between the nuclei in a molecule consisting of identical atoms. Atomic Radius The bonding atomic radius tends to: — Decrease from left to right across a row (due to increasing Zeff). — Increase from top to bottom of a column (due to the increasing value of n). Ionic Radius Cation Anion Loss of 1 or more electrons: Gain of 1 or more electrons: - Reduces electron-electron repulsion - Increases electron-electron repulsion - No change in the nuclear charge (p+) - No change in the nuclear charge (p+) - Electron cloud shrinks - Domain of electron cloud enlarges The cation is smaller than its corresponding atom. Na+ (0.095 nm) vs Nao (0.186 nm) The anion is larger than its corresponding atom Cl- (0.181 nm) vs Clo (0.099nm) Practice Excercise Arrange the following sets of atoms and ions in order of increasing size using the periodic table 1. Mg, Al, Ca. 2. S, Cl, S23. Fe, Fe2+, Fe3+ 1. 2. 3. Comparison with reference to Mg: Al is to the right to Mg, thus smaller than Mg. Ca is below Mg, thus larger. The order is Al < Mg < Ca. Comparison with reference to S atom: Cl is to the right to S, thus is smaller. The S2- anion is larger than the S atom. The order is Cl <S < S2-. Comparison with reference to Fe2+ ion: Feo atom is neutral and thus is larger than its cations. The Fe3+ ion is charged by loss of 3 e- while Fe2+ is charged due to loss of 2 e-. The order is Fe3+< Fe2+< Fe. THE ELECTRONIC CONFIGURATION OF ELEMENTS (only outer shell level of electrons is represented) THE CHEMICAL PROPERTIES OF ANY ATOM ARE DETERMINED BY THE CONFIGURATION OF THE ATOM’S VALENCE ELECTRONS. Ionisation Energy • Ionization energy is the minimum energy (in kJ/mol) required to remove an electron from a gaseous atom in its ground state. X + energy X+ + 1 e• The 1st ionization energy (endothermic process = requires E) is the E change for the removal of the outermost e- from a gaseous atom to form a +1 ion. The more difficult it is to remove e-, the larger the ionization energy. • 2nd and 3rd IE (to remove a 2nd and a 3rd e-) are certainly more difficult due to the increasing attraction exerted by the nucleus at every loss of 1 e- after the other. Moreover, there is less shielding effect due to electron loss, therefore a higher Zeff. Trends in First Ionization Energies • As one goes down a group, less energy is required to remove the first electron since the valence electrons are farther from the nucleus. Trends in First Ionization Energies • Generally, as one goes from left to right across a period, more energy is required to remove an electron. – As you go from left to right, Zeff increases (electrons are more tightly held by the nucleus) Exceptions to trends of first IE (1st exception) Between Group 2A and 3A elements in the same period E.g: Be vs B and Mg vs Al. IE of 3A < 2A in the same period: In this case the electron is removed from a p orbital rather than an s orbital. • The electron removed is farther from the nucleus. • There is also a small amount of repulsion by the s electrons (which decreases the Zeff) Exceptions to trends of first IE (2nd exception) Between Groups 5A and 6A elements in the same period E.g: N vs. O and P vs. S IE of 6A < 5A in the same period. In 5A ( ns2np3 ), the p e- are in 3 separate orbitals while in 6A (ns2np4), the additional e- is paired with 1 of the 3 p e- The proximity of two e- in the same orbital leads to high electrostatic repulsion, which makes it easier to ionize an atom of the Group 6A element, even though the nuclear charge has increased by one unit. Test yourself Complete: 1. Ionization energy (IE) …………a………….across the periodic table from left to right and ………b……….. moving down the periodic table. 2. Comparing the trends of ionic radii and ionization energy it is clear that there is an ………c………. correlation between them. 3. The ………d…….. the atom, the more tightly its electrons are held to the positively charged nucleus and the more difficult they are to remove thus the ………e…….. the ionization energy. Answers: a) increases, b) decreases, c) inverse, d) smaller, e) larger, f) large, g) ionization. Test yourself Which atom with following electron configurations has the largest first ionization energy, explain your choice. 1s22s22p6 1s22s22p63s1 1s22s22p63s2 The atom with the largest value of IE is 1s22s22p6 (this is a Ne), because it is found at the right end of period 2, and the IE increases from left to right in the same period of the periodic table. As for the other 2 configurations including 3s electrons they will be of lower IE because it is easier to loose e- from a sublevel that is farther away from the nucleus. Electron Affinity (Electronegativity) Electron affinity is the energy change that occurs when an e- is accepted by an atom in the gaseous state to form an anion. X + e− X− Electronegativity increases from left to right across a period. This is because the Zeff increases from left to right across a period. N.B The halogens (Group 7A) have the highest electronegativity, however irregularities to this trend exists. Exceptions to trends in electron affinity Between Groups 1A and 2A elements in the same period E.g Li (2s1) vs Be (2s2) EA of 2A (ns2) < 1A (ns1) in the same period: • The added electron must go in a higher-energy np orbital, not an s orbital, which is farther from the nucleus. • Moreover, the added electron is effectively shielded by the ns2 electrons, therefore experiences a weaker attraction to the nucleus. Exceptions to trends in electron affinity Between Groups 4A and 5A elements in the same period E.g C (2s2 2p2) vs N (2s2 2p3) EA of 5A (ns2np3) < 4A (ns2np2) in the same period: • The added electron must go into an np orbital that already contains 1 electron, creating greater electrostatic repulsion. Exceptions to trends in electron affinity Group 8A (Noble Gases; ns2np6) E.g Ne (2s2 2p6) • An electron added to an atom with ns2np6 configuration has to enter an (n+1)s orbital, where it is well shielded by the core electrons, is farther away from the nucleus and therefore will only be very weakly attracted by the nucleus (i.e Zeff is v. low). • This also explains why species with complete valence shells are chemically stable. THANK YOU