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Application Report SLVA338 – August 2009 Extending the Input Voltage Range of the TPS6116x/7x/8x/9x WLED Drivers Jeff Falin......................................................................................................................................... ABSTRACT The TPS6116x, TPS6118x and TPS6119x WLED driver and TPS6117x boost converter integrated circuits (IC) can operate with different input voltages, one powering the IC itself and the other powering the boost power stage. This application report explains various options on how to use the WLED drivers with split power rails. This allows these LED drivers to be used in applications where the available power rail exceeds the IC's maximum input voltage. Figure 1 shows a block diagram of the various options available for powering the WLED drivers, in order by increasing cost. VPWR IQ Existing system rail < VINmax VIN C1a Option A IQ VPWR D1B DnB R1B VIN C1b Option B IQ VPWR VIN R1C + VZ - D1C IZ C1C Option C VIN Q1 VPWR R1D IQ/hFE D1D + VZ - WLED Driver or Boost Converter IC IQ VIN C2D IZ C1D Option D Linear Reg VIN_LDO VO_LDO VPWR C1E IQ VIN C2E Option E Figure 1. Options for Powering the WLED Drivers From Split Rails SLVA338 – August 2009 Submit Documentation Feedback Extending the Input Voltage Range of the TPS6116x/7x/8x/9x WLED Drivers 1 www.ti.com Option A is simple. If the system has an existing power rail (e.g., VCC = 3.3 V or 5 V) that can provide the bias power for the IC, then use VCC to provide the IC’s input power. The following table gives the VIN range and maximum quiescent current, IQmax, for each family of ICs. C1x must be at least 1 µF. IC FAMILY VINmin (V) VINmax (V) IQmax (mA) TPS6116x/7x 3 18 2.3 TPS61180/1/2 5 24 3.0 The remaining options assume that the only available power rail, VPWR, may exceed the IC’s maximum operating voltage. Therefore, assuming VPWRmin > VINmin, either a PN diode, Zener diode (D1), or linear regulator steps down VPWR to a voltage low enough to power the IC’s input voltage, VIN. Option B uses multiple series diodes to drop VPWR lower than VINmax. The diodes selected must have forward voltage drops, VFWD, at the current level, IFWD, such that VPWRmax - n ´ VFWDmin@I £ VINmax FWD (1) Because the minimum operating current into the LED driver, IQmin, is not specified and because the current into VIN during shutdown, ISD, is small, set IFWD using R1B = VINmax/IFWD so that the diodes drop a minimum forward voltage, VFWDmin. Option C uses a Zener diode to clamp the voltage at VIN lower than VINmax. The designer must select a Zener diode such that VZmax < VINmax and VZmin > VINmin (2) Where VZ is the Zener breakdown voltage. It is recommended to select a diode with VZmax no more than 10% below VINmax to minimize the power lost through the Zener diode and resistor R1C. Resistor R1C is sized so that it is small enough to provide both the IC’s maximum quiescent current, IQmax, and Zener diode current, IZ, to keep the Zener diode in breakdown, as expressed in Equation 3. V - VZmax V - 0.9 ´ VINmax R1C < PWRmax = PWRmax IZ + IQmax IZ + IQmax (3) C1B must be at least a 1-µF, ceramic capacitor. The voltage clamped by the Zener diode varies inversely as IQ varies and directly as VPWR varies, i.e., the clamped voltage begins to drop as IQ increases because IZ decreases or as VPWR drops. Also, if VPWRmax is significantly larger than VINmax, the power dissipated through R1C, computed as PD_R1c = (VPWRmax – VZ)2/R1C may require R1C to be a costly, large footprint resistor. Option D may be a better solution. Option D shows a discrete linear regulator created by a Zener diode and NPN bipolar transistor. This circuit reduces the current through the resistor from IZ + IQmax to IZ + IQmax/ hFE, where hFE is the bipolar transistor’s current gain. Also, the bipolar transistor’s current gain reduces the variation of the voltage at the IC's VIN pin as IQ changes. Option D requires a Zener diode with slightly larger breakdown voltage: VZmax < VINmax and VZmin > VINmin + VBEmax (4) where VBEmax is the NPN transistor’s maximum base-emitter voltage at IQmax, typically near 0.7 V. Following the same recommendation in Option C, Equation 2 shows how to compute R1D with VZmax 0.9*VINmax. - VZmax VPWRmax - 0.9 ´ VINmax V R1D < PWRmax = IQmax I IZ + IZ + Qmax hFE hFE (5) C1D must be at least 0.01 µF and C2D must be at least 1 µF. Option E is to select a linear regulator IC with: • Wide enough input voltage range to accommodate VPWR 2 Extending the Input Voltage Range of the TPS6116x/7x/8x/9x WLED Drivers SLVA338 – August 2009 Submit Documentation Feedback www.ti.com • • Adjustable output voltage VINmin< VO_LDO < VINmax and PD_LDO > IQmax × (VPWRmax – VO_LDO) where PD_LDO is the LDO package’s maximum power dissipation rating at the application’s maximum ambient temperature. C1E must be sized according to the regulator’s data sheet. C2D must be the larger of the linear regulator’s minimum required output capacitor or 1 µF. TPS71501 is a good choice. Option B Example Specification: TPS61165 powered by a power supply with 20 V maximum Solution: Although its voltage rating is significantly above the minimum for this application, the low-cost 1N4148, 100-mA diode is a good choice. Per the data sheet, the 1N4148 needs at least 1 mA to drop 0.5 V over TA = –40°C to 75°C. Therefore, R1B = 18 V/1 mA = 18 kΩ. Solving Equation 1 for n gives n ≥ (VPWR-VINmax / VFWDmin@IFWD = (20 V–18 V)/0.5 V = 4. As a safeguard, five 1N4148s are recommended with R1B = 18 kΩ are recommended. Option D Example Specification: IC: TPS61181 powered from a supply with 26 V maximum Solution: Using Equation 4, the application requires VZmax < 24 V and VZmin ≥ 4.5 V + 0.7 V. Keeping in mind the 90% recommendation, choose a 0.9 × 24 V = 21.6→ 21 V Zener diode. The MMSZ4707T1 diode gives 19.0 V < VZ < 21.0 V. The BC848 30-V NPN transistor with hFEmin = 200 is a low-cost generic NPN transistor. Other NPN transistors are acceptable if their VCE voltage rating is higher than VPWRmax. Using Equation 5, R2 is sized for the current: - 0.9 ´ VINmax 26 V - 0.9 × 24 V V R1D < PWRmax = = 4.35 kW ® 4.32 k W IQmax 2.3 mA 1 mA + IZ + 200 hFE (6) Power dissipation in the diode is computed in the following equation: PDmax = (VPW Rm ax - VZm in ) × VZmin R1D = (26V - 18.05 V) ´ 18.05 V = 33 m W 4.32 kW (7) This power dissipation is well within the capabilities of the diode’s SOD-123 package. SLVA338 – August 2009 Submit Documentation Feedback Extending the Input Voltage Range of the TPS6116x/7x/8x/9x WLED Drivers 3 IMPORTANT NOTICE Texas Instruments Incorporated and its subsidiaries (TI) reserve the right to make corrections, modifications, enhancements, improvements, and other changes to its products and services at any time and to discontinue any product or service without notice. Customers should obtain the latest relevant information before placing orders and should verify that such information is current and complete. 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