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ORGANIC CHEMISTRY 307 CHAPTER 2 LECTURE NOTES R. Boikess A. Acids and Bases Review (HP. Chap 15), Remember the problems you had with understanding this topic. It is one of the more difficult in Gen Chem. Here we will make a “simplification.” 1. In 162 we did KA and KB. Here we do only KA (and pKA) for all situations: neutral acids and the charged conjugate acids of neutral bases. For example KA of NH4+ and amines etc 2. Review of Lewis Acids and Bases An electron pair donor is a Lewis base. An electron pair acceptor is a Lewis acid. Very general. Includes most Bronsted acids and bases. And in addition nonhydroxylic bases such as NH3 (because of lone pair) and nonprotonic acids such as BF3 (because of incomplete octet). Anions such as X- and some cations (subject to restrictions on octet expansion) can be Lewis acids.. So Ammonium is not a Lewis acid. It can’t accept electrons, but CH3+ is a Lewis acid. It can accept electrons because it has an incomplete octet. 3. Electrophiles and Nucleophiles This classification is another way of thinking about Lewis Acids and Bases. Very important because it allows us to easily characterize chemical properties and behavior. Since a Lewis Acid is an electron pair acceptor, it is a species that wants to get electrons. It is an electron lover or in Greek an electrophile. The more the species wants to get electrons, the stronger it is as a Lewis Acid or the more electrophilic. Electrophilicity is a measure of how strongly the given species wants to accept electrons. A Lewis Base is an electron donor. It is a species that has an electron pair that can be donated to something which can accept an electron pair. (an electrophile) It is a “nucleus” lover or a nucleophile. The more the species wants to donate the electron pair, that is the more it wants to find something to accept its pair, the more nucleophilic. Nucleophilicity is a measure of how strongly a species wants to donate electrons. 1 B Kinetics and Thermodynamics. Review (HP 13.2-13.4, 13.8-13.10, 6.4, 17.1-17.7) Both of these topics are very important in Orgo because they enable us to understand organic reactions and to predict the behavior of organic compounds in many situations. In general, Thermo tells us whether or not something can happen. Kinetics tells us how long it will take to happen if it can. Remember that time is not a thermodynamic variable. In particular, we will focus on and use 1. 2. 3. 4. 5. Enthalpy(usually called “heat” because it is defined as the heat flow that accompanies a process that takes place at constant pressure) and we will refer to such measures of chemical behavior as heat of reaction, heat of combustion, heat of hydrogenation, bond energy, resonance energy, and strain energy, all of which are enthalpies. Entropy, which can be loosely understood as a measure of disorganization, to help us understand and predict chemical behavior. Free Energy as a qualitative and quantitative measure of a chemical system’s tendency to undergo change. Rate laws, the relationship between rate and concentration, because they give a great deal of information about how a reaction takes place. Reaction mechanisms (how a reaction takes place) will be one of the major themes in this course. Activation energy, which comes from the relationship between rate and temperature, similarly can give us a great deal of information about reaction mechanism. C. Overall Organization and Systematization There are over 30 million organic compounds known and more are being synthesized every day. We must have a way to systematize so that we can learn and communicate. a. Remember why there are so many compounds (C-C bonds and chains). So one focus is to describe the carbon skeleton, which consists of a “main” chain of C atoms with various additional C atoms or groups of C atoms (smaller chains) attached at various points. 2 b. Think of it as a “connect the dots puzzle” with “branches” allowed. Let’s draw a big grid of dots and then connect. Do for 3 dots, 4 dots, 5 dots and 6 dots. Each different pattern corresponds to a different carbon skeleton, which is the starting point for describing and naming all organic compounds. Note it’s the pattern of attachment that counts, how many dots a given dot is connected to, not how we draw it, straight, zig-zag, or bent. See a how right angle bend doesn’t matter for propane and butane etc. But look at (and we will return to) rings. For 10 dots there are 75 ways, for 25 dots almost 36.8 million ways (not counting rings). That’s why this is a whole-year course. c. How do we go from a carbon skeleton to a compound? Every C must have 4 bonds. Most carbons in most compounds get to 4 bonds by bearing the requisite number of hydrogens. Introduce 1°, 2°, and 3° carbons, related to the number of C’s to which a given C is attached. Again, go from Kekule to condensed formulas and to condensed formulas with parentheses. [CH3(CH2)4CH3 and CH3C(C2H5)2CH3] Go from dots to skeletal structures. (omit terminal dots (carbons); bend lines so that a vertex of an angle represents a dot. (carbon) as does the end of a line. Show for propane, butane and isobutane Note branches off the main chain. Constitutional isomers, discuss. c. Most org cpds have at least one C that gets to 4 in some other way than maximum H’s. One obvious way is with a multiple (double or triple) bond, which uses 2 carbons. Show also that it can’t happen in some structures (neopentane) and there can be no triple bonds in many others. Discuss pentavalent carbon, which is impossible under ordinary conditions. d. Another way is to use atoms other than H. These are most commonly (in order) O, N, X (halogen). S, and P. Generally there aren’t many of these atoms compared to the number of C’s and H’s. e. Any part of the molecule that is something other than a C bonded to other C’s by single bonds and to H’s is called a functional group. The chemical behavior and to some extent the physical behavior of the molecule is determined primarily (but not entirely) by the functional groups. Most chemical change takes place at the functional groups. So we are going to focus on functional groups, their chemistry, their interconversion, their preparation, and their properties 3 in general. That is the overall organization of the material in the course will be based primarily on functional groups. f. But the carbon skeleton is also very important. Ex: methanol and ethanol. Compare to each other and also to methane and ethane. g. The idea of a homologous series is very useful. When a group of compounds differ only in the number of –CH2- groups in the carbon chain we have a homologous series. The physical properties of the members of a homologous series change in a regular way with each additional CH2. D. Nomenclature In order to communicate we must be able to give every organic compound a name that will unambiguously identify the compound. One name must equal one compound. Unfortunately the reverse is not true, except in a naming system. a. Systematic and Common names; discuss how we will deal with them. b. What must a name do? i. Indicate the number of C atoms ii. Indicate the carbon skeleton iii. Designate the type and location of the functional groups. c. Start with compounds that have no functional groups other than carbon-carbon multiple bonds. These compounds have only C and H and are called hydrocarbons. If they also have no multiple bonds they are called alkanes or saturated hydrocarbons. General formula CnH2n+2. Show why. A C in the middle has two H’s (and two C’s), a C at the end has 3 H’s (and 1 C) and there are two ends. For C’s in the middle that are 3° or 4° it comes back somewhere else in an extra 1°. Once we name these we can then use their names as the basis for everything else by naming and locating functional groups on their carbon skeleton. These names are systematic but some are based on old common names and don’t seem very systematic. The system is called the IUPAC [discuss] system. It has rules that enable us to name any compound we can imagine. It must have a rule for very situation. It is not possible for must chemists to know all the rules. But there are reference works and even experts who can be consulted for new or very complex situations. 4 1. Start at an end and identify the longest continuous chain, called the main chain. Referring to the grid of dots, the ends are the dots with only one line. Remember that the longest chain depends only on how the atoms are connected and not how we draw them. Go back to the grid of dots and regard it as a puzzle. Start at an end and trace the longest path to another end without lifting your pencil from the paper or hitting the same dot twice. Make sure that there are no other ends (at the start or finish) that might produce a longer path. 2. Indicate the number of C atoms in the chain with a numerical prefix. Memorize the first 12 (not the first 20 given in your book), of these prefixes: [Flashcards] i. common: meth, eth, prop, but ii. Greek: pent, hex, hept, oct, dec iii Latin: non iv Latin + Greek undec, dodec 3. Add the suffix “ane” to designate no functional groups (alkane). 4. If there are no more C atoms (no branches) other than the ones in the main chain, we are finished. Homologous series (CH2) of straight chain or ( n-alkanes). For the first four systematic names = common names. 5. If there are branches, we must name and locate them. Same idea for other substituents as we will see. System is arbitrary, usually no real chemical reasons for the names. 6. Name of Branch: The suffix indicates a branch. Drop “ane” add “yl” Meaning of “yl” is one less H (so it can be attached). This species is called a radical R (in this case an alkyl radical). More generally, a radical can be any collection of C and H and even other atoms. Key is point of attachment, which is shown by a line CH3CH2- etc. Radicals derived from n-alkanes with missing H (point of attachment at the end of the chain) take name (systematic = common) from parent: show methyl, ethyl, propyl, butyl (but not isopropyl or s-butyl because the attachment is not at the end of the chain). For branched radicals naming is more complex, will come back to it. 5 7. Location of branch. Number the main chain, according to certain rules. Put number in front of branch. Consider 2-methylpentane and then 3-methylpentane. 2-methylpentane 3-methylpentane Notice that the exact shape of the drawing is determined by the Chem Draw software. (Remember: You can download this software by following the directions on the course web page.) Lowest number. [Note: no 1-methyl, 2-ethyl etc Why?] Punctuation: Separate numbers from words or parentheses by hyphens and from each other by commas. IUPAC names are usually one word. 8. More than one branch. Multiplying prefixes for same branches, di, tri, tetra, penta, Show 2,4-dimethylhexane. Every branch has its own number. Different branches are listed alphabetically. For this purpose multiplying prefixes and sec and tert don’t count. But iso, neo, and cyclo are alphabetized. 9. Numbering is done from the end that gives the lowest number to the first substituent or first different numbered substituent. So 3,4, 6 is better than 3,5,6 and 2,7,8 is better than 3,4, 9 (decane). 6 2,7,8-trimethyldecane Note it’s not the sum. . Simply restated: Start numbering from the end of the chain closest to a substituent. If there is a tie then the lower number goes to the lower substituent alphabetically: 3-ethyl-5-methylheptane. (not 5-ethyl-3-methyl) 3-ethyl-5-methylheptane 10. Branched alkanes; overlap of common and systematic for the alkanes themselves and as parents of branched radicals. Illustrate the branched alkanes with common names. Remember common works only for simple cases and gives the entire compound a name, rather than naming the pieces. Show isobutane = 2-methylpropane, isopentane = 2-methylbutane, isohexane = 2-methylpentane. Get the idea, meaning of iso, not much advantage to the common name in this case. Show neopentane= 2,2-dimethylpropane, neohexane = 2,2dimethylbutane etc. Slightly more useful than iso. Reminder: This type of IUPAC name is one word. Numbers in the word are separated from each other by commas and from letters by hyphens. 11. Branched radicals. Here common names are more useful and more used. Again simple cases: Show, isobutyl, isopentyl, isohexyl etc and what iso means here. Compare to n-alkyl and note 1° C as the point of attachment. Then a few uniquely named radicals: isopropyl (contrast with isobutyl), sec-butyl (s-butyl), and tert-butyl (t-butyl), can be extended but usually isn’t and neopentyl, which also isn’t generally 7 extended. See Table 2.6 of text. All the common names in Table 2.6 are acceptable in this course and can be used, if you wish, in IUPAC names. So given any of these names you must be able to write the structure. Most chemists and other scientists use those common names and many others that we will encounter in ordinary communication. 12. Discuss again meaning of sec and tert and lead into 1°, 2°, and 3° for radicals, functional group substituents, and even H. Note it is always based on C (except for amines, where it is based on N). 13. Systematic names of branched radicals. Like naming branched alkanes with two differences. (a). the suffix is “yl” not “ane”. (b) the chain is numbered with a 1 at the point of attachment. [That means that we can have 1-methyl or 1-ethyl as part of the name of a branched radical]. Also the entire name of the branched radical is put in parentheses to avoid confusion. Show getting to systematic names: isobutyl = (2-methylpropyl), isopentyl = (3-methylbutyl) etc. Isopropyl = (1-methylethyl) note the 1 here but not on alkanes. s-butyl = (1-methylpropyl), t-butyl = (1,1dimethylethyl), and neopentyl = (2,2-dimethylpropyl). You can see why the common names are popular for these radicals, but also see that once you learn the system that’s it. You must learn the system, but you still need to know the common names for communication purposes. Here is a challenging structure to name (You can use common or systematic names for the branched radicals) 8 E. Some Simple Functional Groups Start with some organic derivatives of the binary hydrides of important nonmetals. Systematize: replace one or more H’s with R’s. [Reminder about R] Could also approach these as substituted alkanes HX is a hydrogen halide (F, Cl, Br, I) and RX is an alkyl halide. HOH is water. Replace one H to get ROH, the alcohols, replace both H’s to get ROR’ the ethers (the R’s may or may not be the same). NH3 is ammonia. Replace one H; RNH2 is a primary amine. Replace two H’s; RNHR’ is a secondary amine. Replace all three H’s; RN(R’)R” is a tertiary amine. Note R’s can be the same or different. Contrast this use of 1°, 2°, 3° with that for C which applies to halides and alcohols. Compare isopropyl alcohol (2°) with isopropyl amine (1°) This is an important exception to the rule that 1°, 2°, and 3° refer to R (or C). The structures of these compounds reflect the structure of the parent inorganic compound. There are of course chemical and physical differences that arise from changing H to R. There are many more functional groups in addition to these simple ones, as we shall see.. a. Nomenclature Two main ways to name these: systematic (IUPAC) and common. In simple cases they may be the same. Sometimes there is more than one common name. Sometimes the common name is much simpler and is widely used. IUPAC names as a substituted alkane, designating the type and location of the functional group(s). Common names are generally derived from the parent inorganic hydride. 1. Halides RX. a. If R has a simple or common name then the common name is often used. It is the name of the radical followed by halide (F, Cl, Br, or I) Methyl fluoride, ethyl bromide, isopropyl iodide, neopentyl chloride etc. These names are derivatives of HX (hydrogen chloride-methyl chloride) and are two words b. If not, use the IUPAC system, which treats the X as if it is an alkyl radical, the names are fluoro, chloro, bromo, iodo. (Could just as well be methyl) and they are alphabetized and have the same numerical preference as R. Names are one word. Consider these 9 two names: 3-ethyl-4-fluorohexane and 3-chloro-4-ethylhexane. Draw the structures and understand the numbering and order of the substituents. b. Physical Properties Review H.P. 11.1-11.3, 11.5-11.7, 12.1, 12.3-12.4 Major unifying theme: Physical properties are determined primarily by polarity, secondarily by size and shape. A major factor can be H-bonding. 1. Alkanes are nonpolar. a. Like dissolves like thus alkanes are not soluble in polar solvents. b. Intermolecular forces in alkanes are all due to polarizability, but they can be very important if the alkane gets big. In a homologous series of alkanes the BP increases by about 29 K/CH2 and the ΔH of vaporization increases by a bit more than 4 kJ/C. So an alkane with more than about 80 C’s can’t be boiled. Why? [C-C bond energy is 347 kJ/mol] c. Shape can also influence boiling point: pentane = 36 °C, isopentane 28 °C, and neopentane 9 °C. snakes and balls. Or greater contact area = higher boiling point d. melting point depends even more on shape because of packing, as well as contact area. Good packing = higher melting point if there are comparable intermolecular forces. Notice that odd numbered nalkanes melt slightly lower than expected. (Figure 2.5) This observation can be explained by packing differences. The closer molecules can approach each other in a crystal, the better the packing, and the higher the melting point. The odd numbered n-alkanes do not pack as well as the even numbered ones. [This explanation is not in the book] Consider an n-alkane as a zig-zag chain (a good approximation of its shape) and draw what happens when two zig-zags are next to each other. n-hexane 10 or n-pentane or Pentane In the one with the odd number of carbons the methyl at each end is facing the same way and they bump when the molecules try to get close. 2. Most functional groups are polar so properties are determined by competition between nonpolar alkyl part and polar O or N or X. The larger the alkyl part the less the effect of the polar group on overall properties. Solubility: 3 or 4 C atoms still can be soluble in water. 3. H-bonding especially important in determining physical properties of organic substances in those instances where it is possible. (OH and NH bonds) How do we make the study of the physical and chemical properties of millions of compounds manageable and comprehensible? Physical and chemical properties depend on molecular structure, which has two components, electronic (distribution of electron density in bonds and over the molecule) and steric (the shape, 3-D arrangement of the atoms in space). Both are very important. F. Representations of 3-D Structure (very important) 1. Can do it in 3-D with models. There are different types of models: ball and stick, space filling, framework. Your kit is basically a ball and stick type. 11 2. Projections: a 3-D structure in 2-D, not all atoms need be shown by symbols, just as they are not in condensed formulas. Different types are useful for showing different things. Unlike the “bond-line condensed formulas we have been using, projections often show the H’s when they play a role in the 3-D structure. a. Dotted line-wedge (already presented), easy and good for designating where things are relative to each other. But not so good for helping us to see the actual shape and spatial interactions. b. Sawhorse, like a perspective drawing. Eye is above and to the right of a 3-D framework model. We will use these projections extensively when we look at rings.(Chapter 4) They are good for seeing spatial interactions c. Newman Projection; Note location of the eye and representations of the C atoms. Note how flattening appears to change the angle. Don’t forget to interpret the 2-D back to 3-D. Note how the vertical on the front C is up. G. 3-D Structure of some simple compounds. As we will see it’s usually not as simple as it appears. 1. Methane, this one is simple. Ideal tetrahedral, bond angles, draw dotted line wedge and sawhorse. 2. Ethane, not so simple. Do all this with models and draw sawhorse and Newman projections [Figures 2-7, 2-8. 2-9 in your text] Look at these very carefully for a long time. a. First look at each C. It will be very close to ideal tetrahedral. b. But what about the CH3 groups with respect to each other? Does it matter? Explain why. These structures are all related to each other by rotation around a single bond. They are defined as conformations of the compound. A particular conformation is called a conformer. (Book also uses the term “rotamer,” We will not.) The least stable conformer is called the eclipsed. The relative instability of the eclipsed is the result of repulsions between the electrons in C-H bonds on the adjacent carbons. Relative instabilities related to the shape of a molecule are due to what is called strain. This particular type of strain is called torsional strain. The destabilization (or torsional strain) is the 12 result of bringing bonding electron pairs in C-H bonds too close to eachother. c. Energy differences between conformers Figure 2.10. Understand why. Note and name two extremes eclipsed and staggered. d. Free rotation around C-C single bond. Not totally free so it is T dependent. Note barrier. If we lower the temperature enough we can slow down the rotation greatly. The reason we can treat conformations as a single compound is because the temperature on the surface of the earth is what it is, high enough that most rotations around single bonds are very rapid.. In outer space (outside the satellite) staggered and eclipsed ethane would be isomers. 3. n-Butane is more complicated. Focus on rotation around the 2-3 bond. Methyl is much bigger than H. Thus there are two staggered conformations of different energy and two eclipsed conformations of different energy. Figures 2.12-2.13 The two staggered conformations are called gauche and anti. Energy difference between them of 4 kJ/mol. This number is important because we will use it to help explain relative energies of other compounds. It is called a skew butane interaction. Both are much more stable than the eclipsed conformations, which can be ignored. The relative instability of the gauche is due to what is called steric strain, the result of atoms or groups of atoms approaching each other too closely. 13