Study Guide MBMB 451A Fall 2002
... and IIH. What are TAFs and are they important for basal transcription. 7. What is an enhancer? What is a response element? 8. Describe two models for how an enhancer could effect the level of transcription. 9. What are the transcription factors called that are used by Pol I and Pol III? 10. Discuss ...
... and IIH. What are TAFs and are they important for basal transcription. 7. What is an enhancer? What is a response element? 8. Describe two models for how an enhancer could effect the level of transcription. 9. What are the transcription factors called that are used by Pol I and Pol III? 10. Discuss ...
Next generation sequencing
... a | Molecular-inversion probe (MIP) genotyping uses circularizable probes with 5' and 3' ends that anneal upstream and downstream of the SNP site leaving a 1 bp gap (genomic DNA is shown in blue). Polymerase extension with dNTPs and a non-strand-displacing polymerase is used to fill in the gap. Liga ...
... a | Molecular-inversion probe (MIP) genotyping uses circularizable probes with 5' and 3' ends that anneal upstream and downstream of the SNP site leaving a 1 bp gap (genomic DNA is shown in blue). Polymerase extension with dNTPs and a non-strand-displacing polymerase is used to fill in the gap. Liga ...
DNA, RNA and Protein
... produce a new chain •Each new DNA helix contains one “old” and one “new” chain ...
... produce a new chain •Each new DNA helix contains one “old” and one “new” chain ...
DNA, Chromosomes & Genes
... • There are 23 pairs of chromosomes in the nucleus of any one of your cells • Each chromosome is a single molecule of DNA (deoxyribonucleic acid) which carries the code for a couple of thousand genes ...
... • There are 23 pairs of chromosomes in the nucleus of any one of your cells • Each chromosome is a single molecule of DNA (deoxyribonucleic acid) which carries the code for a couple of thousand genes ...
DNA Fingerprinting and Its Application in Paternity Testing
... Present only in males, inherited from the father as it is to his sons. * Ideogram of the Y-chromosome showing the locations of pseudoautosomal regions (PAR), the testis determining gene, SRYand the long arm heterochromatin (Hurles and ...
... Present only in males, inherited from the father as it is to his sons. * Ideogram of the Y-chromosome showing the locations of pseudoautosomal regions (PAR), the testis determining gene, SRYand the long arm heterochromatin (Hurles and ...
DNA, Chromosomes & Genes - Science
... • There are 23 pairs of chromosomes in the nucleus of any one of your cells • Each chromosome has a single strand of DNA (deoxyribonucleic acid) which carries the code for a couple of thousand genes ...
... • There are 23 pairs of chromosomes in the nucleus of any one of your cells • Each chromosome has a single strand of DNA (deoxyribonucleic acid) which carries the code for a couple of thousand genes ...
Chapter 13: The Molecular Basis of Inheritance
... DNA is the genetic material that is transmitted from one generation to the next and encodes the blueprints that direct the control of biochemical, anatomical, physiological, and behavioral traits of an organism. A strand of DNA is made up of nucleotide monomers, which consist of a pentose (five carb ...
... DNA is the genetic material that is transmitted from one generation to the next and encodes the blueprints that direct the control of biochemical, anatomical, physiological, and behavioral traits of an organism. A strand of DNA is made up of nucleotide monomers, which consist of a pentose (five carb ...
Chap 3
... Brief history of DNA discovery • Erwin Chargaff (Columbia University) – “The Separation and Quantitative Estimation of Purines and Pyrimidines in Minute Amounts”, J. Biol. Chem.(1948) found that the number of A nucleotides in a sequence of DNA equals the number of T nucleotides; similarly, # of C = ...
... Brief history of DNA discovery • Erwin Chargaff (Columbia University) – “The Separation and Quantitative Estimation of Purines and Pyrimidines in Minute Amounts”, J. Biol. Chem.(1948) found that the number of A nucleotides in a sequence of DNA equals the number of T nucleotides; similarly, # of C = ...
coding and non-coding functions of the genome
... All of these marks are different for each cell type. This is why it is so important to understand how they work. For example, it’s not possible to generate pluripotent cells (which can turn into many other types of cells) from mature, stable cells, like those in the skin. These are called iPS cells ...
... All of these marks are different for each cell type. This is why it is so important to understand how they work. For example, it’s not possible to generate pluripotent cells (which can turn into many other types of cells) from mature, stable cells, like those in the skin. These are called iPS cells ...
starter - Dunlap CUSD #323
... - includes transgenic organisms - does not include hybrids - include micro-organisms such as bacteria, yeast, insects, plants, fish, and mammals ...
... - includes transgenic organisms - does not include hybrids - include micro-organisms such as bacteria, yeast, insects, plants, fish, and mammals ...
RC 2 Student Notes
... Complementary bases: C pairs with G A pairs with U Use mRNA on the codon chart to determine amino acid sequence of protein chain ...
... Complementary bases: C pairs with G A pairs with U Use mRNA on the codon chart to determine amino acid sequence of protein chain ...
Polymerase Chain Reaction
... Basic techniques used in molecular biology • PCR • Blotting techniques • DNA sequencing • DNA fingerprinting • RFLP ...
... Basic techniques used in molecular biology • PCR • Blotting techniques • DNA sequencing • DNA fingerprinting • RFLP ...
Slide ()
... complementary to adenine of DNA; cytosine is complementary to guanine and vice versa. “Stop” = peptide chain termination. The three-letter and singleletter abbreviations for the amino acids are as follows: Ala (A) = alanine; Arg (R) = arginine; Asn (N) = asparagine; Asp (D) = aspartic acid; Cys (C) ...
... complementary to adenine of DNA; cytosine is complementary to guanine and vice versa. “Stop” = peptide chain termination. The three-letter and singleletter abbreviations for the amino acids are as follows: Ala (A) = alanine; Arg (R) = arginine; Asn (N) = asparagine; Asp (D) = aspartic acid; Cys (C) ...
Chromosomal Structure HWK
... (b) A telomere is a long sequence of repetitive, noncoding DNA that is found at the end of chromosomes, while a centromere is a constricted region of a chromosome that holds two replicated chromosome strands together (c) A LINE is a DNA sequence of 5000 to 7000 nucleotides that are repetitive and al ...
... (b) A telomere is a long sequence of repetitive, noncoding DNA that is found at the end of chromosomes, while a centromere is a constricted region of a chromosome that holds two replicated chromosome strands together (c) A LINE is a DNA sequence of 5000 to 7000 nucleotides that are repetitive and al ...
Genetic Engineering
... Transformed cell- cell with new DNA Marker gene- a gene that identifies which organisms have been successfully transformed ...
... Transformed cell- cell with new DNA Marker gene- a gene that identifies which organisms have been successfully transformed ...
Voices - Indiana University Bloomington
... If the recent experience of nuclear biology is any guide, the answer is: better than we might have guessed. New proximity ligation methods based on the nuclear ligation assay and its intellectual descendants have made DNA sequencers the platform of choice for rapidly estimating the physical distance ...
... If the recent experience of nuclear biology is any guide, the answer is: better than we might have guessed. New proximity ligation methods based on the nuclear ligation assay and its intellectual descendants have made DNA sequencers the platform of choice for rapidly estimating the physical distance ...
Ch. 11
... 11.3 Genetic Changes A. Mutation: A Change in DNA a. ________________ _ – any change or random error in a DNA sequence 1. ______________________________________ – changes in the nucleotide sequence of an organism’s gametes could affect the genotype of the offspring. 2. _____________________________ ...
... 11.3 Genetic Changes A. Mutation: A Change in DNA a. ________________ _ – any change or random error in a DNA sequence 1. ______________________________________ – changes in the nucleotide sequence of an organism’s gametes could affect the genotype of the offspring. 2. _____________________________ ...
Name: page1 of 7 pages MOLECULAR BIOLOGY BIO372S January
... 7. A new insulin gene was isolated and a study was planned to look at the function of the promoter region. Which of the following would be the best choice for this study? A. southern analysis B. immunoblotting C. reporter gene assay D. PCR E. immunoprecipitation 8. A DNA fragment was treated with Ec ...
... 7. A new insulin gene was isolated and a study was planned to look at the function of the promoter region. Which of the following would be the best choice for this study? A. southern analysis B. immunoblotting C. reporter gene assay D. PCR E. immunoprecipitation 8. A DNA fragment was treated with Ec ...
Title: Ready, Set, Clone! Authors: Kowalski, Kathiann M. Source
... DNA polymerase acts as a catalyst to make DNA copy itself. When DNA replicates, it first unwinds into separate strands. Then individual nucleotides in the DNA pair up with their partners. Adenine (A) always pairs with thymine (T), and cytosine (C) always pairs with guanine (G). The result is two ide ...
... DNA polymerase acts as a catalyst to make DNA copy itself. When DNA replicates, it first unwinds into separate strands. Then individual nucleotides in the DNA pair up with their partners. Adenine (A) always pairs with thymine (T), and cytosine (C) always pairs with guanine (G). The result is two ide ...
Bisulfite sequencing
Bisulphite sequencing (also known as bisulfite sequencing) is the use of bisulphite treatment of DNA to determine its pattern of methylation. DNA methylation was the first discovered epigenetic mark, and remains the most studied. In animals it predominantly involves the addition of a methyl group to the carbon-5 position of cytosine residues of the dinucleotide CpG, and is implicated in repression of transcriptional activity.Treatment of DNA with bisulphite converts cytosine residues to uracil, but leaves 5-methylcytosine residues unaffected. Thus, bisulphite treatment introduces specific changes in the DNA sequence that depend on the methylation status of individual cytosine residues, yielding single- nucleotide resolution information about the methylation status of a segment of DNA. Various analyses can be performed on the altered sequence to retrieve this information. The objective of this analysis is therefore reduced to differentiating between single nucleotide polymorphisms (cytosines and thymidine) resulting from bisulphite conversion (Figure 1).