Honors_Physics_-_Circular_Motion
... TOWARDS the CENTER. To find the MAGNITUDES of each we have: ...
... TOWARDS the CENTER. To find the MAGNITUDES of each we have: ...
PHYS632_L13_ch_33_El..
... polarizing sheets whose polarizing directions make angles of 1 = 40o, 2 = 20o, and 3 = 40o with the direction of the y axis. What percentage of the light’s initial intensity is transmitted by the system? (Hint: Be careful with the angles.) Let Io be the intensity of the unpolarized light that is ...
... polarizing sheets whose polarizing directions make angles of 1 = 40o, 2 = 20o, and 3 = 40o with the direction of the y axis. What percentage of the light’s initial intensity is transmitted by the system? (Hint: Be careful with the angles.) Let Io be the intensity of the unpolarized light that is ...
Changes of Motion
... • What does the slope represent (for both)? •What does the area under the v-t graph represent? graphing review ...
... • What does the slope represent (for both)? •What does the area under the v-t graph represent? graphing review ...
Circular Motion - the SASPhysics.com
... • Velocity is constantly changing, so mass is constantly accelerating towards centre of circle • So there is a constant force on the mass towards the centre of the circle – Tension in string (until you let go!) ...
... • Velocity is constantly changing, so mass is constantly accelerating towards centre of circle • So there is a constant force on the mass towards the centre of the circle – Tension in string (until you let go!) ...
File
... The momentum of an object depends on mass and velocity. Momentum is how hard it is to stop an object that is moving. Momentum is a (vector/scalar) quantity. vector – it has magnitude and direction Write a sentence that uses the word “momentum” that demonstrates that you know the meaning of the word. ...
... The momentum of an object depends on mass and velocity. Momentum is how hard it is to stop an object that is moving. Momentum is a (vector/scalar) quantity. vector – it has magnitude and direction Write a sentence that uses the word “momentum” that demonstrates that you know the meaning of the word. ...
Test 3 Preparation Questions
... B10. An electron is placed in a region of space where there is a uniform electric field which is in the +y direction as shown. The magnitude of the electric field is 51.0 V/m. Determine the magnitude and direction of the force on the electron. ...
... B10. An electron is placed in a region of space where there is a uniform electric field which is in the +y direction as shown. The magnitude of the electric field is 51.0 V/m. Determine the magnitude and direction of the force on the electron. ...
Test 3 Preparation Questions
... B10. An electron is placed in a region of space where there is a uniform electric field which is in the +y direction as shown. The magnitude of the electric field is 51.0 V/m. Determine the magnitude and direction of the force on the electron. ...
... B10. An electron is placed in a region of space where there is a uniform electric field which is in the +y direction as shown. The magnitude of the electric field is 51.0 V/m. Determine the magnitude and direction of the force on the electron. ...
Formula: F coefficent of friction*m*g
... Find omega from this: m*omega^2*r = tension, and use omega here: T= 2*pi/omega 12) You are taking a turn at 39.0 m/s on a ramp of radius 29.0 m. What is your acceleration? A) 0.744 m/s2 B) 52.4 m/s2 C) 1.34 m/s2 D) 21.6 m/s2 a = v^2/r 13) An aircraft performs a maneuver called an aileron roll. Durin ...
... Find omega from this: m*omega^2*r = tension, and use omega here: T= 2*pi/omega 12) You are taking a turn at 39.0 m/s on a ramp of radius 29.0 m. What is your acceleration? A) 0.744 m/s2 B) 52.4 m/s2 C) 1.34 m/s2 D) 21.6 m/s2 a = v^2/r 13) An aircraft performs a maneuver called an aileron roll. Durin ...
Slide 1
... planet P2 At the position shown, the magnitude of the gravitational force of planet P1 on the spacecraft is equal to the magnitude of the gravitational force of planet P2 on the spacecraft. If distance X is greater than distance Y, then the mass of P1 must be A) less than the mass of P2 B) greater t ...
... planet P2 At the position shown, the magnitude of the gravitational force of planet P1 on the spacecraft is equal to the magnitude of the gravitational force of planet P2 on the spacecraft. If distance X is greater than distance Y, then the mass of P1 must be A) less than the mass of P2 B) greater t ...
Topic 6 - Interference
... Frequency of the radiation is constant, so from v = fλ, wavelength must decrease by a factor of 1/n. (NB refractive index depends on the wavelength of the light) ...
... Frequency of the radiation is constant, so from v = fλ, wavelength must decrease by a factor of 1/n. (NB refractive index depends on the wavelength of the light) ...
July 2010
... considered to be different from the Doppler effect. Doppler shifts are caused by relative motion. In that case, the photons are not losing or gaining energy; they just look different to you than they do to the emitter. In contrast, most general relativity or cosmology textbooks say, cosmological red ...
... considered to be different from the Doppler effect. Doppler shifts are caused by relative motion. In that case, the photons are not losing or gaining energy; they just look different to you than they do to the emitter. In contrast, most general relativity or cosmology textbooks say, cosmological red ...
TWGHs. Kap Yan Directors` College
... D. The coin falls faster than the feather, but both take a shorter time than if they were falling from the same height on Earth. 31. A bullet of mass 0.02 kg travelling horizontally at 100 m s-1 is stopped by 0.1 m of concrete. What is the resistive force on the bullet by the concrete? A. 2 N ...
... D. The coin falls faster than the feather, but both take a shorter time than if they were falling from the same height on Earth. 31. A bullet of mass 0.02 kg travelling horizontally at 100 m s-1 is stopped by 0.1 m of concrete. What is the resistive force on the bullet by the concrete? A. 2 N ...
Name
... 42. A uniform bridge span weighs 50 x 103 N and is 40.0 m long. An automobile weighing 15 x 103 N is parked with its center of gravity located 12.0 m from the right pier. What upward support force is provided by the left pier? 43. A child wants to use a 10 kg board that is 3.5 m long as a seesaw. S ...
... 42. A uniform bridge span weighs 50 x 103 N and is 40.0 m long. An automobile weighing 15 x 103 N is parked with its center of gravity located 12.0 m from the right pier. What upward support force is provided by the left pier? 43. A child wants to use a 10 kg board that is 3.5 m long as a seesaw. S ...
marking scheme - The Physics Teacher
... In considering this marking scheme the following points should be noted: 1. In many instances only key words are given – words that must appear in the correct context in the candidate’s answer in order to merit the assigned marks. 2. Words, expressions or statements separated by a solidus, /, are al ...
... In considering this marking scheme the following points should be noted: 1. In many instances only key words are given – words that must appear in the correct context in the candidate’s answer in order to merit the assigned marks. 2. Words, expressions or statements separated by a solidus, /, are al ...
ppt
... In order for it to orbit twice every 24 hours, it must be A. Closer to the Earth B. Farther from the Earth. C. Same distance but moving twice as fast. Centripetal acceleration is v2/r. This acceleration is due to the gravitational force, so equals g, and is constant for all orbits. The speed v is (c ...
... In order for it to orbit twice every 24 hours, it must be A. Closer to the Earth B. Farther from the Earth. C. Same distance but moving twice as fast. Centripetal acceleration is v2/r. This acceleration is due to the gravitational force, so equals g, and is constant for all orbits. The speed v is (c ...
CP PHYSICS
... CP PHYSICS, FINAL EXAM REVIEW – Fall 2008, page 2 13. A semi truck accelerates at 0.64 m/s2 over a distance of 125 m and reaches a velocity of 17 m/s. What was the truck’s initial velocity? 14. How fast does an object move after falling: a. .25 s b. .50 s c. 1.0 s d. 2.0 s 15. When perpendicular ve ...
... CP PHYSICS, FINAL EXAM REVIEW – Fall 2008, page 2 13. A semi truck accelerates at 0.64 m/s2 over a distance of 125 m and reaches a velocity of 17 m/s. What was the truck’s initial velocity? 14. How fast does an object move after falling: a. .25 s b. .50 s c. 1.0 s d. 2.0 s 15. When perpendicular ve ...