CHE 1402 Lab Manual
... 4. Write the ideal-gas equation and give the units for each term when R = 0.0821 L-atm /mol-K. 5. Show by mathematical equations how one can determine the molar mass of a volatile liquid by measurement of the pressure, volume, temperature, and weight of the liquid. 6. If 0.75 g of a gas occupies 300 ...
... 4. Write the ideal-gas equation and give the units for each term when R = 0.0821 L-atm /mol-K. 5. Show by mathematical equations how one can determine the molar mass of a volatile liquid by measurement of the pressure, volume, temperature, and weight of the liquid. 6. If 0.75 g of a gas occupies 300 ...
Bulgarian Chemical Communications, Volume 41, Number 4 (pp
... proposed. The results show that photo-Fenton-like process could be a useful and efficient technology for the mineralization of diazo dyes at lower concentrations of iron in acidic medium. Key words: photo-Fenton-like process, ammonium persulphate, diazo dyes, GC-MS analysis. ...
... proposed. The results show that photo-Fenton-like process could be a useful and efficient technology for the mineralization of diazo dyes at lower concentrations of iron in acidic medium. Key words: photo-Fenton-like process, ammonium persulphate, diazo dyes, GC-MS analysis. ...
1aUnit Two Handouts - Dunmore High School
... K2SO4 HNO3 H2CO3 ZnS NOTE: When H2CO3, H2SO3 or NH4OH are formed as products, they do break down, though not into ions. They break down into H2O and a gaseous substance. ...
... K2SO4 HNO3 H2CO3 ZnS NOTE: When H2CO3, H2SO3 or NH4OH are formed as products, they do break down, though not into ions. They break down into H2O and a gaseous substance. ...
The decomposition of hydrogen peroxide to form water and oxygen
... Your explanation should reference the relative strengths of interactions between molecules of I2 and the solvents H2O and C6H14, and the reasons for the differences. ...
... Your explanation should reference the relative strengths of interactions between molecules of I2 and the solvents H2O and C6H14, and the reasons for the differences. ...
Granta Design • CES Edupack 2009 • Durability - CORE
... The electrons accumulate on the iron giving it a negative charge that grows until the electrostatic attraction starts to pull the Fe++ ions back onto the metal surface, stifling further dissociation. At this point the iron has a potential (relative to a standard, the hydrogen standard) of −0.44 volt ...
... The electrons accumulate on the iron giving it a negative charge that grows until the electrostatic attraction starts to pull the Fe++ ions back onto the metal surface, stifling further dissociation. At this point the iron has a potential (relative to a standard, the hydrogen standard) of −0.44 volt ...
Organic Chemistry
... indole 3 (2 g, 17 mmol) and CH3CN (5 mL) was stirred at room temperature and solution of Br2 (1.3 mL, 51 mmol) in CH3CN (15 mL) was added over 5 min. The mixture was stirred overnight, and the resulting dark-green solid was filtered and washed with acetonitrile (250 mL). At this point, without furth ...
... indole 3 (2 g, 17 mmol) and CH3CN (5 mL) was stirred at room temperature and solution of Br2 (1.3 mL, 51 mmol) in CH3CN (15 mL) was added over 5 min. The mixture was stirred overnight, and the resulting dark-green solid was filtered and washed with acetonitrile (250 mL). At this point, without furth ...
Nutrient uptake by protocells: a liposome model system
... necessarily relied on simple transport mechanisms such as passive diffusion across bilayer membranes to take up nutrients and sources of chemical energy from the environment. At the same time, early membranes must have provided a selective permeability barrier that permitted permeation of monomers w ...
... necessarily relied on simple transport mechanisms such as passive diffusion across bilayer membranes to take up nutrients and sources of chemical energy from the environment. At the same time, early membranes must have provided a selective permeability barrier that permitted permeation of monomers w ...
Chem12 Buffer/Titration : Probs
... 28) Which one of the following equations contains the conjugate acidbase pair from which a buffer solution can be prepared ? a) HI(aq) + H2O(l) <-> H3O +(aq) + I-(aq) b) HBr(aq) + H2O(l) <-> H3O + (aq) + Br-(aq) c) H2SO 4(aq) + H2O(l) <-> H3O +(aq) + HSO4-(aq) d) H2CO3(aq) + H2O(l) <-> H3O+(aq) + HC ...
... 28) Which one of the following equations contains the conjugate acidbase pair from which a buffer solution can be prepared ? a) HI(aq) + H2O(l) <-> H3O +(aq) + I-(aq) b) HBr(aq) + H2O(l) <-> H3O + (aq) + Br-(aq) c) H2SO 4(aq) + H2O(l) <-> H3O +(aq) + HSO4-(aq) d) H2CO3(aq) + H2O(l) <-> H3O+(aq) + HC ...
chapter 15 acids and bases
... At this point, we can make an assumption that x is very small compared to 0.60. Hence, 0.60 − x ≈ 0.60 Oftentimes, assumptions such as these are valid if K is very small. A very small value of K means that a very small amount of reactants go to products. Hence, x is small. If we did not make this as ...
... At this point, we can make an assumption that x is very small compared to 0.60. Hence, 0.60 − x ≈ 0.60 Oftentimes, assumptions such as these are valid if K is very small. A very small value of K means that a very small amount of reactants go to products. Hence, x is small. If we did not make this as ...
Chapter 4
... It could also have been written as a complete ionic equation in which all soluble ionic compounds are split up into their ions, 2 Na+ (aq) + CO32- (aq) + Ba2+ (aq) + 2 NO3- (aq) → BaCO3 (s) + 2 Na+ (aq) + 2 NO3- (aq) Here, the Na+ and NO3- ions are called "spectator ions" because they appear unchan ...
... It could also have been written as a complete ionic equation in which all soluble ionic compounds are split up into their ions, 2 Na+ (aq) + CO32- (aq) + Ba2+ (aq) + 2 NO3- (aq) → BaCO3 (s) + 2 Na+ (aq) + 2 NO3- (aq) Here, the Na+ and NO3- ions are called "spectator ions" because they appear unchan ...
sample chapter
... Na⫹ and Cl⫺ ions are separated from each other. In solution, each Na⫹ ion is surrounded by a number of water molecules orienting their negative ends toward the cation. Similarly, each Cl⫺ ion is surrounded by water molecules with their positive ends oriented toward the anion (Figure 4.2). The proces ...
... Na⫹ and Cl⫺ ions are separated from each other. In solution, each Na⫹ ion is surrounded by a number of water molecules orienting their negative ends toward the cation. Similarly, each Cl⫺ ion is surrounded by water molecules with their positive ends oriented toward the anion (Figure 4.2). The proces ...
s-BLOCK ELEMENTS - einstein classes
... Ionic salt-like hydrides formed at high temperature by Ca, Sr and Ba. ...
... Ionic salt-like hydrides formed at high temperature by Ca, Sr and Ba. ...
Amount of substance
... Q32.On heating, magnesium reacts vigorously with element X to produce compound Y. An aqueous solution of Y, when treated with aqueous silver nitrate, gives a white precipitate that is readily soluble in dilute aqueous ammonia. What is the minimum mass of X that is needed to react completely with 4.0 ...
... Q32.On heating, magnesium reacts vigorously with element X to produce compound Y. An aqueous solution of Y, when treated with aqueous silver nitrate, gives a white precipitate that is readily soluble in dilute aqueous ammonia. What is the minimum mass of X that is needed to react completely with 4.0 ...
Liquid–liquid extraction
Liquid–liquid extraction (LLE) consists in transferring one (or more) solute(s) contained in a feed solution to another immiscible liquid (solvent). The solvent that is enriched in solute(s) is called extract. The feed solution that is depleted in solute(s) is called raffinate.Liquid–liquid extraction also known as solvent extraction and partitioning, is a method to separate compounds based on their relative solubilities in two different immiscible liquids, usually water and an organic solvent. It is an extraction of a substance from one liquid into another liquid phase. Liquid–liquid extraction is a basic technique in chemical laboratories, where it is performed using a variety of apparatus, from separatory funnels to countercurrent distribution equipment. This type of process is commonly performed after a chemical reaction as part of the work-up.The term partitioning is commonly used to refer to the underlying chemical and physical processes involved in liquid–liquid extraction, but on another reading may be fully synonymous with it. The term solvent extraction can also refer to the separation of a substance from a mixture by preferentially dissolving that substance in a suitable solvent. In that case, a soluble compound is separated from an insoluble compound or a complex matrix.Solvent extraction is used in nuclear reprocessing, ore processing, the production of fine organic compounds, the processing of perfumes, the production of vegetable oils and biodiesel, and other industries.Liquid–liquid extraction is possible in non-aqueous systems: In a system consisting of a molten metal in contact with molten salts, metals can be extracted from one phase to the other. This is related to a mercury electrode where a metal can be reduced, the metal will often then dissolve in the mercury to form an amalgam that modifies its electrochemistry greatly. For example, it is possible for sodium cations to be reduced at a mercury cathode to form sodium amalgam, while at an inert electrode (such as platinum) the sodium cations are not reduced. Instead, water is reduced to hydrogen. A detergent or fine solid can be used to stabilize an emulsion, or third phase.