pdfCfE Higher - Unit 3 - Pupil Booklet 2 MB
... zero but the aim is to learn from mistakes and reduce the rate to a minimum. It is essential at this stage to revise all of your National 5 calculations that were based on moles and equations. ...
... zero but the aim is to learn from mistakes and reduce the rate to a minimum. It is essential at this stage to revise all of your National 5 calculations that were based on moles and equations. ...
paper - General Atomics Fusion Group
... transportation fuel that has the potential to displace fossil fuels. Hydrogen will be particularly advantageous when coupled with fuel cells. Fuel cells have higher efficiency than conventional battery/internal combustion engine combinations and do not produce nitrogen oxides during low-temperature ...
... transportation fuel that has the potential to displace fossil fuels. Hydrogen will be particularly advantageous when coupled with fuel cells. Fuel cells have higher efficiency than conventional battery/internal combustion engine combinations and do not produce nitrogen oxides during low-temperature ...
getting started 3.1 hydrocarbons
... 1. A functional group is a structural arrangement of atoms that, because of their electronegativity and bonding type, imparts particular characteristics to the molecule. 2. C=C and C)C bonds are more reactive than C–C bonds because the second and third bonds formed are weaker than the single bonds f ...
... 1. A functional group is a structural arrangement of atoms that, because of their electronegativity and bonding type, imparts particular characteristics to the molecule. 2. C=C and C)C bonds are more reactive than C–C bonds because the second and third bonds formed are weaker than the single bonds f ...
Chem 150 Unit 2 - Hydrocarbons & Functional Groups
... • Esters, on the other hand, produce the sweet, often pleasant order associated with flowers, perfumes and various natural and artificial flavorings. The next slide shows Figure 4.24 from Raymond, which gives some specific examples. ...
... • Esters, on the other hand, produce the sweet, often pleasant order associated with flowers, perfumes and various natural and artificial flavorings. The next slide shows Figure 4.24 from Raymond, which gives some specific examples. ...
Chemistry - Birkenhead School
... Melting and freezing take place at the melting point, boiling and condensing take place at the boiling point. The three states of matter can be represented by a simple model. In this model, particles are represented by small solid spheres. Particle theory can help to explain melting, boiling, freezi ...
... Melting and freezing take place at the melting point, boiling and condensing take place at the boiling point. The three states of matter can be represented by a simple model. In this model, particles are represented by small solid spheres. Particle theory can help to explain melting, boiling, freezi ...
Sulfuric Acid
... catalyst and forming water from burning hydrogen. Step 2. When using sulfur from sources 1 and 2, purification of the SO 2 gas is normally not needed. Other sources of SO2 require wet scrubbing followed by treatment of the gas with electrostatic precipitators to remove fine particles. The catalyst u ...
... catalyst and forming water from burning hydrogen. Step 2. When using sulfur from sources 1 and 2, purification of the SO 2 gas is normally not needed. Other sources of SO2 require wet scrubbing followed by treatment of the gas with electrostatic precipitators to remove fine particles. The catalyst u ...
1. What is the best definition of rate of reaction? A. The time it takes
... Nitrogen monoxide reacts at 1280 °C with hydrogen to form nitrogen and water. All reactants and products are in the gaseous phase. (i) ...
... Nitrogen monoxide reacts at 1280 °C with hydrogen to form nitrogen and water. All reactants and products are in the gaseous phase. (i) ...
Spontaniety Worked Examples
... (a) The reactants are six molecules of gas, and the products are three molecules of gas and four molecules of liquid. Thus, the number of molecules of gas has decreased significantly during the reaction. By using the general rules discussed in Section 19.3, we expect a decrease in the number of gas ...
... (a) The reactants are six molecules of gas, and the products are three molecules of gas and four molecules of liquid. Thus, the number of molecules of gas has decreased significantly during the reaction. By using the general rules discussed in Section 19.3, we expect a decrease in the number of gas ...
hydrogen storage
... recombine to form molecules inside the tube and arrange themselves in a concentric pattern. The hydrogen pressure inside the SWNT increases with the number of injected atoms and reaches 35 GPa for 90 atoms (5 mass%). This simulation does not show condensation of hydrogen inside the nanotube. The cri ...
... recombine to form molecules inside the tube and arrange themselves in a concentric pattern. The hydrogen pressure inside the SWNT increases with the number of injected atoms and reaches 35 GPa for 90 atoms (5 mass%). This simulation does not show condensation of hydrogen inside the nanotube. The cri ...
CfE HIGHER CHEMISTRY Chemistry in Society
... industrial reaction to be cost effective it is important to produce as much of the desired product as possible rather than unwanted by-products. Consideration of the atom economy allows us to calculate the proportion of reactants converted into the desired product. Atom economy ...
... industrial reaction to be cost effective it is important to produce as much of the desired product as possible rather than unwanted by-products. Consideration of the atom economy allows us to calculate the proportion of reactants converted into the desired product. Atom economy ...
www.xtremepapers.net
... The equilibrium pressure inside the syringe will be greater than atmospheric pressure. ...
... The equilibrium pressure inside the syringe will be greater than atmospheric pressure. ...
File - wilson science WEBSITE
... 8. For a certain reactions at 25oC, the value of K is 1.2 x 10-3. At 50oC, the value of K is 3.4 x 10-1. This means that the reaction is a. exothermic b. endothermic c. more information is needed 9. Given the equation A(g) ↔ B(g) + 2C(g). At a particular temperature, K = 1.4 x 105. If you initially ...
... 8. For a certain reactions at 25oC, the value of K is 1.2 x 10-3. At 50oC, the value of K is 3.4 x 10-1. This means that the reaction is a. exothermic b. endothermic c. more information is needed 9. Given the equation A(g) ↔ B(g) + 2C(g). At a particular temperature, K = 1.4 x 105. If you initially ...
Worksheet Key
... b) Using the same reaction, some NH3 is removed from the reaction when it is at equilibrium. Reaction will shift toward products to produce more NH3 c) 2 SO2 (g) + O2 (g) 2 SO3 (g) + heat: the system temperature goes up (heat is added). Toward reactants; heat is a product, adding heat shifts react ...
... b) Using the same reaction, some NH3 is removed from the reaction when it is at equilibrium. Reaction will shift toward products to produce more NH3 c) 2 SO2 (g) + O2 (g) 2 SO3 (g) + heat: the system temperature goes up (heat is added). Toward reactants; heat is a product, adding heat shifts react ...
kinetics, catalysis, and reaction engineering
... factorial design was used to determine which factors had significant effects on HCN conversion in these experiments. We conclude that reaction temperature and gas hourly space velocity (GHSV) had the most significant effects on HCN conversion, whereas no significant effects were caused by the presen ...
... factorial design was used to determine which factors had significant effects on HCN conversion in these experiments. We conclude that reaction temperature and gas hourly space velocity (GHSV) had the most significant effects on HCN conversion, whereas no significant effects were caused by the presen ...
fahad h. ahmad - Fahad`s Academy
... Also, it can VARY melting and boiling points of pure substances. e.g. pure water boil at 100oC, but with salt is at 102oC 1.3 Identification of Ions and Gases Refer to Insert 1. Everything lies there. ...
... Also, it can VARY melting and boiling points of pure substances. e.g. pure water boil at 100oC, but with salt is at 102oC 1.3 Identification of Ions and Gases Refer to Insert 1. Everything lies there. ...
Chemistry 400
... A) At a given temperature, lighter gas particles travel more slowly than heavier gas particles. B) The smaller a gas particle, the slower it will effuse C) The higher the temperature, the lower the average kinetic energy of the sample. D) At low temperatures, intermolecular forces become important a ...
... A) At a given temperature, lighter gas particles travel more slowly than heavier gas particles. B) The smaller a gas particle, the slower it will effuse C) The higher the temperature, the lower the average kinetic energy of the sample. D) At low temperatures, intermolecular forces become important a ...
www.fahadsacademy.com
... Solution is heated, and steam (pure vapour) is produced. The steam is cooled in condenser to form pure liquid. Solute remains in the flask. Fractional Distillation Fractional Distillation – separates mixture of miscible (soluble) liquids with widely differing boiling points. Use of fractionationg co ...
... Solution is heated, and steam (pure vapour) is produced. The steam is cooled in condenser to form pure liquid. Solute remains in the flask. Fractional Distillation Fractional Distillation – separates mixture of miscible (soluble) liquids with widely differing boiling points. Use of fractionationg co ...
Carbon Chemistry - North Allegheny School District
... outer energy level, so it can form four covalent bonds with as many as four other atoms. When carbon atoms form four covalent bonds, they obtain the stability of a noble gas with eight electrons in their outer energy level. One of carbon’s most frequent partners in forming covalent bonds is hydrogen ...
... outer energy level, so it can form four covalent bonds with as many as four other atoms. When carbon atoms form four covalent bonds, they obtain the stability of a noble gas with eight electrons in their outer energy level. One of carbon’s most frequent partners in forming covalent bonds is hydrogen ...
Reactions Balancing Chemical Equations uses Law of conservation
... Sum of oxidation numbers is equal to overall charge of molecule or ion: • For a neutral compound the sum of oxidation numbers equals zero. • For a polyatomic ion, the sum of the oxidation numbers is equal to the charge on the ion. Shared electrons are assigned to the more electronegative atom of t ...
... Sum of oxidation numbers is equal to overall charge of molecule or ion: • For a neutral compound the sum of oxidation numbers equals zero. • For a polyatomic ion, the sum of the oxidation numbers is equal to the charge on the ion. Shared electrons are assigned to the more electronegative atom of t ...
chapter i states of matter - myweb
... separated and recovered as pure substances by means of physical methods. However, in the case of homogenous mixtures one has to be very careful with the recovery of pure solid substances. Consider for example the case of a simple syrup. Water can be removed by boiling the solution and condensing the ...
... separated and recovered as pure substances by means of physical methods. However, in the case of homogenous mixtures one has to be very careful with the recovery of pure solid substances. Consider for example the case of a simple syrup. Water can be removed by boiling the solution and condensing the ...
Exames anteriores a 1994
... (see Fig. 2). The numbers indicated on the maps relate to the electron density in the neighbourhood of the atoms of E as a function of the spatial coordinates. The maxima found in these maps coincide with the locations of the atoms and the values are approximately proportional to the number of elect ...
... (see Fig. 2). The numbers indicated on the maps relate to the electron density in the neighbourhood of the atoms of E as a function of the spatial coordinates. The maxima found in these maps coincide with the locations of the atoms and the values are approximately proportional to the number of elect ...
Chapter 6 - Sites @ Suffolk University
... used today to explain the seeming magic in the transformations of substances. There is a very practical reason for the balanced equation, as well. In performing chemical reactions it is important to know not only what chemicals are involved, but exactly how much. Chemical plants which produce pharma ...
... used today to explain the seeming magic in the transformations of substances. There is a very practical reason for the balanced equation, as well. In performing chemical reactions it is important to know not only what chemicals are involved, but exactly how much. Chemical plants which produce pharma ...
Chapter 5 Chemical Equilibrium 1 State whether each of the
... pressure is decreased? Why? The equilibrium will shift to the left to increase the pressure, since thee are 1.5 moles of gas on the left and only 1 mole of gas on the right. 11. Graphite is the standard state of carbon. Why do diamonds exist at 25cC and 1 atm? Diamond is thermodynamically unstable, ...
... pressure is decreased? Why? The equilibrium will shift to the left to increase the pressure, since thee are 1.5 moles of gas on the left and only 1 mole of gas on the right. 11. Graphite is the standard state of carbon. Why do diamonds exist at 25cC and 1 atm? Diamond is thermodynamically unstable, ...
Multiple-choice questions : 1. The following graph shows the volume
... Each question below consists of two separate statements. Decide whether each of the two statements is true or false; if both are true, then decide whether or not the second statement is a correct explanation of the first statement. Then select one option from A to D according to the following table: ...
... Each question below consists of two separate statements. Decide whether each of the two statements is true or false; if both are true, then decide whether or not the second statement is a correct explanation of the first statement. Then select one option from A to D according to the following table: ...
Cambridge International Examinations Cambridge
... Describe a chemical test to show that the fat is unsaturated. name of reagent ................................................................................................................ result of test .............................................................................................. ...
... Describe a chemical test to show that the fat is unsaturated. name of reagent ................................................................................................................ result of test .............................................................................................. ...
Catalytic reforming
Catalytic reforming is a chemical process used to convert petroleum refinery naphthas distilled from crude oil (typically having low octane ratings) into high-octane liquid products called reformates, which are premium blending stocks for high-octane gasoline. The process converts low-octane linear hydrocarbons (paraffins) into branched alkanes (isoparaffins) and cyclic naphthenes, which are then partially dehydrogenated to produce high-octane aromatic hydrocarbons. The dehydrogenation also produces significant amounts of byproduct hydrogen gas, which is fed into other refinery processes such as hydrocracking. A side reaction is hydrogenolysis, which produces light hydrocarbons of lower value, such as methane, ethane, propane and butanes.In addition to a gasoline blending stock, reformate is the main source of aromatic bulk chemicals such as benzene, toluene, xylene and ethylbenzene which have diverse uses, most importantly as raw materials for conversion into plastics. However, the benzene content of reformate makes it carcinogenic, which has led to governmental regulations effectively requiring further processing to reduce its benzene content.This process is quite different from and not to be confused with the catalytic steam reforming process used industrially to produce products such as hydrogen, ammonia, and methanol from natural gas, naphtha or other petroleum-derived feedstocks. Nor is this process to be confused with various other catalytic reforming processes that use methanol or biomass-derived feedstocks to produce hydrogen for fuel cells or other uses.