Text S1.
... For parameterization of metal centers, to avoid any bias the initial structure was taken from the PDB entry 2OQ75 (2.13 Å) which is not one of our initial structures of MD simulations. In the PDB file Ni(II) ion was replaced by a Fe(II) ion whereas the cofactor NOG was kept. Normally at physiologica ...
... For parameterization of metal centers, to avoid any bias the initial structure was taken from the PDB entry 2OQ75 (2.13 Å) which is not one of our initial structures of MD simulations. In the PDB file Ni(II) ion was replaced by a Fe(II) ion whereas the cofactor NOG was kept. Normally at physiologica ...
A Diels-Alder Synthesis
... The Diels-Alder reaction usually proceeds with endo selectivity. This means that the product in which the activating electron-withdrawing group of the dienophile is located in the endo position is formed faster than the alternative exo isomer. This happens even though the exo product is sometimes mo ...
... The Diels-Alder reaction usually proceeds with endo selectivity. This means that the product in which the activating electron-withdrawing group of the dienophile is located in the endo position is formed faster than the alternative exo isomer. This happens even though the exo product is sometimes mo ...
• Life`s diversity results from the variety of molecules in cells • A
... Spider Silk: Stronger than Steel • Life’s diversity results from the variety of molecules in cells • A spider’s web-building skill depends on its DNA molecules • DNA also determines the structure of silk proteins – These make a spider web strong and resilient ...
... Spider Silk: Stronger than Steel • Life’s diversity results from the variety of molecules in cells • A spider’s web-building skill depends on its DNA molecules • DNA also determines the structure of silk proteins – These make a spider web strong and resilient ...
4 Reactions Alcohol Thiols GOB Structures
... The dehydration of a secondary alcohol can result in the formation of a minor product and a major product. Saytzeff’s rule states that • the major product is the one that forms by removing the hydrogen from the carbon atom that has the smaller number of hydrogen atoms. • hydrogen atoms are easier to ...
... The dehydration of a secondary alcohol can result in the formation of a minor product and a major product. Saytzeff’s rule states that • the major product is the one that forms by removing the hydrogen from the carbon atom that has the smaller number of hydrogen atoms. • hydrogen atoms are easier to ...
Chemical Reactions and Equations
... Starting with elements that only occur in one substance on each side of the equation, make sure that each side of the equation has an equal # of that element. Proceed with all elements. Remember that changing the # of one element may alter elements that have already been ...
... Starting with elements that only occur in one substance on each side of the equation, make sure that each side of the equation has an equal # of that element. Proceed with all elements. Remember that changing the # of one element may alter elements that have already been ...
handout alkenes from alcohols
... Elimination reactions. In this experiment, cyclohexanol will be dehydrated (loss of H2O) to form cyclohexene under acidic conditions (see Figure 1). OH ...
... Elimination reactions. In this experiment, cyclohexanol will be dehydrated (loss of H2O) to form cyclohexene under acidic conditions (see Figure 1). OH ...
CHAPTER 1 -Chemistry -Matter -Elements -Atoms
... 2) A solid white substance A is heated strongly in the absence of air. It decomposes to form a new white substance B and a gas C. The gas has exactly the same properties as the product obtained when carbon is burned in an excess of oxygen. Based on these observations, can you determine whether A and ...
... 2) A solid white substance A is heated strongly in the absence of air. It decomposes to form a new white substance B and a gas C. The gas has exactly the same properties as the product obtained when carbon is burned in an excess of oxygen. Based on these observations, can you determine whether A and ...
Unit 9 – Behavior of Gases
... 1. Which subatomic particle plays the largest role in determining the physical and chemical properties of an element? Explain. 2. Describe Bohr’s model of the atom. 3. Write the full electron configuration for the following: a. potassium atom b. sulfur atom c. Chlorine ion d. Calcium ion 4. Create a ...
... 1. Which subatomic particle plays the largest role in determining the physical and chemical properties of an element? Explain. 2. Describe Bohr’s model of the atom. 3. Write the full electron configuration for the following: a. potassium atom b. sulfur atom c. Chlorine ion d. Calcium ion 4. Create a ...
Chapter 16 Handout
... reactions have not ceased. They occur simultaneously at the same rate. During dynamic equilibrium: –The ____________________. and concentrations of chemical substances remain constant. –The total gas ____________________. is constant (if gases are involved) –The ____________________. us constant –Th ...
... reactions have not ceased. They occur simultaneously at the same rate. During dynamic equilibrium: –The ____________________. and concentrations of chemical substances remain constant. –The total gas ____________________. is constant (if gases are involved) –The ____________________. us constant –Th ...
Section 7.5~7.6 - www .alexandria .k12 .mn .us
... 1) Why is it important to understand the acid-base behavior of organic molecules? 2) What are the differences in behavior between Lewis acids and Bronsted-Lowry acids? 2.5) In equation 3.53, is the amide ion ( NH2- ) functioning as an acid or a base? 3) How would you explain the concept of pKa to th ...
... 1) Why is it important to understand the acid-base behavior of organic molecules? 2) What are the differences in behavior between Lewis acids and Bronsted-Lowry acids? 2.5) In equation 3.53, is the amide ion ( NH2- ) functioning as an acid or a base? 3) How would you explain the concept of pKa to th ...
File
... Ammonia can be oxidized by oxygen to produce nitrogen dioxide according to the equation: 4NH3(g) + 7O2(g) 4NO2(g) + 6H2O(g) If, in this reaction, water is formed at a rate of 36 mol L-1 min-1, a. at what rate is the ammonia used? c. at what rate is the nitrogen dioxide b. at what rate is the oxyge ...
... Ammonia can be oxidized by oxygen to produce nitrogen dioxide according to the equation: 4NH3(g) + 7O2(g) 4NO2(g) + 6H2O(g) If, in this reaction, water is formed at a rate of 36 mol L-1 min-1, a. at what rate is the ammonia used? c. at what rate is the nitrogen dioxide b. at what rate is the oxyge ...
DEPARTMENT OF CHEMISTRY
... CY60002 Adsorption and Catalysis (3-0-0 : 3 Credits) Prerequisite : CY41002 Adsorption Equilibrium. Green technology. Phase transfer and reverse phase transfer catalysis, general principles, physical, dynamic and thermodynamic principles, applications, homogeneous catalysis, energetics, homogeneous ...
... CY60002 Adsorption and Catalysis (3-0-0 : 3 Credits) Prerequisite : CY41002 Adsorption Equilibrium. Green technology. Phase transfer and reverse phase transfer catalysis, general principles, physical, dynamic and thermodynamic principles, applications, homogeneous catalysis, energetics, homogeneous ...
Stoichiometry
... Regular reactions: atoms and masses balance Redox reactions: atoms, masses, and charges balance Here there will be change in the oxidation state of ions during the reaction. One element will be oxidized; that means that it will lose electrons and become more positive. One element will be r ...
... Regular reactions: atoms and masses balance Redox reactions: atoms, masses, and charges balance Here there will be change in the oxidation state of ions during the reaction. One element will be oxidized; that means that it will lose electrons and become more positive. One element will be r ...
Elementary my dear Watson review
... For example, carbon dioxide (CO2) is made up of 1 atom of carbon and two atoms of oxygen. ...
... For example, carbon dioxide (CO2) is made up of 1 atom of carbon and two atoms of oxygen. ...
Chemistry of Life – Chapter 8 ANSWERS Directions: Answer all the
... Directions: Answer all the questions in your notebook. Do not write on this sheet. You will need to use the book to help answer some of the questions. Reduce, reuse, recycle – Especially carbon and carbon based organic molecules. ...
... Directions: Answer all the questions in your notebook. Do not write on this sheet. You will need to use the book to help answer some of the questions. Reduce, reuse, recycle – Especially carbon and carbon based organic molecules. ...