Review 1
... 32) If 2 molecules of the general type shown in Figure 5.1 were linked together, carbon 1 of one molecule to carbon 4 of the other, the single molecule that would result would be A) glucose. B) maltose. C) fructose. D) galactose. E) sucrose. ...
... 32) If 2 molecules of the general type shown in Figure 5.1 were linked together, carbon 1 of one molecule to carbon 4 of the other, the single molecule that would result would be A) glucose. B) maltose. C) fructose. D) galactose. E) sucrose. ...
DEPARTMENT OF CHEMISTRY Subject information (overview of syllabus)
... Chemical thermodynamics – first, second and third laws. Changes of phase diagrams. Electrochemical, conductivity, transport numbers, electrolysis. Reaction kinetics orders, Arrhenius equation, composite mechanisms, catalysis. Quantum chemistry, atomic spectra, emission and absorption spectra, rotati ...
... Chemical thermodynamics – first, second and third laws. Changes of phase diagrams. Electrochemical, conductivity, transport numbers, electrolysis. Reaction kinetics orders, Arrhenius equation, composite mechanisms, catalysis. Quantum chemistry, atomic spectra, emission and absorption spectra, rotati ...
History and Current Status of the Plastics Industry
... • Groups 3B- are referred to as the transition metal groups. – These metals are not as predictable because of the shielding effect of the inner electrons. As for the "shielding effect" this refers to the inner electrons found in the transition state elements and the inner transition (rare earth)elem ...
... • Groups 3B- are referred to as the transition metal groups. – These metals are not as predictable because of the shielding effect of the inner electrons. As for the "shielding effect" this refers to the inner electrons found in the transition state elements and the inner transition (rare earth)elem ...
Chem 480A
... an increase in temperature favors reactants. This is easy to see because for an increase in temperature the temperature part is negative so that a positive H o causes the original equilibrium constant to be multiplied by a number larger than 1. Example 1 First, let's find the equilibrium constant ...
... an increase in temperature favors reactants. This is easy to see because for an increase in temperature the temperature part is negative so that a positive H o causes the original equilibrium constant to be multiplied by a number larger than 1. Example 1 First, let's find the equilibrium constant ...
Reactions to functionalize benzene
... Reactions that transform substituents: Reactions (1) – (5) can be starting points for obtaining other substituents by transforming the product to another group 6) Grignard reactions with aryl halides: can prepare alcohols, benzoic acid ...
... Reactions that transform substituents: Reactions (1) – (5) can be starting points for obtaining other substituents by transforming the product to another group 6) Grignard reactions with aryl halides: can prepare alcohols, benzoic acid ...
Topic 7: Manipulating Molecules and Designing Drugs
... FUNCTIONAL GROUPS ............................................................................................................................... 13 ...
... FUNCTIONAL GROUPS ............................................................................................................................... 13 ...
LEWIS DOT STRUCTURES , MOLECULAR SHAPES, AND
... 5. Add connect the atoms by adding electron pair bonds. 6. Add unshared electron pairs around the remaining atoms so that everything is satisfied with an octet (note some atoms like hydrogen are satisfied when they have 2 valence electrons). 7. Count to make sure that the number of electrons used eq ...
... 5. Add connect the atoms by adding electron pair bonds. 6. Add unshared electron pairs around the remaining atoms so that everything is satisfied with an octet (note some atoms like hydrogen are satisfied when they have 2 valence electrons). 7. Count to make sure that the number of electrons used eq ...
Chapter 3 – part I Sections 1-3
... • What is oxidized and reduced are always reactants, the products are the result of the redox. • So if asked “what is ox or red?”, answer is reactant ...
... • What is oxidized and reduced are always reactants, the products are the result of the redox. • So if asked “what is ox or red?”, answer is reactant ...
Ch. 3 Sections 3.9-3.10 Notes
... Al (s) + Fe2O3 (s) → Al2O3 (s) + Fe (l) A certain welding operation, used over and over, requires that each time at least 86.0 g of Fe be produced. What is the minimum mass in grams of Fe2O3 that must be used for each operation? Calculate also how many grams of aluminum are needed. ...
... Al (s) + Fe2O3 (s) → Al2O3 (s) + Fe (l) A certain welding operation, used over and over, requires that each time at least 86.0 g of Fe be produced. What is the minimum mass in grams of Fe2O3 that must be used for each operation? Calculate also how many grams of aluminum are needed. ...
EXPERIMENT 3: Preparation and Reactivity of Alkyl Halides
... Although one might expect such a reaction to be reversible, it can be driven to formation of R-I by using anhydrous acetone as the solvent. Sodium iodide (NaI) is soluble in this solvent, but sodium chloride and sodium bromide are not. If a reaction occurs, a precipitate of sodium chloride or sodium ...
... Although one might expect such a reaction to be reversible, it can be driven to formation of R-I by using anhydrous acetone as the solvent. Sodium iodide (NaI) is soluble in this solvent, but sodium chloride and sodium bromide are not. If a reaction occurs, a precipitate of sodium chloride or sodium ...
Chapter 8 Thermochemistry: Chemical Energy
... When 25.0 mL of 1.0 M H2SO4 is added to 50.0 mL of 1.0 M NaOH at 25.0°C in a calorimeter, the temperature of the solution increases to 33.9°C. Assume specific heat of solution is 4.184 J/(g–1·°C–1), and the density is 1.00 g/mL–1, calculate ΔH for the ...
... When 25.0 mL of 1.0 M H2SO4 is added to 50.0 mL of 1.0 M NaOH at 25.0°C in a calorimeter, the temperature of the solution increases to 33.9°C. Assume specific heat of solution is 4.184 J/(g–1·°C–1), and the density is 1.00 g/mL–1, calculate ΔH for the ...
Name - cloudfront.net
... If a reaction has an equilibrium constant (Keq) just greater than 1, how do we interpret that information? A catalyst works by ____. If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction? What is the effect of adding more water to the following equilibrium react ...
... If a reaction has an equilibrium constant (Keq) just greater than 1, how do we interpret that information? A catalyst works by ____. If sulfur dioxide and oxygen can be made into sulfur trioxide, what is the reverse reaction? What is the effect of adding more water to the following equilibrium react ...
Chemical Properties of Organic Compounds
... The chemistry of carbon compounds is a special field because carbon has the unique property of uniting with other carbon atoms through strong covalent bonds to form long chains and rings. Compounds containing C, H and O give rise to a large section of organic chemistry. This experiment provides an i ...
... The chemistry of carbon compounds is a special field because carbon has the unique property of uniting with other carbon atoms through strong covalent bonds to form long chains and rings. Compounds containing C, H and O give rise to a large section of organic chemistry. This experiment provides an i ...
word-doc Practice for the final exam!
... A compound contains 40.0% C, 6.71% H, and 53.29% O by mass. The molecular mass of the compound is 60.05 amu. The molecular formula of this compound is __________. a. C2H4O2 b. CH2O c. C2H3O4 d. C2H2O4 e. CHO2 ...
... A compound contains 40.0% C, 6.71% H, and 53.29% O by mass. The molecular mass of the compound is 60.05 amu. The molecular formula of this compound is __________. a. C2H4O2 b. CH2O c. C2H3O4 d. C2H2O4 e. CHO2 ...