Unit F325 - Equilibria, energetics and elements
... Level qualifications, NVQs and vocational qualifications in areas such as IT, business, languages, teaching/training, administration and secretarial skills. It is also responsible for developing new specifications to meet national requirements and the needs of students and teachers. OCR is a not-for ...
... Level qualifications, NVQs and vocational qualifications in areas such as IT, business, languages, teaching/training, administration and secretarial skills. It is also responsible for developing new specifications to meet national requirements and the needs of students and teachers. OCR is a not-for ...
chapter 5 gases
... The system is the specific part of the universe that is of interest to us. The surroundings are the rest of the universe outside the system. An open system can exchange mass and energy, usually in the form of heat with its surroundings. A closed system allows the transfer of energy (heat) but not ma ...
... The system is the specific part of the universe that is of interest to us. The surroundings are the rest of the universe outside the system. An open system can exchange mass and energy, usually in the form of heat with its surroundings. A closed system allows the transfer of energy (heat) but not ma ...
Chapter 3
... where n is the number of atoms of the element in a molecule or formula unit of the compound. For example, in a molecule of hydrogen peroxide (H2O2), there are two H atoms and two O atoms. The atomic masses of H and O are 1.008 and 16.00 amu, respectively, so the molecular mass of H2O2 is 34.02 amu. ...
... where n is the number of atoms of the element in a molecule or formula unit of the compound. For example, in a molecule of hydrogen peroxide (H2O2), there are two H atoms and two O atoms. The atomic masses of H and O are 1.008 and 16.00 amu, respectively, so the molecular mass of H2O2 is 34.02 amu. ...
Equilibrium Booklet - mrstorie
... 13. The decomposition of hydrogen iodide to hydrogen and iodine occurs by the reaction 2 HI (g) ↔ H2 (g) + I2 (g) Hydrogen iodide is placed in a container at 450°C an equilibrium mixture contains 0.50 moles of hydrogen iodide. The equilibrium constant is 0.020 for the reaction. How many moles of iod ...
... 13. The decomposition of hydrogen iodide to hydrogen and iodine occurs by the reaction 2 HI (g) ↔ H2 (g) + I2 (g) Hydrogen iodide is placed in a container at 450°C an equilibrium mixture contains 0.50 moles of hydrogen iodide. The equilibrium constant is 0.020 for the reaction. How many moles of iod ...
Mole Concept - Shailendra Kumar Chemistry
... 1 g of dry green algae absorbs 4.7 × 10–3 mole of CO2 per hour by photosynthesis. If the fixed carbon atoms were all stored after photosynthesis as starch, (C6H10O5)n, how long would it take for the algae to double their own weight assuming photosynthesis takes place at a constant ...
... 1 g of dry green algae absorbs 4.7 × 10–3 mole of CO2 per hour by photosynthesis. If the fixed carbon atoms were all stored after photosynthesis as starch, (C6H10O5)n, how long would it take for the algae to double their own weight assuming photosynthesis takes place at a constant ...
LaBrake, Fundamentals Diagnostic Questions
... d) A compound is a specific combination of atoms of more than one element. e) In a chemical reaction, atoms are neither created nor destroyed; they exchange partners to produce new substances. 19. All of the following statements are true regarding the nuclear model of the atom, except: a) The positi ...
... d) A compound is a specific combination of atoms of more than one element. e) In a chemical reaction, atoms are neither created nor destroyed; they exchange partners to produce new substances. 19. All of the following statements are true regarding the nuclear model of the atom, except: a) The positi ...
AS/A level
... Further evidence for this model comes from successive ionisation energies. Explain how these provide evidence for aspects of the model described. Sketch the expected pattern of successive ionisation energies for an atom of aluminium and use it to illustrate your answer. ...
... Further evidence for this model comes from successive ionisation energies. Explain how these provide evidence for aspects of the model described. Sketch the expected pattern of successive ionisation energies for an atom of aluminium and use it to illustrate your answer. ...
5 Steps
... THE FIVE-STEP PROGRAM The Basics Not too long ago, you enrolled in AP Chemistry. A curiosity about chemistry, encouragement from a respected teacher, or the simple fact that it was a requirement may have been your motivation. No matter what the reason, you find yourself flipping through a book, whic ...
... THE FIVE-STEP PROGRAM The Basics Not too long ago, you enrolled in AP Chemistry. A curiosity about chemistry, encouragement from a respected teacher, or the simple fact that it was a requirement may have been your motivation. No matter what the reason, you find yourself flipping through a book, whic ...
CHAPTER 14 CHEMICAL KINETICS
... is given by Equations (14.3) and (14.4) of the text. We are asked to determine the time required for 95% of the phosphine to decompose. If we initially have 100% of the compound and 95% has reacted, then what is left must be (100% 95%), or 5%. Thus, the ratio of the percentages will be equal to th ...
... is given by Equations (14.3) and (14.4) of the text. We are asked to determine the time required for 95% of the phosphine to decompose. If we initially have 100% of the compound and 95% has reacted, then what is left must be (100% 95%), or 5%. Thus, the ratio of the percentages will be equal to th ...
The science of chemistry is concerned
... which does not go to completion. Commercial production of ammonia is accomplished using this reaction in what is called the Haber process. Even at the rather unusual temperatures and pressures used for this industrial synthesis, only about one-quarter of the reactants can be converted to the desired ...
... which does not go to completion. Commercial production of ammonia is accomplished using this reaction in what is called the Haber process. Even at the rather unusual temperatures and pressures used for this industrial synthesis, only about one-quarter of the reactants can be converted to the desired ...
Limiting Reactants and Percentage Yield
... Sample Problem G The black oxide of iron, Fe3O4, occurs in nature as the mineral magnetite. This substance can also be made in the laboratory by the reaction between red-hot iron and steam according to the following equation. 3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g) a. When 36.0 g H2O are mixed with ...
... Sample Problem G The black oxide of iron, Fe3O4, occurs in nature as the mineral magnetite. This substance can also be made in the laboratory by the reaction between red-hot iron and steam according to the following equation. 3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g) a. When 36.0 g H2O are mixed with ...
Problem 1-2
... The position of atoms and ions in a unit cell can be described by their relative locations xyz (fractional coordinates). Their values lie normally between 0 and 1. For the compound mentioned on the previous page the following fractional coordinates were found: xc ...
... The position of atoms and ions in a unit cell can be described by their relative locations xyz (fractional coordinates). Their values lie normally between 0 and 1. For the compound mentioned on the previous page the following fractional coordinates were found: xc ...
A Model For the Calculation of Solvent ... Reaction Rates for Process Design Purposes
... models for the assessment of solvents as reaction media that are fast, and therefore able to screen large numbers of molecules in a reasonable time, as well as applicable to a wide range of solvents and reactions and able to provide results that are accurate for process design needs. Solvent effects ...
... models for the assessment of solvents as reaction media that are fast, and therefore able to screen large numbers of molecules in a reasonable time, as well as applicable to a wide range of solvents and reactions and able to provide results that are accurate for process design needs. Solvent effects ...
chapter 21
... Strategy: We are given information as to how the concentrations of X2, Y, and Z affect the rate of the reaction and are asked to determine the rate law. We assume that the rate law takes the form rate k[X2]x[Y]y[Z]z How do we use the information to determine x, y, and z? Solution: Since the reacti ...
... Strategy: We are given information as to how the concentrations of X2, Y, and Z affect the rate of the reaction and are asked to determine the rate law. We assume that the rate law takes the form rate k[X2]x[Y]y[Z]z How do we use the information to determine x, y, and z? Solution: Since the reacti ...
visual problems - Western Oregon University
... decomposition of stratospheric ozone. Trichlorofluoromethane (CCl3F) boils at 23.8°C and its molar heat of vaporization is 24.8 kJ/mol. What is the molar entropy of evaporation of CCl 3F(ℓ)? 12.72. Methane-Producing Bacteria Methanogenic bacteria convert liquid acetic acid (CH3COOH) into CO2(g) and ...
... decomposition of stratospheric ozone. Trichlorofluoromethane (CCl3F) boils at 23.8°C and its molar heat of vaporization is 24.8 kJ/mol. What is the molar entropy of evaporation of CCl 3F(ℓ)? 12.72. Methane-Producing Bacteria Methanogenic bacteria convert liquid acetic acid (CH3COOH) into CO2(g) and ...
5 Steps to a 5 AP Chemistry, 2008-2009 Edition
... THE FIVE-STEP PROGRAM The Basics Not too long ago, you enrolled in AP Chemistry. A curiosity about chemistry, encouragement from a respected teacher, or the simple fact that it was a requirement may have been your motivation. No matter what the reason, you find yourself flipping through a book, whic ...
... THE FIVE-STEP PROGRAM The Basics Not too long ago, you enrolled in AP Chemistry. A curiosity about chemistry, encouragement from a respected teacher, or the simple fact that it was a requirement may have been your motivation. No matter what the reason, you find yourself flipping through a book, whic ...
Review of N and Metal co-Doped TiO for Water Purification under
... towards larger visible spectra, which is partially due to reducing the band gap of the semiconductor by N doping. Ag nanoparticles could transfer the plasmonic energy from the Ag0 to the TiO2 semiconductor due to its surface plasmonic resonance (SPR) effect [40], this also contributed to enlarging l ...
... towards larger visible spectra, which is partially due to reducing the band gap of the semiconductor by N doping. Ag nanoparticles could transfer the plasmonic energy from the Ag0 to the TiO2 semiconductor due to its surface plasmonic resonance (SPR) effect [40], this also contributed to enlarging l ...
IB Chemistry Online SAQ_Ans
... d Main energy level 2 (second shell) i.e. n = 2 e Each element has its own characteristic line spectrum. Therefore an element can be identified by its line spectrum just as a criminal can be identified from a fingerprint. f An unknown yellow emission line was observed in the solar spectrum during ...
... d Main energy level 2 (second shell) i.e. n = 2 e Each element has its own characteristic line spectrum. Therefore an element can be identified by its line spectrum just as a criminal can be identified from a fingerprint. f An unknown yellow emission line was observed in the solar spectrum during ...
CO2 Dissociation using the Versatile Atmospheric Dielectric Barrier
... carbon sequestration [8]. Even so, large amounts of research have and are currently being done to overcome these issues. ...
... carbon sequestration [8]. Even so, large amounts of research have and are currently being done to overcome these issues. ...
GCE Chemistry SAMs 2009 onwards pdf
... You are reminded that assessment will take into account the quality of written communication used in your answers. No certificate will be awarded to a candidate detected in any unfair practice during the examination. ...
... You are reminded that assessment will take into account the quality of written communication used in your answers. No certificate will be awarded to a candidate detected in any unfair practice during the examination. ...
Fall Practice Final
... the number of neutrons ____ 14. The nucleus of an atom is ____. a. the central core and is composed of protons and neutrons b. positively charged and has more protons than neutrons c. negatively charged and has a high density d. negatively charged and has a low density ____ 15. The sum of the proton ...
... the number of neutrons ____ 14. The nucleus of an atom is ____. a. the central core and is composed of protons and neutrons b. positively charged and has more protons than neutrons c. negatively charged and has a high density d. negatively charged and has a low density ____ 15. The sum of the proton ...
Unit 6 Chemical Energy
... Using a match, light the nut. When it has finished burning, measure the final temperature of the water. Calculate how much energy was absorbed by the water. Where did this energy Figure 2 come from? Calculate the quantity Experimental set-up of energy produced per gram of fuel (nut) burned. Compare ...
... Using a match, light the nut. When it has finished burning, measure the final temperature of the water. Calculate how much energy was absorbed by the water. Where did this energy Figure 2 come from? Calculate the quantity Experimental set-up of energy produced per gram of fuel (nut) burned. Compare ...