Fall Final Rev 2014
... °C. What is the volume of the cold balloon? The pressure and amount of gas remain constant. b. A small gas cylinder contains 3.22 L of argon at 11.7 atm pressure. What is the volume of the gas at 1.05 atm? Assume temperature and amount of gas remain constant. c. 325 mL of air at room pressure (765 m ...
... °C. What is the volume of the cold balloon? The pressure and amount of gas remain constant. b. A small gas cylinder contains 3.22 L of argon at 11.7 atm pressure. What is the volume of the gas at 1.05 atm? Assume temperature and amount of gas remain constant. c. 325 mL of air at room pressure (765 m ...
Enzymes: “Helper” Protein molecules
... Each enzyme is the specific helper to a specific reaction each enzyme needs to be the right shape for the job enzymes are named for the reaction they help ...
... Each enzyme is the specific helper to a specific reaction each enzyme needs to be the right shape for the job enzymes are named for the reaction they help ...
PRACTICE EXAM for FALL 2013 FINAL EXAM (Unit 6 + review) 1
... °C. What is the volume of the cold balloon? The pressure and amount of gas remain constant. b. A small gas cylinder contains 3.22 L of argon at 11.7 atm pressure. What is the volume of the gas at 1.05 atm? Assume temperature and amount of gas remain constant. c. 325 mL of air at room pressure (765 m ...
... °C. What is the volume of the cold balloon? The pressure and amount of gas remain constant. b. A small gas cylinder contains 3.22 L of argon at 11.7 atm pressure. What is the volume of the gas at 1.05 atm? Assume temperature and amount of gas remain constant. c. 325 mL of air at room pressure (765 m ...
Chapter 3 Mass Relationships in Chemical Reactions
... 89. One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na5(CO3)2(HCO3)·2H2O, Na5(CO3)2(HCO3)·2H2O(s) → 5Na2CO3(s) + CO2(g) + 3H2O(g) When 1.00 metric ton (1 × 103 kg) of trona is decomposed, 0.74 metric ton of Na2CO3 is recovered. What is the percent yield ...
... 89. One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na5(CO3)2(HCO3)·2H2O, Na5(CO3)2(HCO3)·2H2O(s) → 5Na2CO3(s) + CO2(g) + 3H2O(g) When 1.00 metric ton (1 × 103 kg) of trona is decomposed, 0.74 metric ton of Na2CO3 is recovered. What is the percent yield ...
9/6/12 - Note: Once it is downloaded, click SET
... Compounds are Pure Substances - Pure substances that are not elements are compounds. Compounds are composed of more than one kind of atom. o Example: carbon dioxide - There may be easier ways of preparing them, but compounds can be made from their elements. - Compounds can be broken down into their ...
... Compounds are Pure Substances - Pure substances that are not elements are compounds. Compounds are composed of more than one kind of atom. o Example: carbon dioxide - There may be easier ways of preparing them, but compounds can be made from their elements. - Compounds can be broken down into their ...
Matter - Clayton State University
... - Pure substances that cannot be reduced to simpler substances by normal chemical means - Fundamental building blocks of all matter Examples silver, carbon, sodium, oxygen, hydrogen - Note that O2, N2, S8, are elements ...
... - Pure substances that cannot be reduced to simpler substances by normal chemical means - Fundamental building blocks of all matter Examples silver, carbon, sodium, oxygen, hydrogen - Note that O2, N2, S8, are elements ...
Introductory Chemistry, 2nd Edition Nivaldo Tro
... We can use the ratios of the coefficients to convert between moles of substances in a chemical reaction ...
... We can use the ratios of the coefficients to convert between moles of substances in a chemical reaction ...
Bk2P06EE
... To determine the standard electrode potential of the I2(aq) / I(aq) system, a solution containing iodine and potassium iodide (each of concentration 1 mol dm3) is prepared. A platinum electrode is dipped into this solution. This is the I2(aq) / I(aq) half-cell. The half-cell of I2(aq) / I(aq) is ...
... To determine the standard electrode potential of the I2(aq) / I(aq) system, a solution containing iodine and potassium iodide (each of concentration 1 mol dm3) is prepared. A platinum electrode is dipped into this solution. This is the I2(aq) / I(aq) half-cell. The half-cell of I2(aq) / I(aq) is ...
Chemistry Simulations
... This simulation allows the students to see how they can put energy into the system to overcome the activation energy. They can increase the temperature as well as the number of molecules. There is also a timer feature, so students can measure how long it takes for a reaction to occur, and how the ra ...
... This simulation allows the students to see how they can put energy into the system to overcome the activation energy. They can increase the temperature as well as the number of molecules. There is also a timer feature, so students can measure how long it takes for a reaction to occur, and how the ra ...
Unit 8: Reactions
... If 15.0 g of nitrogen gas reacts with 3.2 g of hydrogen gas, how many grams of ammonia gas will be formed? _1_ N2(g) + _3_ H2(g) _2_ NH3(g) 15.0 g of N2(g) + 3.2 g of H2(g) = 18.2 g of N & H 18.2 g of NH3(g) ...
... If 15.0 g of nitrogen gas reacts with 3.2 g of hydrogen gas, how many grams of ammonia gas will be formed? _1_ N2(g) + _3_ H2(g) _2_ NH3(g) 15.0 g of N2(g) + 3.2 g of H2(g) = 18.2 g of N & H 18.2 g of NH3(g) ...
here - Chemical Engineering
... For each mole of hydrogen consumed, two moles of electrons are passed through the electric load. To convert electron flow (moles of electrons/s) to electrical current (coulombs/s or amps), one would use Faraday’s constant: F 96,485 coulombs / mole of electrons. The primary objective of a fuel cell ...
... For each mole of hydrogen consumed, two moles of electrons are passed through the electric load. To convert electron flow (moles of electrons/s) to electrical current (coulombs/s or amps), one would use Faraday’s constant: F 96,485 coulombs / mole of electrons. The primary objective of a fuel cell ...
www.XtremePapers.com
... Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included ...
... Permission to reproduce items where third-party owned material protected by copyright is included has been sought and cleared where possible. Every reasonable effort has been made by the publisher (UCLES) to trace copyright holders, but if any items requiring clearance have unwittingly been included ...
Redox - edl.io
... where each oxygen is assigned an oxidation state of -1, as in hydrogen peroxide (H2O2), and OF2 in which oxygen is assigned a +2 oxidation state. 6. In its covalent compounds with nonmetals, hydrogen is assigned an oxidation state of +1. Metal hydrides are an exception; H is at the end of the chemic ...
... where each oxygen is assigned an oxidation state of -1, as in hydrogen peroxide (H2O2), and OF2 in which oxygen is assigned a +2 oxidation state. 6. In its covalent compounds with nonmetals, hydrogen is assigned an oxidation state of +1. Metal hydrides are an exception; H is at the end of the chemic ...
Thermodynamics
... The required reaction in terms of dissociation energy is OH(g) ✆ O(g) + H(g); ✄H = ? This equation can be achieved by (a) reversing the equation (i), (b) dividing equation (ii) and (iii) each by 2, and (c) adding the three resulting equations. OH(g) ✆ 1/2 H2(g) + 1/2 O2(g); ✄H = + 10.06 kcal [Revers ...
... The required reaction in terms of dissociation energy is OH(g) ✆ O(g) + H(g); ✄H = ? This equation can be achieved by (a) reversing the equation (i), (b) dividing equation (ii) and (iii) each by 2, and (c) adding the three resulting equations. OH(g) ✆ 1/2 H2(g) + 1/2 O2(g); ✄H = + 10.06 kcal [Revers ...
高雄醫學大學九十二學年度學士後醫學系招生考試試題 科目:化學 考試
... 14. The order of the end point sharpness for titration of 50-mL of I-, BrO3-, Br- and Cl- with AgNO3 in the same concentration is (A) I- > BrO3- > Br- > Cl- (B) I- > Br- > BrO3- > Cl- (C) I- > Br- > Cl- > BrO3- (D) BrO3- > I- > Br- > Cl(E) BrO3- > Cl- > I- > Br15. Which one is not correct about stan ...
... 14. The order of the end point sharpness for titration of 50-mL of I-, BrO3-, Br- and Cl- with AgNO3 in the same concentration is (A) I- > BrO3- > Br- > Cl- (B) I- > Br- > BrO3- > Cl- (C) I- > Br- > Cl- > BrO3- (D) BrO3- > I- > Br- > Cl(E) BrO3- > Cl- > I- > Br15. Which one is not correct about stan ...
organic chemistry - Peoria Public Schools
... It is because of this greater reactivity that alkenes, especially ethene, are important starting materials in organic synthesis of useful chemicals. It is important to note that alkenes also easily combust and undergo both complete and incomplete combustion. Alkanes undergo addition reaction that me ...
... It is because of this greater reactivity that alkenes, especially ethene, are important starting materials in organic synthesis of useful chemicals. It is important to note that alkenes also easily combust and undergo both complete and incomplete combustion. Alkanes undergo addition reaction that me ...
Chapter 1: Moles and equations - Assets
... 2 What mass of sodium hydroxide, NaOH, is present in 0.25 mol of sodium hydroxide? ...
... 2 What mass of sodium hydroxide, NaOH, is present in 0.25 mol of sodium hydroxide? ...
Stoichiometry
Stoichiometry /ˌstɔɪkiˈɒmɨtri/ is the calculation of relative quantities of reactants and products in chemical reactions.Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of product can be empirically determined, then the amount of the other reactants can also be calculated.As seen in the image to the right, where the balanced equation is:CH4 + 2 O2 → CO2 + 2 H2O.Here, one molecule of methane reacts with two molecules of oxygen gas to yield one molecule of carbon dioxide and two molecules of water. Stoichiometry measures these quantitative relationships, and is used to determine the amount of products/reactants that are produced/needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry. In the example above, reaction stoichiometry measures the relationship between the methane and oxygen as they react to form carbon dioxide and water.Because of the well known relationship of moles to atomic weights, the ratios that are arrived at by stoichiometry can be used to determine quantities by weight in a reaction described by a balanced equation. This is called composition stoichiometry.Gas stoichiometry deals with reactions involving gases, where the gases are at a known temperature, pressure, and volume and can be assumed to be ideal gases. For gases, the volume ratio is ideally the same by the ideal gas law, but the mass ratio of a single reaction has to be calculated from the molecular masses of the reactants and products. In practice, due to the existence of isotopes, molar masses are used instead when calculating the mass ratio.