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1-14
Status: - - - - - - - - - - - - - Newton, Isaac
Set 4, Due Wed, Sep 25, 2013 at 08:00
1. [1pt]
The location of a particle (in m) is given by its x, y and z coordinates as function of the time (in s) as:
x = -99+7t-3t2 and y = 35-27t and z = 41+15t-13t2
Calculate the z-component of the instantaneous velocity at t = -3.00s.
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2. [1pt]
What the magnitude of the object's acceleration at t = 10.00s?
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3. [1pt]
An athlete executing a long jump leaves the ground at a 27.9o angle and travels a horizontal distance
7.72m. What was the take-off speed?
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4. [1pt]
A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge H = 229m below.
If the plane is traveling horizontally with a speed of 223km/hr (61.9m/s), how far in advance of the
recipients (horizontal distance) must the goods be dropped?
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5. [1pt]
A small steel ball bearing with a mass of 18.0 g is on a short compressed spring. When aimed vertically
and suddenly released, the spring sends the bearing to a height of 1.43 m. Calculate the horizontal
distance the ball would travel if the same spring were aimed 29.0o from the horizontal.
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6. [1pt]
A 1.49 kg mass is suspended from a string which is pulled upward. The mass accelerates upwards with
an acceleration of 2.10 m/s2. What is the tension in the string?
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7. [1pt]
A mass M of 1.35kg is attached to the end of a string whose length is 0.590m. The mass slides
without friction on a horizontal surface as indicated in the diagram. If the string can withstand a
maximum tension of 57.3N, what is the maximum tangential speed the ball can have before the cord
breaks?
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8. [1pt]
Indicate whether the following statements are always true or can be false.
(Select T-True, F-False. If the first is F and the rest T, enter
FTTTTT).
A) If two objects have the same acceleration, they are under the influence of equal forces.
B) If an object's speed does not change, no net force is acting on the object.
C) In order not to slow down, a car moving at a constant velocity needs a small net force applied.
D) An object's velocity will change if a non-zero net force acts on the object.
E) The net force which acts on an object which remains at rest is zero.
F) During the collision of a large truck with a car, the car exerts an equal size force on the truck as the
truck exerts on the car.
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9. [1pt]
A sphere of mass of 1.27kg is accelerated upwards by a string to which the sphere is attached. Its speed
increases from 2.61m/s to 5.79m/s in a time of 2.58s. Calculate the tension in the string, assuming that
the tension remains constant during that time.
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10. [1pt]
A 3.70 kg penguin runs onto a huge sheet of frictionless Arctic ice. At t=0 it is at x=0 and y=0 with an
initial velocity of 0.47 m/s along the positive x-axis. It slides while being pushed by the wind with a
force of 0.47 N directed along the positive y-axis. Calculate the magnitude of the penguin's velocity at t
= 10.73 s.
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11. [1pt]
Two forces F1 and F2 are acting on a mass M=5kg. The force F1 = 9i + 6j + 1k, in N. The acceleration
of the mass is given by a = 3i + 7j + 2k, in m/s2. Calculate the magnitude of F2 .
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12.[1pt]
An object having velocity v0 undergoes an acceleration a as depicted in the figure. The acceleration
lasts for a definite nonzero period of time.
Which of the following vectors could represent the velocity vector after acceleration? The arrows are
all drawn to the same scale. (Give ALL correct answers in alphabetical order, i.e., B, AC, BCD...)
A) It is impossible to answer because the duration of the acceleration is not specified.
B)
C)
D)
E)
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13.[1pt]
A body pulled by a constant force accelerates from 10 cm/s to 40 cm/s in 2.0 s. A second force
accelerates the same body from rest to 80 cm/s in 10.5 s. If the first force is known to be 6.5 N, that
what is the second force?
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14.[1pt]
The graph below shows the velocities of two objects of equal mass as a function of time. Forces FA,
FB, ... FF acted on the objects during intervals A, B, ... F. Which of the statements below are correct
descriptions of the magnitudes of the forces? (If A and E are, and the others are not, enter TFFFT).
A) FE > FC > FF
B) FB < FD < FE
C) FB = FE
D) FC > FA > FF
E) FA = FD = FC
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