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Transcript
DT021-1 Electrical Machine and Power Electronics
POWER ELECTRONICS Lecture 2: Fundamental Switching Concepts
1. Duty Cycle, Switching Period, Switching Frequency
Switch is closed for time = ton
Switch is open for time = toff
Switching pattern repeats with period Tswitch=ton+toff
Switching frequency = fswitch = 1/Tswitch
Duty Cycle (D) = proportion of cycle for which switch is closed:
t on
t
D=
= on
t on + t off Tswitch
2. Ripple / Noise
Switching creates square wave voltage waveforms which are filtered by the circuit L
and C. Some underlying ripple remains on the output voltage. The higher the
switching frequency the easier it is to filter out and the smaller L and C required.
ripple
Vout
noise
time
Ripple: Refers to a low or medium frequency repeating oscillation on the
output voltage at the switching frequency fswitch. Ripple is usually
sinusoidal or triangular and is specified by its root mean square value.
Noise: Refers to high frequency (MHz) spikes superimposed on the
output voltage. Noise is caused by ringing of parasitic Ls and Cs in the
circuit at every switching instant. Noise is usually specified by its peak to
peak value.
3. Losses in an ideal switch
The ideal switch has zero impedance when closed and infinite impedance when open
and switches between the two states instantaneously. In the closed state losses are
zero because voltage drop is zero. In the off state losses are zero because the current
is zero. The ideal switch has zero losses.
4. Losses in a real switch switching a resistive circuit
i(t)
+
v(t)
-
R
Vs
v(t)
Vs
Ion
Von
i(t)
trise
tfall
time
At any instant of time the losses in the switch can be said to be P(t ) = v(t ).i (t )
In practise the average loss over time can be broken down into three components:
1. Conduction losses – arising from the non zero voltage drop during the on-state
2. Switching losses – arising from the finite switching speed from one state to
another
3. Additional losses would arise if there were a small leakage current during the off
state. This type of loss is almost always negligible.
Conduction loss calculation:
Assuming that the rise and fall times of the current are much less than ton
Conduction loss = Pcl = Von.Ion.D
Switching loss calculation:
Assume that current i(t )rises linearly during trise and falls linearly during tfall
This means that v(t) = Vs-i(t).R must fall and rise linearly during these respective
periods.
The energy lost in the switch during the rise time of the current =
trise
trise
t −t   t 
VI t
Erise = ∫ v(t ).i(t ).dt = ∫ Vs  rise .I on  dt = s on rise
0
0
6
 trise   t rise 
Similarly the energy lost in the switch during the fall time of the current =
 t   t fall − t 
VI t
t fall
t fall
dt = s on fall
.I 
E fall = ∫ v(t ).i (t ).dt = ∫ Vs 

 t  on  t
0
0
6
 fall   fall 
Since each of these losses occurs once during a switching cycle the average power
lost due to switching is:
E rise + E fall Vs I on × (t rise + t fall ) Vs I on × (t rise + t fall )
=
=
. f switch
Switching loss = Psl =
6Tswitch
6
Tswitch
Notice: Conduction losses depend on duty cycle but are independent of switching
frequency. Switching losses are independent of duty cycle but depend on switching
frequency.
Design Trade-off: A high switching frequency is desirable in order to minimise
ripple and allow the use of smaller L and C in the filter. However a high switching
frequency causes increased switching losses.
5. Losses in a real switch switching an inductive circuit
In an inductive circuit the circuit inductance will attempt to keep current flowing
while the switch is opening. Inductive circuits must have some form of alternative
path (usually a freewheel diode) to allow the inductor current to continue to flow after
the switch has opened otherwise very large induced voltages (v=Ldi/dt) would
damage the switch.
Example:
Step down DC/DC switching converter (Buck Converter)
+ v(t)
Q1
-
L1
Vs
D1
Io
C1
Square
Wave
Generator
+
Load
i(t)
Vo
-
Assume that the inductor L1 is sufficiently large that the current flowing in it does not
vary through the switching cycle and has very little ripple. Since C1 cannot carry a
DC current then the current in L1 is equal to Io the DC output current. As explained in
lecture 1 the opening and closing of the switch creates a square wave voltage across
the diode. The output voltage Vo is the filtered average of this square wave.
Useful Formula for step down converter: Vo = D.Vs
Switch Waveforms:
V(t)
Vs
Ion
Von
i(t)
trise
tfall
time
Explanation: When the switch is open the inductor current must flow through the diode.
Therefore the diode is conducting and the emitter of Q1 is pulled down to one diode drop
above ground. If we assume that the diode drop is small enough to be negligible then the
switch sees the full supply voltage Vs while it is turned off.
When the switch turns on it starts to take some of the inductor current. However until the
switch is carrying the full inductor current the diode must supply the balance. Thus the
diode remains conducting for the whole of the rise time trise and the switch continues to
see the full supply voltage for the whole of the rise time.
On the turn off of the switch – as soon as the switch current starts to fall the diode must
begin conducting in order to carry the balance of the inductor current. Therefore the
switch voltage rises abruptly to the full value of Vs the moment the switch turns off.
Contrast this situation with the resistive circuit where the voltage rises and falls in
proportion to the current.
Conduction losses
Are unchanged from resistive circuit Pcl=Von.Ion..D
In the step down converter Ion = Iothe output current.
Switching losses:
The energy lost in the switch during the rise time of the current =
t rise
t rise
 t 
VI t
dt = s on rise
E rise = ∫ v(t ).i(t ).dt = ∫ Vs I on 
0
0
2
 t rise 
Similarly the energy lost in the switch during the fall time of the current =
 t fall − t 
V I t
t fall
t fall
dt = s on fall
E fall = ∫ v(t ).i(t ).dt = ∫ Vs .I on 

 t
0
0
2
 fall 
Since each of these losses occurs once during a switching cycle the average power
lost due to switching is:
E rise + E fall Vs I on × (t rise + t fall ) Vs I on × (t rise + t fall )
Switching loss = Psl =
=
=
. f switch
2Tswitch
2
Tswitch
Sample Problem:
1. A switch mode step down dc/dc converter produces a 20V, 10Amp output from a
48V input. The converter uses a MOSFET switch operating at 100kHz. The rise
time of the switch current is 100ns and the fall time is also 100ns. The MOSFET
has an on state resistance of 0.1 OHM. The inductor has a series resistance of 0.05
Ohm and the diode has a forward voltage drop of 0.7V at 10A. The capacitor may
be considered ideal.
Estimate the Switch conduction losses and switching losses (4.17W, 4.8W)
a.
b. Estimate the inductor losses and the diode losses (5W, 4.08W)
c. Estimate the efficiency of the converter (0.92)