Set Prob 7 - Non-Mutually Exclusive
... e.g. 1) Reid’s mother buys a new washer and dryer set and is trying to decide whether to buy the 3-year extended warranty for $450. Reid does some research on the repair statistics for this particular brand of washer and dryer and summarizes the findings in the table below: Probability of needing Av ...
... e.g. 1) Reid’s mother buys a new washer and dryer set and is trying to decide whether to buy the 3-year extended warranty for $450. Reid does some research on the repair statistics for this particular brand of washer and dryer and summarizes the findings in the table below: Probability of needing Av ...
Probability - Cornell Computer Science
... Formally, we define a probabilistic Turing machine to be an ordinary deterministic TM with an extra semi-infinite read-only tape containing a binary string called the random bits. The machine runs as an ordinary deterministic TM, consulting its random bits in a read-only fashion. We write M (x, y) for ...
... Formally, we define a probabilistic Turing machine to be an ordinary deterministic TM with an extra semi-infinite read-only tape containing a binary string called the random bits. The machine runs as an ordinary deterministic TM, consulting its random bits in a read-only fashion. We write M (x, y) for ...
p - Tanya Khovanova
... The probability that an ordered pair of kids is mixed is (8x7 +7*8)/15x14 = 8/15; thus each of the 14 adjacent pairs of seats has 8/15 mixed pairs in it on average. Since expectations add regardless of dependence, the expected number of mixed adjacent pairs is 14x8/15 = 212/15. 100 passengers on a t ...
... The probability that an ordered pair of kids is mixed is (8x7 +7*8)/15x14 = 8/15; thus each of the 14 adjacent pairs of seats has 8/15 mixed pairs in it on average. Since expectations add regardless of dependence, the expected number of mixed adjacent pairs is 14x8/15 = 212/15. 100 passengers on a t ...
NEW PPT 5.1
... 3 5 2 1 5 2 3 5 4 9 boxes 4 3 5 3 5 1 1 1 5 3 1 5 4 5 2 15 boxes 5 5 5 2 4 1 2 1 5 3 10 boxes We never had to buy more than 22 boxes to get the full set of cards in 50 repetitions of our simulation. Our estimate of the probability that it takes 23 or more boxes to get a full set is roughly 0. ...
... 3 5 2 1 5 2 3 5 4 9 boxes 4 3 5 3 5 1 1 1 5 3 1 5 4 5 2 15 boxes 5 5 5 2 4 1 2 1 5 3 10 boxes We never had to buy more than 22 boxes to get the full set of cards in 50 repetitions of our simulation. Our estimate of the probability that it takes 23 or more boxes to get a full set is roughly 0. ...
Binomial Distributions on the ClassPad
... A basketball player misses 30% of her free throw shots in a typical game. During one particular game, she attempts 17 free throw shots and misses 7 of the 17. All of her free throw shots are independent and the probability that she makes a single free throw is 0.70. What is the probability that she ...
... A basketball player misses 30% of her free throw shots in a typical game. During one particular game, she attempts 17 free throw shots and misses 7 of the 17. All of her free throw shots are independent and the probability that she makes a single free throw is 0.70. What is the probability that she ...
probability - ellenmduffy
... • Count the total number of possible events • Count the total number of successful events • P(success) = # successful events # total possible events ...
... • Count the total number of possible events • Count the total number of successful events • P(success) = # successful events # total possible events ...
Independent continuous random variables Several - STAT-LLC
... the joint CDF (joint cumulative distribution function) factors into a product of two functions, one of which only has x’s, and the other of which only has y’s. Again, with some possible rescaling, the result is that the joint CDF factors into the CDF of X times the CDF of Y . I.e., X and Y are indep ...
... the joint CDF (joint cumulative distribution function) factors into a product of two functions, one of which only has x’s, and the other of which only has y’s. Again, with some possible rescaling, the result is that the joint CDF factors into the CDF of X times the CDF of Y . I.e., X and Y are indep ...
Unit 10
... When making judgments about probability, what must be true about the probability if one were to support an alternative hypothesis? ...
... When making judgments about probability, what must be true about the probability if one were to support an alternative hypothesis? ...
tps5e_Ch5_1 Winegar
... The myth of short-run regularity: The idea of probability is that randomness is predictable in the long run. Our intuition tries to tell us random phenomena should also be predictable in the short run. However, probability does not allow us to make short-run predictions. The myth of the “law of aver ...
... The myth of short-run regularity: The idea of probability is that randomness is predictable in the long run. Our intuition tries to tell us random phenomena should also be predictable in the short run. However, probability does not allow us to make short-run predictions. The myth of the “law of aver ...
On the Interpretation of Quantum Mechanics
... there is only the wavefunction |ψ> – there is no answer to the question where is the particle as we think of it in classical terms. The natural question following this introduction is “what is the wavefunction |ψ>?” Or, “what is waving?” In this interpretation, the only allowed answer is that the ( ...
... there is only the wavefunction |ψ> – there is no answer to the question where is the particle as we think of it in classical terms. The natural question following this introduction is “what is the wavefunction |ψ>?” Or, “what is waving?” In this interpretation, the only allowed answer is that the ( ...