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Statistics Sampling and Sampling Distribution 1/101 STATISTICS in PRACTICE MeadWestvaco Corporation’s products include textbook paper, magazine paper, and office products. MeadWestvaco’s internal consulting group uses sampling to provide information that enables the company to obtain significant productivity benefits and remain competitive. 2/101 STATISTICS in PRACTICE Managers need reliable and accurate information about the timberlands and forests to evaluate the company’s ability to meet its future raw material needs. Data collected from sample plots throughout the forests are the basis for learning about the population of trees owned by the company. 3/101 Contents The Electronics Associates Sampling Problem Simple Random Sampling Point Estimation Introduction to Sampling Distributions Sampling Distribution of p Properties of Point Estimators Other Sampling Methods 4/101 Statistical Inference The purpose of statistical inference is to obtain information about a population from information contained in a sample. A population is the set of all the elements of interest. A sample is a subset of the population. 5/101 Statistical Inference The sample results provide only estimates of the values of the population characteristics. With proper sampling methods, the sample results can provide “good” estimates of the population characteristics. A parameter is a numerical characteristic of a population. 6/101 The Electronics Associates Sampling Problem Often the cost of collecting information from a sample is substantially less than from a population, Especially when personal interviews must be conducted to collect the information. 7/101 Simple Random Sampling: Finite Population Finite populations are often defined by lists such as: Organization membership roster Credit card account numbers Inventory product numbers 8/101 Simple Random Sampling: Finite Population A simple random sample of size n from a finite population of size N is a sample selected such that each possible sample of size n has the same probability of being selected. 9/101 Simple Random Sampling: Finite Population Replacing each sampled element before selecting subsequent elements is called sampling with replacement. Sampling without replacement is the procedure used most often. 10/101 Simple Random Sampling Random Numbers: the numbers in the table are random, these four-digit numbers are equally likely. 11/101 Simple Random Sampling: Infinite Population Infinite populations are often defined by an ongoing process whereby the elements of the population consist of items generated as though the process would operate indefinitely. 12/101 Simple Random Sampling: Infinite Population A simple random sample from an infinite population is a sample selected such that the following conditions are satisfied. Each element selected comes from the same population. Each element is selected independently. 13/101 Simple Random Sampling: Infinite Population In the case of infinite populations, it is impossible to obtain a list of all elements in the population. The random number selection procedure cannot be used for infinite populations. 14/101 Point Estimation In point estimation we use the data from the sample to compute a value of a sample statistic that serves as an estimate of a population parameter. We refer to x as the point estimator of the population mean . 15/101 Point Estimation s is the point estimator of the population standard deviation . p is the point estimator of the population proportion p. 16/101 Point Estimation Example: to estimate the population mean, the population standard deviation and population proportion. 17/101 Sampling Error When the expected value of a point estimator is equal to the population parameter, the point estimator is said to be unbiased. The absolute value of the difference between an unbiased point estimate and the corresponding population parameter is called the sampling error. 18/101 Sampling Error Sampling error is the result of using a subset of the population (the sample), and not the entire population. Statistical methods can be used to make probability statements about the size of the sampling error. 19/101 Sampling Error The sampling errors are: |x | for |s | sample mean for sample standard deviation | p p| for sample proportion 20/101 Example: St. Andrew’s St. Andrew’s College receives 900 applications annually from prospective students. The application form contains a variety of information including the individual’s scholastic aptitude test (SAT) score and whether or not the individual desires on-campus housing. 21/101 Example: St. Andrew’s The director of admissions would like to know the following information: the average SAT score for the 900 applicants, and the proportion of applicants that want to live on campus. 22/101 Example: St. Andrew’s We will now look at three alternatives for obtaining The desired information. Conducting a census of the entire 900 applicants Selecting a sample of 30 applicants, using a random number table Selecting a sample of 30 applicants, using Excel 23/101 Conducting a Census If the relevant data for the entire 900 applicants were in the college’s database, the population parameters of interest could be calculated using the formulas presented in Chapter 3. We will assume for the moment that conducting a census is practical in this example. 24/101 Conducting a Census Population Mean SAT Score Population Standard Deviation for SAT Score Population Proportion Wanting On-Campus Housing 25/101 Simple Random Sampling Now suppose that the necessary data on the current year’s applicants were not yet entered in the college’s database. Furthermore, the Director of Admissions must obtain estimates of the population parameters of interest for a meeting taking place in a few hours. 26/101 Simple Random Sampling Now suppose that the necessary data on the current year’s applicants were not yet entered in the college’s database. Furthermore, the Director of Admissions must obtain estimates of the population parameters of interest for a meeting taking place in a few hours. 27/101 Simple Random Sampling The applicants were numbered, from 1 to 900, as their applications arrived. 28/101 Simple Random Sampling: Using a Random Number Table Taking a Sample of 30 Applicants Because the finite population has 900 elements, we will need 3-digit random numbers to randomly select applicants numbered from 1 to 900. We will use the last three digits of the 5-digit random numbers in the third column of the textbook’s random number table , and continue into the fourth column as needed.29/101 Simple Random Sampling: Using a Random Number Table Taking a Sample of 30 Applicants The numbers we draw will be the numbers of the applicants we will sample unless the random number is greater than 900 or the random number has already been used. We will continue to draw random numbers until we have selected 30 applicants for our sample. 30/101 Simple Random Sampling: Using a Random Number Table (We will go through all of column 3 and part of column 4 of the random number table, encountering in the process five numbers greater than 900 and one duplicate, 835.) 31/101 Simple Random Sampling: Using a Random Number Table Use of Random Numbers for Sampling 3-Digit Applicant Random Number Included in Sample 744 No. 744 436 No. 436 865 No. 865 790 No. 790 835 No. 835 902 Number exceeds 900 190 No. 190 836 No. 836 . . . and so on 32/101 Simple Random Sampling: Using a Random Number Table Sample Data Random No. Number 1 744 2 436 3 865 4 790 5 835 . . . . SAT Score Applicant Conrad Harris 1025 Enrique Romero 950 Fabian Avante 1090 Lucila Cruz 1120 Chan Chiang 930 . . . . 30 Emily Morse 498 1010 Live OnCampus Yes Yes No Yes No . . No 33/101 Simple Random Sampling: Using a Computer Taking a Sample of 30 Applicants • Computers can be used to generate random numbers for selecting random samples. • For example, Excel’s function = RANDBETWEEN(1,900) can be used to generate random numbers between 1 and 900. • Then we choose the 30 applicants corresponding to the 30 smallest random 34/101 numbers as our sample. Point Estimation wx x as Point Estimator of w i i i s as Point Estimator of –p as Point Estimator of p 35/101 Point Estimation Note: Different random numbers would have identified a different sample which would have resulted in different point estimates. 36/101 Summary of Point Estimates Obtained from a Simple Random Sample Population Parameter Parameter Value = Population mean 990 x = Sample mean 997 = Population std. 80 s = Sample std. deviation for SAT score 75.2 p = Population proportion wanting campus housing .72 SAT score Point Estimator Point Estimate SAT score deviation for SAT score p = Sample proportion wanting campus housing .68 37/101 Sampling Distribution Example: Relative Frequency Histogram of Sample Mean Values from 500 Simple Random Samples of 30 each. 38/101 Sampling Distribution Example: Relative Frequency Histogram of Sample Proportion Values from 500 Simple Random Samples of 30 each. 39/101 Sampling Distribution of x Process of Statistical Inference Population with mean =? The value of x is used to make inferences about the value of . A simple random sample of n elements is selected from the population. The sample data provide a value for the sample mean x. Sampling Distribution of x w x i i The sampling distribution of x is the probability wi distribution of all possible values of the sample wi xi mean x . wi wi xi Expected Value of x w E( x ) = i where: = the population mean 41/101 Sampling Distribution of x Standard Deviation of x Finite Population N n x ( ) n N 1 Infinite Population x n • A finite population is treated as being infinite if n/N < .05. 42/101 Sampling Distribution of x ( N n) /( N 1) • is the finite correction factor. • x is referred to as the standard error of the mean. 43/101 Form of the Sampling Distribution wi xi of x w If we use a large (n > 30) simple random sample, i the central limit theorem enables us to conclude that the sampling distribution of x can be approximated by a normal distribution. When the simple random sample is small (n < 30), the sampling distribution of x can be considered normal only if we assume the population has a normal distribution. 44/101 Central Limit Theorem Illustration of The Central Limit Theorem 45/101 Relationship Between the Sample Size and the Sampling Distribution of Sample Mean A Comparison of The Sampling Distributions of Sample Mean for Simple Random Samples of n = 30 and n = 100. 46/101 w x for w i Sampling Distribution of SAT Scores Sampling Distribution of x E( x ) 990 x 80 14.6 n 30 x 47/71 wx Sampling Distribution of x for w SAT Scores i i i What is the probability that a simple random sample of 30 applicants will provide an estimate of the population mean SAT score that is within +/-10 of the actual population mean ? In other words, what is the probability that x will be between 980 and 1000? 48/101 wx Sampling Distribution of x for w i i SAT Scores Step 1: Calculate the z-value at the upper endpoint of the interval. z = (1000 - 990)/14.6= .68 Step 2: Find the area under the curve to the left of the upper endpoint. P(z < .68) = .7517 49/101 i wx Sampling Distribution of x for w SAT Scores i i Cumulative Probabilities for the Standard Normal Distribution z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 . . . . . . . . . . . .5 .6915 .6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 .7224 .6 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486 .7517 .7549 .7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 .7823 .7852 .8 .7881 .7910 .7939 .7967 .7995 .8023 .8051 .8078 .8106 .8133 .9 .8159 .8186 .8212 .8238 .8264 .8289 .8315 .8340 .8365 .8389 . . . . . . . . . . . 50/101 wx Sampling Distribution of x for w SAT Scores i i i Sampling Distribution of x x 14.6 Area = .7517 x 990 1000 51/101 w Sampling Distribution of x for w SAT Scores Step 3: Calculate the z-value at the lower endpoint of the interval. z = (980 - 990)/14.6= - .68 Step 4: Find the area under the curve to the left of the lower endpoint. P(z < -.68) = P(z > .68) = 1 - P(z < .68) = 1 - . 7517 = .2483 52/101 wx Sampling Distribution of x for w SAT Scores i i Sampling Distribution of x x 14.6 Area = .2483 x 980 990 53/101 i w Sampling Distribution of x for SAT Scores Step 5: Calculate the area under the curve between the lower and upper endpoints of the interval. P(-.68 < z < .68) = P(z < .68) - P(z < -.68) = .7517 - .2483 = .5034 The probability that the sample mean SAT score will be between 980 and 1000 is: P(980 <x < 1000) = .5034 54/101 wx Sampling Distribution of x for w i i i SAT Scores Sampling Distribution of x x 14.6 Area = .5034 980 990 1000 x 55/101 Relationship Between the Sample Size x and the Sampling Distribution of Suppose we select a simple random sample of 100 applicants instead of the 30 originally considered. wx E(x )= m regardless of the sample size. wx w in our example, E(x ) remains at 990. w i i i i i i 56/101 Relationship Between the Sample Size and the Sampling Distribution of x Whenever the sample size is increased, the standard error of the mean σ x is decreased. With the increase in the sample size to n = 100, the standard error of the mean is decreased to: 57/101 Relationship Between the Sample Size and the Sampling Distribution of x With n = 100, x 8 With n = 30, x 14.6 E( x ) 990 x 58/101 Relationship Between the Sample Size wi x and the Sampling Distribution of x w i Recall that when n = 30, wi xi P(980 < x < 1000) = .5034. w i We follow the same steps to solve for wi xi P(980 < x < 1000) w i when n = 100 as we showed earlier when n = 30. 59/101 Relationship Between the Sample Size w and the Sampling Distribution of x w wx Now, with n = 100, P(980 < x<1000) = .7888. w Because the sampling distribution with n = 100 w has a smaller standard error, the values of xhave w less variability and tend to be closer to the wx population mean than the values of x with n = 30. w i i i i i i 60/101 Relationship Between the Sample Size w and the Sampling Distribution of x Sampling Distribution of x x 8 Area = .7888 x 980 990 1000 61/101 Sampling Distribution Example: Relative Frequency Histogram of Sample Proportion Values from 500 Simple Random Samples of 30 each. 62/101 Sampling Distribution of p Making Inferences about a Population Proportion Population with proportion p=? The value of p is used to make inferences about the value of p. A simple random sample of n elements is selected from the population. The sample data provide a value for the sample proportion p. 63/101 Sampling Distribution of p The sampling distribution of p is the probability distribution of all possible values of the sample proportion p . Expected Value of p E ( p) p where: p = the population proportion 64/101 Sampling Distribution of p Standard Deviation of p Finite Population p p p (1 p ) N n n N 1 Infinite Population p p (1 p ) n is referred to as the standard error of the proportion. Form of the Sampling Distribution of p The sampling distribution of p can be approximated by a normal distribution whenever the sample size is large. The sample size is considered large whenever these conditions are satisfied: np > 5 and n(1 – p) > 5 Form of the Sampling Distribution of p For values of p near .50, sample sizes as small as 10 permit a normal approximation. With very small (approaching 0) or very large (approaching 1) values of p, much larger samples are needed. 67/101 Sampling Distribution of p Example: St. Andrew’s College Recall that 72% of the prospective students applying to St. Andrew’s College desire on-campus housing. 68/101 Sampling Distribution of p Example: St. Andrew’s College What is the probability that a simple random sample of 30 applicants will provide an estimate of the population proportion of applicant desiring on-campus housing that is within plus or minus .05 of the actual population proportion? 69/101 Sampling Distribution of p For our example, with n = 30 and p = .72, the normal distribution is an acceptable approximation because: np = 30(.72) = 21.6 > 5 and n(1 - p) = 30(.28) = 8.4 > 5 Sampling Distribution of Sampling Distribution of p Sampling Distribution of p Step 1: Calculate the z-value at the upper endpoint of the interval. z = (.77 - .72) /.082 = .61 Step 2: Find the area under the curve to the left of the upper endpoint. P(z < .61) = .7291 72/101 Sampling Distribution of p Cumulative Probabilities for the Standard Normal Distribution z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 . . . . . . . . . . . .5 .6915 .6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 .7224 .6 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486 .7517 .7549 .7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 .7823 .7852 .8 .7881 .7910 .7939 .7967 .7995 .8023 .8051 .8078 .8106 .8133 .9 .8159 .8186 .8212 .8238 .8264 .8289 .8315 .8340 .8365 .8389 . . . . . . . . . . . 73/101 Sampling Distribution of p p .082 Sampling Distribution of p Area = .7291 p .72 .77 74/101 Sampling Distribution of p Step 3: Calculate the z-value at the lower endpoint of the interval. z = (.67 - .72) /.082 = - .61 Step 4: Find the area under the curve to the left of the lower endpoint. P(z < -.61) = P(z > .61) = 1 - P(z < .61) = 1 - . 7291 = .2709 75/101 Sampling Distribution of p Sampling Distribution of Area = .2709 .67 .72 76/101 Sampling Distribution of p Step 5: Calculate the area under the curve between the lower and upper endpoints of the interval. P(-.61 < z < .61) = P(z < .61) - P(z < -.61) = .7291 - .2709 = .4582 The probability that the sample proportion of applicants wanting on-campus housing will be within +/-.05 of the actual population proportion : P(.67 < < .77) = .4582 77/101 Sampling Distribution of Sampling Distribution of p p p .082 Area = .4582 p .67 .72 .77 78/101 Point Estimators Notations: ^ θ = the population parameter of interest. For example, population mean, population standard deviation, population proportion, and so on. 79/101 Point Estimators Notations: ^ θ = the sample statistic or point estimator of θ . Represents the corresponding sample statistic such as the sample mean, sample standard deviation, and sample proportion. The notation θ is the Greek letter theta. ^ the notation θ is pronounced “theta-hat.” 80/101 Properties of Point Estimators Before using a sample statistic as a point estimator, statisticians check to see whether the sample statistic has the following properties associated with good point estimators. Unbiased Efficiency Consistency 81/101 Properties of Point Estimators Unbised If the expected value of the sample statistic is equal to the population parameter being estimated, the sample statistic is said to be an unbiased estimator of the population parameter. 82/101 Properties of Point Estimators Unbised The sample statistic ^θ is unbiased estimator of the population parameter θ if E(θ)= ^θ where ^ E(θ)=the expected value of the sample statistic θ 83/101 Properties of Point Estimators Examples of Unbiased and Biased Point Estimators 84/101 Properties of Point Estimators Efficiency Given the choice of two unbiased estimators of the same population parameter, we would prefer to use the point estimator with the smaller standard deviation, since it tends to provide estimates closer to the population parameter. The point estimator with the smaller standard deviation is said to have greater 85/101 relative efficiency than the other. Properties of Point Estimators Example: Sampling Distributions of Two Unbiased Point Estimators. 86/101 Properties of Point Estimators Consistency A point estimator is consistent if the values of the point estimator tend to become closer to the population parameter as the sample size becomes larger. 87/101 Other Sampling Methods Stratified Random Sampling(分層隨機抽樣) Cluster Sampling(部落抽樣) Systematic Sampling(系統抽樣) Convenience Sampling(便利抽樣) Judgment Sampling(判斷抽樣) 88/101 Stratified Random Sampling The population is first divided into groups of elements called strata. Each element in the population belongs to one and only one stratum. Best results are obtained when the elements within each stratum are as much alike as possible (i.e. a homogeneous group). 89/101 Stratified Random Sampling Diagram for Stratified Random Sampling 90/101 Stratified Random Sampling A simple random sample is taken from each stratum. Formulas are available for combining the stratum sample results into one population parameter estimate. 91/101 Stratified Random Sampling Advantage: If strata are homogeneous, this method is as “precise” as simple random sampling but with a smaller total sample size. Example: The basis for forming the strata might be department, location, age, industry type, and so on. 92/101 Cluster Sampling The population is first divided into separate groups of elements called clusters. Ideally, each cluster is a representative smallscale version of the population (i.e. heterogeneous group). A simple random sample of the clusters is then taken. All elements within each sampled (chosen) cluster form the sample. 93/101 Cluster Sampling Diagram for Cluster Sampling 94/101 Cluster Sampling Example: A primary application is area sampling, where clusters are city blocks or other well-defined areas. Advantage: The close proximity of elements can be cost effective (i.e. many sample observations can be obtained in a short time). Disadvantage: This method generally requires a larger total sample size than simple or stratified random sampling. 95/101 Systematic Sampling If a sample size of n is desired from a population containing N elements, we might sample one element for every n/N elements in the population. We randomly select one of the first n/N elements from the population list. We then select every n/Nth element that follows in the population list. 96/101 Systematic Sampling This method has the properties of a simple random sample, especially if the list of the population elements is a random ordering. Advantage: The sample usually will be easier to identify than it would be if simple random sampling were used. Example: Selecting every 100th listing in a telephone book after the first randomly selected 97/101 listing Convenience Sampling It is a nonprobability sampling technique. Items are included in the sample without known probabilities of being selected. The sample is identified primarily by convenience. Example: A professor conducting research might use student volunteers to constitute a sample. 98/101 Convenience Sampling Advantage: Sample selection and data collection are relatively easy. Disadvantage: It is impossible to determine how representative of the population the sample is. 99/101 Judgment Sampling The person most knowledgeable on the subject of the study selects elements of the population that he or she feels are most representative of the population. It is a nonprobability sampling technique. Example: A reporter might sample three or four senators, judging them as reflecting the general opinion of the senate. 100/101 Judgment Sampling Advantage: It is a relatively easy way of selecting a sample. Disadvantage: The quality of the sample results depends on the judgment of the person selecting the sample. 101/101