I - Holland Public Schools
... *When you look at the equations above on paper, there is no way to tell which one is faster It can only be determined by experiment * reaction rate is affected by two factors: - collision effectiveness – an effective collision is one in which product is formed - collision frequency- a measure of how ...
... *When you look at the equations above on paper, there is no way to tell which one is faster It can only be determined by experiment * reaction rate is affected by two factors: - collision effectiveness – an effective collision is one in which product is formed - collision frequency- a measure of how ...
Solubility Equilibria
... A salt is an ionic compound usually a metal cation bonded to a non-metal anion. The dissolving of a salt is an example of equilibrium. The cations and anions are attracted to each other in the salt. They are also attracted to the water molecules. The water molecules will start to pull out some of th ...
... A salt is an ionic compound usually a metal cation bonded to a non-metal anion. The dissolving of a salt is an example of equilibrium. The cations and anions are attracted to each other in the salt. They are also attracted to the water molecules. The water molecules will start to pull out some of th ...
Chapter 6-States of Matter: Gases, Liquids, and Solids
... Unlike the gaseous state liquid state has cannot be compressed. Like the solid state, the liquid state tends to have very little ability to be compressed. The fact break fluid in a vehicle works with no air leaks into break line is based on non compressibility of liquids. ...
... Unlike the gaseous state liquid state has cannot be compressed. Like the solid state, the liquid state tends to have very little ability to be compressed. The fact break fluid in a vehicle works with no air leaks into break line is based on non compressibility of liquids. ...
Final Study Guide (Semester 2) Answer Key
... CuSO4(aq) + 2KOH(aq) Cu(OH)2(s ) + K2SO4(aq) Which compounds above are strong electrolytes? CuSO4 , KOH , K2SO4 a. Which chemical above is not soluble in water? Cu(OH)2 c. Which chemical above is the precipitate? Cu(OH)2 2. Solutions of Barium nitrate and potassium sulfate are mixed. ***The first ...
... CuSO4(aq) + 2KOH(aq) Cu(OH)2(s ) + K2SO4(aq) Which compounds above are strong electrolytes? CuSO4 , KOH , K2SO4 a. Which chemical above is not soluble in water? Cu(OH)2 c. Which chemical above is the precipitate? Cu(OH)2 2. Solutions of Barium nitrate and potassium sulfate are mixed. ***The first ...
CHEMISTRY - careerpoint.ac.in
... these laws has been found to be not true. But till date, for simple chemical reaction, these laws are used. The five laws are : (a) The law of conservation of mass (Levoisier 1774). (b) The law of constant proportion or definte proportions (proust 1799) (c) The law of multiple proportions (Dalton 18 ...
... these laws has been found to be not true. But till date, for simple chemical reaction, these laws are used. The five laws are : (a) The law of conservation of mass (Levoisier 1774). (b) The law of constant proportion or definte proportions (proust 1799) (c) The law of multiple proportions (Dalton 18 ...
Energy and Chemistry
... You may have noticed that the ΔH for a chemical reaction may be positive or negative. The number is assumed to be positive if it has no sign; a + sign can be added explicitly to avoid confusion. A chemical reaction that has a positive ΔH is said to be endothermic, while a chemical reaction that has ...
... You may have noticed that the ΔH for a chemical reaction may be positive or negative. The number is assumed to be positive if it has no sign; a + sign can be added explicitly to avoid confusion. A chemical reaction that has a positive ΔH is said to be endothermic, while a chemical reaction that has ...
Prep UK-intro.p65
... constant, depending on the particular circumstances, have to be specified. If the constant appears in thermodynamic equations, the equilibrium constant (Ka) is dimensionless and its value depends on the choice of standard state. We hope that your students will learn a considerable amount of chemistr ...
... constant, depending on the particular circumstances, have to be specified. If the constant appears in thermodynamic equations, the equilibrium constant (Ka) is dimensionless and its value depends on the choice of standard state. We hope that your students will learn a considerable amount of chemistr ...
Chemistry A level transition - baseline assessment
... Chemistry topic 9 – Organic chemistry – functional groups At GCSE you would have come across hydrocarbons such as alkanes (ethane etc) and alkenes (ethene etc). You may have come across molecules such as alcohols and carboxylic acids. At A level you will learn about a wide range of molecules that ha ...
... Chemistry topic 9 – Organic chemistry – functional groups At GCSE you would have come across hydrocarbons such as alkanes (ethane etc) and alkenes (ethene etc). You may have come across molecules such as alcohols and carboxylic acids. At A level you will learn about a wide range of molecules that ha ...
First Law of Thermodynamics
... the reactants and products, not on the manner in which they react! This is an important property because it allows us to determine ΔE for a reaction using any path - even one that is unreasonable - as long as the reactants and products remain the same. Both q and w are path dependent, so they are no ...
... the reactants and products, not on the manner in which they react! This is an important property because it allows us to determine ΔE for a reaction using any path - even one that is unreasonable - as long as the reactants and products remain the same. Both q and w are path dependent, so they are no ...
formula writing and nomenclature of inorganic compounds
... share electrons in forming a chemical bond. The number of electrons that an atom loses, gains, or shares when it bonds with another atom is known as the oxidation number of the atom. Elements which lose electrons in a chemical reaction, or which have electrons which are shared with another element d ...
... share electrons in forming a chemical bond. The number of electrons that an atom loses, gains, or shares when it bonds with another atom is known as the oxidation number of the atom. Elements which lose electrons in a chemical reaction, or which have electrons which are shared with another element d ...
Mole Concept
... 4 handlebars (with 3 handlebars left over), and only 2 bicycles from 8 wheels and 2 handlebars (with 4 wheels left over), in chemical reactions some species are limiting while others may be present in excess. In the case of a bicycle, we need ...
... 4 handlebars (with 3 handlebars left over), and only 2 bicycles from 8 wheels and 2 handlebars (with 4 wheels left over), in chemical reactions some species are limiting while others may be present in excess. In the case of a bicycle, we need ...
379 - FTP
... Formula: H2S; MW 34.08 Synonyms: sulfur hydride; sulfureted hydrogen Occurrence and Uses Hydrogen sulfide occurs in natural gas. It also is found in many sewer gases. It is a by-product of many industrial processes. Trace amounts of dissolved H2S are found in wastewaters in equilibrium with dissolve ...
... Formula: H2S; MW 34.08 Synonyms: sulfur hydride; sulfureted hydrogen Occurrence and Uses Hydrogen sulfide occurs in natural gas. It also is found in many sewer gases. It is a by-product of many industrial processes. Trace amounts of dissolved H2S are found in wastewaters in equilibrium with dissolve ...
CHAPTER 12 Study Guide
... 36. a. Two formula units KClO3 decompose to form two formula units KCl and three molecules O2. b. Four molecules NH3 react with six molecules NO to form five molecules N2 and six molecules H2O. c. Four atoms K react with one molecule O2 to form two formula units K2O. 37. a. Two mol KClO3 decompose t ...
... 36. a. Two formula units KClO3 decompose to form two formula units KCl and three molecules O2. b. Four molecules NH3 react with six molecules NO to form five molecules N2 and six molecules H2O. c. Four atoms K react with one molecule O2 to form two formula units K2O. 37. a. Two mol KClO3 decompose t ...
Chem 12 Prov Exam PLO Review
... • reactions are the result of collisions between reactant particles • not all collisions are successful • sufficient kinetic energy (KE) and favourable geometry are required • to increase the rate of a reaction one must increase the frequency of successful collisions • energy changes are involved in ...
... • reactions are the result of collisions between reactant particles • not all collisions are successful • sufficient kinetic energy (KE) and favourable geometry are required • to increase the rate of a reaction one must increase the frequency of successful collisions • energy changes are involved in ...
Gases - chemmybear.com
... (a) When a gas-filled balloon is cooled, it shrinks in volume; this occurs no matter what gas is originally placed in the balloon. (b) When the balloon described in (a) is cooled further, the volume does not become zero; rather, the gas becomes a liquid or solid. (c) When NH3 gas is introduced at on ...
... (a) When a gas-filled balloon is cooled, it shrinks in volume; this occurs no matter what gas is originally placed in the balloon. (b) When the balloon described in (a) is cooled further, the volume does not become zero; rather, the gas becomes a liquid or solid. (c) When NH3 gas is introduced at on ...
Chemistry Unit 1
... Hydrogen peroxide decomposes to release oxygen. This reaction is slow but can be speeded up by the addition of manganese (IV) oxide, MnO2, as a catalyst. Æ ...
... Hydrogen peroxide decomposes to release oxygen. This reaction is slow but can be speeded up by the addition of manganese (IV) oxide, MnO2, as a catalyst. Æ ...
Introduction - Bulgarian Chemical Communications
... The gem-dimethyl effect, GDME, or dialkyl effect, defined by the acceleration of cyclization reactions or the retardation of ring-opening by substituents in the chain, can not be satisfactory predicted by means of Hammett linear free energy relationships, LFER, e.g. using Taft’s ES-values. The reaso ...
... The gem-dimethyl effect, GDME, or dialkyl effect, defined by the acceleration of cyclization reactions or the retardation of ring-opening by substituents in the chain, can not be satisfactory predicted by means of Hammett linear free energy relationships, LFER, e.g. using Taft’s ES-values. The reaso ...
Gases Honors
... between the particles is great enough for the substance to flow. • Gases have low density, because of the relatively large distances between gas particles and long distance before particles collide with each other. • Gases are highly compressible, because gas particles can be pushed closer together. ...
... between the particles is great enough for the substance to flow. • Gases have low density, because of the relatively large distances between gas particles and long distance before particles collide with each other. • Gases are highly compressible, because gas particles can be pushed closer together. ...
E:\My Documents\sch4u\SCH4U review McKay answers.wpd
... 3) The combustion of ethane is illustrated by the following equation: 2C2H6(g) + 7O2(g) –> 4CO2(g) + 6H2O(g) a) Show how the following equations can be combined using Hess’ Law to determine the enthalpy of combustion of Ethane. (Ans: -3028 kJ) (HS says -2973.8 kJ) )H1 = -1409 kJ 1) C2H4(g) + 3O2(g) ...
... 3) The combustion of ethane is illustrated by the following equation: 2C2H6(g) + 7O2(g) –> 4CO2(g) + 6H2O(g) a) Show how the following equations can be combined using Hess’ Law to determine the enthalpy of combustion of Ethane. (Ans: -3028 kJ) (HS says -2973.8 kJ) )H1 = -1409 kJ 1) C2H4(g) + 3O2(g) ...
Chemical reaction
... How many moles of O2 are required to react completely with 5.6 moles C4H10? This question can be answered very easily based on the mole:mole ratios that are inherent in a balanced chemical equation. For example for the above equation 2 moles of C4H10 will react with every 13 moles of O2. This can al ...
... How many moles of O2 are required to react completely with 5.6 moles C4H10? This question can be answered very easily based on the mole:mole ratios that are inherent in a balanced chemical equation. For example for the above equation 2 moles of C4H10 will react with every 13 moles of O2. This can al ...
Solutions for Practice Problems
... The small mass of oxygen seems reasonable, given the mole ratio in the balanced chemical equation and the small volume of water vapour that was produced. The answer correctly shows two significant digits. 39. Practice Problem (page 560) One method of producing ammonia gas involves the reaction of am ...
... The small mass of oxygen seems reasonable, given the mole ratio in the balanced chemical equation and the small volume of water vapour that was produced. The answer correctly shows two significant digits. 39. Practice Problem (page 560) One method of producing ammonia gas involves the reaction of am ...
Electrolysis of water
Electrolysis of water is the decomposition of water (H2O) into oxygen (O2) and hydrogen gas (H2) due to an electric current being passed through the water.This technique can be used to make hydrogen fuel (hydrogen gas) and breathable oxygen; though currently most industrial methods make hydrogen fuel from natural gas instead.