1) Slope = (-2 +4) / (-5 + 5) = 2/0, the slope is undefined. 2)
... 10) Plot two points (0, 2) and (2, 6) and draw a straight line passing through them. 11) 1990 means x=0, So one point is (0, 17). 1995 means x=5, so second point is (5, 23). Straight line passing through these two points is (y-17) = (23-17)x/5 Or y = 17 + 1.2x 12) y + 3 = (8+3)(x+5)/(-8+5) ...
... 10) Plot two points (0, 2) and (2, 6) and draw a straight line passing through them. 11) 1990 means x=0, So one point is (0, 17). 1995 means x=5, so second point is (5, 23). Straight line passing through these two points is (y-17) = (23-17)x/5 Or y = 17 + 1.2x 12) y + 3 = (8+3)(x+5)/(-8+5) ...
Dr David`s Chemistry Revision Themes
... The 1st ionisation energy of elements in a group decreases as the group is descended. This is because the atoms are increasing in size (increasing atomic radius) as the shielding effect balances the increase in nuclear charge. The outer electrons are becoming further removed from the nucleus and eas ...
... The 1st ionisation energy of elements in a group decreases as the group is descended. This is because the atoms are increasing in size (increasing atomic radius) as the shielding effect balances the increase in nuclear charge. The outer electrons are becoming further removed from the nucleus and eas ...
Examples
... Since Molar Mass is… The number of grams in 1 mole of atoms, ions, or molecules, We can make conversion factors from these. ...
... Since Molar Mass is… The number of grams in 1 mole of atoms, ions, or molecules, We can make conversion factors from these. ...
Stoichiometry, % Comp, Empirical & Molecular Formula
... with a mass of 12.00000 amu (98.892%), and C-13 with a mass of 13.00335 amu (1.108%). What is the average atomic mass. C-12 = 0.98892 x 12.00000 = 11.86704 C-13 = 0.01108 x 13.00335 = 0.14408 C = 12.01 Wow! it matches the periodic table ...
... with a mass of 12.00000 amu (98.892%), and C-13 with a mass of 13.00335 amu (1.108%). What is the average atomic mass. C-12 = 0.98892 x 12.00000 = 11.86704 C-13 = 0.01108 x 13.00335 = 0.14408 C = 12.01 Wow! it matches the periodic table ...
Test - Regents
... This is a test of your knowledge of chemistry. Use that knowledge to answer all questions in this examination. Some questions may require the use of the Reference Tables for Physical Setting/Chemistry. You are to answer all questions in all parts of this examination according to the directions provi ...
... This is a test of your knowledge of chemistry. Use that knowledge to answer all questions in this examination. Some questions may require the use of the Reference Tables for Physical Setting/Chemistry. You are to answer all questions in all parts of this examination according to the directions provi ...
Open questions (66 points total
... 2p 10 Give the electron formula of the ion formed in partial reaction 1, when a H+-ion is extracted from the chloroethane. In the electron formula, put the charge with the correct atom. For some monochloroalkanes, with at least 2 C-atoms per molecule, no alkene formation will take place during a r ...
... 2p 10 Give the electron formula of the ion formed in partial reaction 1, when a H+-ion is extracted from the chloroethane. In the electron formula, put the charge with the correct atom. For some monochloroalkanes, with at least 2 C-atoms per molecule, no alkene formation will take place during a r ...
Regents Review Questions
... cobalt-60, a source of gamma rays, when the radioactivity level falls to 1/8 of its initial level. The nuclide cesium-137 is also a source of radiation for the prevention of food spoilage. ...
... cobalt-60, a source of gamma rays, when the radioactivity level falls to 1/8 of its initial level. The nuclide cesium-137 is also a source of radiation for the prevention of food spoilage. ...
SHORTCUT IN SOLVING LINEAR EQUATIONS (Basic Step to
... existing linear equation solving process very different from what they had learned in their countries. Let’s see what the differences are and how can the existing solving process be improved? The basic difference shows itself in the way we teach students on how to solve a linear equation. We teach t ...
... existing linear equation solving process very different from what they had learned in their countries. Let’s see what the differences are and how can the existing solving process be improved? The basic difference shows itself in the way we teach students on how to solve a linear equation. We teach t ...
algebra ii - MooreMath23
... Property 1: loga1 = 0 because a0 = 1. Example 1: In the equation 140 = 1, the base is 14 and the exponent is 0. Remember that a logarithm is an exponent, and the corresponding logarithmic equation is log14 1 = 0 where the 0 is the exponent. Example 2: In the equation (1/2)0 = 1, the base is ½ and t ...
... Property 1: loga1 = 0 because a0 = 1. Example 1: In the equation 140 = 1, the base is 14 and the exponent is 0. Remember that a logarithm is an exponent, and the corresponding logarithmic equation is log14 1 = 0 where the 0 is the exponent. Example 2: In the equation (1/2)0 = 1, the base is ½ and t ...
problems - chem.msu.su
... 3. What factors affect the solubility of K3[Co(NO2)6] in the mother solution after precipitate formation? Choose the right answers: a) stability constant of complex ion [Co(NO2)6]3–; b) solubility product of the precipitate; c) concentration of K+; d) concentration of Co(II); e) concentration of NO2 ...
... 3. What factors affect the solubility of K3[Co(NO2)6] in the mother solution after precipitate formation? Choose the right answers: a) stability constant of complex ion [Co(NO2)6]3–; b) solubility product of the precipitate; c) concentration of K+; d) concentration of Co(II); e) concentration of NO2 ...
No Slide Title
... • Used to predict how an atom will react with other atoms. • For ionic compounds, ON’s are equal to the ion charge as determined by each atom’s group number • For molecules, ON’s change depending on what atoms they bond to and follow a set of rules. ...
... • Used to predict how an atom will react with other atoms. • For ionic compounds, ON’s are equal to the ion charge as determined by each atom’s group number • For molecules, ON’s change depending on what atoms they bond to and follow a set of rules. ...
Section 4.8: Acid-Base Reactions
... The LiNO3 (aq) dissociates (separates) as soon as it is formed, since all nitrates are soluble in water (see rules below). The Li+ and NO3- are soluble and have not formed a new visible product, so we call these spectator ions. In a net ionic equation, we leave these out, so the only action we obser ...
... The LiNO3 (aq) dissociates (separates) as soon as it is formed, since all nitrates are soluble in water (see rules below). The Li+ and NO3- are soluble and have not formed a new visible product, so we call these spectator ions. In a net ionic equation, we leave these out, so the only action we obser ...
im11
... 66. No, drinking only pure water with no detectable salt content would not be healthy for two main reasons. First, your body requires ions such as sodium, potassium, calcium, and magnesium for normal function. Many of the ions we need come from the water we drink. Second, water devoid of ions is ver ...
... 66. No, drinking only pure water with no detectable salt content would not be healthy for two main reasons. First, your body requires ions such as sodium, potassium, calcium, and magnesium for normal function. Many of the ions we need come from the water we drink. Second, water devoid of ions is ver ...
Name: Northwest Vista College Chem 1311
... 28. A 4.691 g sample of MgCl2 is dissolved in enough water to give 750. mL of solution. What is the magnesium ion concentration in this solution? A) 3.70 x 10–2 M B) 1.05 x 10–2 M C) 6.57 x 10–2 M (NOTE: conc of Mg2+ same as MgCl2 since they are 1:1 in the formula) D) 4.93 x 10–2 M E) 0.131 M 29. Wh ...
... 28. A 4.691 g sample of MgCl2 is dissolved in enough water to give 750. mL of solution. What is the magnesium ion concentration in this solution? A) 3.70 x 10–2 M B) 1.05 x 10–2 M C) 6.57 x 10–2 M (NOTE: conc of Mg2+ same as MgCl2 since they are 1:1 in the formula) D) 4.93 x 10–2 M E) 0.131 M 29. Wh ...
