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Ch 4 Summary L1 Key Name ____________________________ Chapter 4: Discovering and Proving Triangle Properties Triangle Angles Triangle Sum Conjecture The sum of the measures of the angles in every triangle is 180°. Third Angle Conjecture If two angles of one triangle are congruent to two angles of another triangle, then the third angles of the triangles are congruent. A I C T Z P m∠A + m∠C + m∠T = 180 m∠A = m∠I and m∠T = m∠P , then m∠ C = m∠ Z . If C Triangle Exterior Angle Conjecture The measure of an exterior angle of a triangle is equal to the sum of the measures of the remote interior angles. D B A Triangles Inequalities Triangle Inequality Conjecture The sum of the lengths of any two sides of a triangle is greater than the length of the third side. Side-Angle Inequality Conjecture (only applies to triangles!) In a triangle, if one side is the longest side, then the angle opposite the longest side is the largest angle. m∠CBD = m∠A + m∠C 5 2 10 Since 2 + 5 < 10 , you cannot make a triangle. Lg Medium Short Md Longes t Sm Likewise, if one side is the shortest side, then the angle opposite the shortest side is the smallest angle. S. Stirling Page 1 of 6 Ch 4 Summary L1 Key Name ____________________________ B Isosceles Triangle Properties (also for Equilateral-equiangular) Vocab: leg, base, base angles, vertex angle. S V Isosceles Triangle Conjecture If a triangle is isosceles, then its base angles are congruent. Converse of the Isosceles Triangle Conj. If a triangle has two congruent angles, then it is an isosceles triangle. Equilateral/Equiangular Triangle Conjecture Every equilateral triangle is equiangular. Conversely, every equiangular triangle is equilateral. Vertex Angle Bisector Conjecture In an isosceles triangle, the bisector of the vertex angle is also the altitude and the median to the base and the perpendicular bisector of the base. ΔVBS is isosceles, then ∠ B ≅ ∠ S . If ∠B ≅ ∠S , then ΔVBS is isosceles. If ΔEQU is equilateral, then ΔEQU is E If equiangular. U Q ΔVBS is isosceles VX bisects ∠BVS , then VX is an altitude, If median and perpendicular bisector of BS B X S 20 20 V . A Medians to the Congruent Sides Thm In an isosceles triangle, the medians to the congruent sides are congruent. Angle Bisectors to the Congruent Sides Thm In an isosceles triangle, the angle bisectors to the congruent sides are congruent. If BN and MC are altitudes of isosceles ΔABC , then BN = MC . C B If BS and CP are angle bisectors of A ΔABC , SB = CP . P isosceles then N M S C B A Altitudes to the Congruent Sides Thm In an isosceles triangle, the altitudes to the congruent sides are congruent. S. Stirling If BT and LC are altitudes of isosceles ΔABC , then BT = LC . L T C B Page 2 of 6 Ch 4 Summary L1 Key Name ____________________________ Definition of Congruence (aka CPCTC) Two polygons are congruent if they have the Same shape → corresponding angles are congruent Same size → corresponding sides are congruent. Triangle Congruence Shortcuts SSS Congruence Conjecture If the three sides of one triangle are congruent to the three sides of another triangle, then the triangles are congruent. SAS Congruence Conjecture If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent. ASA Congruence Conjecture If two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. SAA or AAS Congruence Conjecture If two angles and a non-included side of one triangle are congruent to the corresponding angles and side of another triangle, then the triangles are congruent. A C AAA Congruence Conjecture If three angles of one triangle are congruent to the corresponding angles of another triangle, then the triangles are NOT necessarily congruent. S. Stirling T Z P A I C T Z P A I C T Z P A I C Hypotenuse Leg Theorem If the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle, then the two triangles are congruent. What DOES NOT guarantee Triangles Congruence SSA or ASS Congruence? If two sides and the non-included angle of one triangle are congruent to two sides and the nonincluded angle of another triangle, then the triangles are NOT necessarily congruent. I T Z P A I C T Z P Y B A X C X B Y A C X Z Page 3 of 6 Z Ch 4 Summary L1 Key Name ____________________________ Ways to Get Equal Angles [to Get Congruent Triangles] Isosceles Triangle Conjecture Corresponding Angles Conjecture, or CA Conjecture If a triangle is isosceles, then its base angles are congruent. V ΔVBS If isosceles or VB ≅ VS , then ∠ B ≅ ∠ S . If two parallel lines are cut by a transversal, then corresponding angles are congruent. S HJJG HJJG If AB & DC , then ∠ EFA ≅ ∠ FGD . B E B A F Converse If you have an angle bisector, then the ray cuts the angle into two equal angles. A JJJG If BD bisects ∠ ABC then ∠ ABD ≅ ∠ DBC . Alternate Interior Angles Conjecture, or AIA Conjecture C If two parallel lines are cut by a transversal, then alternate interior angles are congruent.. If ∠ABD ≅ ∠DBC , HJJG HJJG If LK & NJ , then ∠ KHM ≅ ∠HMN JJJG then BD bisects ∠ ABC . Def. perpendicular lines L . Converse B ∠LHM ≅ ∠HMJ HJJG HJJG then LK & NJ . If M D A CD ⊥ AB , then m∠CMA = m∠CMB = 90° . M N , Vertical Angle Conjecture If two angles are vertical, then they are congruent. Converse m∠AMD = 90° , then CD ⊥ AB . If T V E R C ∠VET and ∠CER are vertical, then ∠ VET ≅ ∠ CER . If Def. Altitude R No Converse I A RA is an altitude of ΔTRI then m∠RAT = m∠RAI = 90° . If Converse m∠RAT = 90° , then RA is an altitude of ΔTRI “Same Angle” Use when two triangles share the exact same angle. ∠TIA ≅ ∠RIN I A R G If S. Stirling K H J C If A segment in a triangle that goes from a vertex perpendicular to the line that contain the opposite side. T G D D B Converse Two lines that intersect to form equal 90° angles. C ∠EFB ≅ ∠FGC , HJJG HJJG then AB & DC . If Definition of Angle Bisector T N . Page 4 of 6 Ch 4 Summary L1 Key Name ____________________________ Ways to Get Equal Segments [to Get Congruent Triangles] Converse of the Isosceles Triangle Conj. Def. Isosceles Triangle If a triangle has two congruent angles, then it is an isosceles triangle. If a triangle is isosceles, then its legs are congruent. If ∠ B ≅ ∠ S , then VB ≅ VS or ΔVBS is isosceles. V ΔVBS isosceles then VB ≅ VS . If S V S B B Perpendicular Bisector Conjecture If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints. Def. Midpoint A point that divides a segment into two equal segments. If M is the midpoint of SG , If C is on perp. bisect of AB , C then AC = CB . M S then SM ≅ MG . Converse Converse G If SM = MG then M is the midpoint of SG . CM bisects AB , then AM ≅ MB . If AM ≅ MB , then CM bisects AB . then D is on perp. bisect of AB . A median is a segment that connects a vertex of a triangle to the midpoint of the opposite side. A line (or part of a line) that passes through the midpoint of the segment. C If D Def. Median Def. segment bisector Converse A If AD = DB M B If AM is median in ΔABC , then BM ≅ MC B . M B M A Converse C A If BM = MC then AM is median in ΔABC . “Same Segment” Use when two triangles share the exact same segment. ET ≅ TE B W O E S. Stirling T Page 5 of 6 Ch 4 Summary L1 Key Ways to Get equal Angles and Sides [to Get Congruent Triangles] Name ____________________________ Def. perpendicular bisector A line (or part of a line) that passes through the midpoint of a segment and is perpendicular to the segment. C B M A D CD is the perp. bisector of AB , then ∠ CMA = ∠ CMB = 90° and AM ≅ MB . If Converse AM ≅ MB and ∠CMA = 90° , then CD is the perp. bisector of AB . If Basic Procedure for Proofs “parts” refers to sides and/or angles. 1. Get equal parts by using given info. and known definitions and conjectures. 2. State the triangles are congruent by SSS, SAS, ASA or AAS. 3. Use CPCTC to get more equal parts. 4. Connect that info. to what you were trying to prove . Hints [if you get stuck]: Mark the diagram with what you have stated as congruent in your proof. ( If given M is the midpoint of midpoint before marking the diagram!) AB , convert it to AM = MB by def. of Look at the diagram to find equal parts. Brainstorm and then apply previous conjectures and definitions. Work (or think) backwards! Draw overlapping triangles separately. Re-draw figures without all of the “extra segments” in there. Draw an auxillary line. Break a problem into smaller parts. S. Stirling Page 6 of 6