Chemistry Definitions
... Dative bond: A bond in which both electrons come from a single donator atom. Complex ion: A species containing ligands, usually large. Synthesis: The coming together of two molecules. Decompose: A reaction in which a single compound is broken down into two or more products. Pi bond: In a pi bond, th ...
... Dative bond: A bond in which both electrons come from a single donator atom. Complex ion: A species containing ligands, usually large. Synthesis: The coming together of two molecules. Decompose: A reaction in which a single compound is broken down into two or more products. Pi bond: In a pi bond, th ...
Unit 6 Naming Binary Compounds
... 1. Name the elements in the order listed in the formula. 2. Use prefixes to indicate the number of each kind of atom. 3. Omit the prefix mono- when the formula contains only one atom of the first element in the name. 4. The suffix of the name of the second element is -ide. ...
... 1. Name the elements in the order listed in the formula. 2. Use prefixes to indicate the number of each kind of atom. 3. Omit the prefix mono- when the formula contains only one atom of the first element in the name. 4. The suffix of the name of the second element is -ide. ...
enthalpy changes
... ∆H depends on: -the reaction (products and reactants) -the coefficients of the balanced equation Example N2(g) + 3 H2(g) --> 2 NH3(g) ...
... ∆H depends on: -the reaction (products and reactants) -the coefficients of the balanced equation Example N2(g) + 3 H2(g) --> 2 NH3(g) ...
Take notes on this document while you are watching the recorded
... 1. The lipids are a large and diverse group of naturally occurring organic compounds that are related by their solubility (will dissolve) in nonpolar5 organic solvents (e.g. ether, chloroform, acetone & benzene) and general insolubility in water (do not dissolve in water - repel water; hydrophobic). ...
... 1. The lipids are a large and diverse group of naturally occurring organic compounds that are related by their solubility (will dissolve) in nonpolar5 organic solvents (e.g. ether, chloroform, acetone & benzene) and general insolubility in water (do not dissolve in water - repel water; hydrophobic). ...
Document
... 21. If 2.891 g MgCl2 is dissolved in enough water to make 500.0 mL of solution, what is the molarity of the magnesium chloride solution? ...
... 21. If 2.891 g MgCl2 is dissolved in enough water to make 500.0 mL of solution, what is the molarity of the magnesium chloride solution? ...
Theoretical problems - Scheikundeolympiade
... iv) The concentrations at pH 7.5 of HOCl and ClO– in a solution where the total concentration of hypochlorite (chlorate (I)) is 0.20 mmol dm–3, and the electrode potential for the reduction of this system to chlorine at this pH with unit activity of chlorine. These conditions are typical of a swimmi ...
... iv) The concentrations at pH 7.5 of HOCl and ClO– in a solution where the total concentration of hypochlorite (chlorate (I)) is 0.20 mmol dm–3, and the electrode potential for the reduction of this system to chlorine at this pH with unit activity of chlorine. These conditions are typical of a swimmi ...
IB Chemistry Online EQ_Ans
... in the presence of excess oxygen under standard conditions.[2] c Hess’s law states that the total enthalpy change for a reaction is independent of the route taken. It depends only on the initial and final states. ...
... in the presence of excess oxygen under standard conditions.[2] c Hess’s law states that the total enthalpy change for a reaction is independent of the route taken. It depends only on the initial and final states. ...
IB Chemistry HL Topic5 Questions 1. Which combination of ionic
... The lattice enthalpy of an ionic compound can be calculated using a Born-Haber cycle. Using lithium fluoride as the example, construct a Born-Haber cycle, labelling the cycle with the formulas and state symbols of the species present at each stage. ...
... The lattice enthalpy of an ionic compound can be calculated using a Born-Haber cycle. Using lithium fluoride as the example, construct a Born-Haber cycle, labelling the cycle with the formulas and state symbols of the species present at each stage. ...
Chem152
... E) V5O2 48. Fructose is a sugar found in fruit and honey. Calculate the empirical formula for fructose given its percent composition: 40.00% C, 6.72% H, and 53.29% O. A) CHO B) CH2O C) CHO2 D) C3H6O3 E) C6HO8 49. What is the molecular formula for lactic acid if the percent composition is 40.00% C, 6 ...
... E) V5O2 48. Fructose is a sugar found in fruit and honey. Calculate the empirical formula for fructose given its percent composition: 40.00% C, 6.72% H, and 53.29% O. A) CHO B) CH2O C) CHO2 D) C3H6O3 E) C6HO8 49. What is the molecular formula for lactic acid if the percent composition is 40.00% C, 6 ...
Describing Chemical Reactions
... The principle called conservation of mass was first demonstrated in the late 1700s. The principle of conservation of mass states that in a chemical reaction, the total mass of the reactants must equal the total mass of the products. In an open system, matter can enter from or escape to the surroundi ...
... The principle called conservation of mass was first demonstrated in the late 1700s. The principle of conservation of mass states that in a chemical reaction, the total mass of the reactants must equal the total mass of the products. In an open system, matter can enter from or escape to the surroundi ...
Honors Chemistry Unit 4 Student Packet: Honors Chemistry Problem
... 1. The coefficients in a balanced chemical equation can be used to form mole ratios relating reactants to products. 2. To convert molecules to grams you can either use molar mass or Avogadro’s number. 3. One mole of any gas occupies a volume of 22.4L. 4. Mass and the number of moles are conserved in ...
... 1. The coefficients in a balanced chemical equation can be used to form mole ratios relating reactants to products. 2. To convert molecules to grams you can either use molar mass or Avogadro’s number. 3. One mole of any gas occupies a volume of 22.4L. 4. Mass and the number of moles are conserved in ...
Chemistry Chapter 12
... 12.3 Limiting Reagent and Percent Yield (Reaction Efficiency) Review: -balanced chemical reactions can be used to make predictions -balanced chemical reactions may be written that do not occur -the equation does not give the exact conditions needed to make the reaction occur -the equation does not d ...
... 12.3 Limiting Reagent and Percent Yield (Reaction Efficiency) Review: -balanced chemical reactions can be used to make predictions -balanced chemical reactions may be written that do not occur -the equation does not give the exact conditions needed to make the reaction occur -the equation does not d ...
Chapter 9 Balancing Equations
... Balancing Equation Strategy • Balance elements that occur in only one compound on each side first. • Balance free elements last. • Balance unchanged polyatomic ions as groups. • Fractional coefficients are acceptable but must be cleared at the end using multiplication. ...
... Balancing Equation Strategy • Balance elements that occur in only one compound on each side first. • Balance free elements last. • Balance unchanged polyatomic ions as groups. • Fractional coefficients are acceptable but must be cleared at the end using multiplication. ...
cbse class – x science solutions
... Write the formula of the compound formed by the reaction of the element A with oxygen. (iv) Show the formation of the compound by a combination of element C with chlorine with the help of electronic structure. (v) What would be the ratio of number of combining atoms in a compound formed by the combi ...
... Write the formula of the compound formed by the reaction of the element A with oxygen. (iv) Show the formation of the compound by a combination of element C with chlorine with the help of electronic structure. (v) What would be the ratio of number of combining atoms in a compound formed by the combi ...
Density of solutions answers The concentration of solutions is often
... Density of solutions answers The concentration of solutions is often conveniently described in terms of the solutions’ percentage composition on a weight basis. For example, a 5% sodium chloride solution contains 5g of sodium chloride in every 100g of solution (which corresponds to 5g of sodium chlo ...
... Density of solutions answers The concentration of solutions is often conveniently described in terms of the solutions’ percentage composition on a weight basis. For example, a 5% sodium chloride solution contains 5g of sodium chloride in every 100g of solution (which corresponds to 5g of sodium chlo ...
AP Chemistry Summer Assignment 2016 revised
... Future AP Chemistry Student, Welcome to AP Chemistry! We, your teachers, look forward to meeting you in the fall. In order to ensure the best start for everyone at the start of that challenge, we have prepared a summer assignment that reviews basic chemistry concepts. If you have taken HS chemistry ...
... Future AP Chemistry Student, Welcome to AP Chemistry! We, your teachers, look forward to meeting you in the fall. In order to ensure the best start for everyone at the start of that challenge, we have prepared a summer assignment that reviews basic chemistry concepts. If you have taken HS chemistry ...
H = 890kJ - George Mason University
... Energy and Enthalpy From the first law: q = E + PV. With no change in volume the equation simplifies to qV = E. At constant pressure: qP = E + PV. There are times when both volume and pressure can change; the heat involved in the reaction is then a more complicated function of E. Enth ...
... Energy and Enthalpy From the first law: q = E + PV. With no change in volume the equation simplifies to qV = E. At constant pressure: qP = E + PV. There are times when both volume and pressure can change; the heat involved in the reaction is then a more complicated function of E. Enth ...
Slide 1
... reaction. In part (b) we must calculate the value for and compare this value with our qualitative prediction. Plan The free–energy change incorporates both the change in enthalpy and the change in entropy for the reaction (Equation 19.11), so under standard conditions ¢G° = ¢H° – T¢S° To determine w ...
... reaction. In part (b) we must calculate the value for and compare this value with our qualitative prediction. Plan The free–energy change incorporates both the change in enthalpy and the change in entropy for the reaction (Equation 19.11), so under standard conditions ¢G° = ¢H° – T¢S° To determine w ...
Chapter 8
... – The formulas of the reactants and products must be correct. – The reactants are written to the left of the arrow and the products to the right of the arrow. ...
... – The formulas of the reactants and products must be correct. – The reactants are written to the left of the arrow and the products to the right of the arrow. ...
+ H 2 O(l )
... Metals can replace other metals provided that they are above the metal that they are trying to replace. Metals above hydrogen can replace hydrogen in acids. Metals from sodium upward can replace hydrogen in water ...
... Metals can replace other metals provided that they are above the metal that they are trying to replace. Metals above hydrogen can replace hydrogen in acids. Metals from sodium upward can replace hydrogen in water ...
Bioorthogonal chemistry
The term bioorthogonal chemistry refers to any chemical reaction that can occur inside of living systems without interfering with native biochemical processes. The term was coined by Carolyn R. Bertozzi in 2003. Since its introduction, the concept of the bioorthogonal reaction has enabled the study of biomolecules such as glycans, proteins, and lipids in real time in living systems without cellular toxicity. A number of chemical ligation strategies have been developed that fulfill the requirements of bioorthogonality, including the 1,3-dipolar cycloaddition between azides and cyclooctynes (also termed copper-free click chemistry), between nitrones and cyclooctynes, oxime/hydrazone formation from aldehydes and ketones, the tetrazine ligation, the isocyanide-based click reaction, and most recently, the quadricyclane ligation.The use of bioorthogonal chemistry typically proceeds in two steps. First, a cellular substrate is modified with a bioorthogonal functional group (chemical reporter) and introduced to the cell; substrates include metabolites, enzyme inhibitors, etc. The chemical reporter must not alter the structure of the substrate dramatically to avoid affecting its bioactivity. Secondly, a probe containing the complementary functional group is introduced to react and label the substrate.Although effective bioorthogonal reactions such as copper-free click chemistry have been developed, development of new reactions continues to generate orthogonal methods for labeling to allow multiple methods of labeling to be used in the same biosystems.