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Differential inductance of superconducting magnets: the role of coupling currents Vittorio Marinozzi CERN, 14/06/2016 Vittorio Marinozzi, CERN 14/06/2016 Outline: 1. Experimental motivation 2. Differential inductance 3. IFCC electromagnetic model 4. Implementation in QLASA 5. Experimental comparison 6. Effects on quench protection 7. Conclusions 2 Vittorio Marinozzi, CERN 14/06/2016 1.1 β Experimental motivation ο Larp tests in 2013 ο Fast extraction on dump resistor π π π π π‘ ο πΌ = πΌ0 π β πΏ Using measured inductance, it is impossible to fit the decay, even at the very beginning! 3 Vittorio Marinozzi, CERN 14/06/2016 1.2 β Experimental motivation The HQ inductance from exponential fit of the decay beginning is about 30% lower than the one measured at low ramp rate 4 5 Vittorio Marinozzi, CERN 14/06/2016 1.3 β Experimental motivation ο Same phenomenon seen in LQ tests ο Impossible to justify with quench back, AC losses, current redistributionβ¦. β’ Too fast Can the inductance actually change at high ramp rate? If yes, why? I want to justify this behavior with coupling currents effect on differential inductance 6 Vittorio Marinozzi, CERN 14/06/2016 2.1 β Differential inductance What is the inductance? π(π΅) πΏπ = πΌ ππΌ π. π. π. = βπΏπ ππ‘ πΏ = π0 π2 πππ 2 The inductance of a device depends only on the geometry! What happens when the magnetic flux is not linear? Inductance depends on the current! ππΌ π. π. π. β βπΏπ ππ‘ 7 Vittorio Marinozzi, CERN 14/06/2016 2.2 β Differential inductance Faraday-Neumann-Lenz: ππ π΅ ππΌ π πΏπ πΌ ππΌ π=β =β ππΌ ππ‘ ππΌ ππ‘ ππ π΅ π=β ππ‘ π = β πΏπ + ππΏπ ππΌ πΌ ππΌ ππ‘ ο It is useful to define a βdifferential inductanceβ ππΏπ ππ(π΅) πΏπ = πΏπ + πΌ= ππΌ ππΌ Such that ππΌ π = βπΏπ ππ‘ βStandardβ inductance and differential inductance are quantities conceptually different! Standard inductance is related to the field flux Differential inductance is related to the flux change (voltage) 8 Vittorio Marinozzi, CERN 14/06/2016 2.3 β Differential inductance Example: iron saturation ββ¦remember that the inductance is lower at high current because of the iron saturationβ¦β ββ¦remember that the inductance is larger at low current because of the iron saturationβ¦β Because of the iron, the standard inductance is larger at high current. Instead, the differential inductance is larger at low current, while iron does not affect it at all at high current! 9 Vittorio Marinozzi, CERN 14/06/2016 2.4 β Differential inductance Example: magnetized materials π΅ = π0 π + π» = π0 π» 1 + π ππ’ = π»ππ΅ π = ππ» ππ’ = π0 π»ππ»+π0 ππ»ππ» +π0 ππ»2 1 ππ πΏπ = πΌ ππΌ ππ(π΅) πΏπ = ππΌ ππΌ π = βπΏπ ππ‘ ππ = βππΌ ππ‘ πΏπ = π0 π» ππ» π0 ππ» ππ» π0 π»2 ππ + + ππ πΌ ππΌ πΌ ππΌ πΌ ππΌ Known the susceptivity of the material, one can compute the inductance from the integration of the field 10 Vittorio Marinozzi, CERN 14/06/2016 3.1 βIFCC electromagnetic model Extracted from M. N. Wilson βSupercoducting magnetsβ π0 π π= 2ππ 2π ππ΅π π΅π = π΅π β π ππ‘ ππ is the effective transverse resistance between filaments From direct integration of the current, one can compute the magnetization associated to IFCC 2ππ ππ΅π π= π0 ππ‘ π is the packing factor π is the decay time constant of the IFCC 2 π is the filament twist pitch lenght From the known relations π΅ = π0 π + π» and π = ππ», one can compute the susceptivity associated to IFCC 1 π=β 1+ 1 1 2π 1 β π΅π π΅π 11 Vittorio Marinozzi, CERN 14/06/2016 3.2 βIFCC electromagnetic model A qualitative explanation We have seen that IFCC can be seen as a magnetization of the coils It is the same phenomenon that we see with the iron! Iron makes the differential inductance higher at low current. Then it saturates and it does not affect the inductance at all IFCC are basically screening currents. They try to keep the flux constant. This is why they make the differential inductance lower! 12 Vittorio Marinozzi, CERN 14/06/2016 3.3 βIFCC electromagnetic model Exponential approximation ππ΅π π΅π = π΅π β π ππ‘ π΅π = π΅0 π βπ‘ ππ π΅π 0 = π΅π (0) = π΅0 π is the IFCC decay time ππ is the transport current decay time ππ = πΏ/π π‘ π‘ π΅0 β βπ π΅π = ππ β ππ π ππ π β ππ With a simple assumption, one can find a solution for the field produced by inter-filament currents With a simple assumption, one can find an analytical formula for the susceptivity related to the inter-filament currents 2ππ π(π‘) = ππ π‘ βπ β ππ π‘ βπ π π π‘ βπ π π β π‘ βπ π β 2ππ π π‘ βπ π β π‘ βπ π V. Marinozzi et al., "Effect of coupling currents on the dynamic inductance during fast transient in superconducting magnets", Physical Review Special Topics β Accelerators and beams, 2015. 13 Vittorio Marinozzi, CERN 14/06/2016 3.4 βIFCC electromagnetic model Main issue of the βexponentialβ model: We do not want to calculate the new inductance, we want to use it! π΅π = π΅0 π βπ‘ ππ ππ = πΏ/π depends on the inductance, therefore it cannot be used as input. The current decay depends on the magnet inductance BUT The magnet inductance depends on the decay! ο First conclusion: differential inductance of superconducting magnets is not a defined value, but it depends on the current decay, and vice-versa. Vittorio Marinozzi, CERN 14/06/2016 4.1 βImplementation in QLASA ο QLASA is a software for the simulation of quench propagation in superconducting magnets. ο Very useful for a simple implementation of the IFCC model β’ It is semi-analytical β’ Magnet inductance is an input (not from a BEM-FEM or similar) β’ Inductance can be changed using a simple analytical formula I will use the exponential approximation, in an iterative and step-by-step way 14 15 Vittorio Marinozzi, CERN 14/06/2016 4.2 βImplementation in QLASA Important assumption: we assume that the coupling currents do not affect the magnetic field πΏπ = π0 π» ππ» π0 ππ» ππ» π0 π»2 ππ + + ππ = πΏβ² + ΞπΏ πΌ ππΌ πΌ ππΌ πΌ ππΌ We can talk of inductance variation π0 π π ΞπΏ = 2πΌ ππΌ π»2 ππ π0 ππ + πΌ ππΌ π»2 ππ Computation of the field integral can be done numerically 16 Vittorio Marinozzi, CERN 14/06/2016 4.3 βImplementation in QLASA Circuit solution ππΌ π π + π π πΌ + πΏ = 0 ππ‘ At each time step, the quantities are constant The exponential approximation can be used! Inductance variation is computed through the susceptivity at each time step, and used in the following step as input 17 Vittorio Marinozzi, CERN 14/06/2016 4.4 βImplementation in QLASA Analytical solution for a costheta quadrupole π0 π π ΞπΏ = 2πΌ ππΌ π0 ππ π» ππ + πΌ ππΌ 2 π2 π»2 ππ π1 The field integral is limited to the magnetized material volume, i.e. to the coils For a quadrupole, the field in the coils is analytical and can be integrated π»2 ππ ππ½02 π 3 4 π14 π2 π2 π14 2 = π β 16 ln + ln + 4+2 2 64 2 64 π1 π1 π2 With the exponential approximation, and for cos ππ magnets, the inductance reduction can be computed analytically, and can be implemented very easily in any software 18 Vittorio Marinozzi, CERN 14/06/2016 4.5 βImplementation in QLASA Example: discharge on a dump resistor We assume that a quadrupole is short-circuited on a dump resistor, and that quench resistance is null From excel sheet! We expect an exponential decay πΌ = πΌ0 π βπ‘ ππ We can use: β’ Exponential approximation β’ Analytical magnetic field β’ We do not have the complication of quench resistance 19 Vittorio Marinozzi, CERN 14/06/2016 5.1 βExperimental comparison ο Comparison with HQ test on exponential decay (60 mΞ© dump resistor) ο IFCC π = 15 ms (average value) ο The model can describe the decay at the beginning ο In order to describe the whole decay, one should add coupling currents power dissipation and subsequent quench back Very good agreement! Vittorio Marinozzi, CERN 14/06/2016 5.2 βExperimental comparison We can describe a current decay. Is that a proof? ο A current decay is a basically combination of dump resistor, magnet inductance and quench resistance ο We know very well the dump resistor ο We have understood that we do not know well the inductance, even if we have measured it at low ramp rate β’ Therefore, we do not know the quench resistance! ο We have a model that predicts the inductance, but when quench resistance begins to become important, the model cannot be validated β’ We know only that the decay time is good if we describe well the decay, i.e. that the ratio L/R is good, but we do not have any hint on them separately We need to measure inductance and resistance during a quench, both of them separately 20 21 Vittorio Marinozzi, CERN 14/06/2016 5.3 βExperimental comparison Inductance measurement during a quench ο You need at least two coils of the magnet with no resistance β’ You can extract the inductive voltage β’ You can subtract the inductive voltage to the other coils, in order to obtain the resistive voltage πΏππππ = πππΆ ππππ πΌ Why two coils? You should have one, but you have to be sure that it has only inductive voltage. The easiest way to be sure is to compare to another one. If voltages are identical, you are sure that coils are superconductive. π ππππ ππ ππππ β πΏππππ πΌ = πΌ It can be proved that the magnet inductance is πΏ = πππππ πΏππππ This method works only for identical coils! 22 Vittorio Marinozzi, CERN 14/06/2016 5.4 βExperimental comparison ο Another HQ test ο No dump resistor ο Quench induced by heaters in two coils ο Again, dynamic effects needed to describe well the decay ο Coil 15 and 16 are clearly resistive ο Coil 17 and 20 have identical voltages until about 100 ms β’ You can compute inductance and resistance! Vittorio Marinozzi, CERN 14/06/2016 5.5 βExperimental comparison ο Good agreement between simulated and experimental resistance until 100 ms. β’ After 100 ms, resistance cannot be measured! Important conclusion: you can measure magnet resistance only if you have one (better two) superconducting coils! 23 Vittorio Marinozzi, CERN 14/06/2016 5.6 βExperimental comparison ο The inductance measured during the quench is very different from the inductance measured at low ramp rate (factor 2!) ο The model of the IFCC allows to describe well the experimental inductance! Important conclusion: you have to compute the differential inductance of a magnet case by case. Every quench has conceptually a different inductance! 24 25 Vittorio Marinozzi, CERN 14/06/2016 5.7 βExperimental comparison Recent test of QXFS1 at Fermilab The dynamic effects on differential inductance are needed! 26 Vittorio Marinozzi, CERN 14/06/2016 5.8 βLEDET ο Ledet is the program developed by Emmanuele Ravaioli for the CLIQ simulation CLIQ exploit coupling currents in order to induce quench Coupling currents cannot be added as external source power in the code! Courtesy of Emmanuele Ravaioli Similar results with independent, completely different approach! Coupling currents are described with lumped elements (small L-R circuits), which takes energy from the main circuit in order to be generated E. Ravaioli et al., "Lumped-Element Dynamic Electro-Thermal model of a superconducting Magnet", Cryogenics. 27 Vittorio Marinozzi, CERN 14/06/2016 6.1 β Quench protection Does this study really affects quench protection analysis? Nominal (IL+OL PH) MQXF hot spot temperature [K] Including inductance reduction Neglecting inductance reduction ~260 K ~285 K ο Neglecting the inductance reduction gives ~25 K more in the MQXF quench simulation. ο MQXF has high inductance, no dump resistor β’ In smaller magnets, with dump resistor, it can be more β’ For example, in the first slide quench we have ~40 K ο This model could strongly affect protection study of magnets Vittorio Marinozzi, CERN 14/06/2016 28 7.1 βConclusions ο Experimental evidences show that the magnet inductance measured at low ramp rate cannot be used to describe the current decay. ο An electromagnetic model shows that the IFCC affects the magnet differential inductance. ο The model can be implemented in a simple analytical way in a quench software. ο The model can describe very well current decays, and it has been experimentally validated on LARP tests. ο The magnet inductance has been experimentally measured during a quench, showing that: β’ Inductance is not the one measured at low ramp rate β’ Inductance is lower than expected β’ IFCC model can describe the inductance behavior β’ Resistance measurement is possible only using reduced inductance (measured, or even simulated). Using nominal inductance you get wrong. ο This method really affects protection studies, and gives more realistic and accurate simulations. Future steps: ο Implement the method with FEM (not average π, magnetic fieldβ¦) ο Add inter-strand coupling currents ο New inductance measurements with more accurate signal analysis