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Combination Circuits Steps to Solve Combined Series-Parallel Circuits 1. If necessary, draw a diagram of the circuit. 2. Find any parallel resistors in the circuit and simplify them into one equivalent resistance using the formula for parallel equivalent resistance. 3. If necessary, draw a new diagram using the equivalent resistor instead of the multiple previous resistors. 4. Find any resistors that are now in series and replace them with the equivalent resistance using the formula for series equivalent resistance. 5. If necessary, draw a new diagram using the equivalent resistance. 6. Once the circuit is reduced into a single resistor, you can now solve for the current using Ohm’s Law. Calculate the following: a)total equivalent resistance b)total current c)the current across each resistor d)the voltage drop across each resistor Draw the Circuit Solve for Req for parallel resistors Remember, the first step in combination circuits is ALWAYS to calculate the equivalent resistance of the parallel resistors! 1/Req = 1/4 + 1/12 1/Req = .333 Req = 3 Ω Redraw the Circuit 5Ω 24 V 3Ω 8Ω Solve for Req for series resistors Req = 8 + 3 + 5 Req = 16 Ω Note: the 3Ω resistor came from the result of our solving for the Req for the parallel circuit section 5Ω 24 V 3Ω 8Ω Redraw the Circuit 24 V 16 Ω Solve for the Total Current Ohm’s Law: V = IR Vt = (It)(Rt) 24 = It(16) It = 1.5 amps Solve for the Current through Each Resistor Since resistors R1 and R4 are in series, the current in series-connected resistors is the same everywhere. Therefore, It = I1 = I4 = 1.5 amps Note: In a Series Circuit, to solve for total current: It = I1 = I2 = I3 =… Solving for the Current through Each Resistor Since resistors R2 and R3 are in parallel, the current in parallel-connected resistors is added up to equal the total current. Therefore, It = I1 + I4 = 1.5 amps However, this gets a bit tricky because the resistors do not have the same value; therefore we must first calculate the voltage drop through each resistor and then come back to calculate the current Series Circuit, to solve for total voltage: Vt = V1 + V2 + V3 +… Calculate the voltage drop across the seriesconnected resistors. (R1 and R4 in diagram) V1 = I1R1 V1 = (1.5)(5) = 7.5 V V4 = I4R4 V4 = (1.5)(8) = 12 V Next, subtract the values for the series voltage from the total voltage VT – Vseries = Vparallel 24 V – 7.5 V – 12 V = 4.5 V This tells us that the voltage drop across EACH parallel resistor is 4.5 V because Vt = V1 = V2 = V3 = … Lastly, using Ohm’s Law calculate the current traveling through each parallel resistor V2 = I2R2 4.5 = I2(4) I2 = 1.125 amps Remember, current varies through each parallel resistor since there is more than one path for the electrons to take! V3 = I3R3 4.5 = I3(12) I3 = .375 amps Results of our calculations: