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Sublimation • A sample of ice in a vacuum will sublimate, and the vapour will fill the ⎛ HL HL ⎞ ⎟⎟ , − kT kT 0 ⎝ ⎠ chamber until it reaches the vapour pressure, pv = p0 exp⎜⎜ where HL is the latent heat of vapourization (the amount of energy required to remove one molecule). T0, p0 are constants Gas p0 (Pa) T0 (K) HL (10-20 J/molecule) N2 133 47 1.1 CH4 133 67 1.5 CO2 133 139 3.8 NH3 133 164 5.0 H2O 133 256 7.6 • In a vapour in thermal equilibrium, the molecules of mass m are moving randomly, with velocities v, and the kinetic energy is equal to the thermal energy: µm H v 2 2 = 3 kT 2 • The number of molecules per unit volume striking a surface, per unit time, is just ⎛ 1 ⎞⎛ 1 ⎞ Z = ⎜ ⎟⎜ ⎟nv , ⎝ 2 ⎠⎝ 3 ⎠ where the factor 1/6 is due to the fact that we only count particles moving in the (say) +x direction • Using the ideal gas law to relate n and vapour pressure pV, we get an expression for the outflow rate (molecules per unit time per unit area sublimating): ⎛1⎞ p Z =⎜ ⎟ v ⎝ 6 ⎠ kT 3kT pv = µmH 12kTµmH • Comet activity at >3 AU indicates the presence of volatile ices such as NH3 (ammonia), CH4 (methane), CO2, and N2. 1. We see the sublimated gas because of the photons the atoms absorb from solar radiation and then reemit. Comet Orbits • Long-period comets have: ¾ Highly eccentric orbits ¾ Large semi-major axes and, therefore, aphelion distances ¾ Originate from all directions ¾ Postulated to originate from the Oort cloud, a spherical shell surrounding the SS at great distance (at least ~104 AU). Short-period comets: ¾ Represent about 20% of all known comets ¾ Eccentricities typically 0.6-0.8, lower than for long-period comets ¾ Most orbital inclinations within ~30 degrees of ecliptic ¾ Likely originated in the Kuiper belt. ¾ Prograde orbits ¾ Halley’s comet is an exception, with a high inclination, retrograde orbit, e=0.97, but P=76 yr. Halley and comets like it probably originated in the Oort cloud but had their orbit perturbed. Orbits can change because of ¾ Gravitational effects ¾ Mass loss (leads to jets and evaporation) Origin and Evolution • How many passes can a comet makes? ¾ Halley’s comet loses 0.1% of its total mass on each passage through the inner solar system ¾ Therefore it can only survive ~1000 orbits ¾ With a period of ~100 years, it indicates a typical lifetime of 105 years. • Only the very longest period comets (P>millions of years) could conceivably survive for the lifetime of the solar system ¾ Must be only occaisionally ejected from the Oort cloud or Kuiper belt. ¾ Ejected from Oort cloud by gravitational perturbations from passing, nearby stars, or tidal action of the Milky Way disk. ¾ To account for the number of comets seen, Oort cloud must contain about 1012 comet nuclei! • Comets will experience strongest outgassing on their first passage. Afterwards, they probably develop a rocky crust that prevents escape of gas. ¾ Therefore many comets that visit the inner solar system will either disappear or become much smaller (fainter) on subsequent approaches. Coma • The large, bright spherical head of a comet is called the coma. ¾ Spectra of comets tell us the gases present in the coma and in approximately what proportion. ¾ There is also a much larger hydrogen coma, that emits at UV wavelengths • • • • Tails Tails are extremely elongated features which can extend millions of km from the coma and as much as a third of the way across the sky. The tail always points in a direction away from the Sun. Usually two distinct tails can be seen: ¾ a broad, curved, yellowish dust tail and ¾ a narrow, straighter, bluish ion tail. The dust tail is pushed away from the Sun by radiation pressure, while the ion tail is dragged out by the solar wind (which drags magnetic field lines). Radiation pressure is insignificant for ions, which only absorb specific frequencies of light. Comet Nuclei • Difficult to observe because when the comet is close, the coma is bright • Size can be estimated from brightness when comet is at large distances (>4 AU). Generally smaller than 10 km • From appearance of coma and tails, we know the nucleus is primarily dirty water ice. • Images from visiting spacecraft show nuclei are: ¾ Irregular in shape ¾ Heavily pitted ¾ Low albedo (3-5%) ¾ Close to solar abundance • Are they solid masses of ice (icebergs), or loosely bound pebbles with icy mantles? • Several lines of evidence point to the iceberg theory: ¾ Comets can revisit the inner solar system many times and still show bright coma/ tail. • Comets can survive close passages by the Sun, within the Roche limit. Halley’s comet • Within 4600 km of nucleus, there is no solar wind or solar magnetic field. Gas is pure outflowing cometary gas, at about 300 K • Gas near the nucleus is 80% water, 10% CO, 3% CO2, 2% methane, <1.5% NH3 and 0.1% HCN. • Dust contains rocky material but also some organic molecules • Nuclear material is closer to solar abundances than even carbonaceous chondrites. Thus comets may be the most primordial objects in the SS. • Relatively large nucleus, 12km x 8 km ¾ Implies a low density of only 300 kg m-3. ¾ Nucleus is honeycombed with voids and tunnels. ¾ Due to evaporation of ices? Or loose binding of planetesimals? • Losing gas at a rate of 20 tonnes per second. Losing dust at 3-10 tonnes per second. Fate of Comets 1. Orbit can be perturbed by giant planets, and ejected from the solar system 2. Weaker tidal effects could alter orbits of the longest-period comets such that perihelion no longer brings it into the inner solar system. 3. Could run out of volatiles to sublime, and become an asteroid. 4. Collisions with planets or the Sun are rare, but do occur. Exercises 1. Calculate the vapour pressure of water at 273 K and at 177 K. The vapour pressure of a given substance at temperature T is given by : where HL is the latent heat of ⎛H H ⎞ pv = p0 exp⎜⎜ L − L ⎟⎟ vaporization, and p0 is the vapour ⎝ kT0 kT ⎠ pressure at some temperature T0. ⎛ 7.6 × 10 −20 pv = 133Pa exp⎜⎜ − 23 ⎝ 1.38 × 10 1 ⎤⎞ ⎡ 1 − ⎢⎣ 256 273 ⎥⎦ ⎟⎟ = 507Pa ⎠ ⎛ 7.6 × 10 −20 At 177 K we get pv = 133Pa exp⎜⎜ − 23 × 1 . 38 10 ⎝ 1 ⎤⎞ ⎡ 1 ⎢⎣ 256 − 177 ⎥⎦ ⎟⎟ = 0.009Pa ⎠ Note the pressure due to the solar wind is about 10-15 Pa, so water ice will sublimate if T>90 K. 2. Write the energy balance equation for an object a distance r from the Sun, with radius R, and including sublimation. The heating term (visible light absorbed from the Sun) must be equal to the cooling due to thermal radiation in the infrared and sublimation. These terms have been previously defined, so we have: LSun (1 − AV ) 2 πR 2 = (1 − AIR )4πσR 2T 4 + 4πR 2 ZH L 4πr The πR2 term cancels out, so we have: LSun 4 (1 − AV ) ( ) − Z ( T ) H = 1 − A σ T L IR 16πr 2 For a given material, for which we know the heat of vapourization and the visible/IR albedos, we can solve for the equilibrium temperature as a function of distance r. 3. Calculate the change in period caused by a small change in velocity as a comet approaches the Sun. The change in period is related to a change in semimajor axis, a: 4π 2 3 P = a GM 4π 2 2 2 PdP = 3 a da GM dP 3 da = 2 a P 2 Using the vis-viva equation, we can relate da/a to a change in velocity, dv (at fixed r): ⎡1 1 ⎤ v 2 = 2GM ⎢ − ⎥ ⎣ r 2a ⎦ GM 2vdv = 2 da a dv GM da = v2 v 2a a Assuming a is large, we can approximate v2~2GM/r: 2GM dv GM da = 2a a r v da ⎛ a ⎞ dv = 4⎜ ⎟ a ⎝r⎠ v dP 3 da ⎛ a ⎞ dv = = 6⎜ ⎟ 2 a P ⎝r⎠ v For a=40 AU, a 1% change in velocity at r=1 AU results in a factor 2.4 change in Period. 4. Consider a hypothetical comet, with a pure water-ice nucleus 1km in radius. If the sublimation rate is Z~1022 molecules/m2/s, how many passages will the comet be able to make through the inner solar system? For a nucleus of pure water, the mean molecular mass is 18mH. So the rate of mass loss due to sublimation is: 4πR 2 Zµm H = 4π (1km ) 10 22 (18)(1.67 × 10 −27 kg ) = 3800 kg / s 2 Sublimation of water begins when the comet is within r~2AU of the Sun. If we assume that the semimajor axis a is much larger than 2GM 2AU, then the velocity is v≈ ≈ 3 × 10 4 m / s r approximately To guess how long the comet spends near the Sun, assume it travels at that velocity over a distance 4AU (directly to the Sun and back), so t~4AU/v~200 days. So during each passage within r=2AU, the comet loses a mass m=6.6x1010 kg. The total mass, assuming a density 900 kg/m3, is M=4/3πR3ρ=3.8x1013 kg. So it will survive ~57 passages (~11,000 years if P=200 y).