Download 4-4 Part II Perpendicular Lines

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Elementary algebra wikipedia , lookup

System of linear equations wikipedia , lookup

Linear algebra wikipedia , lookup

History of algebra wikipedia , lookup

Signal-flow graph wikipedia , lookup

Equation wikipedia , lookup

Transcript
Name_____________________________
ALGEBRA 1
Period______
Date______________
Chapter 4 Equations of Linear Functions
Lesson 4-4 Part II Perpendicular Lines
UEQ: How are Linear Functions used to solve problems?
LEQ:
__________________________________________________________________________________________
CCS: F.LE.2 Construct linear and exponential functions, including arithmetic and geometric sequences, given a
graph, a description of a relationship, or two input-output pairs ( including reading these from a table ).
Warm-Up Exercises
Directions: Identify the reciprocal of each number.
1.
2
5
2.
4
3.
−
3
2
3.
-5
Vocabulary
Perpendicular Lines – are lines that _________________________________________________________________
- Perpendicular lines __________________________________________________________
meaning: _________________________________________________________________
Key Concept #1
Parallel or Perpendicular Lines
Directions:
Use the properties of the slopes of parallel and perpendicular lines to determine whether the given lines
are parallel or perpendicular.
Given:
3x + y = 12
y =
1
3
x + 2
2x - 6y = -5
Key Concept # 2
Perpendicular Line through a Given Point
Directions: Write an equation in slope-intercept form for the line that passes through
( -4 , 6 ) and is perpendicular to the graph of 2x + 3y = 12.
Step 1: Find (Identify) slope of the given line.
2x + 3y = 12
 convert to ____________________ form
Step 2: Use the point-slope form of an equation, then convert to slope-intercept form.
y - y 1 = m ( x - x1 )
Assignment:
CW:
_______________________________________________________________
HW:
_______________________________________________________________