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Transcript
1.4. The Source-Free Parallel RLC Circuits
οƒ˜ Applying KCL at the top node gives;
οƒ˜ takig derivative with respect to t and dividing by C results in;
1.4. The Source-Free Parallel RLC Circuits
𝑑2
𝑑𝑑 2
𝑠2
𝑑
𝑑𝑑
s
1.4. The Source-Free Parallel RLC Circuits
Overdamped Case (∝> 𝝎𝟎 )
𝑠1 π‘Žπ‘›π‘‘ 𝑠2 negative and real
Critically Damped Case (∝= 𝝎𝟎 )
𝑠1 π‘Žπ‘›π‘‘ 𝑠2 real and equal
1.4. The Source-Free Parallel RLC Circuits
Under Damped Case (∝< 𝝎𝟎 )
𝑠1 π‘Žπ‘›π‘‘ 𝑠2 are complex
𝐴1 π‘Žπ‘›π‘‘ 𝐴2 can be determined from initial conditions;
Example 1.5.
In the parallel circuit of fig. , find 𝑣(𝑑) for t>0,
assuming
𝑣 0 = 5 𝑉, 𝑖 0 = 0, 𝐿 = 1𝐻 π‘Žπ‘›π‘‘ 𝐢 = 10 π‘šπΉ.
Consider these cases;
R=1.923 Ω, R=5 Ω, R=6.25 Ω.
Δ°f R=1.923 Ω
Example 1.5.
Since (∝> 𝝎𝟎 ) in this case, overdamped.
The roots of the characteristic equation are;
Apply initial conditions to get π‘¨πŸ and π‘¨πŸ
At t =0
Example 1.5.
Must be differeantiated
At t =0
With π‘¨πŸ and π‘¨πŸ the solution gets…
Example 1.5.
When R=5 Ω
πœ”0 remains 10;
Since Ξ±= πœ”0 , the responce is
Critically damped…
Apply initial conditions to get π‘¨πŸ and π‘¨πŸ
Example 1.5.
Must be differeantiated
With π‘¨πŸ and π‘¨πŸ the solution gets…
Example 1.5.
Δ°n the last case R=6.25 Ω…
Solution is…
Response for three
degrees of damping
1.5. Step Response of Series RLC Circuits
This equation has two compenants;
Natural response;
𝒗𝒏 (𝒕)
Forced response;
𝒗𝒇 (𝒕)
1.5. Step Response of Series RLC Circuits
οƒ˜ Δ°f we set 𝑉𝑠 = 0, 𝑣(𝑑) contains only natural response (𝑣𝑛 )
οƒ˜ 𝑣𝑛 (t) can be expressed as three conditions;
οƒ˜ The forced response is the steady-state or final value of 𝑣(𝑑)
οƒ˜ The final value of the capacitor voltage is the same as the source
voltage 𝑉𝑠 .
1.5. Step Response of Series RLC Circuits
οƒ˜ Thus the complate solution…
Example 1.6.
For the circuit in Fig., find
𝑣 𝑑 π‘Žπ‘›π‘‘ 𝑖(𝑑) for t>0. Consider these
cases:
R=5Ω, R=4Ω,R=1Ω.
Example 1.6.
Example 1.6.
οƒ˜ 𝑣𝑓 is the forced response or steady-state
response.
οƒ˜ It is final value of the capacitor voltage.
οƒ˜ 𝑣𝑓 =24 V.
For t>0 , current i,
Example 1.6.
οƒ˜ Finally,
οƒ˜ but we have to solve i(t)…
1.6. Step Response of Parallel RLC
Circuits
Example 1.7.
Solution:
οƒ˜ For t<0, the switch is open
οƒ˜ The circuit partitioned into two independent subcircuits.
Capacitor voltage equal the
voltage of 20Ω resistor.
Example 1.7.
οƒ˜ For t>0, the switch is closed
οƒ˜ We have parallel RLC circuit.
οƒ˜ The voltage source is off or short-circuited.
Example 1.7.
The final value of I…
Using initial conditions we get π‘¨πŸ and π‘¨πŸ
Example 1.7.
From i(t) we obtain v(t)…