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PX211-0406 The following questions were randomly selected for topics in Chapters 4 – 6 of the Chem 1411 lecture outline, Dr. J. Pelezo, LSC-Tomball. Note: The question answers for each are attached at the end of the practice exam and include selected suggestions for solving the problems and/or question. If needed, please direct question for assistance to [email protected]. ____ 1. What is the molecular mass of the hydrocarbon styrene (shown in the figure)? A) B) C) D) E) 104.1 amu. 91.1 amu. 103.1 amu. 13.0 amu. 78.1 amu. ____ 2. What is the molar mass of zinc sulfate heptahydrate, ZnSO4 • 7H2O? A) 180. g/mol B) 288 g/mol C) 384 g/mol D) 162 g/mol E) 582 g/mol ____ 3. Which of the following samples contains the largest number of molecules? A) 10. g Pb B) 10. g Cl2 C) 10. g Kr D) 10. g O2 E) 10. g S8 ____ 4. Which of the following compounds has the highest percentage of nitrogen by mass? A) (NH4)2SO3 B) NaNO3 C) N2Cl4 D) NH4NO2 E) HNO3 ____ 5. How many grams of hydrogen atoms are present in 18.4 g of water? A) 37.1 g B) 1.02 g C) 2.06 g D) 1.96 g E) 12.3 g ____ 6. A compound containing only carbon, hydrogen, and oxygen is subjected to elemental analysis. Upon complete combustion, a 0.1804-g sample of the compound produced 0.3051 g of CO2 and 0.1249 g of H2O. What is the empirical formula of the compound? A) C3H6O3 B) C3H3O C) C4H8O3 D) C2H2O E) CH2O3 ____ 7. A compound composed of only C and F contains 17.39 % C by mass. What is its empirical formula? A) CF3 B) CF C) C2F D) CF4 E) CF2 ____ 8. The analysis of an organic compound showed that it contained 1.386 mol of C, 0.0660 mol of H, 0.924 mol of O, and 0.462 mol of N. How many nitrogen atoms are there in the empirical formula for this compound? A) 9 B) 7 C) 2 D) 4 E) 3 ____ 9. A sample containing 0.700 mol of a compound is composed of 4.21 1023 atoms of sodium, 24.79 g of chlorine atoms, and 33.57 g of oxygen atoms. The formula of the compound is A) NaClO3. B) NaClO5. C) NaClO. D) NaClO4. E) NaClO2. ____ 10. Complete combustion of a 0.30-mol sample of a hydrocarbon, CxHy, gives 1.20 mol of CO2 and 1.50 mol of H2O. The molecular formula of the original hydrocarbon is A) C3H8. B) C4H10. C) C8H20. D) C3H5. E) C5H7. ____ 11. One step in the isolation of pure rhodium metal (Rh) is the precipitation of rhodium(III) hydroxide from a solution containing rhodium(III) sulfate according to the following balanced chemical equation: Rh2(SO4)3(aq) + 6NaOH(aq) 2Rh(OH)3(s) + 3Na2SO4(aq) If 2.40 g of rhodium(III) sulfate reacts with excess sodium hydroxide, what mass of rhodium(III) hydroxide may be produced? A) 1.50 g B) 4.80 g C) 2.40 g D) 0.374 g E) 2.99 g ____ 12. The limiting reactant is the reactant A) that has the lowest coefficient in the balanced equation. B) that has the lowest molar mass. C) that is left over after the reaction has gone to completion. D) for which there is the lowest mass in grams. E) none of the above ____ 13. The commercial production of phosphoric acid, H3PO4, can be represented by the equation 1500 g 300 g Ca3(PO4)2 + 3SiO2 + 310 g/mol 60.1 g/mol 307 g 5C + 12.0 g/mol 1180 g 5O2 + 32.0 g/mol 300 g 3H2O 18.0 g/mol 3CaSiO3 + 5CO2 + 2H3PO4 The molar mass for each reactant is shown below the reactant, and the mass of each reactant for this problem is given above. Which substance is the limiting reactant? A) H2O B) C C) O2 D) Ca3(PO4)2 E) SiO2 ____ 14. When 20.0 g C2H6 and 60.0 g O2 react to form CO2 and H2O, how many grams of water are formed? A) 14.5 g B) 58.0 g C) 18.0 g D) 20.0 g E) none of these ____ 15. A 5.95-g sample of AgNO3 is reacted with BaCl2 according to the equation 2AgNO3(aq) + BaCl2(aq) 2AgCl(s) + Ba(NO3)2(aq) to give 3.36 g of AgCl. What is the percent yield of AgCl? A) 44.6 % B) 33.5 % C) 66.9 % D) 56.5 % E) 100 % ____ 16. A 2.00-L glass soda bottle filled only with air is tightly capped at 24°C and 744.0 mmHg. If the bottle is placed in water at 75°C, what is the pressure in the bottle? A) 238 mmHg B) 872 mmHg C) 2330 mmHg D) 635 mmHg E) 383 mmHg ____ 17. When the valve between the 2.00-L bulb, in which the gas pressure is 3.00 atm, and the 3.00-L bulb, in which the gas pressure is 2.50 atm, is opened, what will be the final pressure in the two bulbs? Assume the temperature remains constant. A) B) C) D) E) ____ 2.70 atm 5.50 atm 2.83 atm 2.80 atm 2.67 atm 18. Which of the following is a correct statement of Charles’s law, A) B) C) D) E) ? The volume of a gas varies proportionally with the pressure. The volume of a gas sample varies directly with the absolute temperature. All gas samples of the same volume at STP contain the same number of atoms. The pressure of a gas sample varies inversely with the volume. All gas samples of the same volume at STP contain the same number of molecules. ____ 19. The pressure of 4.2 L of nitrogen gas in a flexible container is decreased to one-half its original pressure, and its absolute temperature is increased to double the original temperature. The volume is now A) 2.1 L. B) 4.2 L. C) 8 L. D) 17 L. E) 1.1 L. ____ 20. A fixed amount of gas in a rigid container is heated from 100°C to 700°C. Which of the following responses best describes what will happen to the pressure of the gas? A) The pressure will increase by a factor greater than 7. B) The pressure will increase by a factor of 7. C) The pressure will increase by a factor less than 7. D) The pressure will decrease by a factor of 7. E) The pressure will remain the same. ____ 21. The volume of 1 mol of nitrogen A) is lower than that of 1mol ammonia at high pressures. B) is decreased by decreasing the pressure of the gas. C) has the value of 22.4 L at 0°C and 1.00 atm. D) is decreased by increasing its kinetic energy. E) is increased by decreasing the temperature. ____ 22. Which of the following graphs does not correctly describe the ideal gas law? A) B) They all correctly represent the ideal gas law. C) D) E) ____ 23. What is the pressure of a 59.6-L gas sample containing 3.01 mol of gas at 44.9°C? (R = 0.0821 L • atm/(K • mol), 1 atm = 760 torr) A) 1.41 102 mmHg B) 1.73 10–3 mmHg C) 1.32 mmHg D) 1.00 103 mmHg E) 5.77 102 mmHg ____ 24. The density of ethane, C2H6 (30.1 g/mol), at 32°C and 1.31 atm pressure is A) 1.57 g/L. B) 19.2 g/L. C) 1.34 g/L. D) 0.635 g/L. E) 0.162 g/L. ____ 25. At 28°C and 452 mmHg, an unknown pure gas has a density of 0.674 g/L. Which of the following gases could be the unknown gas? A) F2 B) C3H6 C) N2O D) Ne E) N2 ____ 26. Calcium nitrate will react with ammonium chloride at slightly elevated temperatures, as represented in the equation below. Ca(NO3)2(s) + 2NH4Cl(s) 2N2O(g) + CaCl2(s) + 4H2O(g) What is the maximum volume of N2O at STP that could be produced using a 3.40-mol sample of each reactant? A) 9.28 102 L B) 152 L C) 1.31 10–2 L D) 76.2 L E) 22.4 L ____ 27. A 24.1-g mixture of nitrogen and carbon dioxide is found to occupy a volume of 15.1 L when measured at 870.2 mmHg and 31.2oC. What is the mole fraction of nitrogen in this mixture? A) 0.539 B) 0.500 C) 0.461 D) 0.426 E) 0.574 ____ 28. A sample of oxygen is collected over water at a total pressure of 690.7 mmHg at 19°C. The vapor pressure of water at 19°C is 16.5 mmHg. The partial pressure of the O2 is A) 0.9305 atm. B) 0.9349 atm. C) 0.9088 atm. D) 1.070 atm. E) 0.8871 atm. ____ 29. Which of the following statements is least likely to be true of a sample of nitrogen gas at STP? A) Collisions between the gaseous molecules are elastic. B) The intermolecular forces between nitrogen molecules are not negligible. C) Molecules of gaseous nitrogen are in constant random motion. D) The average kinetic energy of the gaseous nitrogen is proportional to the absolute temperature of the gas. E) The pressure exerted by gaseous nitrogen is due to collisions of the molecules with the walls of the container. ____ 30. At STP, as the molar mass of the molecules that make up a pure gas increases, the A) root mean square speed of the molecules increases. B) root mean square speed of the molecules decreases. C) root mean square speed of the molecules remains constant. D) root mean square speed increases to a maximum, then decreases. E) none of the above. ____ 31. Molecular speed distributions for a gas at two different temperatures are shown below. Which of the following graphs correctly describes the distributions at the two temperatures, where T2 > T1? NOTE: The small vertical lines indicate average speed. A) B) C) D) E) none of the above ____ 32. Which of the following relates the rate of effusion of a gas to the square root of its molar mass? A) Boyle’s law B) Graham’s law C) Charles’s law D) Dalton’s law E) Avogadro’s hypothesis ____ 33. If 250 mL of methane, CH4, effuses through a small hole in 28 s, the time required for the same volume of helium to pass through the hole under the same conditions will be A) 56 s. B) 7 s. C) 1.8 s. D) 14 s. E) 112 s. ____ 34. Using the van der Waals equation, determine the pressure of 459.0 g of SO2(g) in a 4.40-L vessel at 625 K. For SO2(g), a = 6.865 L2 • atm/mol2 and b = 0.05679 L/mol. (R = 0.0821 L • atm/(K • mol)) A) 110 atm B) 8.06 atm C) 73.9 atm D) 83.6 atm E) 8.36 atm ____ 35. The air whipped up by a tornado possesses what type(s) of energy? A) potential energy only B) internal energy only C) kinetic energy only D) kinetic energy, potential energy, and internal energy E) kinetic energy and potential energy only ____ 36. Calculate U of a gas for a process in which the gas absorbs 9 J of heat and does 25 J of work by expanding. A) 16 J B) 34 J C) –34 J D) 0, because U is a state function E) –16 J ____ 37. The phrase “the heat absorbed or released by a system undergoing a physical or chemical change at constant pressure” is A) the change in enthalpy of the system. B) the change in internal energy of the system. C) the definition of a state function. D) the temperature change of the system. E) a statement of Hess’s law. ____ 38. What is the quantity of heat evolved at constant pressure when 60.3 g H2O(l) is formed from the combustion of H2(g) and O2(g)? H2(g) + O2(g) H2O(l); H° = –285.8 kJ A) B) C) D) E) ____ 1.17 10–2 kJ 285.8 kJ 1.72 104 kJ 85.4 kJ 9.57 102 kJ 39. What mass of hydrogen is consumed when 587.9 kJ of energy is evolved from the combustion of a mixture of H2(g) and O2(g)? H2(g) + O2(g) H2O(l); H° = –285.8 kJ A) B) C) D) E) ____ 4.147 g 2.073 g 0.2412 g 6.162 g 2.131 g 40. How much heat is liberated at constant pressure when 58.5 g of calcium oxide reacts with 83.9 L of carbon dioxide gas, measured at 1.00 atm pressure and 25.0°C? (R = 0.0821 L • atm/(K • mol)) CaO(s) + CO2(g) CaCO3(s); H° = –178.3 kJ A) B) C) D) E) ____ –6.11 102 kJ –1.04 104 kJ –7.97 102 kJ –1.86 102 kJ –1.50 104 kJ 41. A 5.09-g sample of solid silver reacted in excess chlorine gas to give a 6.76-g sample of pure solid AgCl. The heat given off in this reaction was 6.00 kJ at constant pressure. Given this information, what is the enthalpy of formation of AgCl(s)? A) –127 kJ/mol B) –63.6 kJ/mol C) 127 kJ/mol D) –6.00 kJ/mol E) 6.00 kJ/mol ____ 42. The heat required to raise the temperature of 52.00 g of chromium by 1°C is called its A) heat of vaporization. B) specific heat. C) heat of fusion. D) entropy. E) molar heat capacity. ____ 43. The molar heat capacity of gaseous heptane at 25.0°C is 165.2 J/(mol°C). What is its specific heat? A) 0.6065 J/(g°C) B) 1.649 J/(g°C) C) 6.041 10–5 J/(g°C) D) 165.2 J/(g°C) E) 1.655 104 J/(g°C) ____ 44. A 170.0-g sample of metal at 79.00°C is added to 170.0 g of H2O(l) at 14.00°C in an insulated container. The temperature rises to 16.19°C. Neglecting the heat capacity of the container, what is the specific heat of the metal? The specific heat of H2O(l) is 4.18 J/(g°C). A) 4.18 J/(g°C) B) 120 J/(g°C) C) 0.146 J/(g°C) D) –0.146 J/(g°C) E) 28.6 J/(g°C) ____ 45. A 94.7-g sample of silver (s = 0.237 J/(g°C)), initially at 348.25°C, is added to an insulated vessel containing 143.6 g of water (s = 4.18 J/(g°C)), initially at 13.97°C. At equilibrium, the final temperature of the metal–water mixture is 22.63°C. How much heat was absorbed by the water? The heat capacity of the vessel is 0.244 kJ/°C. A) 5.20 kJ B) 3.09 kJ C) 7.31 kJ D) 9.12 kJ E) 129 kJ ____ 46. In a bomb calorimeter, reactions are carried out A) at 1 atm pressure and 0°C. B) at a constant pressure. C) at a constant volume. D) at a constant pressure and 25°C. E) at 1 atm pressure and 25°C. ____ 47. Which of the following has a standard enthalpy of formation value of zero at 25°C? A) Cl(g) B) Cl2(l) C) Cl2(g) D) Cl(s) E) Cl2(s) ____ 48. What is the standard enthalpy of formation of liquid butyraldehyde, CH3CH2CH2CHO(l)? CH3CH2CH2CHO(l) + O2(g) 4H2O(l) + 4CO2(g); H° = –2471.8 kJ Substance CO2(g) H2O(l) A) B) C) D) E) ____ H°f (kJ/mol) –393.5 –285.8 –245.4 kJ/mol +245.4 kJ/mol –1792.5 kJ/mol –3151.1 kJ/mol +3151.1 kJ/mol 49. What is the standard enthalpy change for the following reaction? N2H4(l) + 2NO2(g) 2N2O(g) + 2H2O(l) Substance N2H4(l) NO2(g) N2O(g) H2O(l) A) B) C) D) E) ____ H°f (kJ/mol) +50.6 +33.1 +82.1 –285.8 –290.6 kJ –524.2 kJ –119.7 kJ +290.6 kJ +119.7 kJ 50. From the following information, determine the enthalpy of formation of C2H4(g). C2H4(g) C(s) + H2(g); H = –26.2 kJ A) –26.2 kJ/mol B) 26.2 kJ/mol C) 104.8 kJ/mol D) –52.4 kJ/mol E) 52.4 kJ/mol PX211-0406 Answer Section 1. ANS: A PTS: 1 DIF: easy REF: 3.1 OBJ: Calculate the formula mass from molecular models. (Example 3.2) TOP: stoichiometry | mass and moles of substance KEY: molecular mass MSC: general chemistry 2. ANS: B PTS: 1 DIF: easy REF: 3.2 OBJ: Understand how the molar mass is related to the formula weight of a substance. TOP: stoichiometry | mass and moles of substance KEY: formula mass MSC: general chemistry 3. ANS: D PTS: 1 DIF: moderate REF: 3.2 OBJ: Calculate the number of molecules in a given mass of substance. (Example 3.6) TOP: stoichiometry | mass and moles of substance KEY: mole | mole calculations MSC: general chemistry 4. ANS: D PTS: 1 DIF: easy REF: 3.3 OBJ: Calculate the percentage composition of the elements in a compound. (Example 3.7) TOP: stoichiometry | determining chemical formulas KEY: mass percentage MSC: general chemistry 5. ANS: C PTS: 1 DIF: easy REF: 3.3 OBJ: Calculate the mass of an element in a given mass of compound. (Example 3.8) TOP: stoichiometry | mass and moles of substance KEY: mole | mole calculations MSC: general chemistry 6. ANS: C PTS: 1 DIF: moderate REF: 3.4 OBJ: Calculate the percentage of C, H, and O from combustion data. (Example 3.9) TOP: stoichiometry | determining chemical formulas KEY: elemental analysis MSC: general chemistry 7. ANS: A PTS: 1 DIF: easy REF: 3.5 OBJ: Determine the empirical formula from the percentage composition. (Example 3.11) TOP: stoichiometry | determining chemical formulas KEY: empirical formula MSC: general chemistry 8. ANS: B PTS: 1 DIF: easy REF: 3.5 OBJ: Determine the empirical formula from the percentage composition. (Example 3.11) TOP: stoichiometry | determining chemical formulas KEY: empirical formula MSC: general chemistry 9. ANS: A PTS: 1 DIF: moderate REF: 3.5 OBJ: Determine the empirical formula from the percentage composition. (Example 3.11) TOP: stoichiometry | determining chemical formulas KEY: empirical formula MSC: general chemistry 10. ANS: B PTS: 1 DIF: difficult REF: 3.5 OBJ: Determine the molecular formula from the percentage composition and molecular mass. (Example 3.12) TOP: stoichiometry | determining chemical formulas KEY: molecular formula MSC: general chemistry 11. ANS: A PTS: 1 DIF: easy REF: 3.7 OBJ: Relate the quantities of reactant to the quantity of product. (Example 3.13) TOP: stoichiometry | stoichiometry calculation KEY: amounts of substances 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. MSC: general chemistry ANS: E PTS: 1 DIF: easy REF: 3.8 OBJ: Understand how a limiting reactant or limiting reagent determines the moles of product formed during a chemical reaction and how much excess reactant remains. TOP: stoichiometry | stoichiometry calculation KEY: limiting reactant MSC: general chemistry ANS: E PTS: 1 DIF: moderate REF: 3.8 OBJ: Calculate with a limiting reactant involving masses. (Example 3.16) TOP: stoichiometry | stoichiometry calculation KEY: limiting reactant MSC: general chemistry ANS: E PTS: 1 DIF: moderate REF: 3.8 OBJ: Calculate with a limiting reactant involving masses. (Example 3.16) TOP: stoichiometry | stoichiometry calculation KEY: limiting reactant MSC: general chemistry ANS: C PTS: 1 DIF: moderate REF: 3.8 OBJ: Determine the percentage yield of a chemical reaction. TOP: stoichiometry | stoichiometry calculation MSC: general chemistry ANS: B PTS: 1 DIF: easy REF: 5.2 OBJ: Use Boyle's law. (Example 5.2) TOP: phases | gas KEY: empirical gas laws | Boyle's law MSC: general chemistry ANS: A PTS: 1 DIF: moderate REF: 5.2 OBJ: Use Boyle's law. (Example 5.2) TOP: phases | gas KEY: empirical gas laws | Boyle's law MSC: general chemistry ANS: B PTS: 1 DIF: easy REF: 5.2 OBJ: Express Charles's law in words and as an equation. TOP: phases | gas KEY: empirical gas laws | Charles's law MSC: general chemistry ANS: D PTS: 1 DIF: easy REF: 5.2 OBJ: Use the combined gas law. (Example 5.4) TOP: phases | gas KEY: empirical gas laws | combined gas law MSC: general chemistry ANS: C PTS: 1 DIF: easy REF: 5.2 OBJ: Use the combined gas law. (Example 5.4) TOP: phases | gas KEY: empirical gas laws | combined gas law MSC: general chemistry ANS: C PTS: 1 DIF: easy REF: 5.3 OBJ: Learn the ideal gas law equation. TOP: phases | gas KEY: ideal gas law MSC: general chemistry ANS: B PTS: 1 DIF: moderate REF: 5.3 OBJ: Derive the empirical gas laws from the ideal gas law. (Example 5.5) TOP: phases | gas KEY: ideal gas law MSC: general chemistry ANS: D PTS: 1 DIF: easy REF: 5.3 OBJ: Use the ideal gas law. (Example 5.6) TOP: phases | gas KEY: ideal gas law | calculations with the ideal gas law MSC: general chemistry ANS: A PTS: 1 DIF: moderate REF: 5.3 OBJ: Calculate gas density. (Example 5.7) TOP: phases | gas KEY: ideal gas law | gas density MSC: general chemistry ANS: E PTS: 1 DIF: moderate REF: 5.3 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. OBJ: Determine the molecular mass of a vapor. (Example 5.8) TOP: phases | gas KEY: ideal gas law | gas density MSC: general chemistry ANS: D PTS: 1 DIF: difficult REF: 5.4 OBJ: Solving stoichiometry problems involving gas volumes. (Example 5.9) TOP: phases | gas KEY: ideal gas law | stoichiometry and gas volumes MSC: general chemistry ANS: E PTS: 1 DIF: difficult REF: 5.5 OBJ: Calculate the partial pressure and mole fractions of a gas in a mixture. (Example 5.10) TOP: phases | gas KEY: gas mixtures MSC: general chemistry ANS: E PTS: 1 DIF: easy REF: 5.5 OBJ: Calculate the amount of gas collected over water. (Example 5.11) TOP: phases | gas KEY: gas mixtures | collecting gases over water MSC: general chemistry ANS: B PTS: 1 DIF: easy REF: 5.6 OBJ: List the five postulates of the kinetic theory. TOP: phases | gas KEY: kinetic-molecular theory MSC: general chemistry ANS: B PTS: 1 DIF: easy REF: 5.7 OBJ: Describe how the root-mean-square (rms) molecular speed of gas molecules varies with temperature. TOP: phases | gas ANS: A PTS: 1 DIF: moderate REF: 5.7 OBJ: Describe the molecular-speed distribution of gas molecules at different temperatures. TOP: phases | gas KEY: molecular speed MSC: general chemistry ANS: B PTS: 1 DIF: easy REF: 5.7 OBJ: Define effusion and diffusion. TOP: phases | gas KEY: molecular speed | effusion MSC: general chemistry ANS: D PTS: 1 DIF: moderate REF: 5.7 OBJ: Calculate the ratio of effusion rates of gases. (Example 5.13) TOP: phases | gas KEY: molecular speed | effusion MSC: general chemistry ANS: C PTS: 1 DIF: moderate REF: 5.8 OBJ: Use the van der Waals equation. (Example 5.14) TOP: phases | gas KEY: real gases MSC: general chemistry ANS: D PTS: 1 DIF: easy REF: 6.1 OBJ: Define energy, kinetic energy, potential energy, and internal energy. TOP: thermochemistry | heats of reaction ANS: E PTS: 1 DIF: easy REF: 6.2 OBJ: State the law of conservation of energy. TOP: thermochemistry | heats of reaction KEY: energy | law of conservation of energy MSC: general chemistry ANS: A PTS: 1 DIF: easy REF: 6.3 OBJ: Explain how the terms enthalpy of reaction and heat of reaction are related. TOP: thermochemistry | heats of reaction KEY: enthalpy | enthalpy change MSC: general chemistry ANS: E PTS: 1 DIF: easy REF: 6.5 OBJ: Calculate the heat absorbed or evolved from a reaction given its enthalpy of reaction and the mass of a reactant or product. (Example 6.4) 39. 40. 41. 42. 43. 44. 45. 46. 47. 48. TOP: thermochemistry | heats of reaction KEY: thermochemical equation | stoichiometry and heats of reaction MSC: general chemistry ANS: A PTS: 1 DIF: easy REF: 6.5 OBJ: Calculate the heat absorbed or evolved from a reaction given its enthalpy of reaction and the mass of a reactant or product. (Example 6.4) TOP: thermochemistry | heats of reaction ANS: D PTS: 1 DIF: difficult REF: 6.5 OBJ: Calculate the heat absorbed or evolved from a reaction given its enthalpy of reaction and the mass of a reactant or product. (Example 6.4) TOP: thermochemistry | heats of reaction KEY: thermochemical equation | stoichiometry and heats of reaction MSC: general chemistry ANS: A PTS: 1 DIF: difficult REF: 6.5 OBJ: Calculate the heat absorbed or evolved from a reaction given its enthalpy of reaction and the mass of a reactant or product. (Example 6.4) TOP: thermochemistry | heats of reaction KEY: thermochemical equation | stoichiometry and heats of reaction MSC: general chemistry ANS: E PTS: 1 DIF: easy REF: 6.6 OBJ: Define heat capacity and specific heat. TOP: thermochemistry | heats of reaction KEY: calorimetry | heat capacity MSC: general chemistry ANS: B PTS: 1 DIF: easy REF: 6.6 OBJ: Define heat capacity and specific heat. TOP: thermochemistry | heats of reaction KEY: calorimetry | heat capacity MSC: general chemistry ANS: C PTS: 1 DIF: difficult REF: 6.6 OBJ: Calculate using this relation between heat and specific heat. (Example 6. 5) TOP: thermochemistry | heats of reaction KEY: calorimetry | specific heat MSC: general chemistry ANS: A PTS: 1 DIF: difficult REF: 6.6 OBJ: Calculate using this relation between heat and specific heat. (Example 6. 5) TOP: thermochemistry | heats of reaction KEY: calorimetry | specific heat MSC: general chemistry ANS: C PTS: 1 DIF: easy REF: 6.6 OBJ: Define calorimeter. TOP: thermochemistry | heats of reaction KEY: calorimetry | measuring heats of reaction MSC: general chemistry ANS: C PTS: 1 DIF: easy REF: 6.8 OBJ: Define standard state and reference form. TOP: thermochemistry | heats of reaction KEY: standard enthalpies of formation MSC: general chemistry ANS: A PTS: 1 DIF: moderate REF: 6.8 OBJ: Calculate the heat (enthalpy) of reaction from the standard enthalpies of formation of the substances in the reaction. (Example 6.9) TOP: thermochemistry | heats of reaction KEY: standard enthalpies of formation MSC: general chemistry 49. ANS: B PTS: 1 DIF: moderate REF: 6.8 OBJ: Calculate the heat (enthalpy) of reaction from the standard enthalpies of formation of the substances in the reaction. (Example 6.9) TOP: thermochemistry | heats of reaction KEY: standard enthalpies of formation MSC: general chemistry 50. ANS: E PTS: 1 DIF: easy REF: 6.8 OBJ: Calculate the heat (enthalpy) of reaction from the standard enthalpies of formation of the substances in the reaction. (Example 6.9) TOP: thermochemistry | heats of reaction KEY: standard enthalpies of formation MSC: general chemistry