Download Lesson 18: Looking More Carefully at Parallel Lines

Survey
yes no Was this document useful for you?
   Thank you for your participation!

* Your assessment is very important for improving the workof artificial intelligence, which forms the content of this project

Document related concepts

Lie sphere geometry wikipedia , lookup

History of geometry wikipedia , lookup

Duality (projective geometry) wikipedia , lookup

Contour line wikipedia , lookup

Riemannian connection on a surface wikipedia , lookup

Rational trigonometry wikipedia , lookup

Euler angles wikipedia , lookup

Perspective (graphical) wikipedia , lookup

Euclidean geometry wikipedia , lookup

Line (geometry) wikipedia , lookup

Transcript
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 18
M1
GEOMETRY
Lesson 18: Looking More Carefully at Parallel Lines
Student Outcomes
๏‚ง
Students learn to construct a line parallel to a given line through a point not on that line using a rotation by
180°. They learn how to prove the alternate interior angles theorem using the parallel postulate and the
construction.
Lesson Notes
Lesson 18 is important. It may take two days to cover all of the information in this lesson. Hiding underneath its ideas
are most of the reasons why reflection and translation can be defined based upon the geometry assumptions students
learn in Lesson 33. (For example, only the geometry assumptions are used to construct a parallel line through a given
point in Example 4.) While these ideas are hiding under the surface, do not focus on them. Instead, concentrate
studentsโ€™ attention on the main geometry assumption of this lesson: the parallel postulate.
Parallel lines have already been defined, and in the missing angles problems (and perhaps discussed casually), the
following two ideas have been used.
1.
Suppose a transversal intersects a pair of lines. If a pair of alternate interior angles is equal in measure, then
the pair of lines are parallel.
2.
(A form of the parallel postulate) Suppose a transversal intersects a pair of lines. If the pair of lines are parallel,
then the pair of alternate interior angles are equal in measure.
However, students have probably not made careful distinctions between these thoughts. More likely, students
remember the following concept:
Suppose a transversal intersects a pair of lines. The pair of lines are parallel if and only if a pair of alternate
interior angles are equal in measure.
Perhaps students simply associate the ideas in this statement. When students see parallel lines cut by a transversal, they
recognize the angle relations and then use those angle relations to recognize parallel lines.
This lesson is designed to help students carefully distinguish between these two ideas. In particular, students are shown
why there is a need for the parallel postulate as one of our geometric assumptions: Through a given external point there
is at most one line parallel to a given line.
Classwork
Opening Exercise (8 minutes)
Opening Exercise
Exchange Problem Sets from Lesson 17 with a classmate. Solve the problems posed by your classmate while he or she
solves yours. Compare your solutions, and then discuss and resolve any discrepancies. Why were you asked only to
locate the point of rotation rather than to rotate a pre-image to obtain the image? How did you use perpendicular
bisectors in constructing your solutions?
Answers will vary.
Lesson 18:
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
149
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 18
M1
GEOMETRY
Discussion
Discussion
We say that two lines are parallel if they lie in the same plane and do not intersect. Two segments or rays are parallel if
the lines containing them are parallel.
Examples 1โ€“7 (30 minutes)
Example 1
Why is the phrase in the plane critical to the definition of parallel lines? Explain and illustrate your reasoning.
Two lines in (3-dimensional space) are called skew lines if they do not lie in the same plane.
In that case, they do not intersect (because if they did, they would share a plane together)
and are not parallel. (If they were parallel, then they would both have to lie in the same
plane.)
In Lesson 7, we recalled some basic facts learned in earlier grades about pairs of lines and angles created by a transversal
to those lines. One of those basic facts is the following:
Suppose a transversal intersects a pair of lines. The lines are parallel if and only if a pair of alternate interior
angles are equal in measure.
Our goal in this lesson is to prove this theorem using basic rigid motions, geometry assumptions, and a geometry
assumption we introduce in this lesson called the parallel postulate. Of all of the geometry assumptions we have given so
far, the parallel postulate gets a special name because of the special role it played in the history of mathematics. (Euclid
included a version of the parallel postulate in his books, and for ๐Ÿ, ๐ŸŽ๐ŸŽ๐ŸŽ years people tried to show that it was not a
necessary assumption. Not only did it turn out that the assumption was necessary for Euclidean geometry, but study of
the parallel postulate led to the creation of non-Euclidean geometries.)
The basic fact above really has two parts, which we prove separately:
1.
Suppose a transversal intersects a pair of lines. If two alternate interior angles are equal in measure, then the pair
of lines are parallel.
2.
Suppose a transversal intersects a pair of lines. If the lines are parallel, then the pair of alternate interior angles are
equal in measure.
The second part turns out to be an equivalent form of the parallel postulate. To build up to the theorem, first we need to
do a construction.
Example 2
Given a line ๐’ and a point ๐‘ท not on the line, follow the steps below to rotate ๐’ by ๐Ÿ๐Ÿ–๐ŸŽ° to a line ๐’โ€ฒ that passes through ๐‘ท:
MP.7
a.
Label any point ๐‘จ on ๐’.
b.
Find the midpoint of segment ๐‘จ๐‘ท using a ruler. (Measure the length of segment ๐‘จ๐‘ท, and locate the point
that is distance
Lesson 18:
๐‘จ๐‘ท
๐Ÿ
from ๐‘จ between ๐‘จ and ๐‘ท.) Label the midpoint ๐‘ช.
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
150
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 18
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
c.
Perform a ๐Ÿ๐Ÿ–๐ŸŽ° rotation around center ๐‘ช. To quickly find
the image of ๐’ under this rotation by hand:
i.
Pick another point ๐‘ฉ on ๐’.
ii.
โƒก .
Draw ๐‘ช๐‘ฉ
iii.
Draw circle: center ๐‘ช, radius ๐‘ช๐‘ฉ.
iv.
โƒก
Label the other point where the circle intersects ๐‘ช๐‘ฉ
by ๐‘ธ.
v.
โƒก .
Draw ๐‘ท๐‘ธ
MP.7
d.
Label the image of the rotation by ๐Ÿ๐Ÿ–๐ŸŽ° of ๐’ by ๐’โ€ฒ = ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐’).
How does your construction relate to the geometry assumption stated above to rotations? Complete the statement
below to clarify your observations:
๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ is a ๐Ÿ๐Ÿ–๐ŸŽ° rotation around ๐‘ช. Rotations preserve lines ; therefore ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ , maps the line ๐’ to the
line ๐’โ€ฒ . What is ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐‘จ)? ๐‘ท
Example 3
The lines ๐’ and ๐’โ€ฒ in the construction certainly look parallel, but we do not have to rely on looks.
Claim: In the construction, ๐’ is parallel to ๐’โ€ฒ .
MP.7
PROOF: We show that assuming they are not parallel leads to a contradiction. If they are not parallel, then they must
intersect somewhere. Call that point ๐‘ฟ. Since ๐‘ฟ is on ๐’โ€ฒ , it must be the image of some point ๐‘บ on ๐’ under the ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ
rotation (i.e., ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐‘บ) = ๐‘ฟ). Since ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ is a ๐Ÿ๐Ÿ–๐ŸŽ° rotation, ๐‘บ and ๐‘ฟ must be the endpoints of a diameter of a circle that
โƒก must contain ๐‘ช. Since ๐‘บ is a point on ๐’, and ๐‘ฟ is a different point on ๐’ (it was the
has center ๐‘ช. In particular, ๐‘บ๐‘ฟ
โƒก because there is only one line through two points. But ๐‘บ๐‘ฟ
โƒก also contains
intersection of both lines), we have that ๐’ = ๐‘บ๐‘ฟ
๐‘ช, which means that ๐’ contains ๐‘ช. However, ๐‘ช was constructed so that it was not on ๐’. This is absurd.
There are only two possibilities for any two distinct lines ๐’ and ๐’โ€ฒ in a plane: either the lines are parallel, or they are not
parallel. Since assuming the lines were not parallel led to a false conclusion, the only possibility left is that ๐’ and ๐’โ€ฒ
were parallel to begin with.
Example 4
The construction and claim together implies the following theorem.
THEOREM: Given a line ๐’ and a point ๐‘ท not on the line, then there exists line ๐’โ€ฒ that contains ๐‘ท and is parallel to ๐’.
This is a theorem we have justified before using compass and straightedge constructions, but now we see it follows
directly from basic rigid motions and our geometry assumptions.
Lesson 18:
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
151
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 18
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Example 5
We are now ready to prove the first part of the basic fact above. We have two lines, ๐’ and ๐’โ€ฒ , and all we know is that a
โƒก intersects ๐’ and ๐’โ€ฒ such that a pair of alternate interior angles are equal in measure. (In the picture below,
transversal ๐‘จ๐‘ท
we are assuming ๐’Žโˆ ๐‘ธ๐‘ท๐‘จ = ๐’Žโˆ ๐‘ฉ๐‘จ๐‘ท.)
ฬ…ฬ…ฬ…ฬ…. What happens if you rotate ๐Ÿ๐Ÿ–๐ŸŽ° around the center ๐‘ช? Is there enough information to
Let ๐‘ช be the midpoint of ๐‘จ๐‘ท
show that ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐’) = ๐’โ€ฒ ?
a.
What is the image of the segment ๐‘จ๐‘ท?
๐‘ท๐‘จ
MP.7
b.
In particular, what is the image of the point ๐‘จ?
๐‘ท
c.
โƒก ?
Why are the points ๐‘ธ and ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐‘ฉ) on the same side of ๐‘จ๐‘ท
โƒก to itself because ๐‘จ๐‘ท
โƒก contains the center ๐‘ช. In
Sketch of the Answer: The rotation by ๐Ÿ๐Ÿ–๐ŸŽ° maps ๐‘จ๐‘ท
โƒก to the other half-plane and vice versa.
particular, it can be shown that the rotation maps one half-plane of ๐‘จ๐‘ท
Since ๐‘ธ and ๐‘ฉ are in opposite half-planes (by definition of alternate interior angles), and ๐‘ฉ and ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐‘ฉ) are
in opposite half-planes, ๐‘ธ and ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐‘ฉ) must be in the same half-plane.
d.
What is the image of ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (โˆ ๐‘ฉ๐‘จ๐‘ท)? Is it โˆ ๐‘ธ๐‘ท๐‘จ? Explain why.
Because under the rotation, the vertex of โˆ ๐‘ฉ๐‘จ๐‘ท maps to the vertex of โˆ ๐‘ธ๐‘ท๐‘จ, ray ๐‘จ๐‘ท maps to ray ๐‘ท๐‘จ, the
point ๐‘ฉ goes to the same side as ๐‘ธ. Since ๐’Žโˆ ๐‘ฉ๐‘จ๐‘ท = ๐’Žโˆ ๐‘ธ๐‘ท๐‘จ (by assumption), ray ๐‘จ๐‘ฉ must map to ray ๐‘ท๐‘ธ.
Thus, โˆ ๐‘ฉ๐‘จ๐‘ท maps to โˆ ๐‘ธ๐‘ท๐‘จ.
e.
Why is ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐’) = ๐’โ€ฒ ?
โƒก = ๐’โ€ฒ.
โƒก ) = ๐‘ท๐‘ธ
Since ๐‘จ๐‘ฉ maps to ๐‘ท๐‘ธ, ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐’) = ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐‘จ๐‘ฉ
We have just proven that a rotation by ๐Ÿ๐Ÿ–๐ŸŽ° takes ๐’ to ๐’โ€ฒ . By the claim in Example 3, lines ๐’ and ๐’โ€ฒ must be parallel, which
is summarized below.
THEOREM: Suppose a transversal intersects a pair of lines. If a pair of alternate interior angles are equal in measure, then
the pair of lines are parallel.
Discussion
In Example 5, suppose we had used a different rotation to construct a line parallel to ๐’ that contains ๐‘ท. Such
constructions are certainly plentiful. For example, for every other point ๐‘ซ on ๐’, we can find the midpoint of segment
๐‘ท๐‘ซ and use the construction in Example 2 to construct a different ๐Ÿ๐Ÿ–๐ŸŽ° rotation around a different center such that the
image of the line ๐’ is a parallel line through the point ๐‘ท. Are any of these parallel lines through ๐‘ท different? In other
words,
Can we draw a line other than the line ๐’โ€ฒ through ๐‘ท that never meets ๐’?
Lesson 18:
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
152
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 18
M1
GEOMETRY
The answer may surprise you; it stumped mathematicians and physicists for centuries. In nature, the answer is that it is
sometimes possible and sometimes not. This is because there are places in the universe (near massive stars, for example)
where the model geometry of space is not plane-like or flat but is actually quite curved. To rule out these other types of
strange but beautiful geometries, we must assume that the answer to the previous question is only one line. That choice
becomes one of our geometry assumptions:
(Parallel Postulate) Through a given external point there is at most one line parallel to a given line.
In other words, we assume that for any point ๐‘ท in the plane not lying on a line ๐“ต, every line in the plane that contains ๐‘ท
intersects ๐“ต except at most one lineโ€”the one we call parallel to ๐“ต.
Example 6
We can use the parallel postulate to prove the second part of the basic fact.
THEOREM: Suppose a transversal intersects a pair of lines. If the pair of lines are parallel, then the pair of alternate
interior angles are equal in measure.
PROOF: Suppose that a transversal โƒก๐‘จ๐‘ท intersects line ๐’ at ๐‘จ and ๐’โ€ฒ at ๐‘ท, pick and label another point ๐‘ฉ on ๐’, and choose a
point ๐‘ธ on ๐’โ€ฒ on the opposite side of โƒก๐‘จ๐‘ท as ๐‘ฉ. The picture might look like the figure below:
Let ๐‘ช be the midpoint of ๐‘จ๐‘ท, and apply a rotation by ๐Ÿ๐Ÿ–๐ŸŽ° around the center ๐‘ช. As in previous discussions, the image of ๐’
is the line ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐’), which is parallel to ๐’ and contains point ๐‘ท. Since ๐’โ€ฒ and ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐’) are both parallel to ๐’ and contain ๐‘ท,
by the parallel postulate, they must be the same line: ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (๐’) = ๐’โ€ฒ. In particular, ๐‘น๐‘ช,๐Ÿ๐Ÿ–๐ŸŽ (โˆ ๐‘ฉ๐‘จ๐‘ท) = โˆ ๐‘ธ๐‘ท๐‘จ. Since
rotations preserve angle measures, ๐’Žโˆ ๐‘ฉ๐‘จ๐‘ท = ๐’Žโˆ ๐‘ธ๐‘ท๐‘จ, which was what we needed to show.
Discussion
It is important to point out that, although we only proved the alternate interior angles theorem, the same sort of proofs
can be done in the exact same way to prove the corresponding angles theorem and the interior angles theorem. Thus, all
of the proofs we have done so far (in class and in the Problem Sets) that use these facts are really based, in part, on our
assumptions about rigid motions.
Example 7
We end this lesson with a theorem that we just state but can be easily proved using the parallel postulate.
THEOREM: If three distinct lines ๐’๐Ÿ , ๐’๐Ÿ , and ๐’๐Ÿ‘ in the plane have the property that ๐’๐Ÿ โˆฅ ๐’๐Ÿ and ๐’๐Ÿ โˆฅ ๐’๐Ÿ‘ , then ๐’๐Ÿ โˆฅ ๐’๐Ÿ‘ . (In
proofs, this can be written as, โ€œIf two lines are parallel to the same line, then they are parallel to each other.โ€)
Note that students should at least remember that, in Euclidean Geometry, two lines are parallel if and only if alternate
interior angles of any transversal are equal in measure and should be able to elaborate on what that means. This one
statement includes both the parallel postulate and its converse. We can construct parallel lines without the parallel
postulate, but in a geometry that does not satisfy the parallel postulate; there are many parallels to a given line through
a point not on it. Without the parallel postulate, parallel lines are plentiful, and we cannot tell much about a line if all we
know is that it passes through a point and is parallel to another line.
Lesson 18:
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
153
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 18
M1
GEOMETRY
Relevant Vocabulary
PARALLEL: Two lines are parallel if they lie in the same plane and do not intersect. Two segments or rays are parallel if the
lines containing them are parallel lines.
TRANSVERSAL: Given a pair of lines ๐’ and ๐’Ž in a plane, a third line ๐’• is a transversal if it intersects ๐’ at a single point and
intersects ๐’Ž at a single but different point.
The definition of transversal rules out the possibility that any two of the lines ๐’, ๐’Ž, and ๐’• are the same line.
ALTERNATE INTERIOR ANGLES: Let line ๐’• be a transversal to lines ๐’ and ๐’Ž such that ๐’• intersects ๐’ at point ๐‘ท and intersects ๐’Ž
at point ๐‘ธ. Let ๐‘น be a point on ๐’ and ๐‘บ be a point on ๐’Ž such that the points ๐‘น and ๐‘บ lie in opposite half planes of ๐’•. Then
the โˆ ๐‘น๐‘ท๐‘ธ and the โˆ ๐‘ท๐‘ธ๐‘บ are called alternate interior angles of the transversal ๐’• with respect to ๐’Ž and ๐’.
CORRESPONDING ANGLES: Let line ๐’• be a transversal to lines ๐’ and ๐’Ž. If โˆ ๐’™ and โˆ ๐’š are alternate interior angles, and โˆ ๐’š and
โˆ ๐’› are vertical angles, then โˆ ๐’™ and โˆ ๐’› are corresponding angles.
Closing (1 minute)
๏‚ง
๏‚ง
Two lines are parallel if and only if alternate interior angles of any transversal are equal in measure. This can
be separated into two statements:
1.
Suppose a transversal intersects a pair of lines. If two alternate interior angles are equal in measure, then
the pair of lines are parallel.
2.
Suppose a transversal intersects a pair of lines. If the lines are parallel, then the pair of alternate interior
angles are equal in measure.
Statement 2 is an equivalent form of the parallel postulate: Through a given external point there is at most
one line parallel to a given line.
Exit Ticket (6 minutes)
Lesson 18:
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
154
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 18
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
Name ___________________________________________________
Date____________________
Lesson 18: Looking More Carefully at Parallel Lines
Exit Ticket
1.
Construct a line through the point ๐‘ƒ below that is parallel to the line ๐‘™ by rotating ๐‘™ by 180° (using the steps outlined
in Example 2).
2.
Why is the parallel line you constructed the only line that contains ๐‘ƒ and is parallel to ๐‘™?
Lesson 18:
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
155
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 18
M1
GEOMETRY
Exit Ticket Sample Solutions
1.
Construct a line through the point ๐‘ท below that is parallel to the line ๐’ by rotating ๐’ by ๐Ÿ๐Ÿ–๐ŸŽ° (using the steps
outlined in Example 2).
The construction should look like the steps in Example 2.
2.
Why is the parallel line you constructed the only line that contains ๐‘ท and is
parallel to ๐’?
The answer should reference the parallel postulate in a meaningful way.
Problem Set Sample Solutions
Notice that we are frequently asked two types of questions about parallel lines. If we are told that two lines are parallel,
then we may be required to use this information to prove the congruence of two angles (corresponding, alternate
interior, etc.). On the other hand, if we are given the fact that two angles are congruent (or perhaps supplementary), we
may have to prove that two lines are parallel.
1.
2.
ฬ…ฬ…ฬ…ฬ…, and ๐‘ฎ๐‘ฒ
ฬ…ฬ…ฬ…ฬ…ฬ… โŠฅ ๐‘ฉ๐‘ด
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฎ๐‘ฒ
ฬ…ฬ…ฬ…ฬ…ฬ….
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฉ๐‘ด
ฬ…ฬ…ฬ…ฬ…ฬ…, ๐‘จ๐‘ณ
ฬ…ฬ…ฬ…ฬ… โŠฅ ๐‘ช๐‘ญ
ฬ…ฬ…ฬ…ฬ…ฬ…. Prove that ๐‘ช๐‘ญ
In the figure, ๐‘จ๐‘ณ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฉ๐‘ด
ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ณ
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ณ โŠฅ ฬ…ฬ…ฬ…ฬ…
๐‘ช๐‘ญ
Given
ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘ฎ๐‘ฒ โŠฅ ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘ฉ๐‘ด
Given
๐’Žโˆ ๐‘จ๐‘ซ๐‘ช = ๐Ÿ—๐ŸŽ°
Definition of perpendicular lines
๐’Žโˆ ๐‘ฉ๐‘ฑ๐‘ฏ = ๐Ÿ—๐ŸŽ°
Definition of perpendicular lines
๐’Žโˆ ๐‘ฉ๐‘ฑ๐‘ฏ = ๐’Žโˆ ๐‘จ๐‘ฏ๐‘ฎ
If two parallel lines are cut by a transversal, then the corresponding angles are equal in
measure.
๐’Žโˆ ๐‘จ๐‘ซ๐‘ช = ๐’Žโˆ ๐‘จ๐‘ฏ๐‘ฎ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฎ๐‘ฒ
ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘ช๐‘ญ
Substitution property of equality
Given
If two lines are cut by a transversal such that the corresponding angles are equal in
measure, then the lines are parallel.
ฬ…ฬ…ฬ…ฬ….
ฬ…ฬ…ฬ…ฬ…๏ƒท๏ƒง๐‘ฉ๐‘ช
Given that โˆ ๐‘ฉ and โˆ ๐‘ช are supplementary and ๐’Žโˆ ๐‘จ = ๐’Žโˆ ๐‘ช, prove that ๐‘จ๐‘ซ
โˆ ๐‘ฉ and โˆ ๐‘ช are supplementary.
Given
๐’Žโˆ ๐‘จ = ๐’Žโˆ ๐‘ช
Given
๐’Žโˆ ๐‘ฉ + ๐’Žโˆ ๐‘ช = ๐Ÿ๐Ÿ–๐ŸŽ
Definition of supplementary angles
๐’Žโˆ ๐‘ฉ + ๐’Žโˆ ๐‘จ = ๐Ÿ๐Ÿ–๐ŸŽ
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ซ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ฉ๐‘ช
Substitution property of equality
Lesson 18:
If a transversal intersects two lines
such that the same side interior angles are supplementary, then the lines are
parallel.
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
156
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
Lesson 18
NYS COMMON CORE MATHEMATICS CURRICULUM
M1
GEOMETRY
3.
4.
5.
6.
Mathematicians state that if a transversal to two parallel lines is perpendicular to one of the lines, then it is
perpendicular to the other. Prove this statement. (Include a labeled drawing with your proof.)
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฉ๐‘ด
ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ณ
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ณ ๏ž ฬ…ฬ…ฬ…ฬ…
๐‘ช๐‘ญ
Given
๐’Žโˆ ๐‘จ๐‘ซ๐‘ช = ๐Ÿ—๐ŸŽ°
Definition of perpendicular lines
๐’Žโˆ ๐‘จ๐‘ซ๐‘ช = ๐’Žโˆ ๐‘ฉ๐‘ฌ๐‘ซ
If two parallel lines are cut by a transversal, then
corresponding angles are equal in measure.
๐’Žโˆ ๐‘ฉ๐‘ฌ๐‘ซ = ๐Ÿ—๐ŸŽ°
ฬ…ฬ…ฬ…ฬ… โŠฅ ๐‘ฉ๐‘ด
ฬ…ฬ…ฬ…ฬ…ฬ…
๐‘ช๐‘ญ
Substitution
Given
Definition of perpendicular lines
ฬ…ฬ…ฬ…ฬ… and ๐‘ฌ๐‘ญ
ฬ…ฬ…ฬ…ฬ…ฬ…. Prove that ๐’Žโˆ ๐‘จ๐‘ญ๐‘ฌ = ๐’Žโˆ ๐‘ซ๐‘ฒ๐‘ฏ.
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ช๐‘ซ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฎ๐‘ฏ
In the figure, ๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ช๐‘ซ
๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ…
๐‘ฌ๐‘ญ โˆฅ ๐‘ฎ๐‘ฏ
Given
๐’Žโˆ ๐‘จ๐‘ญ๐‘ฌ = ๐’Žโˆ ๐‘ฎ๐‘ฑ๐‘ญ
If two parallel lines are cut by a transversal, then
the corresponding angles are equal in measure.
๐’Žโˆ ๐‘ฑ๐‘ฒ๐‘ช = ๐’Žโˆ ๐‘ฎ๐‘ฑ๐‘ญ
If two parallel lines are cut by a transversal, then
the corresponding angles are equal in measure.
๐’Žโˆ ๐‘ฑ๐‘ฒ๐‘ช = ๐’Žโˆ ๐‘ซ๐‘ฒ๐‘ฏ
Vertical angles are equal in measure.
๐’Žโˆ ๐‘จ๐‘ญ๐‘ฌ = ๐’Žโˆ ๐‘ซ๐‘ฒ๐‘ฏ
Transitive property
Given
In the figure, โˆ ๐‘ฌ and โˆ ๐‘จ๐‘ญ๐‘ฌ are complementary, and โˆ ๐‘ช and โˆ ๐‘ฉ๐‘ซ๐‘ช are
ฬ…ฬ…ฬ…ฬ….
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ช๐‘ฉ
complementary. Prove that ๐‘จ๐‘ฌ
โˆ ๐‘ฌ and โˆ ๐‘จ๐‘ญ๐‘ฌ are complementary.
Given
โˆ ๐‘ช and โˆ ๐‘ฉ๐‘ซ๐‘ช are complementary.
Given
๐’Žโˆ ๐‘ฌ + ๐’Žโˆ ๐‘จ๐‘ญ๐‘ฌ = ๐Ÿ—๐ŸŽ°
Definition of complementary angles
๐’Žโˆ ๐‘ช + ๐’Žโˆ ๐‘ฉ๐‘ซ๐‘ช = ๐Ÿ—๐ŸŽ°
Definition of complementary angles
๐’Žโˆ ๐‘ฌ + ๐’Žโˆ ๐‘จ๐‘ญ๐‘ฌ + ๐’Žโˆ ๐‘จ = ๐Ÿ๐Ÿ–๐ŸŽ°
Sum of the angle measures in a triangle is ๐Ÿ๐Ÿ–๐ŸŽ°.
๐’Žโˆ ๐‘ช + ๐’Žโˆ ๐‘ฉ๐‘ซ๐‘ช + ๐’Žโˆ ๐‘ฉ = ๐Ÿ๐Ÿ–๐ŸŽ°
Sum of the angle measures in a triangle is ๐Ÿ๐Ÿ–๐ŸŽ°.
๐’Žโˆ ๐‘จ = ๐Ÿ—๐ŸŽ°; ๐’Žโˆ  = ๐Ÿ—๐ŸŽ°
Subtraction property of equality
๐’Žโˆ ๐‘จ = ๐’Žโˆ ๐‘ฉ
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ฌ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ช๐‘ฉ
Substitution property of equality
If two lines are cut by a transversal such that a pair of alternate interior
angles are equal in measure, then the lines are parallel.
Given a line ๐’ and a point ๐‘ท not on the line, the following directions can be used to draw a line ๐’Ž perpendicular to
the line ๐’ through the point ๐‘ท based upon a rotation by ๐Ÿ๐Ÿ–๐ŸŽ°:
a.
Pick and label a point ๐‘จ on the line ๐’ so that the circle (center ๐‘ท, radius ๐‘จ๐‘ท) intersects ๐’ twice.
b.
Use a protractor to draw a perpendicular line ๐’ through the point ๐‘จ (by constructing a ๐Ÿ—๐ŸŽ° angle).
c.
Use the directions in Example 2 to construct a parallel line ๐’Ž through the point ๐‘ท.
Do the construction. Why is the line ๐’Ž perpendicular to the line ๐’ in the figure you drew? Why is the line ๐’Ž the
only perpendicular line to ๐’ through ๐‘ท?
Figures will vary but should follow the directions outlined.
Students can use Problem 3 or reprove the fact that if a transversal to two parallel lines is perpendicular to one, then
it is perpendicular to the other.
Suppose line ๐’Žโ€ฒ contains ๐‘ท and is perpendicular to ๐’; then by the interior angles theorem (or alternate interior
angles or corresponding interior angles), ๐’Žโ€ฒ is parallel to ๐’. Since ๐’Ž and ๐’Žโ€ฒ are both parallel to ๐’ and contain ๐‘ท, by
the parallel postulate, they must be the same line (i.e., ๐’Žโ€ฒ = ๐’Ž).
A student might answer, โ€œparallel postulate.โ€ If so, partial credit might be awarded (depending on your tastes for
partial credit).
Lesson 18:
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
157
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.
NYS COMMON CORE MATHEMATICS CURRICULUM
Lesson 18
M1
GEOMETRY
Problems 7โ€“10 all refer to the figure to the right. The exercises are otherwise
unrelated to each other.
7.
ฬ…ฬ…ฬ…ฬ… and โˆ ๐‘ฌ๐‘ฑ๐‘ฉ is supplementary to โˆ ๐‘ฑ๐‘ฉ๐‘ฒ. Prove that ๐‘จ๐‘ซ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฉ๐‘ช
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฑ๐‘ฌ
ฬ…ฬ…ฬ….
๐‘จ๐‘ซ
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฉ๐‘ช
๐‘จ๐‘ซ
Given
โˆ ๐‘ฌ๐‘ฑ๐‘ฉ is supplementary to โˆ ๐‘ฑ๐‘ฉ๐‘ฒ.
ฬ…ฬ…ฬ…
๐‘ฌ๐‘ฑ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ฉ๐‘ช
Given
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ซ โˆฅ ฬ…ฬ…ฬ…
๐‘ฌ๐‘ฑ
If a transversal intersects two lines such that the same side interior angles
are supplementary, then the lines are parallel.
If two segments are parallel to the same segment, then they are parallel to
each other.
8.
9.
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ซ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ญ๐‘ฎ and ฬ…ฬ…ฬ…
๐‘ฌ๐‘ฑ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ญ๐‘ฎ. Prove that โˆ ๐‘ซ๐‘จ๐‘ฑ and โˆ ๐‘ฌ๐‘ฑ๐‘จ are supplementary.
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ซ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ญ๐‘ฎ
ฬ…ฬ…ฬ…ฬ…
ฬ…ฬ…ฬ… โˆฅ ๐‘ญ๐‘ฎ
๐‘ฌ๐‘ฑ
Given
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฌ๐‘ฑ
ฬ…ฬ…ฬ…
๐‘จ๐‘ซ
If two segments are parallel to the same segment, then they are parallel to
each other.
๐’Žโˆ ๐‘ซ๐‘จ๐‘ฑ + ๐’Žโˆ ๐‘ฌ๐‘ฑ๐‘จ = ๐Ÿ๐Ÿ–๐ŸŽ°
If a transversal intersects two parallel lines, then the interior angles on the
same side of the transversal are supplementary.
Given
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ….
๐’Žโˆ ๐‘ช = ๐’Žโˆ ๐‘ฎ and โˆ ๐‘ฉ is supplementary to โˆ ๐‘ฎ. Prove that ๐‘ซ๐‘ช
๐’Žโˆ ๐‘ช = ๐’Žโˆ ๐‘ฎ
Given
โˆ ๐‘ฉ is supplementary to โˆ ๐‘ฎ
Given
๐’Žโˆ ๐‘ฉ + ๐’Žโˆ ๐‘ฎ = ๐Ÿ๐Ÿ–๐ŸŽ°
Definition of supplementary angles
๐’Žโˆ ๐‘ฉ + ๐’Žโˆ ๐‘ช = ๐Ÿ๐Ÿ–๐ŸŽ°
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ…
๐‘ซ๐‘ช
Substitution property of equality
If a transversal intersects two lines such that the same side interior angles
are supplementary, then the lines are parallel.
ฬ…ฬ…ฬ…ฬ…, and โˆ ๐‘ฌ๐‘ฒ๐‘ช is supplementary to โˆ ๐‘ฒ๐‘ช๐‘ซ. Prove that ๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ….
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฌ๐‘ญ
ฬ…ฬ…ฬ…ฬ…, ๐‘ฌ๐‘ญ
ฬ…ฬ…ฬ…ฬ… โŠฅ ๐‘ช๐‘ฉ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ซ๐‘ช
10. ๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ… โˆฅ ๐‘ฌ๐‘ญ
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ฉ
ฬ…ฬ…ฬ…ฬ… ๏ž ฬ…ฬ…ฬ…ฬ…
๐‘ฌ๐‘ญ
๐‘ช๐‘ฉ
Given
โˆ ๐‘ฌ๐‘ฒ๐‘ช is supplementary to โˆ ๐‘ฒ๐‘ช๐‘ซ.
Given
๐’Žโˆ ๐‘จ๐‘ฉ๐‘ช + ๐’Žโˆ ๐‘ฉ๐‘ฒ๐‘ฌ = ๐Ÿ๐Ÿ–๐ŸŽ°
If parallel lines are cut by a transversal, then interior angles on the same
side are supplementary.
๐’Žโˆ ๐‘ฌ๐‘ฒ๐‘ช + ๐’Žโˆ ๐‘ฒ๐‘ช๐‘ซ = ๐Ÿ๐Ÿ–๐ŸŽ°
Definition of supplementary angles
๐’Žโˆ ๐‘ฉ๐‘ฒ๐‘ฌ = ๐Ÿ—๐ŸŽ° and ๐’Žโˆ ๐‘ฌ๐‘ฒ๐‘ช = ๐Ÿ—๐ŸŽ°
Definition of right angles
๐’Žโˆ ๐‘จ๐‘ฉ๐‘ช = ๐Ÿ—๐ŸŽ° and ๐’Žโˆ ๐‘ฒ๐‘ช๐‘ฌ = ๐Ÿ—๐ŸŽ°
Subtraction property of equality
โˆ ๐‘จ๐‘ฉ๐‘ช and โˆ ๐‘ฒ๐‘ช๐‘ฌ are supplementary.
ฬ…ฬ…ฬ…ฬ…
๐‘จ๐‘ฉ โˆฅ ฬ…ฬ…ฬ…ฬ…
๐‘ซ๐‘ช
Definition of supplementary angles
Given
Lesson 18:
If two lines are cut by a transversal such that a pair of interior angles on
the same side are supplementary, then the lines are parallel.
Looking More Carefully at Parallel Lines
This work is derived from Eureka Math โ„ข and licensed by Great Minds. ©2015 Great Minds. eureka-math.org
This file derived from GEO-M1-TE-1.3.0-07.2015
158
This work is licensed under a
Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported License.