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Solutions - ChemConnections
Solutions - ChemConnections

... hydrogen in HCl is +1. To be reduced, the oxidation state of H must decrease. The obvious choice for the hydrogen product is H2(g), where hydrogen has a zero oxidation state. The balanced reaction is Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g). Mg goes from the 0 to the +2 oxidation state by losing two ele ...
2.6 M - Thierry Karsenti
2.6 M - Thierry Karsenti

... Chloroform was used as a medical anesthetic in the past, but has been found to be carcinogenic. Carbon tetrachloride also has a long history of use in fire extinguishers, as a fabric cleaner, and as a solvent, but it causes liver damage and now is used much less. An important class of alkyl halides ...
chem textbook 2015 - Manitowoc Public School District
chem textbook 2015 - Manitowoc Public School District

... This generally means that your notes are incomplete, meaning that you wrote down much of what was on the board but did not record any of the verbal discussion or rationale used to explain what was taking place. It is important that your notes include your thoughts rather than just what I right on th ...
CHAPTER 16
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Atoms and bonds in molecules and chemical
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... of the event from a set of true propositions involving at least a scientific law or principle. The unification approach intends to derive the occurrence of the event using a theory that unifies many phenomena or the theory that unifies the phenomena better than any other. In the causal model the exp ...
Practice Test: Equilibrium
Practice Test: Equilibrium

... 6. If the system is at equilibrium and 5.0 moles of chlorine are added, what will be the new Keq? ______ 7. If the system is at equilibrium and the container is doubled in size, what will be the new Keq? ______ 8. What will happen to Keq if the temperature is lowered? ____________ 9. In summary, wha ...
CHEM 1411 Exam #2 - HCC Learning Web
CHEM 1411 Exam #2 - HCC Learning Web

... ∆H = +1560 kJ Divide equation 2 by 2 2. C2H2(g) + (5/2)O2(g)  2CO2(g) + H2O(l) ∆H = -2599/2 kJ Multiply equation 3 by 2 3. 2H2(g) + O2(g) 2 H2O(l) ∆H = -286 x 2 = -572kJ Add all three steps, simplify and add the heats 2CO2(g) + 3H2O(l) + C2H2(g) + (5/2)O2(g)+ O2(g) + 2H2(g)  C2H6(g) + (7/2) O2(g) ...
Unit 2 Powerpoint Notes
Unit 2 Powerpoint Notes

... Write an equation for the reaction that occurs when solid copper metal reacts with aqueous silver nitrate to produce solid silver metal and aqueous copper(II) nitrate. Solution: • First, use correct formulas and symbols to write a chemical equation. • Then, balance your equation. ...
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... valence electrons are involved in bond formation with neighboring Si atom. A vacancy is left which can be filled by the transfer of a valence electron from a neighboring Si atom. The movement of electron into the vacancy leaves behind a hole which carries positive charge. Another electron from a nei ...
Task 4 6 points - Austrian Chemistry Olympiad
Task 4 6 points - Austrian Chemistry Olympiad

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Chemistry - RESONANCE PCCP IDEAL for NTSE, IJSO, Olympiads
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1.8 M - Thierry Karsenti
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Chemical Equilibrium - The Gurukul Institute
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... When NaNO3 is heated in a closed vessel, oxygen is liberated and NaNO2 is left behind. At equilibrium: (A) addition of NaNO2 favors reverse reaction (B) addition of NaNO3 favors forward reaction (C) increasing temperature favours forward reaction (D) decreasing pressure favours reverse reaction 11. ...
Module 1 Predictor Questions
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... All of the formulas and symbols introduced up to now can also be used to represent moles of a species. Thus, if asked how many atoms, ions, or molecules there are in one mole of each of these species, simply multiply the answers given above by Avogadro’s number, 6.022 x 1023. Remember that 1 mole = ...
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... This equation has three O atoms on the left side of the arrow and two O atoms on the right side. We can increase the number of O atoms by placing a coefficient 2 on the product side: O2 + NO → 2 NO2 (unbalanced) Now there are two N atoms and four O atoms on the right. Placing the coefficient 2 in fr ...
mass mass calc
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Mechanistic Studies on the Galvanic Replacement Reaction
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... of various noble metals could be synthesized via galvanic replacement reaction in an aqueous solution by reacting sacrificial Ag template with a precursor compound of the desired metal such as Au, Pd, or Pt. For example, Ag templates with a variety of shapes, including nanocubes, nanoplates, nanosph ...
Chapter 3 Molecules Molecules, Compounds, and Chemical
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chapter 20 - United International College
chapter 20 - United International College

... requirement is satisfied by a salt bridge, which, in its simplest form, is an inverted U tube containing an inert electrolyte solution, such as KCl or NH4NO3, whose ions will not react with other ions in solution or with the electrodes (see Figure 19.1 of the text). If we physically separate the oxi ...
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... 2 was first observed experimentally in the early sixties. This means that although coulombic repulsion is important at short distances, covalent bonding must be very strong and, indeed, takes over stabilizing the system. A triple bond is formed by the coupling of the three unpaired p electrons on ea ...
LABORATORY MANUAL CHEMISTRY 121
LABORATORY MANUAL CHEMISTRY 121

... reaction can be followed visually because the products are red while the reactant is green. The purpose of this exercise is to determine the rate law for the hydrolysis of trans-[Co(en)2Cl2]+ and to determine the activation energy for the hydrolysis reaction by carrying out the reaction at several d ...
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Redox



Redox reactions include all chemical reactions in which atoms have their oxidation state changed; in general, redox reactions involve the transfer of electrons between species. The term ""redox"" comes from two concepts involved with electron transfer: reduction and oxidation. It can be explained in simple terms: Oxidation is the loss of electrons or an increase in oxidation state by a molecule, atom, or ion. Reduction is the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.Although oxidation reactions are commonly associated with the formation of oxides from oxygen molecules, these are only specific examples of a more general concept of reactions involving electron transfer.Redox reactions, or oxidation-reduction reactions, have a number of similarities to acid–base reactions. Like acid–base reactions, redox reactions are a matched set, that is, there cannot be an oxidation reaction without a reduction reaction happening simultaneously. The oxidation alone and the reduction alone are each called a half-reaction, because two half-reactions always occur together to form a whole reaction. When writing half-reactions, the gained or lost electrons are typically included explicitly in order that the half-reaction be balanced with respect to electric charge.Though sufficient for many purposes, these descriptions are not precisely correct. Oxidation and reduction properly refer to a change in oxidation state — the actual transfer of electrons may never occur. The oxidation state of an atom is the fictitious charge that an atom would have if all bonds between atoms of different elements were 100% ionic. Thus, oxidation is better defined as an increase in oxidation state, and reduction as a decrease in oxidation state. In practice, the transfer of electrons will always cause a change in oxidation state, but there are many reactions that are classed as ""redox"" even though no electron transfer occurs (such as those involving covalent bonds).There are simple redox processes, such as the oxidation of carbon to yield carbon dioxide (CO2) or the reduction of carbon by hydrogen to yield methane (CH4), and more complex processes such as the oxidation of glucose (C6H12O6) in the human body through a series of complex electron transfer processes.
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