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Notes: Going Further With Energy Level 1: Conservation of Mechanical Energy So far, weβve mostly studied situations where the mechanical energy of a system has stayed the same- like roller coasters without friction and objects in free fall. This helped us learn a lot about how mechanical, potential, and kinetic energy work. Notice, in the example below, the mechanical energy (potential + kinetic energy) stays the same the whole way through the roller coaster. When the mechanical energy doesnβt change, we say it is conserved. This roller coaster shows mechanical energy being conserved. Mechanical energy is conserved if you donβt have a force adding energy to the system or taking it away. For example, there are no engines speeding a car up, no friction slowing it down, no jet packs making it accelerate, no air resistance causing drag. When the mechanical energy does change, we say it is not the energy was not conserved. We say energy is not conserved when a car puts on its brakes and comes to a stop, when a rocket booster speeds the shuttle up into the sky, when friction makes a ball roll to a stop. In these situations, energy was either entering the system or leaving it. Level 2: Work Letβs say we did want the mechanical energy to change- we wanted a car to speed up or we wanted to an object to slow down. How can we change the mechanical energy? Something that changes the mechanical energy of a system is called work. πΌπππ‘πππ πππβππππππ πΈπππππ¦ + ππππ = πΉππππ πππβππππππ πΈπππππ¦ ππΈππππ‘πππ + π = ππΈπππππ Positive Work Lets say a child is sliding past on a sled. She has no potential energy and 400 J of kinetic energy. How much mechanical energy does she have? If you wrote 400 J, thatβs right. Now, imagine you rushed up to the child and gave her a push. You would be doing work on her. Letβs say gave her a push that added 300 J to her energy. We can find out how much mechanical energy she would have now. ππΈππππ‘πππ + π = ππΈπππππ 400π½ + 300π½ = 700π½ She now has more mechanical energy. Sheβs still flat on the ground, so all of this turns into kinetic energy. She is now moving faster. She has more mechanical energy. Her potential is the same (sheβs on flat ground) so she has more kinetic energy. Work can be positive or negative. Positive work adds energy to the object. Negative work takes energy away. Letβs try an example with negative work. Negative Work A car is speeding along a flat road at night. It has 12000 J of kinetic energy. How much mechanical energy does it have? Yup, 12000 J. Suddenly, a deer jumps out of nowhere. The car hits the brakes, and the friction between the tires and the road does -8000 J of work on the car. How much mechanical energy does the car have now? ππΈππππ‘πππ + π = ππΈπππππ 12000π½ β 8000π½ = 4000π½ The car now has less mechanical energy. The potential energy is the same (flat road). Therefore, it has less kinetic energy. It is moving slower. No Work When mechanical energy is conserved, no work is done on the object. The mechanical energy stayed the same (it is conserved). We practiced identifying these in the last level. A big hint to identifying these is that the author will usually go out of their way to say there is no friction, no air resistance (Fair), no thermal energy lossβ¦ they are trying to make it obvious that there is no work (positive or negative) being done on the object. These donβt actually happen in real life. There is always friction or air resistance or thermal energy. In some situations, we pretend like there is no work because there is so little we donβt have to worry about it. Level 3: Using Kinetic and Potential Energy with Work We can take this one step further. In the last level we learned: ππΈππππ‘πππ + π = ππΈπππππ and in a previous section we learned: πππβππππππ πΈπππππ¦ = πππ‘πππ‘πππ πΈπππππ¦ + πΎππππ‘ππ πΈπππππ¦ ππΈ = π + πΎ If we put this all together we get: πΌπππ‘πππ πππ‘πππ‘πππ πΈπππππ¦ + πΌππ‘πππ πΎππππ‘ππ πΈπππππ¦ + ππππ = πΉππππ πππ‘πππ‘πππ πΈππππ¦ + πΉππππ πΎππππ‘ππ πΈπππππ¦ ππ + πΎπ + π = ππ + πΎπ Example: Finding the Final Kinetic Energy A car over the top of a hill, where it has a potential energy of 30000 J and a kinetic energy of 20000 J. As it goes down the hill, the driver hits the gas and the engine does +5000 J of work. At the bottom of the hill, none of the potential energy is left. What is the carβs new kinetic energy? What we know: Pi= 30000 J Ki= 20000 J W= +5000 J Pf = 0 J Kf =? ππ + πΎπ + π = ππ + πΎπ 30000π½ + 20000π½ + 5000π½ = 0 + πΎπ 55000 π½ = πΎπ Level 4: Real Life If there is a situation where no outside forces are acting on an object, the mechanical energy is conserved. That means no friction, nobody pushes on the object, no air resistance, no brakes, no jet packs, no kicks to the rearβ¦ nothing. If nothing tries to speed the object up or slow the object down, we can say mechanical energy is conserved. In real life, mechanical energy generally does change. Take the example of the swing. If mechanical energy didnβt change, it would just keep changing from potential to kinetic, then go back to kinetic. If the mechanical energy didnβt decrease, the swing would go right back up to the same height it started at. A child on a swing wouldnβt need to pump- they would just keep going back and forth- rising to the exact same height each time. Remember the guy in the skate park, how he kept going back up to the same height. The computer was programmed to have mechanical energy be conserved. In real life, the mechanical energy of a swing decreases if you donβt pump. Imagine you just sat in the swing. You wouldnβt go as high each time you went back and forth. Your mechanical energy would be slowly decreasing, until you finally came to a complete stop. Each time you went back and forth, youβd have a little less mechanical energy, until you didnβt have any left at all. Friction (thermal energy) is always going to steal a little. It is one of the laws of the universe. If mechanical energy is conserved, we can use the following equation. πΎπ + ππ = πΎπ + ππ Letβs build off what we learned in our last section. Imagine you lifted a ball with a mass of 4 kg up in the air so that it was 10 m off the ground. Letβs calculate the potential energy below. Iβll put the answer here so that youβll know if you did it right or not. P= 392 J Now, letβs say you dropped the ball. Just before the ball hit the ground, all the potential energy would be converted into kinetic energy. So, when the ball hits the ground, it has 392 J of kinetic energy. Letβs take it one step further. Use this kinetic energy to calculate the velocity of the ball. Remember the mass is 4 kg. Iβll put the correct answer at the bottom so you can make sure you got it right. v= 14 m/s