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* exponential and logarithm functions and derivatives: 1.logarithms(log): y = a is normally a number greater than 1 (although it need only be greater than 0 and not equal to 1). The function is defined for all x > 0. Here is its graph for any base a. Note the following: • For any base, the x-intercept is 1. Why? The logarithm of 1 is 0. y = • The graph passes through the point (a, 1). Why? The logarithm of the base is 1. Loga a= 1. *the graph is below x-axis ,the logarithm is negative for 0<x<1. .the function is defined for positive values of x, . .the range of function is all real numbers. .the negative y-axis is a vertical asymptote. Important relation Properties: x= 2.natural logarithims(ln) Y=ln x ,ln1=0 ,ln 0= Domain={x:x>o}, range={all real numbers} Properties: ln 1=0; Ln =ln 1- ln x= -ln x ;ln(xy)=ln x+ln y 2.exponential functions: a-The exponential function with positive base a > 1 is the function It is defined for every real number x. Here is its graph: There are two important things to note: • The y-intercept is at (0, 1). For, a0 = 1. • The negative x-axis is a horizontal asymptote. For, when x is a large negative number -- e.g. b−10,000 -- then y is a very small positive number. Properties: , b- y= ; ; ; ; Ex: Let f(x) = ex. Write the function f(−x)and draw it . F(-x)= (the argument x is replaced by –x) The graph of y= is the reflection of y= ex Important relations: A- 2. From 1 &2 let f(x)= F(g(x))= and g(x)= and g(f(x))= a the functions : f(x)= B- f(x)=lnx and g(x)= & g(x)= therefore for any base are inverses F(g(x))=ln g(f(x))= =x ;lne=1 ; ; therefore f(x)= ln x and g(x)= are inverses Here are the graphs of y = ex and y = ln x : CD- ln a=b a= Ex: find 1. 1. b=-2 ; 2. ; ? 3. Ex: evaluate the following: 1. 2.ln =x+1 3.1og 106.2=6.2 4. Ex: solve the equations:1. {to release x+1 from exponent take the inverse function (the logarithm with base 5) of both sides as} X+1=4 2. x-4=x ; x=3 (take log of base 2 or 3 for both sides) ;x- x =4; x= 3. Take the inverse function 5x of both sides ;let each sides be the exponent with base 5 as: 2x+3=125 ;2x=125-3 ;x=61 4.ln(5x-1)=ln(2x+8) take exponent with base e for each sides; *Derivative of logatithm and exponent functions: 2. 1. Or y= ( 3. *lnu)= 4. Ex :derivative the following : 1.y=ln *3 2.y= 3.y= 4. ; +lnx*3