* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project
Download 09/11/03 lecture
Electron configuration wikipedia , lookup
Size-exclusion chromatography wikipedia , lookup
History of chemistry wikipedia , lookup
Molecular orbital diagram wikipedia , lookup
Rutherford backscattering spectrometry wikipedia , lookup
Abundance of the chemical elements wikipedia , lookup
Atomic nucleus wikipedia , lookup
Chemical element wikipedia , lookup
IUPAC nomenclature of inorganic chemistry 2005 wikipedia , lookup
Stoichiometry wikipedia , lookup
Allotropes of carbon wikipedia , lookup
Chemistry: A Volatile History wikipedia , lookup
Isotopic labeling wikipedia , lookup
History of molecular theory wikipedia , lookup
From “Microscopic” to “Macroscopic” Chem 101 Lecture 09/10/03 What we need to learn… (the macroscopic world) • How do we describe/characterize “bulk” properties of different compounds? (i.e., large collections of atoms and molecules). • How do the atomic and molecular structures related to physical and chemical properties of “bulk” materials? Atomic masses revisited... • We’ve talked about atomic masses in terms of the number of neutrons and protons present in an atom…but how much does an atom weigh? What units do we describe the mass of an atom in? • The atomic mass unit (amu): defined explicitly in terms of the 12C atom--the mass of 1 12C atom = 12 amu. • All other atomic masses are defined relative to the 12C atom. 1 Return to isotopes... • Some elements can have a number of different possible atomic structures which differ only in the number of neutrons in the nucleus--isotopes. • For example, there are three different atomic structures for C : 12C, 13C, and 14 C. • When dealing with bulk quantities of carbon, more useful to think of an average atomic weight which will take into account the individual atomic masses and their relative abundance. Finding the average mass of carbon • The relative abundances of the isotopes of carbon are : – – 12C 13C : 98.89% : 1.11% • The average mass of carbon = (0.9889)*(12.00 amu) + (0.0111)*(13.00 amu) = 12.01 amu • This is the mass of carbon we use when calculating amounts of the “bulk” carbon. Going from amu to grams... • Atomic mass units are still really small…how do we relate amu to something we can measure easily in the lab (like grams)? • Introduce a new unit: the mole • A mole is equal to the number of carbon atoms in exactly 12 grams of carbon. This number is called Avogadro’s number and is equal to 6.022 x 10 23. • In other words, 12 g of carbon contain 1 mole of carbon atoms (or 6.022 x 10 23 carbon atoms). 2 Random facts about moles • A mole is analogous to a dozen…a unit for counting things. • The unit “mole” (abbreviated “mol”) should be accompanied by the object being counted (just as we say “one dozen eggs,” we should say “one mole of carbon atoms”). So, we can think of molar mass as well as atomic mass • Molar mass = mass of a mole of atoms (if its an element) or molecules (if a compound) of a substance. • For elements, molar mass is defined in such a way that the molar mass is the average atomic weight expressed in grams: Element Molar mass Aluminum Atomic weight 26.98 amu Carbon 12.01 amu 12.01 g 26.98 g Hydrogen 1.01 amu 1.01 g Potassium 39.10 amu 39.10 g The molecular weight of a molecule is the sum of the atomic weight of its constituent atoms • What is the molecular weight of methanol CH4O ? – – – – Mass of 1 C = 12.01 amu Mass of 4 H = 4 x 1.008 amu Mass of 1 O = 16.00 amu Total mass of CH 4O : 32.04 amu • What is the molar mass of methanol? – Molar mass (mass of 1 mole) of CH 4O = 32.04 g/mol 3 Key skills • Convert from # grams to # mol and convert from # mol to # grams. • From a molecular formula, calculate mass percent composition. • From a mass percent composition, calculate empirical formula. • From empirical formula and molar mass, calculate molecular formula. 4