Week 6
... move in elliptical orbits with the sun at one focus. Why is the sun at one focus of the orbit? Because... A. Otherwise the planets wouldn’t all be in the same orbital plane. B. In two-body central-force motion one mass is always at the focus on the orbit. C. In two-body central-force motion the cent ...
... move in elliptical orbits with the sun at one focus. Why is the sun at one focus of the orbit? Because... A. Otherwise the planets wouldn’t all be in the same orbital plane. B. In two-body central-force motion one mass is always at the focus on the orbit. C. In two-body central-force motion the cent ...
laws of motion - WordPress.com
... Exercise: Law of acceleration 1. The combined mass of a stretcher & a patient is 100 kg. If the force applied in pushing the stretcher carrying the patient is 300 N then what is the acceleration of the stretcher? 2. The acceleration of a stretcher towards the emergency room is 1.2 m/s2. Find the fo ...
... Exercise: Law of acceleration 1. The combined mass of a stretcher & a patient is 100 kg. If the force applied in pushing the stretcher carrying the patient is 300 N then what is the acceleration of the stretcher? 2. The acceleration of a stretcher towards the emergency room is 1.2 m/s2. Find the fo ...
IB Mechanics objectives
... Calculate and interpret the gradients of displacement–time graphs and velocity–time graphs, and the areas under velocity–time graphs and acceleration–time graphs. Determine relative velocity in one and in two dimensions. ...
... Calculate and interpret the gradients of displacement–time graphs and velocity–time graphs, and the areas under velocity–time graphs and acceleration–time graphs. Determine relative velocity in one and in two dimensions. ...
Newton Review
... Use Chapters 1 & 2 in your book to help you find the answers to the questions below. 1. Write Newton’s first law. Law of Inertia: objects remain in motion, or at rest, until a force acts upon them. 2. Give an example of Newton’s first law using a tiny pebble and a boulder in your example. The tiny p ...
... Use Chapters 1 & 2 in your book to help you find the answers to the questions below. 1. Write Newton’s first law. Law of Inertia: objects remain in motion, or at rest, until a force acts upon them. 2. Give an example of Newton’s first law using a tiny pebble and a boulder in your example. The tiny p ...
Multiple Choice
... 1988M3 The two uniform disks shown above have equal mass, and each can rotate on frictionless bearings about a fixed axis through its center. The smaller disk has a radius R and moment of inertia I about its axis. The larger disk has a radius 2R a. Determine the moment of inertia of the larger disk ...
... 1988M3 The two uniform disks shown above have equal mass, and each can rotate on frictionless bearings about a fixed axis through its center. The smaller disk has a radius R and moment of inertia I about its axis. The larger disk has a radius 2R a. Determine the moment of inertia of the larger disk ...
A P COURSE AUDIT
... logarithmic? How will you find out? By trial and error method, derive the formula for T and see that T2 vs. m is a straight line. Read both intercepts and interpret them. Can you predict the mass of the spring? 10. Find the velocity of the projectile by two methods. Newton’s 2 nd law and projectile ...
... logarithmic? How will you find out? By trial and error method, derive the formula for T and see that T2 vs. m is a straight line. Read both intercepts and interpret them. Can you predict the mass of the spring? 10. Find the velocity of the projectile by two methods. Newton’s 2 nd law and projectile ...
Class14
... a , F and v are constantly changing •However, the magnitudes a, F, v and r are constants of the motion. •The frame in which the mass is moving is not inertial, i.e. it is accelerating. ...
... a , F and v are constantly changing •However, the magnitudes a, F, v and r are constants of the motion. •The frame in which the mass is moving is not inertial, i.e. it is accelerating. ...
lecture ch7-8-Circles
... • A person bending forward to lift a load “with his back” rather than “with his knees” can be injured by large forces exerted on the muscles and vertebrae. The spine pivots mainly at the fifth lumbar vertebra, with the principal supporting force provided by the erector spinalis muscle in the back. C ...
... • A person bending forward to lift a load “with his back” rather than “with his knees” can be injured by large forces exerted on the muscles and vertebrae. The spine pivots mainly at the fifth lumbar vertebra, with the principal supporting force provided by the erector spinalis muscle in the back. C ...
Lecture9 (Motion)
... • A body is in Equilibrium if it moves with constant velocity. A body at rest is a special case of constant velocity i.e. v = 0 = constant. • For a body to be in Equilibrium the resultant force (meaning the vector addition of all the forces) acting on the body must be zero. • Resulting force = vecto ...
... • A body is in Equilibrium if it moves with constant velocity. A body at rest is a special case of constant velocity i.e. v = 0 = constant. • For a body to be in Equilibrium the resultant force (meaning the vector addition of all the forces) acting on the body must be zero. • Resulting force = vecto ...
List of Topics for the Final Exam
... F = ma, a = Fnet/m Force directly related to acceleration, acceleration inversely related to mass no acceleration means no net force and vice versa (it does not mean no force at all, just that the forces balance; also, it does not mean no velocity, just no CHANGE in velocity) friction, pressure (for ...
... F = ma, a = Fnet/m Force directly related to acceleration, acceleration inversely related to mass no acceleration means no net force and vice versa (it does not mean no force at all, just that the forces balance; also, it does not mean no velocity, just no CHANGE in velocity) friction, pressure (for ...
Circular Motion
... whirled in a horizontal circle of radius 2 m. If the body makes three complete revolutions every second, determine its period and linear speed m = 2 kg r=2m f = 3 rev/s ...
... whirled in a horizontal circle of radius 2 m. If the body makes three complete revolutions every second, determine its period and linear speed m = 2 kg r=2m f = 3 rev/s ...
Newton*s 1st Law * Objectives:
... If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. ...
... If two individual forces are of equal magnitude and opposite direction, then the forces are said to be balanced. ...
Ch. 9 Rotational Kinematics
... MOI is a property of physics that indicates the relative difference in how easy or difficult it will be to set any object in motion about a defined axis of rotation. MOI is always measured relative to a point of reference. MOI depends on an object’s mass and on its shape. MOI depends on the d ...
... MOI is a property of physics that indicates the relative difference in how easy or difficult it will be to set any object in motion about a defined axis of rotation. MOI is always measured relative to a point of reference. MOI depends on an object’s mass and on its shape. MOI depends on the d ...
Concept Questions
... Object A sits at the outer edge (rim) of a merry-go-round, and object B sits halfway between the rim and the axis of rotation. The merry-go-round makes a complete revolution once every thirty seconds. The magnitude of the angular velocity of Object B is ...
... Object A sits at the outer edge (rim) of a merry-go-round, and object B sits halfway between the rim and the axis of rotation. The merry-go-round makes a complete revolution once every thirty seconds. The magnitude of the angular velocity of Object B is ...
Torque, Atwood Machines, Angular M.
... Angular Momentum is also conserved Here is what this says: IF THE NET TORQUE is equal to ZERO the CHANGE ANGULAR MOMENTUM is equal to ZERO and thus the ANGULAR MOMENTUM is CONSERVED. Here is a common example. An ice skater begins a spin with his arms out. His angular velocity at the beginning of th ...
... Angular Momentum is also conserved Here is what this says: IF THE NET TORQUE is equal to ZERO the CHANGE ANGULAR MOMENTUM is equal to ZERO and thus the ANGULAR MOMENTUM is CONSERVED. Here is a common example. An ice skater begins a spin with his arms out. His angular velocity at the beginning of th ...