In_Class_Practice Chapter 17 PreAP
... Calculate Keq for this equilibrium using the data [NOBr] = 0.0474 mol/L, [NO] = 0.312 mol/L, and [Br2] = 0.259 mol/L. Practice Problems 3. The following is the chemical equation for the decomposition of formamide. HCONH2(g) NH3(g) + CO(g) Calculate Keq using the equilibrium data [HCONH2] = 0.0637 ...
... Calculate Keq for this equilibrium using the data [NOBr] = 0.0474 mol/L, [NO] = 0.312 mol/L, and [Br2] = 0.259 mol/L. Practice Problems 3. The following is the chemical equation for the decomposition of formamide. HCONH2(g) NH3(g) + CO(g) Calculate Keq using the equilibrium data [HCONH2] = 0.0637 ...
C:\D\Books\Cambridge University Press\CUP Problems\Problems.wpd
... 97. In the design of a wastewater treatment plant the organic matter in the sewage was assumed to have the composition C18H19O9N. This waste can be oxidized by aerobic, heterotrophic bacteria in two ways: a without and b with nitrification. Write balanced reaction equations and find the maximum biol ...
... 97. In the design of a wastewater treatment plant the organic matter in the sewage was assumed to have the composition C18H19O9N. This waste can be oxidized by aerobic, heterotrophic bacteria in two ways: a without and b with nitrification. Write balanced reaction equations and find the maximum biol ...
Physical chemistry and transition elements 5.1 Rates, equilibrium
... If a white precipitate of silver chloride is produced it must be potassium chloride. If a yellow precipitate of silver iodide is produced it must be potassium iodide. If the colour is hard to distinguish, first add dilute ammonia, then concentrated ammonia. Potassium chloride is soluble in d ...
... If a white precipitate of silver chloride is produced it must be potassium chloride. If a yellow precipitate of silver iodide is produced it must be potassium iodide. If the colour is hard to distinguish, first add dilute ammonia, then concentrated ammonia. Potassium chloride is soluble in d ...
Mole and Energy - Deans Community High School
... Index Chemical energy The mole Molar quantities Avogadro’s constant Gas volume Enthalpy changes and specific heat capacity ...
... Index Chemical energy The mole Molar quantities Avogadro’s constant Gas volume Enthalpy changes and specific heat capacity ...
+ 2 H2O(l Ca(OH)2 aq)
... c) Sulfur dioxide, SO2, is a nonmetal oxide that reacts with oxygen, O2, to form the higher oxide, SO3. Δ 2 SO (g) 2 SO2(g) + O2(g) ── ...
... c) Sulfur dioxide, SO2, is a nonmetal oxide that reacts with oxygen, O2, to form the higher oxide, SO3. Δ 2 SO (g) 2 SO2(g) + O2(g) ── ...
Unit 1 Mole and enthalpy changes
... Enthalpy of neutralisation The enthalpy of neutralisation of a substance is the amount of energy given out when one mole of water is formed in a neutralisation reaction. Worked example 1. 100cm3 of 1 mol l -1 hydrochloric acid, HCl, was mixed with 100 cm3 of 1 mol -1 sodium hydroxide, NaOH, and the ...
... Enthalpy of neutralisation The enthalpy of neutralisation of a substance is the amount of energy given out when one mole of water is formed in a neutralisation reaction. Worked example 1. 100cm3 of 1 mol l -1 hydrochloric acid, HCl, was mixed with 100 cm3 of 1 mol -1 sodium hydroxide, NaOH, and the ...
1.02 x 10 = 3 mol lit 3.4 x 10
... (ii) Electrons trapped in the --------------sites of the ---------------- lattice are called F-centres. Ans: vacant, crystal (iii) An aqueous solution of sugar boils ------------- 100oC and freezes ----------0oC. Ans: above, below (iv) Toluene on -------------- with alkaline potassium permanganate g ...
... (ii) Electrons trapped in the --------------sites of the ---------------- lattice are called F-centres. Ans: vacant, crystal (iii) An aqueous solution of sugar boils ------------- 100oC and freezes ----------0oC. Ans: above, below (iv) Toluene on -------------- with alkaline potassium permanganate g ...
Grade 11 review answers
... 21) Identify a set of test solutions and a correct sequence for adding them to an unknown solution to test for the presence of one or more of the following metal ions: Mercury (2+), Silver, and Barium Use table 1 at the end of the review. 1) Acetate ion (as aqueous Sodium acetate) will precipitate A ...
... 21) Identify a set of test solutions and a correct sequence for adding them to an unknown solution to test for the presence of one or more of the following metal ions: Mercury (2+), Silver, and Barium Use table 1 at the end of the review. 1) Acetate ion (as aqueous Sodium acetate) will precipitate A ...
CHAPTER 3 STOICHIOMETRY:
... reactants are LR reactions. Convert grams of reactants to moles. Divide the results of each mole on its coefficient in the balanced equation. The smallest value is for the LR substance. Your calculations should be based on the LR. ...
... reactants are LR reactions. Convert grams of reactants to moles. Divide the results of each mole on its coefficient in the balanced equation. The smallest value is for the LR substance. Your calculations should be based on the LR. ...
SCH4U Exam Review
... allowed to react, what would be the equilibrium concentration of each gas? ANS: 0.0621 M, 0.088 M 9. At a certain temperature the reaction: CO(g) + H2O(g) CO2 (g) + H2 (g) has K = 0.400. Exactly 1.00 mol of each gas was placed into a 100 L vessel and the mixture was allowed to react. What was the ...
... allowed to react, what would be the equilibrium concentration of each gas? ANS: 0.0621 M, 0.088 M 9. At a certain temperature the reaction: CO(g) + H2O(g) CO2 (g) + H2 (g) has K = 0.400. Exactly 1.00 mol of each gas was placed into a 100 L vessel and the mixture was allowed to react. What was the ...
Chapter 17 Green chemistry
... account when deciding which method of production should be used. A4. Some factors would include: • The difference between the atom economies of each process • The degree of hazard of the starting material • Whether the hazardous material in the second method can be degraded into a benign compound Q5 ...
... account when deciding which method of production should be used. A4. Some factors would include: • The difference between the atom economies of each process • The degree of hazard of the starting material • Whether the hazardous material in the second method can be degraded into a benign compound Q5 ...
vce chemistry trial exam 1
... C is correct. HPLC allows the separation of organic compounds such as esters. NMR spectroscopy allows the estimation of the structure of organic compounds based on their 13C and 1H spectra. A is incorrect because neither UV-visible spectroscopy nor NMR spectroscopy allow the separation of compounds. ...
... C is correct. HPLC allows the separation of organic compounds such as esters. NMR spectroscopy allows the estimation of the structure of organic compounds based on their 13C and 1H spectra. A is incorrect because neither UV-visible spectroscopy nor NMR spectroscopy allow the separation of compounds. ...
Chapter 4 Student Presentation
... • To form the net ionic equation, cross out anything that does not change from the left side of the equation to the right. • The only things left in the equation are those things that change (i.e., react) during the course of the reaction. • Those things that didn’t change (and were deleted from the ...
... • To form the net ionic equation, cross out anything that does not change from the left side of the equation to the right. • The only things left in the equation are those things that change (i.e., react) during the course of the reaction. • Those things that didn’t change (and were deleted from the ...
Prep UK-intro.p65
... The aim of the scientific committee has been that as many as possible of the preparatory problems should take their starting point in issues of general chemical, public or environmental interest. Therefore some of the problems cover several topics from the International Chemistry Olympiad. We have a ...
... The aim of the scientific committee has been that as many as possible of the preparatory problems should take their starting point in issues of general chemical, public or environmental interest. Therefore some of the problems cover several topics from the International Chemistry Olympiad. We have a ...
Basic Concepts - Department of Chemistry
... Calculating an Equilibrium Constant from Equilibrium Concentrations • can be calculated when equilibrium concentrations, or partial pressures are substituted into the equilibrium constant expression for the reaction. • When equilibrium concentrations are not given the equilibrium concentrations can ...
... Calculating an Equilibrium Constant from Equilibrium Concentrations • can be calculated when equilibrium concentrations, or partial pressures are substituted into the equilibrium constant expression for the reaction. • When equilibrium concentrations are not given the equilibrium concentrations can ...
Basic Concepts
... Nitrosyl bromide, NOBr, is 34% dissociated by the following reaction at 25oC, in a vessel in which the total pressure is 0.25 atmosphere. What is the value of Kp? ...
... Nitrosyl bromide, NOBr, is 34% dissociated by the following reaction at 25oC, in a vessel in which the total pressure is 0.25 atmosphere. What is the value of Kp? ...
19_Worked_Examples
... (a) This process is spontaneous. Whenever two objects at different temperatures are brought into contact, heat is transferred from the hotter object to the colder one. (Section 5.1) Thus, heat is transferred from the hot metal to the cooler water. The final temperature, after the metal and water ach ...
... (a) This process is spontaneous. Whenever two objects at different temperatures are brought into contact, heat is transferred from the hotter object to the colder one. (Section 5.1) Thus, heat is transferred from the hot metal to the cooler water. The final temperature, after the metal and water ach ...
____ 1. The energy required to convert a ground
... 45. The graph above shows the results of a study of the reaction of X with a large excess of Y to yield Z. The concentrations of X and Y were measured over a period of time. According to the results, which of the following can be concluded about the rate law for the reaction under the conditions stu ...
... 45. The graph above shows the results of a study of the reaction of X with a large excess of Y to yield Z. The concentrations of X and Y were measured over a period of time. According to the results, which of the following can be concluded about the rate law for the reaction under the conditions stu ...
U6B _13-14
... Complete Ionic Equation: shows all the particles in a solution as they really exist, as IONS or MOLECULES. Anything aqueous needs to be split apart into the cation and anion Anything solid stays intact Coefficients need to be multiplied by subscripts to determine the exact amount of each catio ...
... Complete Ionic Equation: shows all the particles in a solution as they really exist, as IONS or MOLECULES. Anything aqueous needs to be split apart into the cation and anion Anything solid stays intact Coefficients need to be multiplied by subscripts to determine the exact amount of each catio ...
111 Exam III OUTLINE TRO 1-3-11
... 1. The forward reaction (⇀ ) and reverse (↽ ) reactions are occurring simultaneously. 2. The rate for the forward reaction is equal to the rate of the reverse reaction and a dynamic equilibrium is achieved. 3. The ratio of the concentrations of the products to reactants is constant. B. THE EQUILIBRI ...
... 1. The forward reaction (⇀ ) and reverse (↽ ) reactions are occurring simultaneously. 2. The rate for the forward reaction is equal to the rate of the reverse reaction and a dynamic equilibrium is achieved. 3. The ratio of the concentrations of the products to reactants is constant. B. THE EQUILIBRI ...
L-11 Chemical thermodynamics
... The heat evolved or absorbed in a reaction is affected by the physical state of the reacting substances. Therefore, gaseous, liquid and solid states are represented by putting symbols (g), (l), and (s) along side the chemical formulae respectively. For example, to represent burning of methane in oxy ...
... The heat evolved or absorbed in a reaction is affected by the physical state of the reacting substances. Therefore, gaseous, liquid and solid states are represented by putting symbols (g), (l), and (s) along side the chemical formulae respectively. For example, to represent burning of methane in oxy ...
OCR Gateway Science
... (c) The synthesis of ammonia is carried out in a closed system. What is meant by the term closed system? (d) At the start of the reaction only hydrogen and nitrogen are present. Describe how the rate of the forward and back reactions change as equilibrium is established. ...
... (c) The synthesis of ammonia is carried out in a closed system. What is meant by the term closed system? (d) At the start of the reaction only hydrogen and nitrogen are present. Describe how the rate of the forward and back reactions change as equilibrium is established. ...
Activity C14: Rate of a Chemical Reaction 1
... In this activity you will determine the effect of changes in concentration of the reactants on the rate of the chemical reaction. The reaction for this activity is the acidic reduction of the thiosulfate ion to sulfur and sulfur dioxide. The equation for the reaction is: S2O32-(aq) + 2 H+(aq) ====== ...
... In this activity you will determine the effect of changes in concentration of the reactants on the rate of the chemical reaction. The reaction for this activity is the acidic reduction of the thiosulfate ion to sulfur and sulfur dioxide. The equation for the reaction is: S2O32-(aq) + 2 H+(aq) ====== ...
Practice Exam 4
... Consider the following processes. (Treat all gases as ideal.) I) The pressure of one mole of oxygen gas is allowed to double isothermally. II) Carbon dioxide is allowed to expand isothermally to 10 times its original volume. III) The temperature of one mole of helium is increased 25◦ C at constant p ...
... Consider the following processes. (Treat all gases as ideal.) I) The pressure of one mole of oxygen gas is allowed to double isothermally. II) Carbon dioxide is allowed to expand isothermally to 10 times its original volume. III) The temperature of one mole of helium is increased 25◦ C at constant p ...
Amount of substance
... Q31.The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 g of a copper(II) salt was dissolved in water and added to an excess of potassium iodide solution, liberating iodine according to the following equation: 2Cu2+(aq) + 4I−(aq) → 2CuI(s) + I2(aq ...
... Q31.The percentage of copper in a copper(II) salt can be determined by using a thiosulphate titration. 0.305 g of a copper(II) salt was dissolved in water and added to an excess of potassium iodide solution, liberating iodine according to the following equation: 2Cu2+(aq) + 4I−(aq) → 2CuI(s) + I2(aq ...
Thermometric titration
A thermometric titration is one of a number of instrumental titration techniques where endpoints can be located accurately and precisely without a subjective interpretation on the part of the analyst as to their location. Enthalpy change is arguably the most fundamental and universal property of chemical reactions, so the observation of temperature change is a natural choice in monitoring their progress. It is not a new technique, with possibly the first recognizable thermometric titration method reported early in the 20th century (Bell and Cowell, 1913). In spite of its attractive features, and in spite of the considerable research that has been conducted in the field and a large body of applications that have been developed; it has been until now an under-utilized technique in the critical area of industrial process and quality control. Automated potentiometric titration systems have pre-dominated in this area since the 1970s. With the advent of cheap computers able to handle the powerful thermometric titration software, development has now reached the stage where easy to use automated thermometric titration systems can in many cases offer a superior alternative to potentiometric titrimetry.The applications of thermometric titrimetry discussed on this page are by no means exhaustive. The reader is referred to the bibliography for further reading on the subject.