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Week 11 – Linear Kinetics – Relationship between force and motion • • • • Read Chapter 12 in text Classification of forces Types of forces encountered by humans Force and motion relationships – Instantaneous effect – Newton’s law of acceleration (F=ma) – Force applied through time (Impulse-momentum) • Conservation of Momentum – Force applied through distance (work-energy) • Conservation of Energy • Problems – Introductory problems, p 411: 1,3,5,7,8,10 – Additional problems, p 412: 6,8,9 Classification of Forces • • • • Action vs reaction Internal vs external Motive vs resistive Force resolution – horizontal and vertical components • Simultaneous application of forces – determining the net force through vector summation Types of external forces encountered by humans • Gravitational force (weight = mg) • Ground Reaction Force (GRF)(Figure 12-4, p 386) – Vertical – Horizontal (frictional) • Frictional force (coefficient of friction) (pp 389-395) • Elastic force (coefficient of restitution) (pp 399-402) • Free body diagram - force graph (p 63) Force Plates – Measurement of ground reaction forces While walking Cfr = Frf /Nof Sample Prob # 2, p 392 Coefficient of restitution: Sample problem #5, p 402 Free body diagrams: Instantaneous Effect of Force on an Object • Remember the concept of net force? • Need to combine, or add forces, to determine net force • Newton’s third law of motion (F = ma) • Inverse dynamics – estimating net forces from the acceleration of an object • Illustrations from Kreighbaum: Figures F.4, F.5, and F.6 (pp 283-284) Force Applied Through a Time: ImpulseMomentum Relationship (pp 295-399) • • • • Force applied through a time Impulse - the area under the force-time curve Momentum - total amount of movement (mass x velocity) An impulse applied to an object will cause a change in its momentum (Ft = mv) • Conservation of momentum (collisions, or impacts) – in a closed system, momentum will not change – what is a closed system? Impulse: area under forcetime curve Impulse produces a change in momentum (mV) Sample problem #4, p 397 Vertical impulse While Running: Area under Force-time curve Anterioposterior (frictional) component of GRF: impulse Is area under Force-time curve Positive and Negative impulse Are equal if Horizontal comp Of velocity is constant Conservation of momentum: when net impulse is zero (i.e. the system is closed), momentum does not change Conservation of momentum: is this a closed system? Sample prob #3, p 396 Force Applied Through a Distance: Work, Power, Energy (pp 403-409) • Work - force X distance (Newton-meters, or Joules) – On a bicycle: Work = F (2r X N) – On a treadmill: Work = Weightd X per cent grade • Power - work rate, or combination of strength and speed (Newton-meters/second, or watts) – On a treadmill: P = Weightd X per cent grade/ time – On a bicycle: P = F (2r X N) / time • What about kilogram-meters/min? • Energy - capacity to do work – kinetic, the energy by virtue of movement (KE = 1/2 mv2 ) – gravitational potential, energy of position (PE = Weight x height) – elastic potential, or strain, energy of condition (PE = Fd) Work while pedaling on bicycle: From McArdle and Katch. Exercise Physiology Work while running on treadmill: From McArdle and Katch. Exercise Physiology Note that %grade = tan θ X 100, and tan θ and sin θ are very similar below 20% grade Homework: Calculating Power on a Treadmill • Problem: What is workload (power) of a 100 kg man running on a treadmill at 10% grade at 4 m/s? • Solution: – Power = force x velocity – Force is simply body weight, or 100 x 9.8 = 980 N – Velocity is vertical velocity, or rate of climbing • Rate of climbing = treadmill speed x percent grade = 4 m/s x .1 = .4 m/s – Workload, workrate, or power = 980N X .4 m/s = 392 Watts • Note: 4 m/s = 9 mph, or a 6 min, 40 sec mile • Calculate your workload if you are running on a treadmill set at 5% grade and 5 m/s. – Answer for 200 lb wt is: 223 Watts Power running up stairs: Work rate = (weight X vertical dist) ÷ time Sample prob #6, p 405 Conservation of Energy • In some situations, total amount of mechanical energy (potential + kinetic) does not change – Stored elastic energy converted to kinetic energy • • • • diving board bow (archery) bending of pole in pole vault landing on an elastic object (trampoline) – Gravitational potential energy converted to kinetic energy • Falling objects • Videodisk on pole vault Energy conservation – Case I : elastic potential (strain) and kinetic Potential energy (FD) + Kinetic energy (1/2mv2) remains constant Energy conservation – Case II : gravitational potential and kinetic Potential energy (Wh) + kinetic energy (1/2mv2) remains constant Linear Kinetics Formulae