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1 Energy Bands in Solids 1.1 INTRODUCTION Electronics (coined from the word ‘electron’) is the branch of science and engineering dealing with the theory and use of a class of devices in which electrons are transported through a vacuum, gas or semiconductor. The motion of electrons in such devices, called electron devices, is usually controlled by electric fields. Diodes, triodes, transistors etc. are examples of electron devices. Electronics can be broadly classified into two branches: physical electronics and electronic engineering. Physical electronics treats the motion of electrons in a vacuum, gas or semiconductor. The design, fabrication, and application of electron devices form the subject matter of electronic engineering. Electronics has inroads into many fields of science and technology, and has profoundly influenced the life of modern man. Modern computers and communication systems are intimately linked with advances in electronics. We list below some areas of application of electronics; the list is, however, far from complete. (i) In home, we use a variety of electronic systems: radios, TVs, VCRs, CD players, telephone answering machines, PCs, microwave ovens, pocket calculators, digital watches, etc. (ii) Round-the-globe communication via microwave or fibre-optic links and satellites, and access to internets have been possible with advances in electronics. This has shaped the global village. (iii) Sophisticated electronic instruments are used for researches in various fields of science and engineering. (iv) The commercial and industrial sectors rely on electronic communication, information processing, and control systems. (v) Electronic radar systems are employed for a safe flight from one airport to another. A modern aircraft is equipped with electronic sensors and computers. (vi) Electronic communication and radars play a vital role in meleorology, defence, and military services. (vii) Modern medical practice relies on precise diagonistic and monitoring electronic systems. For better times, and at times for worse, electronics has shaped our lives. Our living standards have improved, but we are also at the peril of deadly weapons that would not have appeared without the progress in electronics. 1 2 1.2 Electron Devices and Circuits CHARGED PARTICLES Electric charges, positive or negative, occur in multiples of the electronic charge. The electron is one of the fundamental particles constituting the atom. The charge of an electron is negative and is denoted by e. The magnitude of e is 1.6 × 10–19 coulomb. The mass of an electron changes with its velocity in accordance with the theory of relativity. An electron moving with a velocity v has the mass m= m0 1 − v2 / c 2 (1.1) where c is the velocity of light in free space (c = 3 × 108 m/s). If v << c, m ≈ m0, called the rest mass of the electron. The rest mass of the electron has the value m0 = 9.11 × 10–31 kg. Equation (1.1) shows that the mass m increases with the velocity v and approaches infinity as v → c. An electron, starting from rest and accelerated through a potential difference of 6 kV, acquires a velocity of 0.15 c. At this high speed, the mass of the electron increases only by 1 per cent. Therefore, the change of the mass of an electron with velocity can be neglected for accelerating potentials less than 6 kV. The radius of an electron is about 10–15 m and that of an atom is 10–10 m. The radii are so small that electrons and atoms are ordinarily taken as point masses. Electron Volt: Unit of Energy For energies involved in electron devices, ‘joule’ is too large a unit. Such small energies are conveniently measured in electron volt, abbreviated eV. The electron volt is the kinetic energy gained by an electron, initially at rest, in moving through a potential difference of 1 volt. Since e = 1.6 × 10–19 coulomb, 1 eV = 1.6 × 10–19 coulomb × 1 volt = 1.6 × 10–19 joule. 1.3 ATOMIC ENERGY LEVELS An atom of an element is generally made up of electrons, protons, and neutrons. The only exception is the hydrogen atom which possesses one electron and one proton, but no neutron. While an electron is negatively charged, the proton is a positively charged particle. The charge of a proton is numerically equal to that of an electron, but the mass of a proton is 1837 times that of an electron. A neutron is a neutral particle having a mass nearly equal to the proton mass. Because the protons and neutrons carry practically the entire mass of the atom, they remain almost immobile in a region, called the atomic nucleus. The electrons revolve round the nucleus in definite orbits which are circular or elliptical. The motion is analogous to that of planets around the sun. The atom is electrically neutral because the number of orbital electrons is equal to the number of protons in the nucleus. The atom of one element differs from that of another due to the differing numbers of protons, neutrons, and electrons in the atom. In the Bohr atomic model, the electrons are assumed to move about the nucleus in certain discrete circular orbits without radiating any energy. In any orbit, the angular momentum of the electron is equal to an integral multiple of h/(2π), where h is Planck’s constant (h = 6.62 × 10–34 J.s). The integral number n has values 1, 2, 3 etc. for different orbits. The higher the value of n, the larger the radius of the orbit. dharm E:\N-up\ana1-1.p65 3 The allowable discrete values of n show that all energies are not permitted for the electrons. The electrons can have only certain discrete energies corresponding to the different integral values of n. In other words, the electron energy is quantised. The allowable energies are represented by horizontal lines in a diagram, called the energy level diagram of the atom. Fig. 1.1 shows such a diagram. When an electron jumps from a higher energy level Eh to a lower energy level El , an electromagnetic radiation of frequency ν is emitted, where Energy (eV) Energy Bands in Solids n ¥ 5 4 3 2 1 Fig. 1.1 Energy level diagram of an atom. Eh − El (1.2) h h being Planck’s constant. On the contrary, on absorbing a photon of energy hν, an electron initially at the energy state El can move to the energy state Eh. An electron normally occupies the lowest energy state, called the ground level, in the atom. The other higher lying energy levels are called the excited levels of the atom. By absorbing more and more energies, an electron can move into excited states which are farther and farther away from the nucleus. If the energy is sufficiently high, the electron can overcome the attraction of the nucleus and gets detached from the atom. The energy required for this to occur is known as the ionization potential. The energy level corresponding to n = ∞ in Fig. 1.1 represents the ionization level. As the electrons are electrostatically attracted by the positively charged nucleus, the allowed energies for the electrons are negative. The ionization level represents the zero level of energy. The energies become more and more negative with decreasing values of n. The wavelengths emitted from the atom due to electronic transitions from higher energy states to lower ones give the spectral lines characterising the atom. To explain the details of the spectral lines of some elements, improvements over the simple Bohr model have been made. Quantum mechanical treatments have introduced four quantum numbers, designated by n, l, ml and ms. The quantum numbers can take the following values: n = 1, 2, 3, ... l = 0, 1, 2, ..., (n – 1) ml = 0, ± 1, ± 2, ..., ± l ν= 1 2 The quantum number n, called the principal quantum number, primarily determines the energy of the orbital electrons. The quantum number l measures the angular momentum of the electron, and is referred to as the orbital angular momentum quantum number. The number ml gives the splitting of the energies for a given n and l in a magnetic field, and is called the magnetic quantum number. The quantity ms, known as the spin quantum number, shows that the spin of the electron about its own axis is quantised. The state of an electron in the atom is uniquely specified by the four quantum numbers. This is a result of Pauli’s exclusion principle. The principle states that no two electrons in an electronic system can occupy the same quantum state described by the same set of four quantum numbers n, l, ml and ms. ms = ± Electronic Shells The specific value of the principal quantum number n determines an electronic shell. All the electrons of a given atom having the same value of n belong to the same electronic shell. The dharm E:\N-up\ana1-1.p65 4 Electron Devices and Circuits letters K, L, M, N, ... denote the shells for n = 1, 2, 3, 4, ... , respectively. The different values of l for a given n define the subshells for the shell. The subshells are represented by s, p, d, f, ... corresponding to l = 0, 1, 2, 3, ... , respectively. For n = 1, there are two states corresponding to l = 0, ml = 0, and ms = ± 1/2. These two states are known as 1s states. For n = 2, we have two 2s states corresponding to l = 0, ml = 0, and ms = ± 1/2. In addition, there are six states for n = 2, l = 1, ml = –1, 0, + 1, and ms = ± 1/2. These are 2p states. The total number of electrons in the K shell (n = 1) is thus 2, and that in the L shell (n = 2) is 2 + 6 = 8. Similarly, it can be shown that a maximum of 10 electrons can be accommodated in a d subshell, a maximum of 14 electrons in an f subshell, and so on. The number of protons in the nucleus is the atomic number Z. Since the atom is electrically neutral, the number of orbiting electrons is also Z. For sodium, Z = 11. The electronic configuration of the sodium atom is 1s2 2s2 2p6 3s1, where the superscripts denote the number of electrons in a particular subshell. Clearly, the sodium atom has one electron in the outermost subshell. 1.4 ENERGY BANDS IN CRYSTALS A crystal is a solid consisting of a regular and r ¬ + Ze ® r zero ¥ repetitive arrangement of atoms or molecules level Ep(r) (strictly speaking, ions) in space. If the positions of the atoms in the crystal are represented by points, called lattice points, we get V(r) a crystal lattice. The distance between the atoms in a crystal is fixed and is termed the –¥ lattice constant of the crystal. r ¬ + Ze ® r (a) (b) To discuss the behaviour of electrons in a crystal, we consider an isolated atom of the Fig. 1.2 Variation of (a) Potential in the field of a crystal. If Z is the atomic number, the atomic nucleus with distance, nucleus has a positive charge Ze. At a dis(b) Potential energy of an electron with its distance from the nucleus. tance r from the nucleus, the electrostatic potential due to the nuclear charge is (in SI units) Ze V(r) = , (1.3) 4 πε 0 r where ε0 is the permittivity of free space. Since an electron carries a negative charge, the potential energy of an electron at a distance r from the nucleus is dharm E:\N-up\ana1-1.p65 Potential energy zero level Ze 2 (1.4) 4πε 0 r V(r) is positive while Ep(r) is negative. Both V(r) and Ep(r) are zero at an infinite distance from the nucleus. Figs. 1.2(a) and (b) show the variation of V(r) and Ep(r), respectively with r. We now consider two identical atoms –¥ + Ze + Ze placed close together. The net potential energy distance of an electron is obtained as the sum of the poFig. 1.3 Potential energy variation of an electron tential energies due to the two individual nuclei. with distance between two identical nuclei. In the region between the two nuclei, the net potential energy is clearly smaller than the potential energy for an isolated nucleus (see Fig. 1.3). Ep (r) = – eV(r) = – Energy Bands in Solids 5 Potential energy A zero level The potential energy along a line through a row of equispaced atomic nuclei, as in a crystal, is diagrammatically shown in Fig. 1.4. The potential energy between the nuclei is found to consist of a series of humps. At the boundary AB of the solid, the potential + Ze + Ze + Ze + Ze B energy increases and approaches zero at infinity, there being no atoms on the other side –¥ Distance of the boundary to bring the curve down. Fig. 1.4 Potential energy of an electron along The total energy of an electron in an a row of atoms in a crystal. atom, kinetic plus potential, is negative and has discrete values. These discrete energy levels in an isolated atom are shown by horizontal lines in Fig. 1.5(a). When a number of atoms are brought close together to form a crystal, each atom will exert an electric force on its neighbours. As a result of this interatomic coupling, the crystal forms a single electronic system obeying Pauli’s exclusion principle. Therefore, each energy level of the isolated atom splits into as many energy levels as there are atoms in the crystal, so that Pauli’s exclusion principle is satisfied. The separation between the split-off energy levels is very small. This large number of discrete and closely spaced energy levels form an energy band. Energy bands are represented schematically by shaded regions in Fig. 1.5(b). The width of an energy band is determined by the parent energy level of the isolated atom and the atomic spacing in the crystal. The lower energy levels are not greatly affected by the interaction among the neighbouring atoms, and hence form narrow bands. The higher energy levels are greatly affected by the interatomic interactions and produce wide bands. The interatomic spacing, although fixed for a given crystal, is different for different crystals. The width of an energy band thus depends on the type of the crystal, and is larger for a crystal with a small interatomic spacing. The width of a band is independent of the number of atoms in the Potential energy Zero level Potential energy Bands Levels + Ze + Ze + Ze + Ze + Ze Crystal surface Distance (a) Isolated atom (b) Crystal Fig. 1.5 Splitting of energy levels of isolated atoms into energy bands as these atoms are brought close together to produce a crystal. crystal, but the number of energy levels in a band is equal to the number of atoms in the solid. Consequently, as the number of atoms in the crystal increases, the separation between the energy levels in a band decreases. As the crystal contains a large number of atoms (≈ 1029 m–3), the spacing between the discrete levels in a band is so small that the band can be treated as continuous. The lower energy bands are normally completely filled by the electrons since the electrons always tend to occupy the lowest available energy states. The higher energy bands may be completely empty or may be partly filled by the electrons. Pauli’s exclusion principle restricts dharm E:\N-up\ana1-1.p65 6 Electron Devices and Circuits the number of electrons that a band can accommodate. A partly filled band appears when a partly filled energy level produces an energy band or when a totally filled band and a totally empty band overlap. As the allowed energy levels of a single atom expand into energy bands in a crystal, the electrons in a crystal cannot have energies in the region between two successive bands. In other words, the energy bands are separated by gaps of forbidden energy. The average energy of the electrons in the highest occupied band is usually much less than the zero level marked in Fig. 1.5(b). The rise of the potential energy near the surface of the crystal, as shown in Fig. 1.5(b), serves as a barrier preventing the electrons from escaping from the crystal. If sufficient energy is imparted to the electrons by external means, they can overcome the surface potential energy barrier, and come out of the crystal surface. 1.5 METAL, INSULATOR, AND SEMICONDUCTOR On the basis of the band structure, crystals can be classified into metals, insulators, and semiconductors. Metal A crystalline solid is called a metal if the uppermost energy band is partly filled [Fig. 1.6(a)] or the uppermost filled band and the next unoccupied band overlap in energy. Here, the electrons in the uppermost band find neighbouring vacant states to move in, and thus behave as free particles. In the presence of an applied electric field, these electrons gain energy from the field and produce an electric current, so that a metal is a good conductor of electricity. The partly filled band is called the conduction band. The electrons in the conduction band are known as free electrons or conduction electrons. Insulator In some crystalline solids, the forbidden energy gap between the uppermost filled band, called the valence band, and the lowermost empty band, called the conduction band, is very large. In such solids, at ordinary temperatures only a few electrons can acquire enough thermal energy to move from the valence band into the conduction band. Such solids are known as insulators. Since only a few free electrons are available in the conduction band, an insulator is a bad conductor of electricity. Diamond having a forbidden gap of 6 eV is a good example of an insulator. The energy band structure of an insulator is schematically shown in Fig. 1.6(b). Semiconductor A material for which the width of the forbidden energy gap between the valence and the conduction band is relatively small (~ 1 eV) is referred to as a semiconductor. Germanium and silicon having forbidden gaps of 0.78 and 1.2 eV, respectively, at 0 K are typical semiconductors. As the forbidden gap is not very wide, some of the valence electrons acquire enough thermal energy to go into the conduction band. These electrons then become free and can move about under the action of an applied electric field. The absence of an electron in the valence band is referred to as a hole. The holes also serve as carriers of electricity. The electrical conductivity of a semiconductor is less than that of a metal but greater than that of an insulator. The band diagram of a semiconductor is given in Fig. 1.6(c). dharm E:\N-up\ana1-1.p65 Energy Bands in Solids 7 Partly full (conduction band) Empty (conduction band) Full valence band Full Full Forbidden gap Nearly empty (conduction band) Forbidden gap Nearly full (valence band) Full (a) Full (b) (c) Fig. 1.6 Energy band structure of (a) metal, (b) insulator, and (c) semiconductor. 1.6 FERMI-DIRAC DISTRIBUTION FUNCTION The free electrons in the conduction band of a metal are essentially in an equipotential region. Only in the regions very close to an ion, there is a variation of potential. Since such regions constitute a very small portion of the total volume available for the movement of electrons, the electrons are assumed to move in a field-free or equipotential space. Due to their thermal energy, the free electrons move about at random just like gas particles. Hence these electrons are said to form an electron gas. Owing to the large number of free electrons (~ 1023 cm–3) in a metal, principles of statistical mechanics are employed to determine their average behaviour. A useful concept is the distribution function that gives the probability of occupancy of a given state by the electrons. The Maxwell-Boltzmann (MB) distribution function is obtained from classical ideas and does not incorporate Pauli’s exclusion principle. The MB distribution can be applied when the number of particles in a system is much less than the number of available quantum states. The free electrons in a metal cannot therefore be treated with the help of the MB distribution function. This shortcoming of the MB function was removed in the FermiDirac (FD) distribution function which can be used to determine the energy distribution of free electrons in a metal. From statistical mechanics*, the FD distribution function is found to be f (E) = 1 1 + exp [( E − EF ) / kB T ] (1.5) where f (E) is the probability of occupancy of the state with energy E, EF is a characteristic energy for a particular solid and is referred to as the Fermi level, T is the absolute temperature and kB is Boltzmann’s constant (kB = 1.38 × 10–23 J/K). At the absolute zero of temperature, i.e. at T = 0 K, 1 Eq. (1.5) shows that f (E) = 1 for E < EF and f (E) = 0 for T=0K T = 300 K E > EF . Thus all the energy states below EF are occupied f (E) − T = 2000 K by the electrons and all the energy states above EF are com1/2 pletely empty. Hence the Fermi energy EF denotes the maximum energy that can be occupied by the electrons at 0 K. At temperatures greater than the absolute zero, f (E) > 0 for E > EF, as shown in Fig. 1.7. This means that at a finite temperature, some of the electrons in the quantum states below EF acquire thermal energy to move into states above EF. 0 1 E/EF Fig. 1.7 Plot of f(E) against E/EF for T = 0.300 and 2000 K. *See, for example, ‘‘Quantum Mechanics, Statistical Mechanics, and Solid State Physics: An Introduction’’ by D. Chattopadhyay and P.C. Rakshit (S. Chand and Co., New Delhi). dharm E:\N-up\ana1-1.p65 8 Electron Devices and Circuits When E = EF, Eq. (1.5) shows that f (E) = 1/2 for T > 0. Thus the Fermi level is the energy level for which the probability of occupancy is 1/2 for a finite non-zero temperature. For most metals, EF is less than 10 eV. For a pure semiconductor and an insulator, the Fermi level lies near the middle of the forbidden energy gap, whereas for a metal, the Fermi level lies within the conduction band (Fig. 1.8). Conduction band Conduction band Fermi level Valence band Valence band Conduction band Fig. 1.8 Schematic diagram showing the position of the Fermi level in (a) an insulator, (b) a semiconductor, and (c) a metal. 1.7 SOLVED PROBLEMS 1. An electron at rest is accelerated through a potential difference of 100 V. Calculate its final kinetic energy in J and eV. What is its final velocity? Ans. The final kinetic energy of the electron is EK = e × 100 J = 1.6 × 10–19 × 100 J = 1.6 × 10–17 J = 100 eV. If v is the final velocity of the electron, we have 1 EK = m0 v2 where m0 is the rest mass of the electron. Thus 2 2 × 1.6 × 10 −17 = 5.927 × 106 m/s 9.11 × 10 −31 Since v << c, the relativistic correction is not necessary. v= 2 EK = m0 2. An ion has a positive charge numerically equal to twice the electronic charge. The mass of the ion is 7360 times that of an electron. The ion is initially stationary and accelerated through a potential difference of 2 kV. Calculate the velocity and the kinetic energy acquired by the ion. Ans. Let m and q be the mass and the charge of the ion, respectively. If v is the velocity of the ion after moving through a potential difference of V volt, we have Given, 1 m v2 2 m = 7360 m0 = 7360 × 9.11 × 10–31 kg, q = 2 | e | = 2 × 1.6 × 10–19 C, V = 2000 V. Hence v= qV= and 2qV = m 2 × 2 × 1.6 × 10 −19 × 2000 = 4.369 × 105 m/s 7360 × 9.11 × 10 −31 The kinetic energy of the ion is 1 mv2 = qV = 2 × 1.6 × 10–19 × 2000 2 = 6.4 × 10–16 J = 4000 eV Since v << c, the relativistic correction is not necessary here. EK = dharm E:\N-up\ana1-1.p65 Energy Bands in Solids 9 3. A system of particles obeys Fermi-Dirac distribution function. Show that the probability of vacancy of an energy level ∆E above the Fermi level EF is the same as the probability of occupancy of an energy level ∆E below EF. Ans. Let the energy above the Fermi energy EF be E1. Then ∆E = E1 –EF, and the probability of occupancy f(E1) of the level E1 is given by the FD distribution function, i.e., f(E1) = 1 1 = 1 + exp ( E1 − E F ) kB T 1 + exp ( ∆E kBT ) The probability of vacancy of the level E1 is 1 – f(E1) = 1 – 1 exp ( ∆E kB T ) = 1 + exp (∆E kB T ) 1 + exp (∆E kB T ) The probability of occupancy of an energy level E2 below EF where EF – E2 = ∆E, is f(E2) = = 1 1 = 1 + exp ( E2 − E F ) kBT 1 + exp ( − ∆E kBT ) exp (∆E kBT ) = 1 – f(E1), 1 + exp (∆E kBT ) which proves the desired result. REVIEW QUESTIONS 1. What do you mean by the rest mass of an electron? Does the mass of an electron vary with its velocity? If so, how? 2. What is ‘electron volt’? What is its relation with joule? 3. State and explain Pauli’s exclusion principle. What are electronic shells? 4. Define a crystal. Draw a diagram showing the variation of the potential energy of an electron along a line of atomic nuclei in a crystal. 5. ‘The energy levels of an atom produce energy bands in a solid’. Explain. 6. What do you mean by the potential energy barrier at the surface of a crystal? 7. What are the factors determining (a) the width of an energy band in a crystal and (b) the number of energy levels in the band? 8. Explain clearly the differences in the band structure of a metal, an insulator, and a semiconductor. 9. Write the Fermi-Dirac distribution function and explain its importance. What is Fermi level? OBJECTIVE-TYPE QUESTIONS 1. Choose the correct answer: (i) The electronic charge is (a) 1 C, (b) 1.6 µC, (c) 1.6 × 10–19 C. (ii) The rest mass of an electron is (a) 10–20 kg, (b) 9.1 × 10–31 kg, (c) 9.1 × 10–28 kg. (iii) The radius of an electron is (a) 10–15 m, (b) 10–10 m, (c) 10–9 m. (iv) The relativistic correction for the electronic mass is necessary for accelerating potentials in the range (a) 0 to 100 V, (b) 100 V to 6 kV, (c) 6 kV to 20 kV. dharm E:\N-up\ana1-1.p65 10 Electron Devices and Circuits (v) A quantum state specified by the four quantum numbers can be occupied by (a) one electron, (b) two electrons, (c) any number of electrons. (vi) The forbidden gap of silicon at 0 K is (a) 0.78 eV, (b) 1.2 eV, (c) 1.5 eV. (vii) The Fermi level in a metal is usually less than (a) 1 eV, (b) 5 eV, (c) 10 eV. (viii) The Fermi level in a pure semiconductor lies (a) near the middle of the forbidden gap, (b) in the valence band, (c) in the conduction band. Answers to Objective-Type Questions 1. (i) (c), (ii) (b), (iii) (a), (iv) (c), (v) (a), (vi) (b), (vii) (c), (viii) (a). PROBLEMS 1. An electron, initially at rest, gains a speed of 107 m/s after being accelerated through a potential difference of V volt. Determine V. What is the final kinetic energy of the electron in J and eV? (Ans. 284.7 volt, 4.555 × 10–17 J, 284.7 eV) 2. A particle carries a positive charge numerically equal to the electronic charge. It acquires a velocity of 200 km/s after moving through a potential difference of 210 V. Determine the mass of the particle relative to the electronic rest mass. (Ans. 1844 m0) 3. A particle of charge 1.2 × 10–8C and mass 5 g travels a distance of 3 m under the action of a potential difference of 500 V. Calculate the final velocity and the acceleration of the particle if it starts from rest. (Ans. 4.898 × 10–2m/s, 4 × 10–4m/s2) 4. A potential difference of 400 volt is applied between two parallel metal plates 4 cm apart. An electron starts from rest from the negative plate. Obtain (i) the kinetic energy of the electron when it reaches the positive plate and (ii) the time required by the electron to reach the positive plate (Mass of an electron = 9.1 × 10–31 kg, electronic charge = 1.6 × 10–19 C). (Ans. 400 eV, 6.745 × 10–9 s) dharm E:\N-up\ana1-1.p65