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Transcript
Exam 2 covers Ch. 27-33,
Lecture, Discussion, HW, Lab
Exam 2 is Tue. Oct. 27, 5:30-7 pm, 145 Birge



Chapter 27: The Electric Field
Chapter 29: Electric potential & work
Chapter 30: Electric potential & field



Chapter 31: Current & Resistance
Chapter 32: Fundamentals of Circuits


(exclude 30.7)
(exclude 32.8)
Chapter 33: The Magnetic Field

(exclude 33.5-33.6, 33.9-10, & Hall effect)
1
Law of Biot-Savart
B out of page
r

ds

Each short length of current
produces contribution to
magnetic field.
I in
plane of page
dB
r
ds
r
r o Ids  rˆ
dB 
4 r 2
Field from very short
r
section of current ds
r = distance from current element
o  4 107 N / A 2 = permeability of free space
Tue. Oct. 27, 2009

Physics 208 Lecture 16
2
r r
CD
Vector cross product
r
r o Ids  rˆ
dB 
4 r 2
r
D


r
dB
r oI r
dB 
ds  rˆ
2
4 r
Dist. to
point at
which field
is evaluated
Short length
of current
r
r
Unit vector
toward point
at which field
is evaluated

r
C

r
ds

Tue. Oct. 27, 2009

Physics 208 Lecture 16
3
Field from a circular loop



Each current element produce dB
All contributions add as vectors
Along axis, all
components cancel
except for x-comp
Tue. Oct. 27, 2009
Physics 208 Lecture 16
4
Magnetic field from loop of current
Looks like magnetic dipole
Tue. Oct. 27, 2009
Physics 208 Lecture 16
5
Building a solenoid
Tue. Oct. 27, 2009
Physics 208 Lecture 16
6
Solenoid: many current loops
Bsolenoid 
Tue. Oct. 27, 2009
oNI
L
 onI
Physics 208 Lecture 16
7
Magnetic Force on a Current
I


Force on each charge qv  B
Force on length ds of wire
Ids  B

 section of
Force on straight
wire, 
length L
 r
r r
F  I  BL
N
Current
S
Magnetic force
Magnetic
field
Tue. Oct. 27, 2009
Physics 208 Lecture 16
8
Quick Quiz
A current I flows in a square loop of wire y
with side length L.
A constant B field points in the x-direction,
perpendicular to the plane of the loop.
 What is the net force on the wire loop?
L
I
I
I
A. 4LB
I
B. 2LB
x
C. LB
D. 0
Tue. Oct. 27, 2009
Physics 208 Lecture 16
9
No force, but torque
Lever arm
Force


r r
Torque is r  F
Net torque can be nonzero even when
net force is zero.

Tue. Oct. 27, 2009
Physics 208 Lecture 16
10
Question on torque
Which of these loop orientations has the largest magnitude
torque? Loops are identical apart from orientation.
(A) a (B) b (C) c
a
b
c
12/09/2002
U. Wisconsin, Physics 208, Fall 2006
11
Quick Quiz
Which of these different sized current loops has
the greatest torque from a uniform magnetic
field to the right? All have same current.
A.
L
B.
2L
W
W/2
C.
L/2
D. All same
r
B
2W
Tue. Oct. 27, 2009
Physics 208 Lecture 16
12
Torque on current loop
  r  F
F


  2 F sin  
2

I
F  IB    AIBsin 
A
2
B
r

=loop area
I
Torque proportional
to
• Loop area
• Current
F
B
• sinθ
Tue. Oct. 27, 2009
Physics 208 Lecture 16
13
Current loops & magnetic dipoles


Current loop produces magnetic dipole field.
Magnetic dipole moment: 

  IA
current
Area of
loop


direction
magnitude
In a uniform magnetic field
Magnetic field exerts torque    B,    B sin 
Torque rotates loop to align  with B
Tue. Oct. 27, 2009
Physics 208 Lecture 16
14
Works for any shape planar loop
r
  IA
r
 perpendicular to loop
Torque in uniform magnetic field
I
   B,    B sin 
r r
Potential energy of rotation: U   B  Bcos

Lowest energy aligned w/ magnetic field

Highest energy perpendicular to magnetic field

Tue. Oct. 27, 2009
Physics 208 Lecture 16
15
Magnetic flux



Magnetic flux is defined
B  B dA
exactly as electric flux
(Component of B  surface) x (Area element)

zero flux
Maximum flux
SI unit of magnetic flux is the Weber ( = 1 T-m2 )
Tue. Oct. 27, 2009
Physics 208 Lecture 16
16
Magnetic Flux


Magnetic flux  through a surface:
(component of B-field  surface) X (surface area)
Proportional to
# B- field lines
penetrating surface
Tue. Oct. 27, 2009
Physics 208 Lecture 16
17
Why perpendicular component?

Suppose surface make angle  surface normal
r
B  B|| sˆ  B nˆ
A  Anˆ
nˆ
Component || surface
Component  surface
Only  component
 ‘goes through’ surface


sˆ

B = BA cos 
B =0 if B parallel A
 B = BA (max) if B  A


Flux SI units are T·m2=Weber
Tue. Oct. 27, 2009
Physics 208 Lecture 16

r r
M  B  A
18
Total flux

E not constant

add up small areas
where it is constant

Surface not flat

add up small areas
where it is ~ flat
r
r
   BiA i cos   Bi  Ai
i
B
r
r
Add them all up: B   B  dA
surface
Tue. Oct. 27, 2009
Physics 208 Lecture 16
19
Magnetic flux
What is that magnetic flux through this
surface?
A. Positive
B. Negative
C. Zero
Tue. Oct. 27, 2009
Physics 208 Lecture 16
20
Properties of flux lines

Net magnetic flux through any closed
surface is always zero:  magnetic  0

For electric charges, and
electric flux
electric 
Qenclosed
o
No magnetic ‘charge’,
so right-hand side=0 for mag.

Tue. Oct. 27, 2009
Basic magnetic element
is the dipole
Physics 208 Lecture 16
21
Time-dependent fields
Up to this point, have discussed only magnetic
and electric fields constant in time.



E-fields arise from charges
B-fields arise from moving charges (currents)
Faraday’s discovery

Another source of electric field

Time-varying magnetic field creates electric field
Tue. Oct. 27, 2009
Physics 208 Lecture 16
22
Measuring the induced field



A changing magnetic flux produces an EMF
around the closed path.
How to measure this?
Use a real loop of wire for the closed path.
The EMF corresponds to a current flow:
  IR

Tue. Oct. 27, 2009
Physics 208 Lecture 16
23