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Transcript
```Lesson 10
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Lesson 10: Unknown Angle ProofsβProofs with
Constructions
Student Outcome
ο§
Students write unknown angle proofs involving auxiliary lines.
Lesson Notes
On the second day of unknown angle proofs, students incorporate the use of constructions, specifically auxiliary lines, to
help them solve problems. In this lesson, students refer to the same list of facts they have been working with in the last
few lessons. The aspect that sets this lesson apart is thatnecessary information in the diagram may not be apparent
without some modification. One of the most common uses for an auxiliary line is in diagrams where multiple sets of
parallel lines exist. Encourage students to mark up diagrams until the necessary relationships for the proof become
more obvious.
Classwork
Opening Exercise (6 minutes)
Review the Problem Set from Lesson 9. Then, the whole class works through an example of a proof requiring auxiliary
lines.
Opening Exercise
In the figure to the right, π¨π© || π«π¬ and π©πͺ || π¬π­. Prove that π = π. (Hint:
Proof:
π=π
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
π=π
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
π=π
Transitive Property
Lesson 10:
Date:
Unknown Angle ProofsβProofs with Constructions
4/29/17
78
Lesson 10
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
In the previous lesson, you used deductive reasoning with labeled diagrams to prove specific conjectures. What is
Drawing or extending segments, lines, or rays (referred to as auxiliary lines) is frequently useful in demonstrating steps in
the deductive reasoning process. Once π©πͺ and π¬π« were extended, it was relatively simple to prove the two angles
congruent based on our knowledge of alternate interior angles. Sometimes there are several possible extensions or
additional lines that would work equally well.
For example, in this diagram, there are at least two possibilities for
auxiliary lines. Can you spot them both?
Prove: π = π + π.
Discussion (7 minutes)
Students explore different ways to add auxiliary lines (construction) to the same diagram.
Discussion
Here is one possibility:
Prove: π = π + π.
Extend the transversal as shown by the dotted line in the diagram.
Label angle measuresπand π, as shown.
What do you know about π and π?
Write a proof using the auxiliary segment drawn in the diagram to the right.
MP.
7
π=π+π
Exterior angle of a triangle equals the sum of the two interior opposite angles
π=π
If parallel lines are cut by a transversal, then corresponding angles are equal in measure
π=π
Vertical angles are equal in measure
π =π+π
Substitution Property of Equality
Another possibility appears here:
Prove:π = π + π.
Draw a segment parallel to π¨π© through the vertex of the anglemeasuring
Lesson 10:
Date:
Unknown Angle ProofsβProofs with Constructions
4/29/17
79
Lesson 10
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
π degrees. This divides it into angles two partsas shown.
What do you know about πand π?
They are equal since they are corresponding angles of parallel lines crossed by a transversal.
They are also equal in measure since they are corresponding angles of parallel lines crossed by a transversal.
Write a proof using the auxiliary segment drawn in this diagram. Notice how this proof differs from the one above.
π=π
If parallel lines are cut by a transversal, then corresponding angles are equal in measure
π=π
If parallel lines are cut by a transversal, then corresponding angles are equal in measure
π=π+π
π =π+π
Substitution Property of Equality
Examples (25 minutes)
Examples
1.
In the figure at the right, π¨π© || πͺπ« and π©πͺ || π«π¬.
(Where will you draw an auxiliary segment?)
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
Transitive Property
c°
2.
In the figure at the right, π¨π© || πͺπ« and π©πͺ || π«π¬.
Prove that π + π = πππ.
Label π.
π=π
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
π + π = πππ
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
π + π = πππ
Substitution Property of Equality
Lesson 10:
Date:
Unknown Angle ProofsβProofs with Constructions
4/29/17
80
Lesson 10
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
3.
In the figure at the right, prove that π = π + π + π.
Z
z
Label πand π.
π =π+π
Exterior angle of a triangle equals the sum of the two interior opposite angles
π= π+π
Exterior angle of a triangle equals the sum of the two interior opposite angles
π= π+π+π
Substitution Property of Equality
Exit Ticket (5 minutes)
Lesson 10:
Date:
Unknown Angle ProofsβProofs with Constructions
4/29/17
81
Lesson 10
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Name ___________________________________________________
Date____________________
Lesson 10: Unknown Angle ProofsβProofs with Constructions
Exit Ticket
Write a proof for each question.
1.
In the figure at the right, ΜΜΜΜ
π΄π΅ β₯ ΜΜΜΜ
πΆπ· . Prove that π = π.
bo
A
C
2.
ao
B
D
Prove πβ π = πβ π.
Lesson 10:
Date:
Unknown Angle ProofsβProofs with Constructions
4/29/17
82
Lesson 10
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Exit Ticket Sample Solutions
Write a proof for each question.
1.
In the figure at the right, ΜΜΜΜ
π¨π© β₯ ΜΜΜΜ
πͺπ«. Prove that π = π.
bo
A
C
ao
B
D
Write in angles πand π.
2.
π=π
Vertical angles are equal in measure
π=π
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
π=π
Vertical angles are equal in measure
π=π
Substitution Property of Equality
Prove πβ π = πβ π.
Mark angles a, b, c, and d.
πβ π + πβ π = πβ π + πβ π
If parallel lines are cut by a transversal, then alternate interior angles are equal
in measure
πβ π = πβ π
If parallel lines are cut by a transversal, then alternate interior angles are equal
in measure
πβ π = πβ π
If parallel lines are cut by a transversal, then alternate interior angles are equal
in measure
πβ π + πβ π = πβ π + πβ π
If parallel lines are cut by a transversal, then alternate interior angles are equal
in measure
πβ π = πβ π
If parallel lines are cut by a transversal, then alternate interior angles are equal
in measure
πβ π = πβ π
Substitution Property of Equality
πβ π = πβ π
Substitution Property of Equality
Lesson 10:
Date:
Unknown Angle ProofsβProofs with Constructions
4/29/17
83
Lesson 10
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Problem Set Sample Solutions
1.
In the figure at the right, π¨π© || π«π¬ and π©πͺ || π¬π­.
Extend DE through BC, and mark the intersection with BC as Z.
2.
If parallel lines are cut by a transversal, then corresponding angles are equal in measure
ποπ¬ππͺ = ποπ«π¬π­
If parallel lines are cut by a transversal, then corresponding angles are equal in measure
Transitive Property
In the figure at the right, π¨π© || πͺπ«.
Prove that ποπ¨π¬πͺ = π° + π°.
ΜΜΜΜ;
ΜΜΜΜand πͺπ«
Draw in line through E parallel to π¨π©
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
ποπ«πͺπ¬ = ποπ­π¬πͺ
If parallel lines are cut by a transversal, then alternate interior angles are equal in measure
ποπ¨π¬πͺ = π° + π°