HANDOUT: Sponge Bob Prob Set #2
... SpongeBob’s aunt, who is a roundpants, has a cute stubby nose. She has finally found the sponge of her dreams and is ready to settle down. Her fiancé always comments on how adorable her nose is (he says it reminds him of his mother’s – aww, how sweet!). They wonder what the chances are of that trait ...
... SpongeBob’s aunt, who is a roundpants, has a cute stubby nose. She has finally found the sponge of her dreams and is ready to settle down. Her fiancé always comments on how adorable her nose is (he says it reminds him of his mother’s – aww, how sweet!). They wonder what the chances are of that trait ...
Problems 10
... b) The probability of obtaining a parental chromosome (non-recombinant) in this region is the product of the probability of no recombination between A & R (70%) and the probability of no recombination between R & B (90%). This would mean that (70%)(90%) = 63% should be “parental” and 1/2 (63%) = 31. ...
... b) The probability of obtaining a parental chromosome (non-recombinant) in this region is the product of the probability of no recombination between A & R (70%) and the probability of no recombination between R & B (90%). This would mean that (70%)(90%) = 63% should be “parental” and 1/2 (63%) = 31. ...
Pedigrees Objectives: to determine the genotypes of individuals in a
... b. How many females in this pedigree have hemophilia? _________ c. How many females in this pedigree are normal? ________ d. How many children did the first couple have? _________ e. How many generations are represented in this pedigree? __________ ...
... b. How many females in this pedigree have hemophilia? _________ c. How many females in this pedigree are normal? ________ d. How many children did the first couple have? _________ e. How many generations are represented in this pedigree? __________ ...
Worksheet - X-Linked Inheritance Practice Problems ANSWER KEY
... 10. Amelogenesis imperfecta is a dental abnormality, which is inherited as an X-linked recessive trait. Neither of your parents have the disorder but your father’s brother does. (Assume your mother is homozygous). What is the chance you will receive the recessive gene? ...
... 10. Amelogenesis imperfecta is a dental abnormality, which is inherited as an X-linked recessive trait. Neither of your parents have the disorder but your father’s brother does. (Assume your mother is homozygous). What is the chance you will receive the recessive gene? ...
Sample Exam 1b answer key
... classes in the F2: anther – an, Br, F/an Br, F and brachytic, fine – An, br, f/An, br, f b) Draw a linkage map for the three genes (include map distances) An – Br: 94 + 20 + 100 + 30/1000 = 0.24 x 100 = 24 m.u. An – F: 100 + 94 + 2 + 2/1000 = 0.198 x 100 = 19.8 m.u. Br – F: 2 + 20 + 30 + 2/1000 = 0. ...
... classes in the F2: anther – an, Br, F/an Br, F and brachytic, fine – An, br, f/An, br, f b) Draw a linkage map for the three genes (include map distances) An – Br: 94 + 20 + 100 + 30/1000 = 0.24 x 100 = 24 m.u. An – F: 100 + 94 + 2 + 2/1000 = 0.198 x 100 = 19.8 m.u. Br – F: 2 + 20 + 30 + 2/1000 = 0. ...
genetics - New Age International
... The Chromosomal Theory of Heredity The Mendelian laws of inheritance, formulated in 1865, still form the basis of our understanding of the transmission of heritable variation, and the inheritance test is still the basic technique for following phenotypic characters through the several generations. I ...
... The Chromosomal Theory of Heredity The Mendelian laws of inheritance, formulated in 1865, still form the basis of our understanding of the transmission of heritable variation, and the inheritance test is still the basic technique for following phenotypic characters through the several generations. I ...
The Discovery of Transposition
... her with the first clue that Ds could move was noticing two exceptional kernels that did not lose all of the dominant markers distal to Ds simultaneously. Among many kernels that looked like that in Figure 4, she observed a small number that had breaks between the C-I locus and the Bz locus (giving ...
... her with the first clue that Ds could move was noticing two exceptional kernels that did not lose all of the dominant markers distal to Ds simultaneously. Among many kernels that looked like that in Figure 4, she observed a small number that had breaks between the C-I locus and the Bz locus (giving ...
Comings et al. (1996)
... Gambling has been defined as an impulse control disorder (DSM-IV, 1994), and has many similarities with alcoholism and substance dependence. Researchers have found a link between the D2A1 allele gene and drug addiction, some forms of severe alcoholism and other impulsive, addictive behaviors. A Unit ...
... Gambling has been defined as an impulse control disorder (DSM-IV, 1994), and has many similarities with alcoholism and substance dependence. Researchers have found a link between the D2A1 allele gene and drug addiction, some forms of severe alcoholism and other impulsive, addictive behaviors. A Unit ...
An effect of the DGAT1 gene polymorphism on breeding
... acids share in milk what may have a negative effect on human health [Schennink et al. 2007]. In addition, it was shown that the K allele has a positive effect on intramuscular fat content of beef in Charolaise and Holstein cattle [Thaller et al. 2003a]. However, Casas et al. [2005] reported no signi ...
... acids share in milk what may have a negative effect on human health [Schennink et al. 2007]. In addition, it was shown that the K allele has a positive effect on intramuscular fat content of beef in Charolaise and Holstein cattle [Thaller et al. 2003a]. However, Casas et al. [2005] reported no signi ...
THE BASIC SELECTION MODEL ASSIGNMENT 1
... The aim of this assignment set is to familiarize with natural selection as a concept in population genetics. Selection = fitness differences of genotypes and/or alleles. Recap the Hardy-Weinberg concept (pages 12-16). One of the messages in HWE is that gene and genotype frequencies do not change fro ...
... The aim of this assignment set is to familiarize with natural selection as a concept in population genetics. Selection = fitness differences of genotypes and/or alleles. Recap the Hardy-Weinberg concept (pages 12-16). One of the messages in HWE is that gene and genotype frequencies do not change fro ...
Virginia State Science Olympiad Regional Tournament
... a. Mitosis results in four haploid daughter cells, while meiosis results in two diploid daughter cells. b. DNA synthesis only occurs once before either mitosis or meiosis. c. During anaphase I, homologous pairs of chromatids are separated; during regular anaphase, homologous pairs of chromosomes are ...
... a. Mitosis results in four haploid daughter cells, while meiosis results in two diploid daughter cells. b. DNA synthesis only occurs once before either mitosis or meiosis. c. During anaphase I, homologous pairs of chromatids are separated; during regular anaphase, homologous pairs of chromosomes are ...
Name Period ______ Date
... SpongeBob Genetics 1. For each genotype below, indicate whether it is a heterozygous (He) OR homozygous (Ho). TT _____ ...
... SpongeBob Genetics 1. For each genotype below, indicate whether it is a heterozygous (He) OR homozygous (Ho). TT _____ ...
Supplementary information (doc 11K)
... in these crosses produced the high frequency of inviable progeny (due to ...
... in these crosses produced the high frequency of inviable progeny (due to ...
Genetics Practice Problems Packet
... The heterozygous shows both traits at the same time The genotypic and phenotypic ratios are always the same ...
... The heterozygous shows both traits at the same time The genotypic and phenotypic ratios are always the same ...
Mendelian Genetics
... or female) and one degree of freedom. This is the case since one class (e.g. female) is “free” to vary in % of the total, but once its value is known the % of the other class (male) is determined by default (no longer “free”). Likewise if there are three values that make up100% of the characteristic ...
... or female) and one degree of freedom. This is the case since one class (e.g. female) is “free” to vary in % of the total, but once its value is known the % of the other class (male) is determined by default (no longer “free”). Likewise if there are three values that make up100% of the characteristic ...
PPT
... Characteristics of autosomal dominant inheritance: 1. A gene is dominant if it is expressed when heterozygous 2. An affected individual has a 50% chance of having an affected child. 3. An affected child will have one affected parent 4. The affected parent can be either the mother or the father 5. A ...
... Characteristics of autosomal dominant inheritance: 1. A gene is dominant if it is expressed when heterozygous 2. An affected individual has a 50% chance of having an affected child. 3. An affected child will have one affected parent 4. The affected parent can be either the mother or the father 5. A ...
Genetics IV: Biochemical Genetics
... How often an “A” allele will be in the egg (in female) = p How often an “a” allele will be in the egg = q ...
... How often an “A” allele will be in the egg (in female) = p How often an “a” allele will be in the egg = q ...
The problem of replication - HAL
... results noted, allowance must be made for multiple testing, and the effect this has on power is quite different for linkage and association studies because of the enormous difference in the effective number of independent tests that each entails. If, on the other hand, there is good motivation for e ...
... results noted, allowance must be made for multiple testing, and the effect this has on power is quite different for linkage and association studies because of the enormous difference in the effective number of independent tests that each entails. If, on the other hand, there is good motivation for e ...
Dominance (genetics)
Dominance in genetics is a relationship between alleles of one gene, in which the effect on phenotype of one allele masks the contribution of a second allele at the same locus. The first allele is dominant and the second allele is recessive. For genes on an autosome (any chromosome other than a sex chromosome), the alleles and their associated traits are autosomal dominant or autosomal recessive. Dominance is a key concept in Mendelian inheritance and classical genetics. Often the dominant allele codes for a functional protein whereas the recessive allele does not.A classic example of dominance is the inheritance of seed shape, for example a pea shape in peas. Peas may be round, associated with allele R or wrinkled, associated with allele r. In this case, three combinations of alleles (genotypes) are possible: RR, Rr, and rr. The RR individuals have round peas and the rr individuals have wrinkled peas. In Rr individuals the R allele masks the presence of the r allele, so these individuals also have round peas. Thus, allele R is dominant to allele r, and allele r is recessive to allele R. This use of upper case letters for dominant alleles and lower caseones for recessive alleles is a widely followed convention.More generally, where a gene exists in two allelic versions (designated A and a), three combinations of alleles are possible: AA, Aa, and aa. If AA and aa individuals (homozygotes) show different forms of some trait (phenotypes), and Aa individuals (heterozygotes) show the same phenotype as AA individuals, then allele A is said to dominate or be dominant to or show dominance to allele a, and a is said to be recessive to A.Dominance is not inherent to an allele. It is a relationship between alleles; one allele can be dominant over a second allele, recessive to a third allele, and codominant to a fourth. Also, an allele may be dominant for a particular aspect of phenotype but not for other aspects influenced by the same gene. Dominance differs from epistasis, a relationship in which an allele of one gene affects the expression of another allele at a different gene.