chemistry 103 - chem.uwec.edu
... containing 1.0 M CH3CO2H and 1.0 M NaCH3CO2. What is the pH of the buffer after the addition of 0.10 moles of gaseous HCl to 1.00 liter of the buffer solution? The Ka for acetic acid is 1.8 x 10-5. Because acetic acid is a weak acid, we can ignore the small amount of dissociation and assume at equil ...
... containing 1.0 M CH3CO2H and 1.0 M NaCH3CO2. What is the pH of the buffer after the addition of 0.10 moles of gaseous HCl to 1.00 liter of the buffer solution? The Ka for acetic acid is 1.8 x 10-5. Because acetic acid is a weak acid, we can ignore the small amount of dissociation and assume at equil ...
Gas Laws
... 5.00 L. If the final pressure of the gas is 585 torr, what is its final temperature in Celsius? 350. oC 10. A gas has a volume of 350. mL at 740. torr. How many milliliters will the gas occupy at 900. torr if the temperature remains constant? 288 mL 10. Calculate the number of liters occupied by the ...
... 5.00 L. If the final pressure of the gas is 585 torr, what is its final temperature in Celsius? 350. oC 10. A gas has a volume of 350. mL at 740. torr. How many milliliters will the gas occupy at 900. torr if the temperature remains constant? 288 mL 10. Calculate the number of liters occupied by the ...
Chemistry - NIC Karnataka
... Kp and Kc expressions for aA + bB Kp = Kc (RT) n --- (b) (to be assumed) , examples for relation between Kp and Kc for reactions, n = 0, n > 0, n < 0 --- (c). Numerical problems on (a), (b) and (c) and on KP, KC. (avoid quadratic equation). Homogeneous and heterogeneous equilibria- examples. App ...
... Kp and Kc expressions for aA + bB Kp = Kc (RT) n --- (b) (to be assumed) , examples for relation between Kp and Kc for reactions, n = 0, n > 0, n < 0 --- (c). Numerical problems on (a), (b) and (c) and on KP, KC. (avoid quadratic equation). Homogeneous and heterogeneous equilibria- examples. App ...
Entropy - Department of Mathematics
... 5. Describe Boltzmann’s distribution, then how it explains the distribution of speeds of molecules in a gas. ...
... 5. Describe Boltzmann’s distribution, then how it explains the distribution of speeds of molecules in a gas. ...
14.1 Dynamic Equilibrium, Keq , and the Mass Action Expression
... Extent of a Reaction Chemical Reaction Most reactions do not occur with 100% conversion to products. At the molecular, when a reaction occurs to form products, some products will back react to form reactants. The extent of the reaction i.e., 20% or 80% can be determine by measuring concentration of ...
... Extent of a Reaction Chemical Reaction Most reactions do not occur with 100% conversion to products. At the molecular, when a reaction occurs to form products, some products will back react to form reactants. The extent of the reaction i.e., 20% or 80% can be determine by measuring concentration of ...
PPT - Unit 5
... 2. Given the following data: -(C2H2(g) + 5/2O2(g) → 2CO2(g) + H2O(l) ΔH = -1300. kJ) 2( C(s) + O2(g) → CO2(g) ) 2(ΔH = -394 kJ) H2(g) + 1/2O2(g) → H2O(l) ΔH = -286 kJ Calculate ΔH for the following reaction: 2C(s) + H2(g) → C2H2(g) 2C(s) + 2O2(g) → 2CO2(g) ΔH = -788 kJ 2CO2(g) + H2O(l) → C2H2(g) + ...
... 2. Given the following data: -(C2H2(g) + 5/2O2(g) → 2CO2(g) + H2O(l) ΔH = -1300. kJ) 2( C(s) + O2(g) → CO2(g) ) 2(ΔH = -394 kJ) H2(g) + 1/2O2(g) → H2O(l) ΔH = -286 kJ Calculate ΔH for the following reaction: 2C(s) + H2(g) → C2H2(g) 2C(s) + 2O2(g) → 2CO2(g) ΔH = -788 kJ 2CO2(g) + H2O(l) → C2H2(g) + ...
Enzymes
... The active site places substrates in the correct orientation for the reaction. As the active site binds the substrate, it may put stress on bonds that must be broken, making it easier to reach the transition state. R groups at the active site may create a conducive ...
... The active site places substrates in the correct orientation for the reaction. As the active site binds the substrate, it may put stress on bonds that must be broken, making it easier to reach the transition state. R groups at the active site may create a conducive ...
Chemical Equations and Reactions
... 2. The relative masses of the reactants and products of a chemical reaction can be determined from the reaction’s coefficients. ...
... 2. The relative masses of the reactants and products of a chemical reaction can be determined from the reaction’s coefficients. ...
Solubility and Solubility Equilibrium
... First things first, you have to memorize the basic solubility rules in order to (1) know which salts dissociate (break apart) in solution and (2) which ions combine to form precipitates when you mix solutions. The other part of this is that if you are given the name of a compound, you have to know t ...
... First things first, you have to memorize the basic solubility rules in order to (1) know which salts dissociate (break apart) in solution and (2) which ions combine to form precipitates when you mix solutions. The other part of this is that if you are given the name of a compound, you have to know t ...
Chapter 8 - Clayton State University
... The First Law of Thermodynamics Also known as Law of Conservation of Energy The total amount of energy in the universe is constant. ...
... The First Law of Thermodynamics Also known as Law of Conservation of Energy The total amount of energy in the universe is constant. ...
Chapter 4: Properties of Gases
... 60.0 mL of O2 was collected over water at a total pressure of 755 torr and at a temperature of 25oC. The vapor pressure of water at 25oC is 24 torr. How many moles of O2 were collected? (a)2.44 x 10-3 mol (c)2.51 x 10-3 mol ...
... 60.0 mL of O2 was collected over water at a total pressure of 755 torr and at a temperature of 25oC. The vapor pressure of water at 25oC is 24 torr. How many moles of O2 were collected? (a)2.44 x 10-3 mol (c)2.51 x 10-3 mol ...
Chapter 19 CHEMICAL THERMODYNAMICS 19.1 SPONTANEOUS
... the number of possible microstates increases and so does the entropy. In water vapor, the molecules are essentially independent of one another and have their full range of translational, vibrational, and rotational motions. Thus, water vapor has an even greater number of possible microstates and the ...
... the number of possible microstates increases and so does the entropy. In water vapor, the molecules are essentially independent of one another and have their full range of translational, vibrational, and rotational motions. Thus, water vapor has an even greater number of possible microstates and the ...
Kinetic Study of the Reaction of Diborane with Phosphine*
... about one percent. This may reflect the presence of a small amount of gaseous addition compound, or the presence of a small amount of reactive impurity. In any case, the gaseous addition compound is present only to a slight extent, and it is this fact which will be used in relating the pressure meas ...
... about one percent. This may reflect the presence of a small amount of gaseous addition compound, or the presence of a small amount of reactive impurity. In any case, the gaseous addition compound is present only to a slight extent, and it is this fact which will be used in relating the pressure meas ...
Chemical equilibrium
In a chemical reaction, chemical equilibrium is the state in which both reactants and products are present in concentrations which have no further tendency to change with time. Usually, this state results when the forward reaction proceeds at the same rate as the reverse reaction. The reaction rates of the forward and backward reactions are generally not zero, but equal. Thus, there are no net changes in the concentrations of the reactant(s) and product(s). Such a state is known as dynamic equilibrium.