Angles, Degrees, and Special Triangles
... Writing an Equation in Standard Form Ex 4: Write the linear equation of the line in standard form: a) Through (-4, -8) with a slope of -¼ b) Through (2, 0) with a slope of 1 ...
... Writing an Equation in Standard Form Ex 4: Write the linear equation of the line in standard form: a) Through (-4, -8) with a slope of -¼ b) Through (2, 0) with a slope of 1 ...
Chapter 4 – Reactions in Aqueous Solutions
... – To obtain the overall equation, we add the two balanced half-equations, but make sure the number of electrons on both half-equations are equal, so that they cancel out. The overall equation should not contain any electrons. In this case, we multiply the above oxidation half-equation by 5 and obtai ...
... – To obtain the overall equation, we add the two balanced half-equations, but make sure the number of electrons on both half-equations are equal, so that they cancel out. The overall equation should not contain any electrons. In this case, we multiply the above oxidation half-equation by 5 and obtai ...
Step 1
... Solving a system of equations by graphing. Let's summarize! There are 3 steps to solving a system using a graph. Step 1: Graph both equations. ...
... Solving a system of equations by graphing. Let's summarize! There are 3 steps to solving a system using a graph. Step 1: Graph both equations. ...
Skills Packet
... 1. Put each inequality into slope-intercept form and graph the boundary line for each inequality. 2. Use a dashed line for <,> and a solid line for ≤, ≥. 3. Shade the region that is true for each ...
... 1. Put each inequality into slope-intercept form and graph the boundary line for each inequality. 2. Use a dashed line for <,> and a solid line for ≤, ≥. 3. Shade the region that is true for each ...
Scientific Measurement
... How much heat is needed to melt 20 g of ice at 0˚C? q = mHf q = 20(334) = 6,680 J (Hf on Table B, don’t plug in temp.) How many grams of water can be heated by 15˚C using 13,500 J of heat? q = mC∆T 13,500 = m(4.18)(15) = 215 g It takes 5,210 J of heat to melt 50 g of ethanol at its melting point. Wh ...
... How much heat is needed to melt 20 g of ice at 0˚C? q = mHf q = 20(334) = 6,680 J (Hf on Table B, don’t plug in temp.) How many grams of water can be heated by 15˚C using 13,500 J of heat? q = mC∆T 13,500 = m(4.18)(15) = 215 g It takes 5,210 J of heat to melt 50 g of ethanol at its melting point. Wh ...
link to the powerpoint file which contained the jeopardy
... question, its instructor’s choice) Your answer must be in the form of a question The person from your group answering the question will be chosen at random If you answer correctly, you get the points If you answer incorrectly, you do not lose points. Other groups can answer, but your group c ...
... question, its instructor’s choice) Your answer must be in the form of a question The person from your group answering the question will be chosen at random If you answer correctly, you get the points If you answer incorrectly, you do not lose points. Other groups can answer, but your group c ...
Notes_Solutions - Anderson High School
... Properties—high specific heat, high heat of vaporization, high cohesive and adhesive forces all of these properties contribute to life on this planet! H2O—the two O—H bonds are polar covalent [oxygen has a higher electronegativity and thus the electrons are more attracted to the oxygen and spe ...
... Properties—high specific heat, high heat of vaporization, high cohesive and adhesive forces all of these properties contribute to life on this planet! H2O—the two O—H bonds are polar covalent [oxygen has a higher electronegativity and thus the electrons are more attracted to the oxygen and spe ...
+ H 2 O
... • HCl(aq) + NaOH(aq) H2O(l) + NaCl(aq) H2SO4(aq) + 2KOH (aq) K2SO4(aq) + 2H2O(l) Notice salt (NaCl) and water are the products Salt = ionic compound whose cation comes from a base and anion from an acid. Neutralization between acid and metal hydroxide produces water and a salt. ...
... • HCl(aq) + NaOH(aq) H2O(l) + NaCl(aq) H2SO4(aq) + 2KOH (aq) K2SO4(aq) + 2H2O(l) Notice salt (NaCl) and water are the products Salt = ionic compound whose cation comes from a base and anion from an acid. Neutralization between acid and metal hydroxide produces water and a salt. ...
Chapter 4
... Water breaks the + and - charged pieces apart and surrounds them. Solubility in water depends on the relative attractions of ions for each other and attraction of ions for water molecules In some ionic compounds, the attraction between ions is greater than the attraction exerted by water (slig ...
... Water breaks the + and - charged pieces apart and surrounds them. Solubility in water depends on the relative attractions of ions for each other and attraction of ions for water molecules In some ionic compounds, the attraction between ions is greater than the attraction exerted by water (slig ...
Document
... • Chemists have set up the periodic table such that the masses on the periodic table correspond to the mass of one mole of atoms in ...
... • Chemists have set up the periodic table such that the masses on the periodic table correspond to the mass of one mole of atoms in ...
Chapter 5 Notes
... 4. Check your solution. 5. Write the solution as an ordered pair (x,y). Ex #1: Solve using substitution method 3x-y=13 2x+2y= -10 1. Solve the 1st eqn for y. 3x-y=13 -y= -3x+13 y=3x-13 2. Now substitute 3x-13 in for the y in the 2nd equation. 2x+2(3x-13)= -10 Now, solve for x. 2x+6x-26= -10 8x=16 x= ...
... 4. Check your solution. 5. Write the solution as an ordered pair (x,y). Ex #1: Solve using substitution method 3x-y=13 2x+2y= -10 1. Solve the 1st eqn for y. 3x-y=13 -y= -3x+13 y=3x-13 2. Now substitute 3x-13 in for the y in the 2nd equation. 2x+2(3x-13)= -10 Now, solve for x. 2x+6x-26= -10 8x=16 x= ...
M-100 10-2 Square root prop.cwk
... The last section introduced the Quadratic Formula method to solve second degree equations of the form Ax 2 + Bx + C = 0 if the second degree expression cannot be factored or you do not want to solve by factoring. This method can be used to solve ALL Quadratic Equations but it requires more work than ...
... The last section introduced the Quadratic Formula method to solve second degree equations of the form Ax 2 + Bx + C = 0 if the second degree expression cannot be factored or you do not want to solve by factoring. This method can be used to solve ALL Quadratic Equations but it requires more work than ...
chapter 6: chemical reactions: an introduction
... BaCrOz(s) on the product side indicates the formation of a solid. HCI(aq) on the reactant side indicates that there is water present. Brz(l) indicates that the bromine is dissolved in liquid water. COz(g) on the product side indicates that at least one product is a gas. Both products and reactants c ...
... BaCrOz(s) on the product side indicates the formation of a solid. HCI(aq) on the reactant side indicates that there is water present. Brz(l) indicates that the bromine is dissolved in liquid water. COz(g) on the product side indicates that at least one product is a gas. Both products and reactants c ...
Mole/Stoich PowerPoint Notes
... • Step One:Convert grams to moles. • Step Two: Divide each by the smallest number of moles to get subscripts • Step Three: If you do not have a whole number,or one that is reasonably close, multiply by an integer to obtain a whole number. ...
... • Step One:Convert grams to moles. • Step Two: Divide each by the smallest number of moles to get subscripts • Step Three: If you do not have a whole number,or one that is reasonably close, multiply by an integer to obtain a whole number. ...
Chapter 4 Aqueous Reactions and Solution Stoichiometry
... separate ions. As the (aq) designations remind us, CaCl2 , Na2CO3, and NaCl are all dissolved in the solution. Furthermore, they are all strong electrolytes. CaCO3 is an ionic compound, but it is not soluble. We do not write the formula of any insoluble compound as its component ions. Thus, the comp ...
... separate ions. As the (aq) designations remind us, CaCl2 , Na2CO3, and NaCl are all dissolved in the solution. Furthermore, they are all strong electrolytes. CaCO3 is an ionic compound, but it is not soluble. We do not write the formula of any insoluble compound as its component ions. Thus, the comp ...