QualGroupD
... solution contains a significant concentration of NH4+. This can be understood by considering the common ion effect and the following equilibrium: NH3(aq) + H2O(l) NH4+(aq) + OH–(aq) In an NH3/NH4+ buffer solution, this equilibrium is shifted left, reducing the hydroxide ion concentration so that M ...
... solution contains a significant concentration of NH4+. This can be understood by considering the common ion effect and the following equilibrium: NH3(aq) + H2O(l) NH4+(aq) + OH–(aq) In an NH3/NH4+ buffer solution, this equilibrium is shifted left, reducing the hydroxide ion concentration so that M ...
Lecture 14
... 1. Write the correct symbols and formulas for all of the reactants and products. 2. Count the number of each type of atom on BOTH sides of the equation. 3. Insert coefficients until there are the equal numbers of each kind of atom on both sides of the equation. ...
... 1. Write the correct symbols and formulas for all of the reactants and products. 2. Count the number of each type of atom on BOTH sides of the equation. 3. Insert coefficients until there are the equal numbers of each kind of atom on both sides of the equation. ...
Solution
... concentration, i.e., {C} = [C], etc., and therefore under these conditions, Q = [C]c [D]d/[A]a[B]b ...
... concentration, i.e., {C} = [C], etc., and therefore under these conditions, Q = [C]c [D]d/[A]a[B]b ...
Learning Targets - KMHSrm223
... ___ I understand that solutions to inequalities having one variable can be represented on a number line using boundary point(s) and shading. ___ I understand that the boundary point for a solution set of an inequality such as 2x + 3 < 11 is found by solving the equation 2x + 3 = 11. ___ I understand ...
... ___ I understand that solutions to inequalities having one variable can be represented on a number line using boundary point(s) and shading. ___ I understand that the boundary point for a solution set of an inequality such as 2x + 3 < 11 is found by solving the equation 2x + 3 = 11. ___ I understand ...
Chapter 4
... subtract 24 e-, 24 OH- and 12 H2O from each side. 3 N2H4 + 4 BrO3- → 4 Br- + 6 NO + 6 H2O (11) If necessary add spectator ions to get the balanced molecular equation. That is not possible in this case because we started with an unbalanced ionic equation. Then, check the final balance -- all atoms a ...
... subtract 24 e-, 24 OH- and 12 H2O from each side. 3 N2H4 + 4 BrO3- → 4 Br- + 6 NO + 6 H2O (11) If necessary add spectator ions to get the balanced molecular equation. That is not possible in this case because we started with an unbalanced ionic equation. Then, check the final balance -- all atoms a ...
CHEMICAL REACTIONS
... • e.g. Excess dilute nitric acid is added to a solution containing the tetraamminecadmium(II) ion. H+ + [Cd(NH3)4]2+ Æ Cd2+ + NH4+ 6. Lewis acid-base reaction An electron pair acceptor Lewis acid) reacts with an electron-pair donor (Lewis base) to form a coordinate covalent compound. • e.g. BF3(g)+ ...
... • e.g. Excess dilute nitric acid is added to a solution containing the tetraamminecadmium(II) ion. H+ + [Cd(NH3)4]2+ Æ Cd2+ + NH4+ 6. Lewis acid-base reaction An electron pair acceptor Lewis acid) reacts with an electron-pair donor (Lewis base) to form a coordinate covalent compound. • e.g. BF3(g)+ ...
Chapter 2—Chemical Formulas and Composition Stoichiometry
... OBJ: Apply the concept of relative atomic mass. TOP: Atomic Weights 29. The molecular formula for a compound is CX4. If 2.819 g of this compound contains 0.102 g of carbon, what is the atomic weight of X? a. 320 b. 160 c. 35.5 d. 79.9 e. 39.9 ANS: D DIF: Harder Question OBJ: Calculate the atomic wei ...
... OBJ: Apply the concept of relative atomic mass. TOP: Atomic Weights 29. The molecular formula for a compound is CX4. If 2.819 g of this compound contains 0.102 g of carbon, what is the atomic weight of X? a. 320 b. 160 c. 35.5 d. 79.9 e. 39.9 ANS: D DIF: Harder Question OBJ: Calculate the atomic wei ...
Moles - IGCSE STUDY BANK
... Methane in the equation has 1 mole, oxygen has 2 moles, Carbon dioxide has 1 mole and water has 2 moles. Now we have to recognize that which reactant is in excess. Methane has 1 mole and 60 cm3 of volume where as oxygen has 2 moles and its volume is 100 cm3 So, 1 moles of oxygen has 50 cm3 of volume ...
... Methane in the equation has 1 mole, oxygen has 2 moles, Carbon dioxide has 1 mole and water has 2 moles. Now we have to recognize that which reactant is in excess. Methane has 1 mole and 60 cm3 of volume where as oxygen has 2 moles and its volume is 100 cm3 So, 1 moles of oxygen has 50 cm3 of volume ...
1. Bromine exists naturally as a mixture of bromine
... How many of the following statements are true concerning chemical equations? I. Coefficients can be fractions. II. Subscripts can be fractions. III. Coefficients represent the relative masses of the reactants and/or products. IV. Changing the subscripts to balance an equation can only be done once. ...
... How many of the following statements are true concerning chemical equations? I. Coefficients can be fractions. II. Subscripts can be fractions. III. Coefficients represent the relative masses of the reactants and/or products. IV. Changing the subscripts to balance an equation can only be done once. ...
