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Concept 9.1: The electric potential is the electric potential energy per unit charge. 9. Electric potential electric potential in Volts (V) = J/C. It exists in the absence of a test charge • potential and potential energy • equipotential surfaces • electric discharge I. At this position, the electric potential due to the positive charges is a) b) c) d) using the potential energy of a collection of point charges qi. 1 Quiz of concept 9.1 Physics 1E03 Lecture 9 + + _ _ + + + + + + + + + + 2 II. The electric potential energy of the charges on the metal plate at distance d, compared to when it is resting on the insulator, is a) b) c) d) -2πkdσ2 2πkdσL2 -2πkdσ2L2 2πkdσ2L2 _ _ _ _ _ _ _ _ σ C/m2 Charge of positive test charge, in C s1 q V (r ) = k ∑ i i ri Physics 1E03 Lecture 9 d U q0 From previous expressions for U, there are two equivalent ways to find the electric potential: s2 r r r r V ( s2 ) − V ( s1 ) = − ∫ E • ds directly from the definition of work, Serway and Beichner Parts of sections 25.1-.4, 25.6 The Electrophorus has a charge density of +σ on the insulating plate. The metal plate is charged by induction and raised a distance d<<L. V= Electric potential energy of the test charge in J. It exists only when the test charge is present. _ _ _ _ _ _ _ _ d + σ C/m2 + _ _ + + + + + + + + + + L L 4πkdσ below the potential on the insulator. 4πkdσ above the potential on the insulator. 2πkdσ below the potential on the insulator. 2πkdσ above the potential on the insulator. Physics 1E03 Lecture 9 3 Physics 1E03 Lecture 9 4 1 Concept 9.2: Lines of constant potential run perpendicular to the electric field lines. Field lines point in the direction of decreasing potential. lines of constant potential electric field lines Quiz of concept 9.2 A conducting object in equilibrium has an excess charge –Q. The potential at the surface of the conductor a) is different than the potential inside the conductor, since the excess charges are forced to the surface b) is constant everywhere on the surface c) is greater at sharply curved regions where there is a greater local charge density σ d) none of the above is always true, since the potential can depend on other nearby charges. +Q s2 r r r r V ( s2 ) − V ( s1 ) = − ∫ E • ds s1 Q=0 If the step ds along a path is perpendicular to E, E ds=0. V(s2) = V(s1), the path is an equipotential. Physics 1E03 Lecture 9 5 Concept 9.3: In order to maintain a constant potential, the charge density on a conductor is greater in regions of greater surface L>>R +R curvature. 1 The potential of a conducting sphere with excess charge Q is R1 2 R2 Q V (r ) = k r When connected to form a single conductor, Q Q Q Q V = k 1 = k 2 so | E ( R1 ) |= k 12 >| E ( R2 ) |= k 22 R1 R2 R1 R2 Physics 1E03 Lecture 9 Application of concept 9.3 Sparks and lightning travel through the air only once it becomes conducting. This happens when E>3x106 N/C. Then a free electron can be accelerated through a constant E to give enough kinetic energy to K f = U i − U f = qEd ≈ knock another electron from average spacing of molecules conducting wire Thus charge density Q/4πR2 is greater for sphere of smaller R. + + + + For a single object with different + curvatures, more charge collects + + ++ at the sharper curves. Physics 1E03 Lecture 9 7 + + + + 6 an atom it hits This creates more free electrons, which knock more free, etc. until there is a cascade with a high enough electron density to conduct the current. This cascade will occur first near sharply pointed conductors where the electric field is strongest. Q: How does a lightning rod work? Physics 1E03 Lecture 9 8 2 Summary • the electric potential, is the electric potential energy divided by the size of the test charge V = U/q0. • lines of constant potential run perpendicular to electric field lines • every point of a conductor in equilibrium is at the same potential • to maintain a constant potential, charge accumulates near sharp points of a conductor Practice problems: Chapter 25, #9, 21, 49, 70 Next lecture: read sections 25.4-.6 Physics 1E03 Lecture 9 9 3