![- Catalyst](http://s1.studyres.com/store/data/015456786_1-b1a9a94a4545b3cd4969b16f3364b309-300x300.png)
K c
... condensed phase are expressed in mol/L (M). In the gaseous phase, the concentrations can be expressed in M. 2. The concentrations of pure solids, pure liquids and solvents do not appear in the equilibrium constant expressions. 3. The equilibrium constant is a dimensionless quantity. 4. In quoting a ...
... condensed phase are expressed in mol/L (M). In the gaseous phase, the concentrations can be expressed in M. 2. The concentrations of pure solids, pure liquids and solvents do not appear in the equilibrium constant expressions. 3. The equilibrium constant is a dimensionless quantity. 4. In quoting a ...
rate - Killeen ISD
... rate= [NO2][F2] This suggests that the rxn does not occur in a single step Thus, this reaction (as many more) must occur in multiple ...
... rate= [NO2][F2] This suggests that the rxn does not occur in a single step Thus, this reaction (as many more) must occur in multiple ...
Question Bank - Edudel.nic.in
... this mineral there are 4 Ca2+ ions and 8F– ions and that Ca2+ ions are arranged in a fcc lattice. The F– ions fill all the tetrahedral holes in the fcc lattice of Ca2+ ions. The edge of the unit cell is 5.46 × 10–8 cm in length. The density of the solid is 3.18 g cm–3 use this information to calcula ...
... this mineral there are 4 Ca2+ ions and 8F– ions and that Ca2+ ions are arranged in a fcc lattice. The F– ions fill all the tetrahedral holes in the fcc lattice of Ca2+ ions. The edge of the unit cell is 5.46 × 10–8 cm in length. The density of the solid is 3.18 g cm–3 use this information to calcula ...
SOLLIQSOL questions
... (d) Does the liquid phase of argon have a density greater than, equal to, or less than the density of the solid phase? Explain your answer, using information given in the introduction to this question. 1989 D Consider three unlabeled bottles, each contain small pieces of one of the following metals. ...
... (d) Does the liquid phase of argon have a density greater than, equal to, or less than the density of the solid phase? Explain your answer, using information given in the introduction to this question. 1989 D Consider three unlabeled bottles, each contain small pieces of one of the following metals. ...
Chem13-14PrecipABNeut
... When to Do the Lessons: You will receive the maximum benefit from these lessons by completing each topic before it is addressed in your class. Where to Start and Lesson Sequence: The order of these lessons may not always match the order in which topics are covered in your course. If you are using th ...
... When to Do the Lessons: You will receive the maximum benefit from these lessons by completing each topic before it is addressed in your class. Where to Start and Lesson Sequence: The order of these lessons may not always match the order in which topics are covered in your course. If you are using th ...
CONVERSION OF NITROGEN OXIDES AND AROMATIC VOLATILE
... case of oxygen, in accordance with experimental results. Oxidation reaction occurs with heat release, but the system is maintained in autothermal regime. In the case of occurrence of benzene total oxidation reaction in adiabatic regime, at a concentration of 50 ppm, temperature variation is equal to ...
... case of oxygen, in accordance with experimental results. Oxidation reaction occurs with heat release, but the system is maintained in autothermal regime. In the case of occurrence of benzene total oxidation reaction in adiabatic regime, at a concentration of 50 ppm, temperature variation is equal to ...
File
... SCH4U b) Determine the oxidation number of the sulfur in the sulfate ion, SO4-2. Remember that the sum of the oxidation numbers must equal the charge of the ion. Step 1: Write All Known Oxidation Numbers Use the symbol N to represent the oxidation number of sulfur in the sulfate. ...
... SCH4U b) Determine the oxidation number of the sulfur in the sulfate ion, SO4-2. Remember that the sum of the oxidation numbers must equal the charge of the ion. Step 1: Write All Known Oxidation Numbers Use the symbol N to represent the oxidation number of sulfur in the sulfate. ...
REDOX EQUILIBRIA SL - chemistryatdulwich
... reduced. Therefore the reactivity of a metal or non-metal is about how easily it is oxidized or reduced or how strong a reducing or oxidizing agent it is. The strength of an oxidising or reducing agent can be found by using it in displacement reactions with other oxidising or reducing agents e.g. li ...
... reduced. Therefore the reactivity of a metal or non-metal is about how easily it is oxidized or reduced or how strong a reducing or oxidizing agent it is. The strength of an oxidising or reducing agent can be found by using it in displacement reactions with other oxidising or reducing agents e.g. li ...
REDOX EQUILIBRIA SL - chemistryatdulwich
... reduced. Therefore the reactivity of a metal or non-metal is about how easily it is oxidized or reduced or how strong a reducing or oxidizing agent it is. The strength of an oxidising or reducing agent can be found by using it in displacement reactions with other oxidising or reducing agents e.g. li ...
... reduced. Therefore the reactivity of a metal or non-metal is about how easily it is oxidized or reduced or how strong a reducing or oxidizing agent it is. The strength of an oxidising or reducing agent can be found by using it in displacement reactions with other oxidising or reducing agents e.g. li ...
Equilib - C.R.C.T.
... between H2O(g) [ideal gas phase] and H2O(L1) [i.e., the ideal boiling point] Equilib 9.2 ...
... between H2O(g) [ideal gas phase] and H2O(L1) [i.e., the ideal boiling point] Equilib 9.2 ...
The Mole - Bakersfield College
... atoms, ions, or formula units) or from particles to moles, use Avogadro’s number as your conversion factor. ...
... atoms, ions, or formula units) or from particles to moles, use Avogadro’s number as your conversion factor. ...
Deuterium fractionation of methylamine through atomic grain
... Institute of Low Temperature Science, Hokkaido University, Japan Interstellar methylamine (CH3NH2) was first found in 1974 toward Sgr B2 and Ori A [1]. This finding is of interest in view of astrobiology because methylamine could be a precursor of amino acid in space [2]. Laboratory studies revealed ...
... Institute of Low Temperature Science, Hokkaido University, Japan Interstellar methylamine (CH3NH2) was first found in 1974 toward Sgr B2 and Ori A [1]. This finding is of interest in view of astrobiology because methylamine could be a precursor of amino acid in space [2]. Laboratory studies revealed ...
431 KB / 47 pages
... iodide, I–(aq)), so iodine, I2(aq), must have been produced at this electrode and reacted with I– (aq). Thus, the anodic reaction is probably the oxidation of I–(aq) to give I2(aq): 2I–(aq) →I2(aq) + 2e– The cathodic reaction must be the reduction of water to yield hydrogen gas and hydroxide in solu ...
... iodide, I–(aq)), so iodine, I2(aq), must have been produced at this electrode and reacted with I– (aq). Thus, the anodic reaction is probably the oxidation of I–(aq) to give I2(aq): 2I–(aq) →I2(aq) + 2e– The cathodic reaction must be the reduction of water to yield hydrogen gas and hydroxide in solu ...
EquiSage
... between H2O(g) [ideal gas phase] and H2O(L1) [i.e., the ideal boiling point] Equilib 9.2 ...
... between H2O(g) [ideal gas phase] and H2O(L1) [i.e., the ideal boiling point] Equilib 9.2 ...
Lab #3 – A Microscale Study of Chemical Changes
... of your graph paper as possible, and use a separate color for the best-fit line for each of the sets of data. ...
... of your graph paper as possible, and use a separate color for the best-fit line for each of the sets of data. ...
7. A timeline of symbols and signs in chemistry
... would be an algebraic meaning. The second + sign means ‘and also’, implying that the chemicals are not combined. Again, use of ‘plus’ would be inappropriate. The arrow is another indication that these are chemical equations, not algebraic equations, where an = sign would be expected. The equations ...
... would be an algebraic meaning. The second + sign means ‘and also’, implying that the chemicals are not combined. Again, use of ‘plus’ would be inappropriate. The arrow is another indication that these are chemical equations, not algebraic equations, where an = sign would be expected. The equations ...
1.02 x 10 = 3 mol lit 3.4 x 10
... All working, including rough work, should be done on the same sheet as, and adjacent to, the rest of the answer. The intended marks for questions or parts of questions are given in brackets [ ]. Balanced equations must be given wherever possible and diagrams where they are helpful. When solving nume ...
... All working, including rough work, should be done on the same sheet as, and adjacent to, the rest of the answer. The intended marks for questions or parts of questions are given in brackets [ ]. Balanced equations must be given wherever possible and diagrams where they are helpful. When solving nume ...
Chapter 4 Aqueous Reactions and Solution Stoichiometry
... the ions that each contains. We then correlate these charged ionic species with the ones shown in the diagram. Solve: The diagram shows twice as many cations as anions, consistent with the formulation K 2SO4. Aqueous Check: Notice that the total net charge in the diagram is zero, as it must be if it ...
... the ions that each contains. We then correlate these charged ionic species with the ones shown in the diagram. Solve: The diagram shows twice as many cations as anions, consistent with the formulation K 2SO4. Aqueous Check: Notice that the total net charge in the diagram is zero, as it must be if it ...
aq - Haverford Alchemy
... the ions that each contains. We then correlate these charged ionic species with the ones shown in the diagram. Solve: The diagram shows twice as many cations as anions, consistent with the formulation K 2SO4. Aqueous Check: Notice that the total net charge in the diagram is zero, as it must be if it ...
... the ions that each contains. We then correlate these charged ionic species with the ones shown in the diagram. Solve: The diagram shows twice as many cations as anions, consistent with the formulation K 2SO4. Aqueous Check: Notice that the total net charge in the diagram is zero, as it must be if it ...
Stoichiometry
![](https://commons.wikimedia.org/wiki/Special:FilePath/Combustion_reaction_of_methane.jpg?width=300)
Stoichiometry /ˌstɔɪkiˈɒmɨtri/ is the calculation of relative quantities of reactants and products in chemical reactions.Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of product can be empirically determined, then the amount of the other reactants can also be calculated.As seen in the image to the right, where the balanced equation is:CH4 + 2 O2 → CO2 + 2 H2O.Here, one molecule of methane reacts with two molecules of oxygen gas to yield one molecule of carbon dioxide and two molecules of water. Stoichiometry measures these quantitative relationships, and is used to determine the amount of products/reactants that are produced/needed in a given reaction. Describing the quantitative relationships among substances as they participate in chemical reactions is known as reaction stoichiometry. In the example above, reaction stoichiometry measures the relationship between the methane and oxygen as they react to form carbon dioxide and water.Because of the well known relationship of moles to atomic weights, the ratios that are arrived at by stoichiometry can be used to determine quantities by weight in a reaction described by a balanced equation. This is called composition stoichiometry.Gas stoichiometry deals with reactions involving gases, where the gases are at a known temperature, pressure, and volume and can be assumed to be ideal gases. For gases, the volume ratio is ideally the same by the ideal gas law, but the mass ratio of a single reaction has to be calculated from the molecular masses of the reactants and products. In practice, due to the existence of isotopes, molar masses are used instead when calculating the mass ratio.