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Worked Examples Uniform Circular Motion A 2 kg ball on a string is rotated about a circle of radius 10 m. The maximum tension allowed in the string is 50 N. What is the maximum speed of the ball? You may wish to view the video clip at: http://www.youtube.com/watch?v=Q5FRbieCU1A (optional) Uniform Circular Motion 2 A 2 kg ball on a string is rotated about a circle of radius 10 m. The maximum tension allowed in the string is 50 N. What is the maximum speed of the ball? The centripetal force in this case is provided entirely by the tension in the string. If the maximum value of the tension is 50 N, and the radius is set at 10 m we only need to plug these two values into the equation for centripetal force: T = Fc = implies that v = thus v = = 15.8 Uniform Circular Motion m/s or 57 km/hr 3 1 km/hr is equivalent to: A. B. C. D. E. 0.1666… m/sec 0.2777… m/sec 0.6 m/sec 1.6 m/sec 3.6 m/sec Uniform Circular Motion 5 1 km/hr is equivalent to: A. B. C. D. E. 0.2777… m/sec Uniform Circular Motion 6 During the course of a turn, an automobile doubles its speed. How much additional frictional force must the tyres provide if the car safely makes around the curve? You may wish to view the video clip at: http://www.youtube.com/watch?v=qiIYEmpWaaQ Uniform Circular Motion 8 During the course of a turn, an automobile doubles its speed. How much additional frictional force must the tyres provide if the car safely makes around the curve? Since Fc varies with v2, an increase in velocity by a factor of two must be accompanied by an increase in centripetal force by a factor of four. Uniform Circular Motion 9 Which of the following statements are true of an object moving in a circle at a constant speed? A. The object experiences a force which has a component directed parallel to the direction of motion. B. Inertia causes objects to move in a circle. C. Because the speed is constant, the acceleration is zero. D. The acceleration and the net force vector are directed perpendicular to each other. E. If the net force acting upon the object is suddenly reduced to zero, then the object would suddenly depart from its circular path and travel tangent to the circle. F. The acceleration of the object is directed tangent to Uniform Circular Motion 11 the circle. Which of the following statements are true of an object moving in a circle at a constant speed? A. B. C. D. E. If the net force acting upon the object is suddenly reduced to zero, then the object would suddenly depart from its circular path and travel tangent to the circle. F. Uniform Circular Motion 12 A satellite is said to be in geosynchronous orbit if it rotates around the earth once every day. For the earth, all satellites in geosynchronous orbit must rotate at a distance of 4.23×107 metres from the earth's centre. What is the magnitude of the acceleration felt by a geosynchronous Please view the video clip at: satellite? http://www.youtube.com/watch?v=FsfcIEmR_b0 Uniform Circular Motion 14 A satellite is said to be in geosynchronous orbit if it rotates around the earth once every day. For the earth, all satellites in geosynchronous orbit must rotate at a distance of 4.23×107 metres from the earth's centre. What is the magnitude of the acceleration felt by a geosynchronous satellite? The acceleration felt by any object in uniform circular motion is given by a = . We are given the radius but must find the velocity of the satellite. We know that in one day, or 86 400 seconds, the satellite travels around the earth once. Thus: v= thus a = = = = = 3 076 m/s = Uniform Circular Motion 0.224 m/s2 15 Identify the type of force which causes the following object (in bold type) to travel along a circular path. An eraser is tied to a string swung in a horizontal circle. a. b. c. d. e. f. g. h. Gravity Normal Tension Applied Friction Spring Electrical Magnetic Uniform Circular Motion 17 Identify the type of force which causes the following object (in bold type) to travel along a circular path. An eraser is tied to a string swung in a horizontal circle. a. b. c. d. e. f. g. h. Tension Uniform Circular Motion 18 Identify the type of force which causes the following object (in bold type) to travel along a circular path. The moon orbits the earth. a. b. c. d. e. f. g. h. Gravity Normal Tension Applied Friction Spring Electrical Magnetic Uniform Circular Motion 19 Identify the type of force which causes the following object (in bold type) to travel along a circular path. The moon orbits the earth. a. b. c. d. e. f. g. h. Gravity Uniform Circular Motion 20 Identify the type of force which causes the following object (in bold type) to travel along a circular path. A car makes a sharp right-hand turn along a level roadway. a. Gravity b. Normal c. Tension d. Applied e. Friction f. Spring g. Electrical h. Magnetic Uniform Circular Motion 21 Identify the type of force which causes the following object (in bold type) to travel along a circular path. A car makes a sharp right-hand turn along a level roadway. a. b. c. d. e. Friction f. g. h. Uniform Circular Motion 22 Identify the type of force which causes the following object (in bold type) to travel along a circular path. A roller coaster car passes through a loop. Consider the car at the bottom of the loop. a. Gravity b. Normal c. Tension d. Applied e. Friction f. Spring g. Electrical h. Magnetic Uniform Circular Motion 23 Identify the type of force which causes the following object (in bold type) to travel along a circular path. A roller coaster car passes through a loop. Consider the car at the bottom of the loop. a. b. Normal c. d. e. f. g. h. Uniform Circular Motion 24 The maximum lift provided by a 500 kg aeroplane is 10 000 N. If the plane travels at 100 m/s, what is its shortest possible turning radius? Please view the video clip at: http://www.youtube.com/watch?v=fmrH-LEZCf0&NR=1 Uniform Circular Motion 26 The maximum lift provided by a 500 kg aeroplane is 10 000 N. If the plane travels at 100 m/s, what is its shortest possible turning radius? Again, we use the equation Fc = . Rearranging, we find that r = . Plugging in the maximum value for the lift of the plane, we find that rmin = = 500m Uniform Circular Motion 27 What is the acceleration of a piece of dust on an old-fashioned record album, 15 cm from the centre, if the record is spinning at 33.3 rpm? a) 0.46 m/s2 b) 0.523 m/s2 c) 0.91 m/s2 d) 1.046 m/s2 e) 1.82 m/s2 Uniform Circular Motion 29 What is the acceleration of a piece of dust on an old-fashioned record album, 15 cm from the centre, if the record is spinning at 33.3 rpm? a) b) - c) d) - e) 1.82 m/s2 Uniform Circular Motion 30 A popular daredevil trick is to complete a vertical loop on a motorcycle or in a small car. This trick is dangerous, however, because if the motorcycle / car does not travel with enough speed, the rider / driver falls off the track before reaching the top of the loop. What is the minimum speed necessary for a rider / driver to successfully go around a vertical loop of 10 metres Please view the video clip at: radius? http://www.youtube.com/watch?v=GMWCsfVNHjg Uniform Circular Motion 32 A popular daredevil trick is to complete a vertical loop on a motorcycle or in a small car. This trick is dangerous, however, because if the motorcycle / car does not travel with enough speed, the rider / driver falls off the track before reaching the top of the loop. What is the minimum speed necessary for a rider / driver to successfully go around a vertical loop of 10 metres radius? • During the entire trip, the rider /driver experiences two different forces: the normal force from the track, and the gravitational force. At the top of the loop, both these forces point down, or towards the centre of the loop. Thus the combination of these forces provides the centripetal force at that point. At the minimum speed of the motorcycle / car, however, s/he experiences no normal force. One can see this by envisioning that if the rider / driver had gone any slower, s/he would have fallen off the track. Thus, at the minimum speed, all the centripetal force is provided by gravity. Uniform Circular Motion 33 A popular daredevil trick is to complete a vertical loop on a motorcycle or in a small car. This trick is dangerous, however, because if the motorcycle / car does not travel with enough speed, the rider / driver falls off the track before reaching the top of the loop. What is the minimum speed necessary for a rider / driver to successfully go around a vertical loop of 10 metres radius? • During the entire trip, the rider /driver experiences two different forces: the normal force from the track, and the gravitational force. At the top of the loop, both these forces point down, or towards the centre of the loop. Thus the combination of these forces provides the centripetal force at that point. At the minimum speed of the motorcycle / car, however, s/he experiences no normal force. One can see this by envisioning that if the rider / driver had gone any slower, s/he would have fallen off the track. Thus, at the minimum speed, all the centripetal force is provided by gravity. • Plugging into our equation for centripetal force, we see that mg = • Rearranging the equation, vmin = = = 9.9 m/sec = 9.9 x 3 600 / 1 000 km/hr = 36 km/hr Thus the rider must be travelling at least 36 km/hr to make it around the loop. Uniform Circular Motion 34 What is the tension in a 0.500 metre rope which carries a 2.50 kg bucket of water in a vertical circle with a velocity of 3.00 m/s when the bucket is at the bottom of its swing? a) b) c) d) e) 2.5 N 20.5 N 24.5 N 45 N 69.5 N Uniform Circular Motion 36 What is the tension in a 0.500 metre rope which carries a 2.50 kg bucket of water in a vertical circle with a velocity of 3.00 m/s when the bucket is at the bottom of its swing? a) b) c) d) e) 69.5 N Uniform Circular Motion 37 The QSA Senior Mathematics C Syllabus suggests the following learning experience: Please view the video clip at: http://www.youtube.com/watch?v=iAYkvp82klM “Investigate the angle of lean required by a motorcycle rider to negotiate a corner at various speeds.” Uniform Circular Motion 39 References / Sources: http://www.youtube.com/watch?v=Q5FRbieCU1A http://www.youtube.com/watch?v=qiIYEmpWaaQ http://www.youtube.com/watch?v=FsfcIEmR_b0 http://www.youtube.com/watch?v=fmrHLEZCf0&NR=1 http://www.youtube.com/watch?v=GMWCsfVNHjg http://www.youtube.com/watch?v=iAYkvp82klM http://www.physicsclassroom.com/reviews/circles/c pmans1.cfm#1 Uniform Circular Motion 40