A Quick Review of MTH070
... – Move all linear terms to one side and all other terms to the other side. – To move a term to the other side, change its sign. – Result: ex = f ...
... – Move all linear terms to one side and all other terms to the other side. – To move a term to the other side, change its sign. – Result: ex = f ...
1st Semester Exam Algebra 2 Page 1 1. Solve 2. Write the standard
... 32. Which of the following is equivalent to x 3 ? 22. Graph: y = | x + 3| 33. Factor: 27x3 – 8 23. Graph: y = (x – 4)2 + 3 34. Factor: 9x2 – 42x + 49: 24. Graph : f(x) = x3 – 5x2 + 4x = 0 ...
... 32. Which of the following is equivalent to x 3 ? 22. Graph: y = | x + 3| 33. Factor: 27x3 – 8 23. Graph: y = (x – 4)2 + 3 34. Factor: 9x2 – 42x + 49: 24. Graph : f(x) = x3 – 5x2 + 4x = 0 ...
Systems of Equations Study Guide
... Solve 4x – 5y = 23 3x + 10y = 31 2[4x – 5y = 23] 3x + 10y = 31 = 8x – 10y = 46 3x + 10y = 31 8x – 10y = 46 3x + 10y = 31 11x ...
... Solve 4x – 5y = 23 3x + 10y = 31 2[4x – 5y = 23] 3x + 10y = 31 = 8x – 10y = 46 3x + 10y = 31 8x – 10y = 46 3x + 10y = 31 11x ...
Unit 11 GHP
... In the process of solving you test 1, 2, 5, and 10 as possible zeros and determine that none of them are actual zeros. You then discover that -5/2 is a zero. You calculate the depressed polynomial to be Do you need to test 1, 2, 5, and 10 again? Why or why not? ...
... In the process of solving you test 1, 2, 5, and 10 as possible zeros and determine that none of them are actual zeros. You then discover that -5/2 is a zero. You calculate the depressed polynomial to be Do you need to test 1, 2, 5, and 10 again? Why or why not? ...
2.4 Classify and Determine Equation Solutions
... For each equation, determine if -2 is a solution. c = -2 24 = 2(c) + 29 8 = 2(c + 6) c+5 = 3 ...
... For each equation, determine if -2 is a solution. c = -2 24 = 2(c) + 29 8 = 2(c + 6) c+5 = 3 ...
